The age of a father 10 years ago was thrice the age of his son. Ten years hence, the father's age will be twice that of his son. The ratio of their present ages is

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17 Jul 2015 Problem on ages The age of a father 10 years ago was thrice the age of his son. Ten years hence, the father's age will be twice that of his son. The ratio of their present ages is: OPtion
1) 5:2
2) 11:2
3) 8:3
4) 5:2
5) 13:4
6) 3:1
7) 9:2
8) 7:2
9) 7:3
10)None of these; Correct Option: 9 Best Solution (73)

G Mounika 9 years AGO

Present age of the son = x years.
10 years ago age of the son = x-10
10 years ago age of a father = 3(x-10)
Ten years hence age of son = x+10
Ten years hence age of father = 2(x+10)

from the above data
2(x+10) = 3(x-10)+20
2x+20 = 3x - 30 +20
x=30.
Ten years ago father's age = 3(x-10) = 3 * 20 =60.
Present father's age = 60+10 = 70.
Hence ration of their ages = 70 :30 = 7:3.

Like? Yes (31) | No (8)

sudiptaa 9 years AGO

Present age of father = x years
present age of son = y years

x-10= 3(y-10) .............(1)
x+10= 2(y+10).............(2)

solving 1 and 2
x= 70
y= 30
ratio = 7:3

Like? Yes (14) | No (5)

Devendra Marghade 9 years AGO

Let the present age of father=f and son=s
Given, f-10=3(s-10) or f-3x=-20 ---(i) and
f+10=2(x+10) or f-2x=10 ---(ii)
On solving (i) & (ii), f=70, s=30
So ratio of their present ages=70/30= 7/3

Answer option(9)

Like? Yes (9) | No (1)

Piyush Telang 9 years AGO

Let X be the present age of father and Y be the present age of son.
Then X - 10 = 3 ( Y - 10 ) => X = 3Y - 20 &
X + 10 = 2 ( Y + 10 ) => X = 2Y + 10
Then Y = 30 and X = 70
Ratio Between their present ages = 7:3

Like? Yes (7) | No (1)

sourav pal 9 years AGO

Let the ages of father and son 10 years ago be 3x and x years respectively.

Then, (3x + 10) + 10 = 2[(x + 10) + 10]

3x + 20 = 2x + 40

x = 20.

Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.

Like? Yes (13) | No (11)

Abhimanyu Kumar 9 years AGO

Assume son's present age to be x

Son's 10 yrs ago=x-10
so father's 10 yrs ago = 3(x-10)

father's present=3x-30+10=3x-20
father's 10 yrs hence=3x-10
Son's 10 yrs hence=x+10

now,
3x-10=2(x+10)
So x=30
So the required ratio is
3x-20/x = 90-20/30
= 7/3

Like? Yes (4) | No (2)

Kethineni Vinodh 9 years AGO

Like? Yes (2) | No

Ashu Kumar 9 years AGO

LET PRESIDENT AGE OF FATHER IS F,SON IS S
10 YEAR AGO ,F-10=3(S-10)
AFTER 10 YEAR ,F+10=2(S+10)
S=30
F=70
SO RATIO=7/3

Like? Yes (3) | No (1)

prem kishor 9 years AGO

let father's age=x
and son's age=y
hence, x-3y=-20
x-2y =10
after solving these two equestion we can get x=70 and y=30 so the ration of x/y=7/3

Like? Yes (2) | No (1)

NIRBHAY KUMAR 9 years AGO

Let the present age of father =x
and the present age of son=y
A/C to question, 10 yrs ago
x-10=3(y-10) ...eq1
and 10 yrs hence
x+10=2(y+10) ......eq2
solving these two eqs..... we get
x=70 and y=30

Like? Yes (2) | No (1)

anand kumar 9 years AGO

let 10 years back sons age was x, and fathers was 3x. 3x+20=2(x+20)
x=20
so, 10 year back father was 60, son was 20. now father 70, son 30. 70/30=7:3

Like? Yes (1) | No

ANKUR ANAND 9 years AGO

x-10=3(y-10)
and x+10=2(y+10)
Solving these two equations we get
x=70 and y=30
so the required ration is 7:3

Like? Yes (1) | No

Narendra Gopi 9 years AGO

son's present age=x years
son's age 10 years ago=x-10
father's age 10 years ago=3*(x-10)
after 10 years son's age=x+10
after 10 years father's age=2*(x+10)
so 3*(x-10)+20=2(x+10)
3x-30+20=2x+20
3x-10=2x+20
son's present age x=30,
and father's present age is= 3(x-10)+10
=3(30-10)+10
=3*20+10
=70
Ratio of theirs age is 70/30=7/3

Like? Yes (1) | No

vivek kashyap 9 years AGO

Like? Yes (1) | No

praveendas 9 years AGO

let assume the ages of father and son be x and y
10 years ago it was x-10=3*(y-10)
10 years hence it wil be x+10=2*(y+10)
solve above two equations for x and y.
we get x=70 and y=30...
the ratio is7:3

Like? Yes (1) | No

Shiva Sharma 9 years AGO

Let x and y is current age of father and son
x-10 = 3*(y-10)
x+10 = 2*(y+10)
after solving two equation
x=70
y=30
so x:y = 7:3

Like? Yes (4) | No (3)

charul kardam 9 years AGO

let present age of father be x
and present age of son be y
then 10 years ago
x-10=3(y-10).... eq (1)
after 10 years
x+10=2(y+10)... eq (2)
solving 1&2 x=70
y=30
hence ratio is 7:3

Like? Yes (1) | No

BINOD BIHARI BEHERA 9 years AGO

10 yrs ago : f=3x, s=x
present: f=3x+10, s=x+10
after 10 yrs : f=3x+20, s=x+20
now 3x+20= 2(x+20)
so x =20
present: f=70 and s=30
so f:s= 7:3

Like? Yes (1) | No

Soumen Maity 9 years AGO

let say, present age of father is 'f' and son is 's'
So, f-10=3*(s-10)
or, 3s-f=20.......................(i)

and, f+10=2*(s+10)
or, f-2s=30......................(ii)

solving these two we get, f=70, s=30
so present ratio of their ages is 7:3

Like? Yes (1) | No

Dheeraj Kumar 9 years AGO

f age : x
s age :y

x-10=3(y-10)
x+10=2(y+10)

after solving this eq. we will get y=30; x=70
hence ratio=7:3

Like? Yes (1) | No

Soma Naresh 9 years AGO

If F and S be present ages of father and son respectively
10 years ago
F-10=3 (S-10)
10 years hence
F+ 10=2 (S+10)
solving F=70
S=30
ratio=7:3

Like? Yes (1) | No

rahul shaw 9 years AGO

father present age: f
son present age: s
two eq are:
(f-10)=3(s-10) and (f+10)=2(s+10)
after solving two eqn...
we get f=70 and s= 30
ratio=7:3

Like? Yes (1) | No

krishna chandrika 9 years AGO

F-10 = 3(S-10)
F+10 = 2(S+10)

Solving the 2 eq, F = 70, S=30

Ratio of their ages F:S = 7:3

Like? Yes (1) | No

SOMA NARESH 9 years AGO

F and S be present ages of father and son respectively
10 years ago
F-10=3 (S-10)
10 years hence
F+ 10=2 (S+10)
solving F=70
S=30
ratio=7:3

Like? Yes (1) | No

manisha 9 years AGO

let 10 yrs before father's age=3x
son's age=x
then 20 yrs after father's age=3x+20
son's age=x+20
so given in the question 3x+20=2(x+20)
3x+20=2x+40
x=20
so
present age of father 3x+10=70
son's age x+10=30
so ration is 7;3

Like? Yes (1) | No

Anil Gautam 9 years AGO

present age of father be x and that of son be y
so,10 years ago (x-10)=3(y-10)
10 years hence (x+10)=2(y+10)
solving above equations
y=30 and x=70
hence the ratio is 7:3

Like? Yes (1) | No

bhavya dubey 9 years AGO

suppose father's age=x
and son's age=y
as per question before 10 years (x-10)=3(y-10)......equation 1
as per question after 10 years (x+10)=2(y+10)......equation 2
solving eqution 1 and eqution 2 we get x=70 and y=30
ratio=70/30=7/3

Like? Yes (1) | No

Riyashree Mukherjee 9 years AGO

Let the present age of the son=x.
ten yrs ago his age=(x-10)
fathers age ten yrs ago=3(x-10)
ten yrs hence=3(x-10)+10+10=2(x+10)
x=30
Father:son=70:30
7:3

Like? Yes (3) | No (2)

Pinku Burnwal 9 years AGO

let present age of father be x,
& of son be y
10yrs ago, x-10=3(y-10)
10yrs hence, x+10=2(y+10)
we get x=70 & y=30
option 9

Like? Yes (2) | No (1)

UJJWAL KANT 9 years AGO

present age of father and son be f an s
ten years ago
f-10=3(s-10)......(1)
ten years hence
f+10=2(s+10).....(2)
solving eqn1 and 2 we get
s=30 and by putting it in eqn we get f=70
hence their ratio is 70/30=7:3

Like? Yes (1) | No

Subham Mahanta 9 years AGO

let, father's age = x years
son's age = y years
so, 10 years ago, (x-10)=3(y-10)........equation (i)
10 years hence, (x+10)=2(y+10)..........equation (ii)
from [ (ii) - (i) ] , we get,
y = 30
so, from equation (ii) we plot the value in equation (ii) , we get,
x= 70
so, the ratio of their present ages are = x : y = 70 : 30 = 7 : 3
ans is option (9)

Like? Yes (1) | No

Shanti Kumari 9 years AGO

x-3y=-20
x-2y=10
y=30
x=70

Like? Yes (1) | No

Rahul kumar 9 years AGO

let fathers present age=x
sons present age=y
a/c to ques
x-10=3(y-10)........eqn 1
also
x+10=2(y+10).....eqn2
solving both eqn we get x=70,y=30
so,x:y=7:3

Like? Yes (1) | No

Nitish Varshney 9 years AGO

let x be father age
y be son age
x-10=3(y-10)
x+10=2(y+10)
x=70
y=30
7:3

Like? Yes (1) | No

Anubhav jain 9 years AGO

Fathers age's=X
Son age=Y
Ist cond.
X-10=3(y-10)
X-3Y+20=0...........(1)
IIst Cond.
X+10=2(Y+10)
X-2Y-10=0..............(2)
Solve
then X=70,Y=30
Ratio is =7/3

Like? Yes (1) | No

santu ghosh 9 years AGO

10 yrs ago ,
son age =x
so father age =3x
10 yrs after,
son=x+20
father=3x+20
so,2(x+20)=3x+20
0r,x=20
hence ratio of thier present ages is 70:30=7:3

Like? Yes (1) | No

aashish kumar 9 years AGO

let present ages of father and son be x nd y respectively.
10 years ago
(x-10)=3 (y-10).....eq 1
after 10 years
(x+10)=2 (y+10)......eq 2
solving both equations we get value of x=70, y=30
ratio=x/y=70/30=7/3

Like? Yes (1) | No

Murali Krishna.P 9 years AGO

Like? Yes (1) | No

santhanalakshmi 9 years AGO

let take father's age X and son's age 3Y before ten years
so X=3Y
Y=X/3
so X=X/3________________(1)
present age will be X+10=X/3+10______________(2)
after 10 years their ages will be
X+10+10=X/3+10+10___________________(3)
solving this equation we get
x=60
by substituting X=60 in equation 2
we get the ages as 70:30
so the answer is 7:3

Like? Yes (1) | No

karthiga 9 years AGO

F - 10 = 3(s - 10)
F - 10 = 3S +20
F+ 10 = 2(s + 10)
F - 10 = 3S - 30;
2S +10 -10 = 3S - 30;
S = 30;
F = 70;
Ratio is 7:3.

Like? Yes (1) | No

Lavanya Rajendran 9 years AGO

(y-10)=3(x-10)
y=3x-20
(y+10)=2(x+10)
y=2x+10
3x-20=2x+10
x=30
(y-10)=60
y=70
x=40
y=100
100/40
5:2

Like? Yes (1) | No

sai 9 years AGO

10 years ago F-10=3(S-10)
10 years hence F+10=2(S+10)
by solving we get F=70, S=30
hence F/S=7/3

Like? Yes (1) | No

sainath somisetty 9 years AGO

consider father: F
son : S
10 years ago: (F-10)=3(S-10)
10 years later: (F+10)=2(S+10)
solving this two equations we get age of father as 70 and son as 30
ratio of their ages is 7:3

Like? Yes (2) | No (1)

k sureshbabu 9 years AGO

ten years back their age are 60:20
after 10 year 80:40
present 70:30
so finally7:3
is the answer

Like? Yes (2) | No (1)

champavat jaydipsinh padamsinh 9 years AGO

f-3s=-20
f-2s=10
so s=30 and f=70
so f/s=70/30=7/3

Like? Yes (1) | No

vertika agrawal 9 years AGO

f-10=3(s-10)
f+10=2(s+10)
solve this.f=70 s=30
ratio is 7:3

Like? Yes (1) | No

Chirag Mathur 9 years AGO

let father's and son's present age is F and S respectively.
10 years ago=
F-10 = 3(S-10)............(1)
after 10 year from present=
F+10 = 2(S+10).............(2)

after solving both equation (1) & (2)
F=70 & S=30
that is the present age ,so the ratio would be == 7:3

Like? Yes (1) | No

kumari jyoti 9 years AGO

Let father's present age=x
& son's present age=y.
Then 10years ago,
X-10=3(y-10).....(1)
And 10 years hence,
X+10=2(y+10)......(2)
Solving the eqns. We get,
X:y=7:3
So, option 9 is the answer.

Like? Yes (1) | No

sahil arora 9 years AGO

let father present age be x and son's present age be y
then 10 years ago
x-10=3(y-10)-------------->(1)
10 years hence
x+10=2(y+10)---------------->(2)

solving both equation (1) & (2)
we get y=30
and we'll calculate x i.e 70

Like? Yes (2) | No (1)

KUMAR HARSH 9 years AGO

let son age 10 year ago was x
so father age is 3x
10 year hance,
2(x+20)=3x+20
x=20
present age ratio=(3x+10):x+10=3:7

Like? Yes (2) | No (1)

DEEPAK RAJ 9 years AGO

Let 10 years ago, Age of the son = x years
then, Fathers's son = 3x years

10 years from hence, 3x + 20 = 2(x+20)
So, x = 20 years.
So. current age of the son = 30 years
Current age of father = 70 years

Ratio = 7:3

Like? Yes (3) | No (3)

SAYAN CHATTERJEE 9 years AGO

let present age of father be x and son be y
so, (x-10)= 3*(y-10)
& (x+10)= 2*(y+10)
solving, we get, x=70, y=30
so ratio of the ages is 7:3 (9)

Like? Yes (1) | No (1)

shivjee yadav 9 years AGO

let son age = x and , father age =y
according to question
10 years ago,y-10=3(x-10).....eq(1)
now,10 years hence,y+10=2(x+10)...(2)
solving both eq we gate x=30,y=70
hence ratio is 7:3

Like? Yes (2) | No (2)

Dinni 9 years AGO

Like? Yes (3) | No (3)

Deepak kushwaha 9 years AGO

10 yeasrs ago
F-10=3(S-10)---------------(1)
10 years from present
F+10=2(S+10)---------(2)
on solving eqn(1) and eqn(2)
we get F=70 and S=30
F:S=7:3(option 9)

Like? Yes (2) | No (2)

anand vijay 9 years AGO

let x be the present age of father and y be the present age of son
then we have two linear equation
x-10 = 3(y-10)
x-3y = -20...........(i)
x+10 = 2(y+10)
x-2y=10..............(ii)
on solving (i) & (ii) we get
x=70, y=30
ratio of present ages is=x:y
=70:30
=7:3
option 9)

Like? Yes (1) | No (1)

Amit Roy 9 years AGO

Let,
at present son's age=x and father's=y
therefore 10 years ago ,
y-10/x-10=3/1
or,3x-y=20-------(i)
again after 10 years,
y+10/x+10=2/1
or,2x-y=-10------(ii)

solving equ (i) and (ii)
we got,x=30
therefore y=70
hence y/x=7:3
option 9 is correct!!

Like? Yes (1) | No (1)

Abhisheak Kumar Missu 9 years AGO

let the age of father be x and son be y.
ten years ago,
(x-10)=3(y-10)...............(1)
ten years hence
(x+10)=2(y+10)...................(2)
solving these two equation
x=70
y=30
ratio= 7:3

Like? Yes (2) | No (2)

Inoka 9 years AGO

Assume Fathers current age is X and Son age is Y.
So The age of a father 10 years ago was thrice the age of his son = X - 10 = 3 (Y-10) --> Statement 1
Ten years hence, the father's age will be twice that of his son = X +10 = 2(Y+10) --> Statement 2

after resolve above 2 statements X = 70, Y = 30 so the ratio is 7: 3
Answer is 9)

Like? Yes (1) | No (1)

sonali gaur 9 years AGO

Let the present age of father be 'x' & that of son be 'y'
10 years ago father's age = x-10 & son's age= y-10
(x-10)= 3(y-10)
x-3y= -20........(1)
10 years later father's age = x+10 & son's age will be y+10
(x+10)=2(y+10)
x-2y = 10.............(2)
Solving (1) & (2)
x=70 and y=30
Ratio (x:y)= 7:3

Like? Yes (1) | No (1)

Anuj Rai 9 years AGO

Like? Yes (1) | No (1)

pankaj kumar 9 years AGO

solu:- let father current age x & son age y . then 10 years ago age will be
equ 1 : x-10= 3(y-10)
and 10 years after age is :- x+10= 2(y+10)
after solving equ x= 70 & y = 30

Like? Yes (2) | No (2)

Santosh Kumar 9 years AGO

let present age of father =y and present age of son=x.
then 10 years ago,
(x-10)3=y-10
i.e3x-y=20
10 yrs later
2(x+10)=(y+10)
i.e2x-y=-10
solving these two eqn we get,
x=30 nd y=70
hence,ratio of father age ans son age =70/30=7/3

Like? Yes (1) | No (1)

ROHIT KUMAR 9 years AGO

Let current age of father= x and son= y
then according to question 10 year back
x-10 = 3(y-10)------------ 1
after 10 years
x+10 =2(y+10)-------------2
solving equation 1 and 2
x=70
y=30
so ratio is 7:3

Like? Yes (1) | No (1)

shivani gupta 9 years AGO

present age of father=x years
present age of son=y years
ten years before father age =(x-10)
10 years before son age=(y-10)
so acc to que
(x-10)=3(y-10)
simillarly 10 years after,
(x+10)=2(y+10)
solving both eq,
we get
x=70
y=30
ie 7:3
so ans is 7:3 option 9

Like? Yes (1) | No (1)

GITANJALI GOSWAMI 9 years AGO

present age of father=x
son=y
x+10=2(y+10)
x-10=3(y-10)

x=70
y=30
x:y=7:3

Like? Yes (1) | No (1)

Rajkumar Swansi 9 years AGO

Let son's present age to be x

Son's 10 years ago= x-10
so father's 10 years ago = 3(x-10)

Father's present= 3x-30+10 = 3x-20
Father's 10 yrs hence= 3x-10
Son's 10 yrs hence=x+10

Then
3x-10=2(x+10)
So x=30
So the required ratio is
3x-20/x = 90-20/30
= 7/3

Like? Yes (1) | No (1)

Biren Patel 9 years AGO

10 years befoe:
x-10 =3(y-10)
10 years hence:
x+10=2(y+10)
by solving this
y=30
x=70
x:y = 7:3

Like? Yes (1) | No (1)

KAVITHA 9 years AGO

Like? Yes (1) | No (1)

Thupakula vasu 9 years AGO

Let father age 3x ,sons age x

Then, (3x + 10) + 10 = 2[(x + 10) + 10]

3x + 20 = 2x + 40

x = 20.

Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.

Like? Yes (1) | No (1)

shyamala 9 years AGO

x-10=3(y-10)
x+10=2(y+10)
on solving,we get
x=70,y=30
ratio=7:3

Like? Yes (1) | No (1)

poojasaisri 9 years AGO

f-10=3s-30
f+10=2s+20
f=70
s=30

Like? Yes (1) | No (2)

pooja jha 9 years AGO

let ten year ago son's age be x
then father age was 3x.
10 year hence son's age will be x+10+10=x+20.
and father age will be 3x+20.
therefore 3x+20=2(x+20).
so x=20.
therefore sons present age=20+10=30
and fathers present age =3*20+10=70.
therefore required ratio=70:30=7:3.

Like? Yes (3) | No (4)

Dimple

India

Punjab

Time: 00:01:33

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17 Jul 2015 Problem on ages