A sum of Rs.41 was divided among 50 boys and girls. Each boy gets 90 paise and a girl 65 paisa. The

Ramdas Singathiya   9 years AGO

assume No. of boys=X
No. of Girls=Y
so

X+Y=50....................(1)
90X+65Y=4100...........(2)

solve these two we get X=34

Like? Yes (34) | No (9)  

viswambher   9 years AGO

let the no of boys =x
no. of girls =y
total no. of boys and girls = x+y =50
each boys gets 90 paise
each girl 65paise
all the boys get 90x paise
girls get 65y paise
total amount 4100 paise

solving
x+y=50
90x+65y=4100
we get x=34
so total no. of boys =34

Like? Yes (11) | No (1)  

ANANTHI.P   9 years AGO

NUMBER OF BOYS=X
NUMBER OF GIRLS=50-X
Xx90+(50-X)x65==4100 PAISE
X=34

Like? Yes (9) | No   

devvrata   9 years AGO

X + Y=50
90X +65Y=4100
By solving this equation we will get X=34

Like? Yes (6) | No   

Radhika   9 years AGO

Let the number of boys be 'x'
let the number of girls be 'y'
then x+y=50 -------------------------- (eq 1)
and 90x+65y=4100 (in paise) --------------(eq 2)
By solving (eq 1) and (eq 2) we get the number of boys is 34 and girls is 16.
Therefore, ans is 34

Like? Yes (6) | No (1)  

prabhat kumar   9 years AGO

let
x no. of boys
y no. of girls
x+y=50
X×90/100+Y×65/100=41
X=34

Like? Yes (5) | No (1)  

padam   9 years AGO

use alligation techniques convert 41rs in paise and divie by 50 to get average
now on soving aligation ratio of boys and girls is 17:8 and boys+girls =50 so boys are 34 and girls are 16

Like? Yes (8) | No (4)  

vishnuvardhan   9 years AGO

0.9b+0.65g=41
b+g=50
b=34
g=16

Like? Yes (4) | No   

poojasaisri   9 years AGO

b+g=50 eqn 1
90b+65g=4100 eqn 2
solving eqn 1 and eqn 2
we get
90b+65g=4100
65b+65g=3250
25b=850
b=34

Like? Yes (3) | No   

ABHINAV PUSHPAM   9 years AGO

Let X be number of boys and (50-X) be number of girls.
=>.90x+.65(50-x)=41
=>.25x=8.5
=>x=34
option 10)

Like? Yes (4) | No (2)  

Yathiraj   9 years AGO

Let B be no. of Boys and G be no. of Girls
B+G = 50
Each boy gets 90 paise and each girl gets 65 paisa and total is 41 rupees
Hence,
0.9B + 0.65G = 41
G=50-B
0.9B + 0.65(50-B)=41
0.9B + 32.5 - 0.65B = 41
0.25B = 8.5
B=34

Option 10.

Like? Yes (2) | No   

SAKTHEESVARI S   9 years AGO

90*boys+65*girls=4100paise:
hence,90*34+65*(50-34)=4100 paise;
so 34 boys

Like? Yes (2) | No   

vivek   9 years AGO

x+y = 50
90x+65y=4100
so, x= 34

Like? Yes (2) | No   

mahak saha   9 years AGO

let the no girls & boys be x & y resptvly
then, x+y=50
and .9y+.65x=41
solve for x & y
then y=34 is the ans

Like? Yes (2) | No   

Supriya Mondal   9 years AGO

Let, number of boys x
Then we can write,
.9*x+.65*(x-50)=41
Solving this equation we get x=34
So, option 10)34 is the right answer

Like? Yes (2) | No   

aman aditya   9 years AGO

Solving equation
X+y=50
And
.90x+.65y=41
Where x= boys
Y=girls
X=34
Y=16

Like? Yes (1) | No   

Karthick Raja   9 years AGO

ASSUME BOYS X AND ASSUME GIRLS Y
X + Y = 50 ------>EQN1
BOYS GET 0.90
GIRLS GET 0.65
0.90X + 0.65 Y = 41 ----> EQN2

(EQN 1 * 0.65) - EQN 2
0.65X + 0.65Y = 32.5 (-)
0.90X + 0.65Y = 41
-0.25X = -8.5
X = (8.5/0.25)
X = 34
TOTAL NUMBER OF BOYS = 34

Like? Yes (1) | No   

MRITUNJAY   9 years AGO

x*0.9+(50-x)*0.65=41
solve this we get
0.25*x=8.5
x= 34
so number of boys is 34
option 10

Like? Yes (1) | No   

Akhil Malhotra   9 years AGO

Let number of boys=x nd number of girls =y
90x+65y=4100
x+y=50
Put value of y frm dis in first
90x+65(50-x)=4100
Solving this we get x=34

Like? Yes (1) | No   

sravani   9 years AGO

let the boys be x.
x(90)+(50-x)65=41*100Paise
x=34.

Like? Yes (1) | No   

N.Dayanithi   9 years AGO

No of Boys and Girls = 50
If Boys = 34, 34*0.9 = 30.6
Then girls will be 16, 16*0.65 = 10.4
30.6 + 10.4 = 41
So no.of Boys = 34

Like? Yes (1) | No   

NESAB JAFAR   9 years AGO

x+y=50
90X+65Y=4100
x=34 num of boys

Like? Yes (1) | No   

Ankita Anand   9 years AGO

90x+65(50-x)=4100
90x-65x=4100-3250
25x=850
x=34

Like? Yes (1) | No   

sompon temtheerakij   9 years AGO

let number of boys = A , number of girl = B
A+B = 50.....1
90A+65B = 4100.....2
A = 34

Like? Yes (1) | No   

Shubham Khandelwal   9 years AGO

X = Number of boys and Y = Number of girls.
X + Y = 50
also 90X + 65Y = 4100
Equating these equations will give X = 34 and Y = 16

Like? Yes (1) | No   

Aishwariya    9 years AGO

Average amount is 82 p(41*2) by allgation and mixture ratio of amounts are
for grls 90-82= 8
for boys it is 82-65 = 17
the ratio of boys to girls are 17:8
the no of boys are: (17/25)*50 = 34

Like? Yes (1) | No   

Girjesh kumar   9 years AGO

Let number of boys are X and number of girls are Y.
then according to problem ....
0.9X + 0.65Y = 41
so now....
Y = (4100 - 90x)/65 --------
and the total number of boys and girls are 50..so
X + Y = 50 ---------
after solving these 2 equation...we get
X = 34
so the number of boys are 34

Like? Yes (1) | No   

shivangi   9 years AGO

b=90paise
g=65paise
90b+65g=41*100paise=4100
n total money=45*100paise
hence b+g=4500
on solving 2 equations ,we get
g=16 and 50-16=34 boys

Like? Yes (1) | No   

naina shukla    9 years AGO

we can check the ans from solution
we take 34 then 34*90=3060
i.e. rs30.60
then no og girls =16, i.e. 16*65=1040. i.e rs 10.40
10.40+30.60=41
so , option (10) is correct answer.

Like? Yes (1) | No   

Deepthi   9 years AGO

let no of boys -X
let no of girls-Y
Total money is 41
i.e 90/100*x+65/100*y=41
we get 18X+13Y=820--------------1
Total members -50
so X+Y=50--------------------2
solving 2 eqns we get X=34 and Y=16

Like? Yes (1) | No   

Pradyumna K S   9 years AGO

Let x be the number of boys. Then 50-x is the number of girls.
given that each boy gets 90 paise and a girl 65 paisa.
This can be written as
90x+(50-x)65=4100
solving.....
x=34
therefore the answer is option 10

Like? Yes (1) | No   

ravi singh   9 years AGO

answer is 34

since, no. of girls and boys are integer.
by putting all value only option 10 will satisfied.
boys=34 and girls=16

Like? Yes (1) | No   

SUSHANT KUMAR   9 years AGO

X+Y=50
90X+65Y=4100
SOLVING FOR X WE GET 34.

Like? Yes (1) | No   

vivek kumaR   9 years AGO

let x is no. of boys
then no. of girl is: 50-x
0.9*x+0.65*(50-x)=41
when we sove this equation we got x=34

Like? Yes (1) | No   

Aashish gohel   9 years AGO

let ,
x be no of boys &
y be no of girls
so as per question
x+y=50 (total no of boys&girls)
90x+65y=4100(90 paisa to boy & 65 paisa to girl & total 4100 paisa that is Rs 41 )
solving both equations we get x=34
that is the no of boys

Like? Yes (1) | No   

nikhil kumar   9 years AGO

let x=no of boys and y=no of girls

x+y =50
and
0.90x + 0.65y = 41 (in rs)
solving the two equations we get
x=34

Like? Yes (1) | No   

Aarti Galar   9 years AGO

Average money received by each of them Rs. 41 = 82paisa
Sum received by each boy 90 paise
Sum received by each girl 65 paise
Average 82 paisa in the ratio 17 : 8
By solving we getno. of boys = 34
therefore the ans. is 34

Like? Yes (1) | No   

vini   9 years AGO

Total strength 50, let 'x' be no.of boys and 50-x be no.of girls

(0.90*x) + (0.65)*(50-x) = 41
0.90x + 32.5 - 0.65x = 41
0.25x= 8.5
x= 34
so, no.of boys = 34

Like? Yes (1) | No   

Meenakshi   9 years AGO

Average money received by each =Rs.41=82 p.
Sum received by each boy=90 p
Sum received by each girl=65 p
Average=82 p
By alligation rule,
ratio of boys=82-65=17
ratio of girls=90-82=8
Ratio of boys and girls=17:8
So,number of boys=17*2=34
option 10)

Like? Yes (1) | No   

Bashitwa Roy   9 years AGO

Let number of boys be x. then 41=.9*x+.65*(50-x). Then solve for x.

Like? Yes (1) | No   

Preethi   9 years AGO

34*90=30.60
16*65=10.40

Like? Yes (1) | No   

kiran   9 years AGO

let no. of boys be x
=> no. of girls = 50-x

according to the problem,
x*90/100 + (50-x)65/100 = 41

on solving x = 34 = no. of boys

Like? Yes (1) | No   

satthi reddyzz   9 years AGO

34*0.90+16*0.65=41

Like? Yes (1) | No   

m.lokeswari   9 years AGO

0.90x+0.65(50-x)=41
Finally x=34

Like? Yes (1) | No   

SUNNY KAMA   9 years AGO

x+y=50 & 90x+65y=4100 on solving x=34

Like? Yes (1) | No   

Rishika Vishwakarma   9 years AGO

let d nos. of boys=x
nos of grls= 50-x

eqation becomes-
(0.91)x+(50-x)(0.65)=41
x=34

Like? Yes (1) | No   

arun sharma   9 years AGO

34*.90=30.6
16*.65=10.4
30.4+10.6=41
so 34 boys

Like? Yes (1) | No   

Rohit   9 years AGO

90b+65g=4500
90b+65g=4100

Like? Yes (1) | No   

Mani Sachdev   9 years AGO

.90x+.65y=41------(i)
x+y=50--------------(ii)
Solve eq.
x(boys)=34 Ans

Like? Yes (1) | No   

BALAJI   9 years AGO

90×34=3060
65×16=1040
so ans:34

Like? Yes (1) | No   

B.venkata suresh   9 years AGO

34*0.90+0.65*65=41

Like? Yes (1) | No   

Dhananjay Gupta   9 years AGO

x+y=50 and 90x+65y=4100.after solving these two equation we will get x=34 which is the number of boys

Like? Yes (1) | No   

PRASHANT KUMAR   9 years AGO

x+y=50
.9x+.65y=41

Like? Yes (1) | No   

anmol jain   9 years AGO

let boys be x n girls be 50-x
then
x *.9 + (50-x)*.65=41

Like? Yes (1) | No   

Y M ANIEF   9 years AGO

90 65
82
17 : 8

25--50
17--34

Like? Yes (1) | No   

Deepak kushwaha   9 years AGO

here
b+g=50........(1)
Rs41==4100 paisa
90b+65g=4100.........(2)
from (1) & (2)
we get b=34

Like? Yes (1) | No   

a.k.gayathridevi   9 years AGO

34*90+16*65=41

Like? Yes (1) | No   

Ayush Gupta   9 years AGO

x+y=50
90x+65y=4100

solve both
x=34(boys)
y=16(girls)

Like? Yes (1) | No   

sahil arora   9 years AGO

let no.of boys be x
no.of girls be y
x+y=50
.90x+.65y=41
on solving both equation y=16
therefore x=34

Like? Yes (1) | No   

Soumen Dofadar   9 years AGO

equation1: x+y=50
equation2: 90x+65y=4100

Like? Yes (1) | No   

neha gupta   9 years AGO

let x=no of boys
y=no of girls

x+y=50
0.90*x + 0.65*y =41

on solving above two equations
we get

0.25x=8.5
x=8.5/0.25
x=850/25

x=34

Like? Yes (1) | No   

Ashiya Bhuyan   9 years AGO

4100=90.b+65(50-b)

Like? Yes (1) | No   

krishna chandrika   9 years AGO

let x boys nd y girls..
x+y=50
90x+65y=4100
solving above 2 eqs x=34,y=16
no.of boys=34

Like? Yes (1) | No   

Aditi Khandagale   9 years AGO

total money=Rs.41
total boys & girls=50

so 34*90=30.60
16*65=10.40

30.60+10.40=41

so no. of boys=34
& no. of girls=16

Like? Yes (1) | No   

Archie   9 years AGO

let x be no. of boys and y be no. of gals
Then,
x+y=50 ---(1)
&
0.90x+0.65y =41 -----(2) [Since amt. distributed among boys+amt. distributed among gals=actual sum]
Solving (1)&(2) we get,
x=34 and y=16
Hence no. of boys=34 and correct option is 10 .

Like? Yes (1) | No   

hari prasath   9 years AGO

assume b-boys,g-girls

From the statement the equation forms

b+g=50
90b+65g=4100

if we solve above two equations than the boys are 34

Like? Yes (1) | No   

anuradha   9 years AGO

0.90*x+0.65*(50-x)=41

Like? Yes (1) | No   

Ajayakumar   9 years AGO

there is total 50 peoples (boys&girls), so take "x"number of boys and remaining is (50-x)are girls. If a boy get 90p than 90X will be the total boys got paise, and (50-X)65 of girls having. Than sum of all paise =4100
i,e: 90x+65(50-X) =4100 => X=34.

Like? Yes (1) | No   

Surit Datta   9 years AGO

The number of boys are 34
so option 10
that's it.

Like? Yes (1) | No (1)  

Divyabala R   9 years AGO

Given 50 boys and girls so consider X(boys) + Y(girls) = 50 ;
And 90 paise to each boy and 65 paise to each girls equals, 41 rupees converting this into paise we get 4100 paise =>
90X+65Y =4100 on solving both equation we get Girls is 16 and boys are 34 .

Like? Yes (1) | No (1)  

akas   9 years AGO

solution:
34(90)+16(65)=4100paise
therefore 34 boys and 16 girls

Like? Yes (1) | No (1)