The average age of a husband and wife was 23 years when they were married 5 years ago. The average a

MRITUNJAY   9 years AGO

sum of age of husband and wife 5 years ago=23*2=46
total present age of husband and wife is 46+10=56
sum of age of husband wife and son is =60

age of son is 60-56=4 year

option 4

Like? Yes (11) | No (1)  

SURAN PRASAD PENKE   9 years AGO

Age of husband=H
Age of wife =W
Age of child =C
((H-5)+W-5))/2=23
H+W=56
(H+W+C)/3=20
C=4yr

Like? Yes (6) | No (1)  

ASHWIN   9 years AGO

within 5 years gap, the average would have been 28 for husband and wife and toltal would be 56 but a child made the average as 20 and total as 60 and so 60-56=4 should be child's age.

Like? Yes (7) | No (2)  

UJJWAL KAMAR   9 years AGO

Current avg age= 28
Now let the age of child be x
So
(28+28+x)/3=20
X=4

Like? Yes (6) | No (2)  

MITHLESH KUMAR   9 years AGO

let present age of husband and wife be x and y respectively.
now
avg age before 5 years be
(( x-5)+(y-5))/2=23
x+y=56 -----------(1)

now at present time
age of child be z
avg age of husband, wife, child is
(x+y+z)/3=20
x+y+z=60 ----------(2)
solving 1& 2
z=4
hence age of child is 4 year

Like? Yes (4) | No   

vamsi krishna   9 years AGO

present age of husband & wife= 2x23+2x5 = 56
present age of husband wife & child = 3x20 = 60
therefore present age of child = 60-56 = 4 years

Like? Yes (4) | No (1)  

avinash kumar   9 years AGO

age of child=[(20*3)-(23*2+5*2)]
=60-56 =4yrs

Like? Yes (3) | No   

Deepanshu Chaturvedi   9 years AGO

let husbands age be x years wife's age be y years and childs age be z years
according to question (x-5+y-5)/2=23 and (x+y+z)/3=20 solving we get z=4 years
option 4)

Like? Yes (2) | No   

Anuj verma   9 years AGO

(x+y)/2=23 five years before
today each of husband and wife age will be increased by 5 ,so total increase of 10 so (x+y+z+10)/3=20 .on solving above and below eq we get z=4 ,which is the age of child.

Like? Yes (2) | No   

Aman   9 years AGO

Sum of present ages of husband and wife = 2 × 23 + 2 × 5 = 46 + 10 = 56
Sum of the present ages of husband, wife and the child = 3 × 20 =60
Therefore, the age of the child = 60 – 56 = 4 years

Like? Yes (2) | No   

RUCHALI RAJ   9 years AGO

let husband age is h
let wife age is w
let child age is c
5 years ago,
(h+w)/2=23 => h+w=46
present age => h+w=56
(h+w+c)/3=20
c=60-56 =4 years

Like? Yes (2) | No   

Anuj Dwivedi   9 years AGO

total age of husband wife 5 year ago is 23*2= 46
and after 5 year and age increased by 5 year both and total age 56 year
and average age of 3 ppl is 20 so total 60 year hence child age =60-56=4 year

Like? Yes (1) | No   

aman aditya   9 years AGO

5 year ago sum of husband and wife=23*2=46
sum of age of husband, wife,child=20*3=60
sum of husband and wife now=28*2=56
so age of child=60-56=4

Like? Yes (1) | No   

YASODA SURENDRA   9 years AGO

Present:-
Age of husband=h
Age of wife=w
Age of child=c
5 years ago:-
Age of husband=h-5
Age of wife=w-5
(((h-5)+(w-5))/2)=23
h+w=56
((h+w+c)/3)=20
h+w+c=60
=>c=60-56
c=4 yrs

Like? Yes (1) | No   

Bairi Sowjanya Reddy   9 years AGO

let present age of wife ,husband,child be w,h and c respectively
then 5 years ago,
husband's age=h-5 and wife's age=w-5
avg of both 5 years ago is 20
therefore ,(h-5+w-5)/2=23
h+w=23*2+10=56
given avg o all the three now is 20
therefore, (h+w+c)/3 = 20
then h+w+c =60
c=60-56 =4

Like? Yes (1) | No   

SHAIK MAHABOOB BASHA   9 years AGO

Sum of present ages of husband and wife = 2 × 23 + 2 × 5 = 46 + 10 = 56
Sum of the present ages of husband, wife and the child = 3 × 20 =60
Therefore, the age of the child = 60 – 56 = 4 years

Like? Yes (1) | No   

sivaswamy cheduluri   9 years AGO

h=husband,w=wife,c=children
h+w/2=23
h+w+c/3=20
solve the above equations we get c=4years

Like? Yes (1) | No   

alpesh kurhade   9 years AGO

Sum of present ages of husband and wife = 2 × 23 + 2 × 5 = 46 + 10 = 56
Sum of the present ages of husband, wife and the child = 3 × 20 =60
Therefore, the age of the child = 60 – 56 = 4 years.

Like? Yes (1) | No   

chetan   9 years AGO

let x is husband and y is wife.
Given that average of their age is 23 years.
so (x+y)/2=23----(1)
when 5 years back so add 5 yrs.
x+y=56.
Let z is child.Given that x+y+z=3*20.
x+y+z=60------(2)
solving 1 & 2 we get z=4.
So option 4 is correct.

Like? Yes (1) | No   

EMANDI KETHAN KUMAR   9 years AGO

x+y=46 when married
x+y=51 now
child age =(20*3)-51-5=4 years

Like? Yes (1) | No   

RUPNARAYAN RANA   9 years AGO

present total age of husband and wife=56
present age of hus,wife & child=60
so child=4

Like? Yes (1) | No   

ramakrishnateja   9 years AGO

(h-5)+(w-5)/2=23. hence h+w=56.( h+w+c)/3=20.(it is given)
so h+w+c=60. c=60-(h+w)=60-56=4yrs.

Like? Yes (1) | No   

Pintu Kumar   9 years AGO

before 5 year avg of both 23*2=46
present year avg of both =46+(5*2)=56
total age of all=20*3=60
age of child=60-56=4

Like? Yes (2) | No (1)  

Devendra Marghade   9 years AGO

Total present age of husband & wife=2*23+2*5=56 years
If present ageof child=x, then (56+x)/3=20, x=4
Option 4)

Like? Yes (1) | No   

sudiptaa   9 years AGO

Sum of present ages of husband and wife = 2 × 23 + 2 × 5 = 46 + 10 = 56
Sum of the present ages of husband, wife and the child = 3 × 20 =60
Therefore, the age of the child = 60 – 56 = 4 years

Like? Yes (1) | No   

Deepak Kumar   9 years AGO

Sum of present ages of husband and wife = 2 × 23 + 2 × 5 = 46 + 10 = 56
Sum of the present ages of husband, wife and the child = 3 × 20 =60
Therefore, the age of the child = 60 – 56 = 4 years. Ans.

Like? Yes (1) | No   

RAGHUNANDAN H M   9 years AGO

5 yrs ago,H+W=23*2
PRESENT, H+W=46+10=56
PRESENT,H+W+C=20*3=60
C=60-56=4YRS

Like? Yes (1) | No   

vikash kumar das   9 years AGO

as the sum oc age of husband and wife 5years ago is=23*2=46
5 years later it will be 56 year.
then the age of child=3*20-56=4years

Like? Yes (1) | No   

Ashutosh   9 years AGO

lets wife age=x, husband=y and child age=z
so x+y=2*46
after five years avg become
(x+5+y+5+z)/3=20
on solving above equations we will get Z=4

Like? Yes (1) | No   

vinay Kumar   9 years AGO

h+w/2=23, h+w=56.present age
h+w+c/3=20 h+w+c=60
60-56=4 ans

Like? Yes (1) | No   

Deepak   9 years AGO

(Husband -5 + wife -5 ) / 2 = 23, -5 because there were married 5 years ago
H + w = 56,

now the average age of the family, (H + W + C)/3 = 20, or c = 4 years.

Like? Yes (1) | No   

Abhisheak Kumar Missu   9 years AGO

Present average age of the husband and the wife=28*2=56 years
Present average age of the husband, the wife and a child=20*3=60 years
Since the age of child=4 years

Like? Yes (1) | No   

saptadeep saha   9 years AGO

father= x, wife=y, son = z
so, x+y=46
again after 5 yrs, (x+5)+(y+)+z=60
solving, x+y+z=50
so z=4 (since x+y=46)

Like? Yes (1) | No   

rakesh sharma   9 years AGO

(a+b)/2=23
a+b=46(before 5 year)
after 5 yr.=>a+b=56
now a+b+c=3*20
56+c=60
c=4
so answer option 4 is true

Like? Yes (1) | No   

KUMAR RAJAT   9 years AGO

total age 5 years before=23*2=46
present age =46+2*5=56
Present total age+20*3=60
so age of child=60-56=4 years

Like? Yes (1) | No   

deepthi   9 years AGO

average of H,w =23 before 5 years
now sum of their ages is 46+10=56
average with new born is 20
son age = 3*20-56=4

Like? Yes (1) | No   

Kalpana Sharma   9 years AGO

((h-5)+(w-5))/2=23
h+w=56
now,
(h+w+c)/3=20
h+w+c=60
56+c=60
c=4

Like? Yes (1) | No   

PRAGATHI G   9 years AGO

present ages h,w,c
(h-5)+(w-5) =(2*23)
h+w+c= 3*20
c=4

Like? Yes (2) | No (1)  

CHITHRA V K   9 years AGO

5 years before avg =23. so total age =46
So now avg = 20
total age = 20 * 3 =60
total age of husband and wife now = 46 + 10 =56
60 -56 =4

Like? Yes (1) | No   

YASWANTH REDDY   9 years AGO

let Husband's age be H and that of wife be W now.
Then before 5 yrs, their ages will be H-5 and W-5 and avg is (H+W-10)/2 = 23. therefore we get H+W = 56
Now, as per the given info, (H+W+C)/3 = 20.
After solving these two eq.s, we get C = 4yrs

Like? Yes (1) | No   

karthiga   9 years AGO

At Present H+W age is 56;
F+W+S = 60;
S=60-56=4;

Like? Yes (1) | No   

ranjit   9 years AGO

5 Year ago
(H-5)+(w-5)=23*2
Now
H+w+c=20*3
So c is 4 years

Like? Yes (1) | No   

rahul kumar   9 years AGO

Let their current age be h,w.
so, their age five year ago are,
(h-5),(w-5);
=> (h-5)+(w-5)/2=23,
=>h+w=56,
now the current avg. of these 3 are 20.
=> (h+w+c)/3=20
(56+c)=60;
=> c=4.
so the age of child is 4 years

Like? Yes (1) | No   

Chirag   9 years AGO

(h-5+w-5)/2=23
h+w=56
(h+w+c)/3=20
c=4

Like? Yes (1) | No   

rohit gandupalli   9 years AGO

Sum of present ages of husband and wife = 2 × 23 + 2 × 5 = 46 + 10 = 56
Sum of the present ages of husband, wife and the child = 3 × 20 =60
Therefore, the age of the child = 60 – 56 = 4 years.

Like? Yes (1) | No   

kirtesh thakre   9 years AGO

23*2+5*2=56
20*3=60
60-56=4 year child age

Like? Yes (1) | No   

santhosh   9 years AGO

let husband age be x
wife is y
child is c
given x+y-10=23*2
x+y=56
x+y+c=20*3
c=4

Like? Yes (1) | No   

Meenakshi   9 years AGO

Age of child = [(20*3)-(23*2+5*2)] years
= 4 years
option 4)

Like? Yes (1) | No   

reena   9 years AGO

h+w/2=23
23*2+5*2=56

h+w+c/3=20
56+c=66
c=4

Like? Yes (1) | No   

premlata   9 years AGO

let husband's present age = x
wife's present age = y
Child's age = w

5 yrs ago avg. age was 23 yrs
so, present avg. age should be 28 and x+y=56
now , present avg. of all three -> (x+y+w)/3 =20 (given)
(56+w)/3=20
so, w=4
Hence child's present age is = 4 yrs.

Like? Yes (1) | No (1)