In a single throw of two dice what is the probability of not getting the same number of both the dic

Ajeet Kumar   9 years AGO

Getting same no. on both dice = 6
so P(E)=6/36
so, Not Getting= 1-P(E)
=5/6

Like? Yes (6) | No (1)  

Sukanya   9 years AGO

1,1 2,2 3,3 4,4 5,5 6,6
Except this 30 combinations are there
so 30/36=5/6

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premlata   9 years AGO

Number of favorable outcomes: 6^2 = 36

Let E1 = event of getting a doublet. The number which doublet will be E = [(1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)] = 6

P(E) = 6/36 = 1/6

Let E2 = event of getting not a doublet.
P(E2)=1-P(E1) = 1- (1/6) = 5/6

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ABHINAV PUSHPAM   9 years AGO

Same number on 2 dice occurs 6 times (1,1) (2,2) (3,3) (4,4) (5,5) (6,6).
Total possibilities are 36 for two dices.
So probability of not getting same number on both sides = 30/36 =5/6
Option 6)

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ANKUR BAJWA   9 years AGO

probability for getting same number=6/36=1/6
not getting =1-1/6=5/6

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TONI PRIYA   9 years AGO

getting same no. on both side is 6/36=1/6
so not getting same on both side is =1-1/6
=5/6

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astha   9 years AGO

probability of getting same no on both dice is 1/6
so p( not getting same no)=1-1/6=5/6

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Aman Amal   9 years AGO

total no. of outcome 6*6=36
probability of getting same no. =6/36=1/6
so probability of not getting same no. is 1-1/6=5/6

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shreya pai   9 years AGO

total probability is 6^2
probability same number will appear 6
6/36=1/6
1-1/6=5/6

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urvashi sharma   9 years AGO

probability of getting same no = 6/36
so
probability of not getting same no both the dice is= ( 1- 6/36)
= 5/6 ans

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ankuta   9 years AGO

same no appear 6 time
so p of same no = 6÷36
= 1÷6
now p of not gttng same no
= 1-(1÷6)
= 5÷6 ans.

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Ankush dhadwal   9 years AGO

Probability of getting samr no. on each dice is 1/6.since cases are (1,1),(2,2),(3,3),(4,4),(5,5)&(6,6).probability of getting no same no is 1-1/6=5/6

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TAUSEEF AMEEN   9 years AGO

Un Favourable outcome=(1,1) ,(2,2),(3,3),(4,4),(5,5),(6,6)
Total outcome=36
Probability of getting same no.on both dice=6/36=1/6
Probability of not getting same no on two dice=1-1/6=5/6
Hence option 6 is correct

Like? Yes (2) | No (1)  

Abhinav Akash   9 years AGO

option 6

Number of sample space for rolling a two dice in single throw = 36
P(getting same no on both dice)=6/36
P(not getting the same no.)=1-(6/36)= 5/6.

Like? Yes (2) | No (1)  

M Sreekanth Yadav   9 years AGO

total number of outcomes is 36
we get doublet when we get [(1,1)(2,2)(3,3)(4,4)(5,5)(6,6)]
and we have to subtract get the probability for non doublet outcomes we get (36-6=30) . So , the probability of getting non doublet is 5/6

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Lakhi kant Roy   9 years AGO

Sample space=36
P(getting same no)=6/36
=1/6
So,P(Not getting same no)=1-(1/6)
=5/6
Ans is Option 6.

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DHAYYALA SREEKANTH REDDY   9 years AGO

probability of getting same numer=1/6
so probability of getting different number=5/6

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H. Sreekanth   9 years AGO

propability of getting the same number is 1/6;
propability of getting the different number is1-1/6=5/6

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S.Hemanth kumar   9 years AGO

no of combinations=n(S)=36
let (k)={(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)}
p(k)=6/36=1/6
so p(1-k)={1-1/6)
ans)5/6

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ramya   9 years AGO

this is what the answer is.
because 36-6 = 30 / 36 = 5/6

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Meenal Sharma   9 years AGO

Because sample space =36
favorable event for same number on two dices=6
favorable event for different number on two dice =30
probability=30/36=5/6

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SORNA KAMALAM S   9 years AGO

probability of not getting the same number of both the dice
=1 - probability of getting the same number of both the dice

sample space, n(s)=6^2=36

possible events=(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)

no.of possible events=6

probability of getting the same number of both the dice
=6/36
=1/6

probability of not getting the same number of both the dice
=1 - 1/6
=5/6

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venkatesh   9 years AGO

probability of getting same number is =1/6
probability of not getting =1-1/6
=5/6
so ans is 5/6

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chetan   9 years AGO

The probability that the numbers are the same is 1/6. So the probability that they are

not the same is 1 - 1/6 = 5/6.

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MADHUBABU   9 years AGO

n(S)=36
let (E)={(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)}
therfore P(E)=6/36=1/6
P(not-E) = 1-1/6 = 5/6

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Arnab Maity   9 years AGO

When two dice are thrown simultaneously, thus number of event can be 6^2 = 36
Now no. of events of getting the same number on both the dice = 6 = (1,1), (2,2) , (3,3), (4,4), (5,5), (6,6)
Therefore the probability of not getting the same number of both the dice is = 1- (6/36) = 30/36 = 5/6

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Thaker Maulik   9 years AGO

Here both dice have 6*6=36 sides
so, N(s)=36, now probability to get same number of both sides is (1,1),(2,2),(3,3),(4,4),(5,5),(6,6) = 6
so, n(E) = 6
Now, P(E)= n(E)/n(s)
= 6/36
=1/6
so probability of not getting same number is 1-1/6= 5/6 is answer

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ramakrishnateja   9 years AGO

total outcomes of two dice=6^2=36. here no of ways of getting same number on two dice is 1,1;2,2;3,3;4,4;5,5;6,6.hence prob is 6/36=1/6. hence prob of not getting same num is 1-1/6=5/6

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Ashu Kumar   9 years AGO

Probability of getting same no. of colour=6/36
So probability of getting no same color=1- 1/6=5/6
So option 6

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Surendra Naraga   9 years AGO

In a single throw of two dice, n(S)=(6*6)=36
Let E=Event of not getting same number of the both side=
{(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5)}
n(E)=30
p(E)= n(E)/n(S)
=30/36
=5/6
option 6

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Gugulothu vijaykumar   9 years AGO

In a single throw of two dice n(s)=6*6=36
Let E=event of not getting the same number of both dice
n(E)=30
P(E)=n(E)/n(S)=30/36
=5/6

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abhishek   9 years AGO

probability of getting the same numbers = 6/36=1/6
probability of not getting the same numbers= 1-(1/6)=5/6

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Rajendra Aware   9 years AGO

two dice thrown sample space 36 and no same number on dice of possibility 30
therefore final answer is 5/6

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sweet   9 years AGO

Probability of throwing two dice is = 3
Probability of getting the same number both the sides = 6
not getting same number both the sides = 36-6=30

probability = 30/36 = 5/6
The answer is 6

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Ankit   9 years AGO

probability of getting same no. on both the dice is 6/36 i.e(11,22,33,44,55,66)so not same is 1-(6/36)=30/36 which is equal to 5/6.

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manu sharma   9 years AGO

prob of getting same no on both dice is 6/36
prob of not getting same no on both dice is 1- 6/36 = 30/36 or 5/6

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C. MUTHU KARTHIKA   9 years AGO

there are total 36.the same number is 6 probabilities so 30/36is 5/6
that is 36-6=30

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Shubham Raj   9 years AGO

p(not getting same)=1-p(getting same no)
=1-(1/6)
=5/6

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sukriti singh   9 years AGO

chances of getting same number on both dice is (1,1),(2,2)(3,3)(4,4)(5,5)(6,6)
not getting same is total chance- chance of getting same num
=36-6=30.
probability= 30/36=5/6ans.

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suvastika   9 years AGO

prob of getting same num on two dice is 6/36......so prob of not getting same num id 1-(6/36)=5/6

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Kiran Notwani    9 years AGO

We have 6 cases where numbers will be same
That is
1-1,2-2,3-3,4-4,5-5,6-6
So probability of getting same number is 6/6*6= 1/6

Hence probability of not getting same numbers is 1-1/6= 5/6

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Abhimanyu Raj   9 years AGO

total no of favourable outcome =36
total no =6
1-6/36=5/6

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Aman   9 years AGO

The probability that the numbers are the same is 1/6. So the probability that they are not the same is 1 - 1/6 = 5/6.

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Moutam Vishnu Murthy   9 years AGO

(1,1) (2,2) (3,3) (4,4) (5,5) (6,6)- 6 outcomes of 36
30/36=5/6

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Pesari Udayasree   9 years AGO

answer:5/6
probability of getting same number on both dice is 1/6
{(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)}=6 sample space,6/6^2=1/6
now probability of getting not same on both dice is 1-1/6=5/6.

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Basha   9 years AGO

probability of getting doublet is 1/6...
so not getting is 1-1/6=5/6

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Nandkishor jaiswal   9 years AGO

total posibility=36
same posibility=6
not getting same= (36-6)/36
=5/6

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PRAGATHI G   9 years AGO

probability of getting same is 1/6. hence probability of not getting same is 5/6

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ragavendiran   9 years AGO

when 2 dice thrown n(s)=36

prabability of same number (1,1) (2,2) (3,3) (4,4) (5,5) (6,6) so 6

6/36 =1/6

then prob of getting not same number= 1-(1/6)
=5/6

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Gaurav Sarkar   9 years AGO

probability of getting the same no. on two dice is on a single throw is 6/36 = 1/6

now, probability of not getting the same no. on both dice is .... 1-1/6 = 5/6
hence, ans is option 6) 5/6

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ABHIJEET ANAND   9 years AGO

there are 6 ways to get same no. like (1,1),(2,2),...(6,6).now as probablity of getting same no is 6/36=1/6.But probality of getting not same no is 1-(1/6)=5/6.

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manikanta   9 years AGO

probabilty of getting same number(1,1),(2,2),(3,3),(4,4)(5,5),(6,6)-->6 out of 36 and remaning are not same number -->30.
Required probability 30/36-->5/6

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Shrey Agrawal   9 years AGO

total events = 6*6 (mutually independent events)
occurance of same numbers = 6
probability of getting same numbers = 1/6
probability of not getting same number = 1-(1/6)=5/6.

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meghna jain   9 years AGO

probability of getting same number is 1/6 therefore not getting the same num. we will subtract it from 1

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Santosh Kumar   9 years AGO

(1,1),(1,2)......(6,6)
Same no=6/36=1/6
not same no=1-1/6=5/6

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Ravikant Bhande   9 years AGO

probability of getting same no is 1/6
so probability of not getting same number is (1-1/6)= 5/6

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Saikrishna   9 years AGO

we get same number of two dice are (1,1),(2,2),(3,3),(4,4),(5,5),(6,6) ----total 6posibilities
total probability of getting similar numbers is 6/36=1/6
so not getting is 1-1/6=5/6

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abhishek kumar sinha   9 years AGO

Total possible 36 =6*6
Exclude 11,22,33,44,55,66
So 36-6=30 , then 30/36
5/6

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Arun Jose Ozhukayil   9 years AGO

Probability for 2 same numbers in two dice is 6/36=1/6 so probability of getting not getting is 5/6

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Devendra Marghade   9 years AGO

Total outcomes=6*6=36
Getting same number on both the dice=(1,1) (2,2) (3,3) (4,4) (5,5) (6,6), total=6
So not getting same number on both the dice=36-6=30
Probability=30/36=5/6
Option 6)

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sumit kumar   9 years AGO

fabour case for same digit on both size is 6
so probability for both dice has same digit on the face is 6/36 =1/6
not getting same no on both face =1-1/6=5/6

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martha rachana   9 years AGO

Total event is 6*6=36
The condition satisfying. Events are (1,2),(1,3),(1,4),(1,5),(1,6)
Similarly do this for renaming numbers therefore sample events are 5*6=30
P(E) =n(S) /n(E)
P(E) =30/36=5/6

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abhijeet gupta   9 years AGO

prob of getting same no =1/6
prob of not getting =1-1/6
=5/6

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Sivaprakash.J   9 years AGO

probility to get same no is 1/6
then for not getting same will be 5/6

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Maneesh Shringi   9 years AGO

Total probability - probability of getting same no. = probability of not getting same no.
Total probability = 1
event of getting same no.= (1,1 ),(2,2),(3,3),(4,4),(5,5),(6,6)
no of elements in sample space n(S)=36
no. elements in event n(E)=6
probability of getting same no.= n(E)n(S)
=636
=16
probability of not getting same no= Total probability- probability of getting same no
=1-16
=56

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jayaram   9 years AGO

clearly n(S)=36
Let(E)={(1,1),(2,2),(3,3),(4,4),(5,),(6,6)}
P(E)=6/36=1/6
P(not-E)=(1-1/6)=5/6

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SOMA NARESH   9 years AGO

Total chances=36
Possibilities of getting same number=6
remaining possibilities=36-6=30
Probability=30/36=5/6

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Umakant gaidhane   9 years AGO

As there are only 6 cases where we are getting the same in both the dies i.e. (1,1),(2,2),(3,3),(4,4),(5,5) and (6,6).. therefore

probability is 6/36= 1/6
this is for getting both the terms same.

so 1-(1/6) =5/6 is for not getting the same number on both the dies.

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abhiraj panja   9 years AGO

as there is the probability of being the sane no in both dice is = 6/36=1/6
so the probability of not getting the same no in both dice is
= 1- 1/6
=5/6

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Dwaipayan Goswami   9 years AGO

If we throw two dice together we will get 36 possible outcomes and only 6 ways we can get same numbers (1,1),(2,2),(3,3),(4,4),(5,5),(6,6). So the probability of not getting same numbers is (36-6)/36 = 30/36 =5/6

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sunl namdev   9 years AGO

total case of same no both dice is (11.22.33.44.55.66) 6 case
and total is 6*6 --36 so (1-6/36) ==5/6

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anju sukumaran   9 years AGO

probability of getting the same number of both the dice is 6/6^2.
so probability of not getting the same number of both the dice is 1-(6/6^2) = 5/6

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Mohan Raj   9 years AGO

probability of getting same numbers of both dice is 6/36=1/6
the probability of not getting same number of both dice is 1-1/6=5/6

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kartik sahgal   9 years AGO

bcoz probability of getting same number is 6/36=1/6 then the probability of not getting same number is 1-1/6= 5/6

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sa satish   9 years AGO

Getting same number on both dice = 6/36= 1/6
Not getting same number = 1 - 1/6 = 5/6

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Arvind kumar   9 years AGO

Probability of getting same number of both the dice=6/36
i.e. 1/6
Probability of not getting same number of both the dice=1-(1/6)
i.e. 5/6

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Deepak Kesharwani   9 years AGO

favorable condition 30
taotal condition 36
so 30/36=5/6

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SAKTHEESVARI S   9 years AGO

probability of getting same number on both dies is equal to 6/36. not getting= 30/36

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sudhir   9 years AGO

probability of getting same number is 6/36=1/6
so not getting =1-1/6
=5/6

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jeetesh gaur   9 years AGO

becouse the prbability of getting the same no is 6 and no .of outcomes ll be 36 then the 36-6=30 ll be no of outcomes nt geeting the same no so probability ll be 30/36=5/6 ...

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pankaj   9 years AGO

no. if favourable outcomes=30
total outcome=36
probability=30/36=5/6

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Sachin B P   9 years AGO

30/36=5/6
30-is not getting same number
36-total number of cases

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praveendas   9 years AGO

probability =no of favour outcomes/total no of outcomes .
total no of outcomes for two dices =36.
no of favour conditions are=30.
probability =30/36=5/6..is the ans
option 6

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BALA   9 years AGO

36/36-6/36=5/6
Total number of dies (in terms of probability ) is 36/36=1
No of dies having same face 6/36=1/6
so the answer is 1-1/6=5/6

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umang agarwal   9 years AGO

probability of getting same no. is=6/36=1/6.
so probabilty of not getting the same no. is=1-1/6=5/6 ans.

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Sandip Shaw   9 years AGO

n(s)=36
total pair of same number=6
therefore n(e)=6
now probablity of getting same number=6/36=1/6
therefore probablity of not getting same number= 1-1/6=5/6

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Venkatesh kadali   9 years AGO

Getting same number on two dices is = 6
and total number of chances is =36
probability of getting same number on two dices is=6/36=1/6
probability of not getting same number on two dices is = 1-1/6
=5/6
so answer is 6 option

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MRITUNJAY   9 years AGO

total number of outcome=36

favourable outcome=30

p=30/36=5/6

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aman aditya   9 years AGO

probability of getting same number= 6 times
so , 30/36=5/6

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