Ashok lent Rs.1200 to Bhupesh for 3 years at certain rate of simple interest and Rs.1000 to Chandan

harsh dhir   9 years AGO

1200*r*3/100 = (1000*r*3/100 ) + 50
36 r= 30 r + 50
r=50/6=25/3

Like? Yes (13) | No (1)  

Neelima Kongathi   9 years AGO

simple interest=PRT/100
Bhupesh:
principle(P)=1200
time(T)=3yrs
rate(R)=r
chandan:
principle(P)=1000
time(T)=3yrs
ashok got 50 more from shubam....so add 50 to chandan's SI to make equal with shubam's SI
(1200*3*r)/100=((1000*3*r)/100)+50
r=25/3

Like? Yes (4) | No   

Devendra Marghade   9 years AGO

If rate of interest=x %, then
(1200*x*3/100)-(1000*x*3/100)=50
x=25/3
Option 6)

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JANARTHANAN RAM   9 years AGO

Assume that rate is x,
(1200*3*x/100)-(1000*3*x/100)=50;
We get x as 25/3.
So option 6 is correct answer.

Like? Yes (2) | No   

Param   9 years AGO

1200*3*r/100=x+50
1000*3*r/100=x
division, x=250
so r=25/3

Like? Yes (2) | No   

Anurag Bawankar   9 years AGO

I=PNR/100

Interest from Bhupesh =36R
Interest from Chandan=30R

Difference=6R=50
Thus R=50/6=25/3
Option6

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HEMA   9 years AGO

THE FORMULA FOR SIMPLE INTEREST = PNR/100
P=100*SI/R*N
R=100*SI/P*N
N=100*SI/P*R
RATE OF INTEREST FOR BHUPESH IS MORE THAN 50 THAN CHANDAN THEN R=50 + Y
THEN BY SOLVING I GOT 25/3 AS MY ANSWER

Like? Yes (2) | No   

sumit kumar   9 years AGO

a/c to question
let rate is x
1200*3*x/100 -1000*3*x/100=50
=>36x-30x=50
=>6x=50
x=25/3
option 6 is right

Like? Yes (2) | No   

Saleel Kulkarni   9 years AGO

The interest from Bhupesh = 1200*3*R/100 =36R___equation 1
The interest from Chandan = 1000*3*R/100 = 30R__equation 2
equation 1 - equation 2 = 50 ___________given
36R-30R=50
6R=50
R=25/3

Option 6)

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Aakash Beniwal   9 years AGO

(12*3*r/100 )-(10*3*r/100)=50
find r

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NIKHIL JAIN   9 years AGO

Let rate = r
r(1200*3-1000*3)/100=50
on solving this we get r=25/3%

Like? Yes (2) | No (1)  

brijesh    9 years AGO

A=(1200*3*R)/100
A=36R
36R+50=(1000*3*R)/100
36R-30R=50
6R=50
R=25/3

Like? Yes (1) | No   

Jamil Ahmed   9 years AGO

Interest on difference of principle of Ashok & Bhupesh which is Rs.(1200-1000=)200 for three years is Rs.50.

Therefore, rate of simple interest = 50*100/3*200 %= 25/3%

Like? Yes (1) | No   

Testing Account   9 years AGO

5+7+4=364730
9+6+3=456990
8+2+9=912672
then
7+3+5=??????

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DEBMALYA GHOSAL   9 years AGO

p=1200*3*r/100=36r
c=1000*3*r/100=30r
36r-30r=50 => r=25/3 (ans.)

Like? Yes (1) | No   

Amutha Jyothi   9 years AGO

pnr/100 (for bhupesh)=prn/100 +50 (for chandan)
so ,
36r=30r+50
r=25/3

Like? Yes (1) | No   

Vipul Puranik   9 years AGO

SI1=1200*3*R/100=36R
SI2=1000*3*R/100=30R
36R-30R=50
6R=50
R=50/6=25/3%

Like? Yes (1) | No   

Venkateswarlu   9 years AGO

I1=1200*3*r/100 ==> I1=36R
I2=1000*3*r/100 ==> I2=30R
given that I1=I2+50 ==>r=50/6 =25/3

Like? Yes (1) | No   

Mahesh Chaurasia   9 years AGO

Ashok gives 200 more to Bhupesh than Chandan. At 200 principal amount 50 is the SI.
SI=PNR/100.
50=200*3*R/100
R=25/3 %

Like? Yes (1) | No   

liza   9 years AGO

Si for bhupesh=(1200*3*x)/100.its equal to 50+((1000*3*x)/100)
X=25/3

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JEGATHA.H   9 years AGO

difference between the amount= 200
simple interest of that amount=50
SI=PNR/100
50= 200*3*r/100
r=25/3%

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jasmine chhabra   9 years AGO

let Simple interest be Rs. x , and rate of interest is same, then,
(x+50)/(1200*3) = x/(1000*3)

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karthiga   9 years AGO

SI = pnr/100;
S I Difference is 50;
1200*3*r/100 - 1000*3*r/100 = 50;
6r = 50;
r = 25/3%.

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richa   9 years AGO

the amount returned from bhupesh minus that returned from chandan is 50rs

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hina yamin   9 years AGO

Taking rs x as interest for bhupesh andx plus50 for chandan
Eqatong two equation Option 6 satisfy thequestin

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Ganesh   9 years AGO

200 for 3 yr interest is 50 so 200 for 1 year is 25% interest(50)=25/3

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swetha rangaraj   9 years AGO

let take x as the rate of interest
(1200*3*x/100)- (1000*3*x/100)= 50
x=25/3

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A SRAVAN KUMAR   9 years AGO

1200*3*r/100 = 1000*3*r/100 +50
=> 36r = 30r + 50
=> r =50/6 =25/3%

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RITESH KUMAR JHA   9 years AGO

interest by bhupesh - 50= interest by chandan. so,
p*r*t/100 - 50=p*r*t/100
1200*r*3/100 - 50= 1000*r*3/100
r=25/3%

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Ritesh kumar   9 years AGO

ashok lent to bhupesh..
S.I=x+50
R=(100*SI)/P*T
=(100*(X+50))/1200*3...eq(1)
ashok lent to chandan
SI=X
R=(X*100)/1000*3....eq2
equating eq1 and 2
then,
X=250
putting the value of X in eq2
get
R=(250*100)/1000*3
R=25/3 % answer

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rahul shaw   9 years AGO

((1200-1000)*3*r)/100=50
after solving we get r=25/3%

Like? Yes (1) | No