Points A and B are 60km apart. A bus starts from A and another from B at the same time. If they go i

JEPHY VARGHESE   8 years AGO

assume bus A starts from point A with greater speed A, and B from point B with B km/h.

if the 2 buses are are travelling in the same direction they will meet after 6 hrs.
assume A travels towards B,
time = distance/speed
6 = (60+x)/A = x/B
A-B = 10 -----(1)

if they travels in opposite direction they will meet after 2 hrs
distance= speed * time
distance traveled by B = 2B
traveled by A = 60-2B

2= (60-2B)/A = 2B/B

A + B = 10 -------------(2)

(1) + (2) ---->
A = 20

speed of the bus with greater speed is speed of bus A ie = 20 km/hr

Like? Yes (8) | No   

Bhavithra Devi   8 years AGO

let the speed of buses be x and y
for same direction speed=x-y
speed=distance/time
=>x-y=60/6
=>x-y=10...(1)
for opposite direction speed=x+y
=>x+y=60/2
=>x+y=30...(2)
solving (1) and (2) ,x=20,y=10
therefore speed of bus with greater speed is 20km/hr

Like? Yes (6) | No   

JENSI KARUNYA.S   8 years AGO

suppose speed of the buses A & B are respectively x km/hr &
y km/hr with x>y then,
6x-6y=60
x-y=10
2x+2y=60
x+y=30
by solving these two equations, x=20 km/hr
y=10 km/hr
therefore the greatest speed is 20 km/hr
the correct option is: 4) 20 km/hr.

Like? Yes (7) | No (2)  

Shagun Chaudhary   8 years AGO

Let the speed of bus from A is u and from B is v,
=>(60/(u-v))=6
=>60/(u+v)=2
so u-v=10;
u+v=30;
u=20
v=10

Like? Yes (6) | No (2)  

vignesh   8 years AGO

1 speed is 20 and another is 10
because both should travel 60km in 2 hours and both meet after 6 hrs when travel in same direction

Like? Yes (4) | No   

Jamil Ahmed   8 years AGO

Let speed of the buses starting from A and B be x km/hr and y km/he respectively where speed of the bus starting from A is greater.
Again, when going in opposite direction, let the buses meet at a point C at a distance a km away from A.
So, x = a/2 or a = 2x
and y = 60-a/2 or a = 30-y
Hence, x = 30-y.

Similarly, when going in the same direction, let they meet at a point D which is b km away from B.
So, x = 60+b/6 or b = 6 (x-10) and y = b/6 or b = 6y
Hence, x = y+10.

Therefore, 30-y = y+10 or y = 10
Hence, x = 20.

Like? Yes (3) | No   

Shinjaa   8 years AGO

sol
x-y=10
x+y=30
x=20

Like? Yes (2) | No   

Berlin Jessie   8 years AGO

let the speed of two buses be x and y..
speed=distance/time
for same direction speed=x-y
therefore x-y=60/6
x-y=10
for opposite direction speed=x+y
therefore x+y=60/2
x+y=30
solving both equations, x=20,y=10
hence speed of bus with greater speed is 20km/hr

Like? Yes (2) | No   

Jaydev Dinda   8 years AGO

Let,The bus started moving from A,speed=X
The Bus started moving from B,Speed =Y
If two buses are opposite direction,
60/(X+Y)=2
=>X+Y=30 .....(1)
If two buses are same direction,
60/(X-Y)=6
=>X-Y=10 ....(2)
after solving eqn1 & eqn 2,
we can get X=20
Y=10...
so The Speed of the Bus with greater speed is 4)20 km/hr.

Like? Yes (2) | No   

vikash ranjan   8 years AGO

let two speed s1, s2;
(60)/(s2-s1)= 6 hr; s2 - s1 =10;

(60) /(s1+s2) = 2hr;
60/(s1+ s1+ 10) = 2hr;
s1=10;
s2=20;

Like? Yes (2) | No   

GOURANGA SUNDAR MANDAL   8 years AGO

let greater speed of one bus is x km/h ,and slower speed of another bus is y km/h
so,when they goes to same direction , the bus which start from B point,it covers 6y km ..and others bus covers 6x km...then they meet
so the 1st equ is..6x=6y+60.....
so x-y=10
when they goes to oposite direction...they covers 2x and 2y km
so the equ 2 is 2x+2y=60
so..x+y=30
now we get calculating equ 1 and equ 2....x=20. and y=10
so option 4 is correct answer

Like? Yes (1) | No   

Ankita Dutta Majumder   8 years AGO

60/(x-y)=6 60/(x+y)=2
x=(60+6y)/6 60-2y/2=x

Like? Yes (1) | No   

Isha Saxena   8 years AGO

When the buses from A and B move in same direction-
then they meet after covering 120 km and 60 km respectively at a rate of 20 km/h and 10 km/h respectively.

When the buses from A and B are moving in opposite direction-
they meet after covering 40 km and 20 km respectively.

Like? Yes (1) | No   

harshwardhan   8 years AGO

let x be faster and y be slower speed x+y = 60/2 and 6x - 6y =60 solving x= 20 y= 10

Like? Yes (1) | No   

Anurag Bawankar   8 years AGO

(A+B)*2=60
A+B=30

(A-B)*6=60
A-B=10

From two equations A=20 B=10
Higher speed A=20

Like? Yes (1) | No   

TARUN CHAUHAN   8 years AGO

let x and y be speed of two buses

x+y=30
x-y=10

solving we get x=20 and y=10
hence the answer is 20km/hr

Like? Yes (1) | No   

mustain ahmed   8 years AGO

2=60/x+y
6=60/x-y.....after calculations x=20
y=10...so,ans is 20 km/hr

Like? Yes (1) | No   

sumit kumar   8 years AGO

from the question
let bus A speed is x km/h, bus B has y km/h
when bus in same direction
60/x-y =6
x-y=10 ...........(1)
60/x+y=2
x+y=30...........(2)
solving (1) and (2)
x=20km/h
y=10km/h
so ans is 20km/h option 4

Like? Yes (1) | No   

RITESH KUMAR JHA   8 years AGO

60/x1+x2=6
60/x1-x2=2
from here x1=20.
x1=speed of busA
x2=speed of bus B

Like? Yes (1) | No   

ANKIT KALE   8 years AGO

Same Direction
RELATIVE Speed will be (A-B)
A-B=60/6=10.....[1]
Opposite Direction
RELATIVE speed will be (A+B)
A+B=60/2=30......[2]
solve [1] and [2] simultaneously
A=20 km/hr
B=10 km/hr

Like? Yes (1) | No   

chandan kumar mania   8 years AGO

let one is going x km/ hr and another y km/ hr
then if they move in opposite direction
60/x+y=2 x+y=30 .....?...(1)
t=distance/ speed
if they move in same direction
6x- 6y=60. x-y=10...........(2)
solving equation 1 and 2 we get
grater speed =20 km/hr.

Like? Yes (1) | No   

v.pravalika   8 years AGO

speed of bus from A=x km/hr
from B=y km/hr
same direction:
relative speed=x-y km/hr
x-y=60/6=10km/hr
x-y=10 km/hr -------------1
opposite direction:
relative spped=x+y km/hr
x+y=60/2=30 km/hr
x+y=30 km/hr -------------2
solving 1&2
x=20 km/hr
y=10 km/hr
bus with greater speed=20 km/hr

Like? Yes (1) | No   

meghana   8 years AGO

x-y=10 -----1
x+y=15 -----2
solving 1 and 2
x=20 ,y=10
so greater speed bus is x=20km/hr

Like? Yes (1) | No   

abhishek   8 years AGO

suppose bus from A & B speed id x & y respectively
same direction time of meeting=distance/(x-y)
so x-y=10
opposite direction time of meeting = distance/(x+y)
so x+y=30
therefore x=20,y=10

Like? Yes (1) | No   

v.sudha   8 years AGO

let speed of bus from A=xkm/hr
let speed of bus from B=ykm/hr
same direction:
relative speed=x-y km/hr
x-y=60/6=10km/hr
x-y=10km/hr ----------->1
opposite direction:
relative speed=x+y km/hr
x+y=60/2=30km/hr
x+y=30km/hr -------->2
solving 1&2
we get x=20 km/hr
y=10km/hr
the bus with greater speed=20km/hr

Like? Yes (1) | No   

MD.IFTEKHAR ANSARI   8 years AGO

let x,y be speed of bus at A and B respectively.
eqn for same direction..
60=2(x+y)
or x+y=30
eqn for opposite direction..
60=6(x-y)
or x-y=10
after solving eqns
x=20(speed of the bus with greater speed)

Like? Yes (1) | No   

Manish Kumar   8 years AGO

6=60/x-y
x-y= 10 & ..........(i)
2=60/x+y
x+y=30..............(ii)
from (I) & (ii)
x=20
y=10

Like? Yes (1) | No   

Saleel Kulkarni   8 years AGO

Let the distance traveled by the two buses be (60+x)km from point A at where they meet while going in same direction and the distance traveled from B be y km while going in opposite direction.
So for going in same direction,
speed of 1st bus=(60+x)/6 km/hr
and for going in opposite direction,
speed = (60-y)/2 km/hr
so speed of 1st bus is
(60+x)/6=(60-y)/2
==>x+3y=120__________equation 1

Now speed of 2nd bus in same direction = x/6 km/hr
and in opposite direction = y/2
==>x=3y________________equation 2

so putting equation 2 in equation 1, we get
x=60km and y=20km

So speed of 1st bus = (60+60)/6 = 20km/hr
and speed of 2nd bus = 20/2 =10km/hr

Option 4)

Like? Yes (1) | No   

B.DINESH KUMAR   8 years AGO

speed of bus A is 20
speed of bus B is 10
then only cdn 1 & 2 satisfy

Like? Yes (1) | No   

JEGATHA.H   8 years AGO

time= distance/speed
let speed a = x & speed b= y
same direction moving then speed=x-y
opposite direction then speed=x+y
based on formula 20km/hr

Like? Yes (1) | No   

Gaurab Kumar Jha   8 years AGO

let the speed of buse's are x and y,
A/Q 6y-6x=60 and 2x+2y=60,
and after solving we get y=20 and x=10,
so the answer will be option 4 i,e 20kmph

Like? Yes (1) | No   

MRITUNJAY   8 years AGO

x-y=60/6=10
x+y=60/2=30
after solving equation we get x=20
y=10
greater speed is 20kmph
option 4

Like? Yes (1) | No (1)  

Harsh Poddar   8 years AGO

let speed of the faster train be x and the speed of the slower train be y
distance between them is 60 km
when the run in same direction they reach in 6 hrs so relative speed is 60/6=10 x-y=10
when they travel in opposite direction their relative speed is 60/2=30 x+y=30
solving the two equations x-y=10 and x+y=30 we get x=20,y=10
so speed of faster train is 20
option 4

Like? Yes (1) | No (1)  

Devendra Marghade   8 years AGO

If speeds of the buses starting from A & B are 'x' & 'y' km/hr respectively then
60/(x-y)=6 or x-y=10 ---(i) &
60/(x+y)=2 or x+y=30 ---(ii)
On solving, x=20, y=10
So speed of the bus with greater speed=20 km/hr
Option 4)

Like? Yes (1) | No (1)  

satish ojha   8 years AGO

vecolity = distance / time
opposite direction velocity added ( relative velocity )

x+y=60/2
same direction velocity sub ( relative velocity )
x-y=60/6
2x=40
x=20

Like? Yes (1) | No (1)  

NIKHIL JAIN   8 years AGO

Relative speed of bus going in same direction= (x-y)= 60/6=10
Relative speed of bus travelling in opposite direction =(x+y) = 60/2=30
On solving 2*x= 40
x=20kmph
y=10kmph

Like? Yes (1) | No (1)  

Yashi Das   8 years AGO

Assumptions,
Speed of bus A is a km/hr
Speed of bus B is b km/hr
and a>b
6a-6b=60
2a+2b=60
therefore,a=20 km/hr
b=10 km/hr
So,the speed of the bus with greater speed is 20km/hr i.e. bus A

Like? Yes (1) | No (1)  

bhaskar   8 years AGO

x+y=60/2
x-y=60/6
x=20
y=10

Like? Yes (1) | No (1)  

harsh dhir   8 years AGO

B=A+60
for same direction
A will meet B in 6 hours.Since B is 60 km ahead of A at start At the speed of 20 km/hr,A will cover 120 km & B will cover 60 km at the speed of 10 km/hr.Since B is already have a start of 60 km,it will have cover 120 km.

For Opposite Direction
A will cover 40 km at the speed of 20 km/hr & B will cover 20 km at the speed of 10 km/hr.So they will meet in 2 hrs. because 40+20=60.

Like? Yes (1) | No (1)  

PRABHAT KUMAR   8 years AGO

x-y=60/6=10
x+y=60/2=30
Solving this equations we get
x=20
y=10
Option 4

Like? Yes (1) | No (1)  

Raghav   8 years AGO

A + B = 60/2
A - B = 60/6

A = 20 B = 10

Like? Yes (1) | No (1)  

Param   8 years AGO

from option dist gap 60m
if Va=20km /h *2=40m from a
Vb=10*2=20m from b
when same dir=20*6=120m
from a ,10*6=60from b

Like? Yes (1) | No (1)  

ROHIT KUMAR DUBEY   8 years AGO

Let speed of bus start from ponit A be A and that of point B be B.
Also let A>B.
6A-6B=60
A-B=10.........I
2A+2B=60
A+B=30......II
Solving above equations
A=20 and B=10

Like? Yes (1) | No (1)  

DEBMALYA GHOSAL   8 years AGO

60/x+y = 2 ; 60/x-y = 6
x+y=30; x-y=10
x=20

Like? Yes (1) | No (1)  

alamuri vijaya sekhar reddy   8 years AGO

60= 2A + 2B
6B= 6A-(2A+2B)
solving above we A= 20 km/hr

Like? Yes (1) | No (1)  

velmala gangadhar   8 years AGO

let v1 be the velocity of first bus and..
v2 be the velocity of second bus...
then v1+v2=30..v1-V2=10..then v1=20 and v2=10 kmph........

Like? Yes (1) | No (1)