Divide 581 among A, B, C so that 4A = 5B = 7C

asim   9 years AGO

here , we have to divide 581 in A,B,C such that
A + B + C = 581 ...................................(i)
let 4A = 5B = 7C = x
=> A = x / 4
=> B = x / 5
=> C = x / 7
on placing values of A,B,C in eq(i)
we get
(x/4) + (x/5) + (x/7) = 581
=> x * ( (1/4) + (1/5) + (1/7) ) = 581
=> x * ( (35+28+20) / 140 ) = 581 .................LCM (4,5,7) = 140
=> x * (83 / 140) = 581
=> x = 581 * 140 / 83
=> x = 140 * 7 ......................................(ii)

now , from eq(ii)
we get
A = x / 4 = 140 * 7 / 4 = 35 * 7 = 245
B = x / 5 = 140 * 7 / 5 = 28 * 7 = 196
C = x / 7 = 140 * 7 / 7 = 140 i.e. option 10) ANS

Like? Yes (20) | No (3)  

kanithi.shanmukharao   9 years AGO

In above problem gives 4timesof A=5times of B=7 times of C.
so their ratios are being:4:5:7
find out L.C.M of 4,5,7 is 140.
Therefore the ratio of A:B:C is 140/4:140/5:140/7=>35:28:20.
=>A:B:C=35:28:20.
Now sum of total ratio is 35x+28x+20x=581=>x=7...
so 35A=35*7=245:
28B=28*7=196:
20C=20*7=140:
So finally the answer is A=245,B=196,C=140

Like? Yes (16) | No (1)  

viswambher   9 years AGO

given 4A = 5B =7C
and since 581 must be divided among A,B,C
A+B+C= 581
B= 4A/ 5
C= 4A/7
(A + 4A/5 +4A/7) =581
therefore we get
A= 245
B=196
C=140

Like? Yes (11) | No   

mohita verma   9 years AGO

A/B=5/4
B/C=7/5
C/A=4/5
A:B:C=35:28:20
A's share=581x(35/(35+28+20))=245
similarly,
B's Share=581X(28/83)=196
C's share=581X(20/83)=140

Like? Yes (5) | No   

k sureshbabu   9 years AGO

as per question a&c must be divisible by 5
in the options 10 only satify that
or
go as per maths rule a=5/4b=7/4c=245
solving this we get answer

Like? Yes (3) | No   

Vivek   9 years AGO

its given that 4A=5B=7C
considering A=x
then B=4x/5
and C=4x/7
Sum of all the 3 is given as 581
Therefore A+B+C=581
i.e x+4x/5+4x/7=581
x(1+4/5+4/7)=581
x(83/35)=581
x=245 -> A=245
then B= 4*245/5=196
C=4*245/7=140
Therefore The Answer is option 10)

Like? Yes (5) | No (2)  

SANTOSH   9 years AGO

A+B+C = 581
A+4A/5+4A/7=581
then A= 245

Like? Yes (3) | No   

RAJESH   9 years AGO

4A=5B=7C
BY OPTION VERIFICATION
4*245=980
5*196=980
7*140=980

Like? Yes (3) | No   

Pranjal   9 years AGO

as 4A=5B=7C
SO A>B>C
option can be as 2,4,5,6,7,9,10
now mutiply the last digit and compares it with B's last digit on multiplying it with 5 if same check for 7C

Like? Yes (3) | No   

poojasaisri   9 years AGO

b=4/5a ,c=4/7a
a+b+c=581
a+(4/5)a+(4/7)a=581
a=245
b=196
c=140

Like? Yes (3) | No   

Math Lovers   9 years AGO

Let 4A = 5B = 7C = x

=> A = x/4
=> B = x/5
=> C = x/7

Now, A+B+C = x/4 + x/5 + x/7 = 581
=> 83x/140 = 581
=> x = 980
so, A=x/4 = 245
B = x/5 = 980/5 = 196
C = x/7 = 140

Like? Yes (3) | No (1)  

Dinni   9 years AGO

A+B+C=581
Given 4A=5B=7C
So, B=4/5A & C=4/7A
Then A+(4/5A)+(4/7A) =581
(83A/35) =581
A=245, B=196, C=140
So option 10 is correct.

Like? Yes (2) | No   

ABHINAV PUSHPAM   9 years AGO

A+4A/5+4A/7 = 581

=> 83A/35=581

SO, A= 245
And in options only in option 10, A=245 so option 10) is the answer

Like? Yes (2) | No   

RAVAL   9 years AGO

because,
4a=5b=7c
a=4/5b=4/7c
a+4/5a+4/7a=581
a=245
b=196
c=140

Like? Yes (2) | No   

Mani Sachdev   9 years AGO

a:b=5/4; b:c=7/5
a:b:c=38:28:20;
a=38/83*581=245
b=28/83*581=196
c=20/83*581=140

Like? Yes (2) | No   

Deepthi   9 years AGO

4A=5B=7C
A+B+C=581
A+4/5A+4/7A=581
83/35A=581
A=245
B=4/5*245=196
C=4/7*245=140

Like? Yes (2) | No   

shree   9 years AGO

the addiction of values a,b , c of option 10 is 581
and if we multiply with 4, 5, 7 then all the values are equal

Like? Yes (2) | No   

anand vijay   9 years AGO

4A=5B=7C
simply we can check from option that after multiplication from 5 the digit at unit place must be 0
If it is even else 5 if it is odd so,
here digit at unit place be 0 so after multiplication by 7 the unit digit must be 0
hence option (10) is correct.

Like? Yes (2) | No   

lokesh   9 years AGO

5B = 7C
which is possible when C ends in 0 or 5
so i tried the last option

Like? Yes (3) | No (2)  

Dharshana   9 years AGO

Reverse Method)
4A=4(245)=5(196)=980
5B=5(196)=980
7C=7(140)=980

Like? Yes (1) | No   

sompon temtheerakij   9 years AGO

B = 4/5A , C = 4/7A
A+4/5A+4/7A = 83/35A = 581
A = 245 ; B = 196 ; C = 140

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nidhi   9 years AGO

4A=5B=7C
4*245=5*196=7*140=980

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K Sudharshan reddy   9 years AGO

Just check the options
5b , so the result ends in or 0
4a to get the value equal to 0 the last digit in a should be 0 or 5
so check only last two options......
or we can solve the problem by writing them in equation form
a+b+c= 581 and 4a=5b=7c.....

Like? Yes (1) | No   

kush nigam   9 years AGO

a+b+c = 581 _____(1)

4a=5b=7c

so putting values in equation 1

a+ 4/5 a+ 4/7 a = 581

a( 1+ 4/5+ 4/7 ) =581

73 a = 20335

a = 245

so b = 4/5 a =196

so c = 4/7 a = 140

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Akhil   9 years AGO

245*4=196*5=140*7=980
245+196+140=581
so option 10.....

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krishna chandrika   9 years AGO

4A=5B=7C
A+B+C=581
A+(4/5)A+(4/7)A=581

83A=581*35

A=245

B=4/5A=4/5*245 = 196

C=4/7A=4/7*245 = 140

Like? Yes (1) | No   

anuanwesh   9 years AGO

4a=5b=7c a=5÷4b, b=7÷5c, so option 10 is rght ans

Like? Yes (1) | No   

Ravi shankar   9 years AGO

we have to choose a option which must be divisible by other two.
for choosing value A: must be divisible by 5 and 7 both
for choosing value B: must be divisible by 4 and 7 both
for choosing value C: must be divisible by 4 and 5 both
only option 10 is correct

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ANANTHI.P   9 years AGO

83 581
35 X =245
28 X =196
20 X =140

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Lavanya Rajendran   9 years AGO

a+b+c=581
b=4a/5
c=4a/7
on equating a=245
4a=5b
So b=196
similarly 4 c

Like? Yes (2) | No (1)  

RISHABH SINGH   9 years AGO

(A/35)=(B/28)=(C/20)=k(let)
so A=35k B=28k C =20k
we know that
A+B+C=581
putting value of A,B and C
we have k=7
So
A=245 B=196 C=140

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RAJAT KHANDELWAL   9 years AGO

A+B+C=581
4A=5B
4A=7C
5B=7C

SOLVING EQUATIONS WE GET B=196
A=245
C=140

Like? Yes (2) | No (1)  

Divyansh jaiswal   9 years AGO

a:b=5:4 b:c=7:5
a:b:c=35:28:20

83x=581
x=7
a=245 b=196 c=140

Like? Yes (1) | No   

pratik   9 years AGO

go through option
jus check digit at once place

only option 10 gives same

4*245= **0. 5*196=**0. 7*140 =**0
so its gotta be option 10

Like? Yes (1) | No   

anuj jain   9 years AGO

since there is a 5B so other answers must be multiple of 5.
And due to 4A ans. must be multiple of 10.
245*4=980
196*5=980
140*7=980
245+196+140=581

Like? Yes (1) | No   

puneet   9 years AGO

we take ratio of them like
1/4:1/5:1/7
we take lcm of them
and we gate the ratio 35:28:20
and dive the value

Like? Yes (1) | No   

Dhanraj Wanjare   9 years AGO

option 10 satisfy the condition i.e.--
4A=5B=7C
A=245 then 4A ==> 4*245= 980;
B=196 then 5B ==> 5*196= 980;
C=140 then 7C ==> 7*140= 980;

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bahul   9 years AGO

a:b=5:4 and b:c=7:5 so, a:b:c=35:28:20
now, we have to divide 581 among a, b, c so
581= 35x+28x+20x ,
x=581/83
x=7
a=7*35=245
b=7*28=196
c=7*20=140

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PRASHANT KUMAR   9 years AGO

4A=5B=7C=K;
581=A+B+C;
SO SOLVE FOR K.....K=980...
SO ANS.--->>(10)

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Jyothi C Allapur   9 years AGO

A + B +C = 581 --- eqn (1)
4A=5B=7C => A = (5/4)*B and C = (5/7)*B
substituting A andC in eqn (1), we get
(5/4)B + B + (5/7)B = 581
B = 196
A = 245 and C = 140

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Abhishek singh   9 years AGO

a/35=b/28=c/20=x
a=35x
b=28x
c=20x
a+b+c=581
x=7
so
a=245
option 10.

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sivakumar   9 years AGO

4 * 245 = 980
196 * 5 = 980
140 * 7 = 980

245+196+140 = 581

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Aravinth   9 years AGO

because all the unit digits are respective place..so that condition is easily satisfiedwhen compared to other ones

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Ganesh garg   9 years AGO

A:B=5:4
B:C=7:5
so the ratio of
A:B:C=35:28:20
now
A=(35/83)*581 = 254
B=(28/83)*581 = 196
C=(20/83)*581 = 140

Like? Yes (1) | No   

Thanakkumar T   9 years AGO

Assume if 5 is multiplied last digit should be zero...then probably last two answers would be correct if multiplied by 4....calculate last two and arrive at answer.

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soumith vooda   9 years AGO

simply option verification
in given options bx5 is always zero in last digit so choose an option while multiplying the other options such that last digit is zero
4*285=5*196=7*140=980

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SWATI   9 years AGO

A+B+C=581
B=(4/5)A
C=(7/5)A
putting values and solving
A=245..
further
B=196 and C=140

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Archie   9 years AGO

Let 4A=5B=7C=x
then A's share =x/4
B's share=x/5
C's share =x/7
-----> x/4+x/5+x/7=581
Solving, we get x=980
------> A=x/4=245
B=x/5=196
C=x/7=140
Hence, option 10 is correct .

Like? Yes (1) | No   

sonu   9 years AGO

Assume 4A=5B=7C=K

Now K/4+K/5+K/7=581 => K=980

Put the value of K.

A = 245, B = 196, C = 140

Like? Yes (1) | No   

Piyush Telang   9 years AGO

A + B + C = 581 -> Equation 1
A = 7C/4
B = 7C/5
Substituting A and B in Equation 1
C = 140
Thus A = 245 and B = 196

Like? Yes (1) | No   

ARUP GHOSH HAZRA   9 years AGO

4A= 5B=7C=x(assume)
i.e. A= x/4,
B= x/5,
C= x/7.
so, A+B+C= 581
or, (x/4+x/5+x/7)= 581
or, x=980

Like? Yes (1) | No   

chitra   9 years AGO

its like trail and error method...check from the options
which satisfies
4a=5b=7c...980
ie..,4*245,5*196,7*140
has a total of 581....a+b+c=581

Like? Yes (1) | No   

Shubham   9 years AGO

As A+B+C =581;
so 5(A+B+C)=5*581 => 9A+5C=2905;
and 4(A+B+C)=5*581 => 9B+4C=2324
and 7(A+B+C)=7*581 => 11A+7B=4067
and solving above 3 Equation we get A=245 ,B=196,C=140

Like? Yes (1) | No   

Nabin   9 years AGO

A:B:C=35:28:20
A=35/83×581=245...similarly find Band C

Like? Yes (1) | No   

ashwin   9 years AGO

jus multiply the last digit of a,b,c with 4,5,7 respectively.....doing so we find that only the 10th option gives the same answer zero...hence answer is (10)

Like? Yes (1) | No   

radhakrishna bajpai   9 years AGO

A+B+C=581
now put A=5B/4
and c=5b/7
then solve for B wr get B=196
after solving A=245 and C=140

Like? Yes (1) | No   

SURAJ KUMAR   9 years AGO

option 10 is correct coz if we multiply A by 4 ,B by 5 and C by 7 then according to option we will get same value of 980 which is possible in option 10 only.

Like? Yes (1) | No   

SAURABH SINGH   9 years AGO

A:B:C=35:28:20
hence, 35k+28k+20k=581
k=7
A=35k=35*7=245

Like? Yes (1) | No   

K.M.AYESHA SHARMIL JAHAN   9 years AGO

divide 581 among A,B,C
4A=5B=7C(given)
4(35*x)+5(28*x)=7(20*x) (by taking l.c.m)
581 is divided only by 7
so,x=7
A=35*x
=35*7
=245
B=28*7
=196
C=20*7
=140

Like? Yes (1) | No   

RAKESH   9 years AGO

a:b:c = 35:28:20
& a+b+c = 581, so,
a=245 , b=196, c=140

Like? Yes (2) | No (2)  

BADRI LAL JAT   9 years AGO

take ratio of A, B, C, AND FIND : 35:28:20 SO A HAS VALUE 245, B HAS 196 AND C HAS 140

Like? Yes (1) | No (1)  

Venkatesh kadali   9 years AGO

4A=5B=7C
4A=5B that implies a:b=5:4
5B=7C that implies b:c=7:5
then a:b:c=35:28:20
A share=810*35/83=245
B share=810*28/83=196
C share=810*20/83=140

Like? Yes (1) | No (1)  

Pradeep   9 years AGO

=>4A=5B=7C=1
=>A:B:C=1/4:1/5:1/7
=>A:B:C= 35:28:20
=>A=35/83 *581 =245
=>B=28/83*581=196
=>C=581-(245+196)=140

Like? Yes (1) | No (1)  

Rats   9 years AGO

A+B+C=581........(1)
4A=5B=7C.......(2)
On solving (1) & (A), we get,
A=245, B=196, C=140

Like? Yes (1) | No (1)  

neha gupta   9 years AGO

4A=5B=7C
from this we get,
A:B=5:4
B:C=7:5
therefore
A:B:C=35:28:20
let the ratio be x
then 35x + 28x + 20x = 581
83x = 581
x=581/83=7
A=35x=35*7=245
B=28x=28*7=196
C=20x=20*7=140

Like? Yes (1) | No (1)  

Nikhil chavan   9 years AGO

check the option to satisfy the given conditions..so answer is 10th option.

Like? Yes (2) | No (2)  

sravani   9 years AGO

B=4/5A
C=4/7A
A+B+C=581
=>A=245
B = 196,
C = 140

Like? Yes (1) | No (1)  

vimal tiwari   9 years AGO

go with the options...

10)

245 * 4 = 196 * 5 = 7*140
980 = 980 = 980

Like? Yes (1) | No (1)  

Vaibhav kumar    9 years AGO

ratio =35:28:20
(35/83)*581=245
(28/83)*581=196
(20/83)*581=140

Like? Yes (1) | No (1)  

Chitra.S   9 years AGO

a/b=5/4..
b/c=7/5
so ..a:b::b:c..5:4::7:5...
the ratio is 35:28:20..
total is 35+28+20=83
581*35/83=245
581*28/83=196
581*20/83=140

Like? Yes (1) | No (1)