Ashok can do a piece of work in 80 days. He works at it for 10 days and then Bhuwnesh alone finishes

Piyush Dubey   8 years AGO

Let total unit of work=80 unit
Unit of work done by Ashok in 1 day=1 unit.
Unit of work done by Bhuvnesh in 1 day=70/42=5/3.
So,(1+5/3)x=80
so, x=30 days.

Like? Yes (35) | No (5)  

GOURANGA SUNDAR MANDAL   8 years AGO

ashok can do the work in 80 days....so in 1 day he can finish the 1/80 portion of work
after 10 days 1/8 portion work is completed ..then the remaining work is 7/8 portion
bhuwnesh can do work 7/8 portion in 42 daya
so bhuwnesh can do work in 1 day 1/48 portion
both of them together can do work in 1 day(1/48 +1/80)=1/30portion
so to finish the work they take 30 days
..so option 5 is correct answer

Like? Yes (7) | No (1)  

Shagun Chaudhary   8 years AGO

ashok completes 1/8 part of work so bhuwnesh will have to complete the 7/8 parts
=>42(1/x)=7/8
=>x=48
thus bhuwnesh takes 48 days to complete the work alone.
when they both work together,
n{(1/80)+(1/48)}=1
n=30 days ??

Like? Yes (7) | No (1)  

satish ojha   8 years AGO

Ashok do =80 days
bhuwesh do =48 days

both r doing = 16*5*3/(8)= 30 days

Like? Yes (11) | No (6)  

Devendra Marghade   8 years AGO

10 day's work of Ashok=10/8=1/8, so remaining work=7/8
If Bhuwnesh alone can finish the work in 'x' days, then his 1 day work=1/x, So (7/8)/(1/x)=42, 1/x=1/42
1 day's work of Ashok & Bhuwnesh=(1/80)+(1/42)=1/30
So together they will finish the work in 30 days
Option 5)

Like? Yes (5) | No (1)  

Digvijay singh tomar   8 years AGO

Ashok did a work in 1 Day = 1/80
let bhuvnesh do a work in 1 Day = 1/x
then ,
(10/80)+(42/x)=1
therefore,
x=48
now,
both combinely can do a work in 1 Day=(1/80)+(1/48)=(1/y)
and hence
they can complete a work in 30 Days.

Like? Yes (5) | No (1)  

TUSHARKANTA SAHOO   8 years AGO

after 10 days ashok had done 1/8 work
rest 7/8 work is done by bhuwnesh in 42 days.so bhuwnesh can alone work it in 42*(8/7)=48 days
ashok & bhuwnesh's 1 days work=1/80+1/48=1/30
so work can be completed in 30 days

Like? Yes (4) | No   

sainath kadam   8 years AGO

time taken by ashok to complete the work=80 days

% of done by ashok in 10 day=(10/80)*100 which is 12.5%

% of work done by ashok in 1 day=(12.5/10) which is 1.25%

in 42 days Bhuwnesh completed (100-12.5)=87.5% work

time taken by Bhuwnesh to complete work=(87.5/42)*100 which is 48 days

time required to complete work together=(80*48)/128 which is 30 days(i.e. H.M of ashok and bhuwnesh)

Like? Yes (4) | No   

MRITUNJAY   8 years AGO

ashok 10 days work =10/80=1/8
remaining work =1-1/8=7/8
bhuwnesh total work done in 42*8/7=48 days
total work by both in 48*80/128=30 days
option 5

Like? Yes (5) | No (2)  

subiraj   8 years AGO

ashok can do 1/80 part of work in one day
in 10 days he can do 1/8 part of work
the remaining 7/8 part is done by bhuwnesh
bhuwnesh completes 7/8 part of work in 42 days
so he completes 1/48 ie (7/8*42) part in one day
ashok requires 80 days and bhuwnesh requores 48 days
so together the require (48*80)/(48+80)=30 days

Like? Yes (3) | No   

harsh dhir   8 years AGO

work done by ashok in 10 days=1/8
remaining work=7/8
days taken by bhuvnesh to complete 7/8 work=42 days.so he can complete whole work in 42*8/7=48 days
togethr they can complete work in 80*48/(80+48)=30 days

Like? Yes (5) | No (2)  

Jamil Ahmed   8 years AGO

Ashok finished 1/8th part of work in 10 days. Hence, remaining part of the work left = 7/8th
Bhuwnesh finished 7/8th part of work in 42 days. So, he could finish the whole work alone in 8/7*42 = 48 days.

Therefore, they will finish the work together in 1/(1/48 + 1/80) days = 30 days

Like? Yes (3) | No   

Jyoti prabha Patel   8 years AGO

work done by ashok in 10 days= 1/80*10 =>1/8
so, remaining work=7/8
Bhuwnesh completes 7/8 work in 42 days,
7 parts of work=42 days so 1 part= 6days
so he will complete the total work in 42+6= 48 days

now time taken by both to complete the work is
t(A+B)=(80*48)/(80+48)= 30days

Like? Yes (3) | No   

venkadesh   8 years AGO

1 Day work of ashok 1
1day work of bhuwnesh 1.67
entire work done by both 2.67
80/2.67=30

Like? Yes (3) | No (1)  

Anusha Kallapu   8 years AGO

finding their one day work.. then we can get the together work of them

Like? Yes (2) | No   

Praveen Gupta   8 years AGO

ashok
100% work = 80days
1 day = 100/80 % work
10days=100*10/80
bhuwnesh
100-100/8 =42 days
700/8 =42 day
both together work in one day=3.33%
to complete 100% work they tks 30 days

Like? Yes (2) | No   

RISHABH   8 years AGO

Ashok 1 day's work=1/80
so, 10 days work=10/80=1/8
So, total work left=1-1/8=7/8
Bhuwnesh finishes the remaining (i.e 7/8)work in 42 days
so alone he can finish the work in 42*8/7 days =48 days
So, both can finish the work in 1/80+1/48=8/240 days
=240/8=30 days

Like? Yes (2) | No   

RITESH KUMAR JHA   8 years AGO

1 day work of ashok is 1/80 . so, 10 day work is 10/80. now. remaining work os 1-10/80=70/80 which is done by bhuwnesh in 42 days. from here bhuwneah 1 day work is 1/48.therefore 1/80+1/48= number of days taken by both is 30. so, ans is 30

Like? Yes (2) | No   

Nitesh kumar   8 years AGO

because ashok done 1/8 works in 10 days and remaining work which is 7/8 done by bhuvanesh in 42 days so bhuvnesh complet alone it in 48 days now they together complet in 1/80 +1/48=30 days

Like? Yes (2) | No   

NIKHIL JAIN   8 years AGO

Ashok one day work = 1/80
work done by him in 10 days= 1/8
remaining work=1-1/8=7/8
Bhuwnesh does 7/8 wprk in 42 days.
His one day work= 1/48
Together they will finish the work in = (80*48)/128=30 daysd

Like? Yes (2) | No   

Saleel Kulkarni   8 years AGO

Ashok does 1/80 part of work in 1 day.
He works for 10 days so 1/8th part is done, and 7/8th part is left.
Bhuwnesh does 7/8 work in 42 days, so he completes 1/48th part of work in 1 day.
When both work together the part of work completed in 1 day=(1/8)+(1+48)=(1/30)
So they require 30 days to complete the work

Option 5)

Like? Yes (2) | No   

Vijay Sharma   8 years AGO

1/80 *10=1/48
bhuvneshwar complete a work in 48 days
1/48 +1/80 = 1/30
he complete the work 30 days

Like? Yes (2) | No   

narendra   8 years AGO

1 day-1/80, 10 days-10/80,remaining=7/8 part is done in 42 days==,second can do in 1day=1/48 adding both answer will be 30

Like? Yes (2) | No   

sumit kumar   8 years AGO

Ashok 10 days work =1/80*10=1/8
rest work =1-1/8=7/8
a/c to question
7/8 work had been finished in 42 day
so 1 work will be finished in 42/(7/8)=48 days
now,
if work will work together
1 day work = 1/42+1/80=1/30
so total time taken by both = 30 days
option 5

Like? Yes (2) | No   

suryakant singh   8 years AGO

ashok can do 100/80%=5/4 % work in a day and bhuwnesh can do (100-10*5/4)/42 % work in a day
then, in 1day together they can do 280/84% then for 100% of work they take 100/(280/84)days= 30 days

Like? Yes (2) | No   

shiva   8 years AGO

ashoka one day work is 1/80
and work done in 10 days is 1/8
remaining work is 7/8
and bhuwanesh finishes in 48 days
together finish in 1/80+1/48=1/30
and = 30

Like? Yes (2) | No   

Shanakar   8 years AGO

One day work of ashok is (1/80),
In 10 days work done by ashok will be 10* (1/80)
= 1/8
Remaining work will be 1-(1/8) = (7/8)
(7/8) work is completed by bhuwnesh in 42 days
So on day work done by him is (7/8)/42
On solving this we get 1/48. This is the one day work of bhuwnesh.
Add (1/80) and (1/48) to get one day work of work done by both ashok and bhuwnesh. On adding , we will get (1/30) as answer.
So, in 30 days both of them can complete the work o if they work together.

Like? Yes (2) | No   

Rajani P C   8 years AGO

ashok 10days work =10/80=1/8
remaining work 1-1/8=7/8
now 7/8 the part completed by bhuwnesh in 42 then
bhuwnesh alone completed in 48days now ashok and bhuwnesh work together= 1/80 +1/48=30

Like? Yes (2) | No   

JENSI KARUNYA.S   8 years AGO

Ashok can complete the work 80 days
he works for 10 days=1/8
bhuwanesh's work=7/8x=42
x=42*8/7
x=48
x/80+x/48=1
(3x+5x)/240=1
x=240/8=30
the correct answer is 5)30

Like? Yes (2) | No   

Sunny Grover   8 years AGO

1/8th work is done by ashok in 10 days.
now 7/8th work is left which is to be done in 42 days.so total work done by bhavesh =42*8/7=48 days.
so if both works together it will take 30 days

Like? Yes (2) | No   

ramakrishnateja   8 years AGO

given part of work done by ashok is 80.
now his 10 days work=1/8. rem work=1-1/8=7/8.
now 7/8th of work is done 42 days. now whole work he does in 42*8/7=48 days. so both does work in 1/80 +1/48 =30 days.

Like? Yes (2) | No   

vignesh   8 years AGO

A can do work 1/80 work in one day
then A will do 1/8 of the work in 10 days

the remining work is 7/8

let x be the days B can complete work

If he works for 42 days
then
42/x = 7/8

thus x = 30

If they both worked together
then
1/80 + 1/48 =1/30

so 30 is the answer

Like? Yes (2) | No   

Rajani Chaganti   8 years AGO

ashok alone can do a piece of work in 80 days.
bhuwnesh can do it alone in 48days
so..both together.. 1/80 +1/48=1/30th work in one day
so 30days

Like? Yes (2) | No   

aditya kataria   8 years AGO

ashok can do a piece of work in 80 so one day work is 1/80 and the he work for 10 days so he complete 10/80 piece of work i.e 1/8 now remaining piece of work is 7/8 which is finished by bhuwnesh in 42 days therefore its one day work is 7/(8*42)=1/48 hence bhuwnesh finish the same work in 48 days when they work together then (1/80+1/48)=(16/480)=1/30 so answere will be 30

Like? Yes (2) | No   

ADITYA   8 years AGO

A one day work=1/80
A 10 day work =1/8
remaining work =7/8
B one day work =1/48
A and B both one day work =1/80 + 1/48=1/30
so two together can finish the work in 30 days

Like? Yes (3) | No (1)  

sachin sawant   8 years AGO

Ashok can do work in 1 day =1/80
For10 days he works=10*1/80=1/8
Work left=1-1/8=7/8
Bhuwnesh finishes7/8 work in 42 days
=>for 1 day he works1*7/8÷42=1/48
Together they can finish work in 48*80÷(48+80)=30days

Like? Yes (2) | No   

Abhineet kumar   8 years AGO

Ashok 1 day work is 1/80
work done by Ashok in 10 days is 1/80*10=1/8
emaining work is 1-1/8=7/8
7/8 work done by Bhuvnesh in 42 days
his 1 days work is 42*8/7=48 days
work done by together is 1/80 +1/48=1/30
so work together done in 30 days

Like? Yes (1) | No (1)  

P J S Sailesh Kumar Reddy   8 years AGO

10/80=1/8.
1-1/8=7/8
8/7*42=48
1/48+1/80=8/240=1/30.
30days

Like? Yes (1) | No (1)  

Jaikumar Bhatia   8 years AGO

work done by ashok in 10 days=(1/80)*10=1/8
Remaining work=(1-1/8)=7/8
Now 7/8 work is done by Bhuvnesh in 42 days.
so whole work will be done by Bhuvnesh in 42*(8/7)=48 days
Ashok's 1 days work=1/80
Bhuvnesh's 1 days work=1/48
Then (Ashok+Bhuvnesh)'s 1 days work
=[(1/80)+(1/48)]
=8/240
1/30
so both will finish the work in 30 days
Ans is 30 days
option is (5)

Like? Yes (1) | No (1)  

Anindita Sarkar   8 years AGO

null

Like? Yes (2) | No (3)  

Rajitha Andela   8 years AGO

work done by Ashok in 10 days = (1/80 * 10) = 1/8

remaining work = (1-1/8) = 7/8

now, 7/8 work is done by Bhuvanesh in 42 days

whole work will be done by Bhuvanesh in (42* 8/7) = 48 days

therefore, Ajay's 1 day's work = 1/80, Bhuvanesh 1 day's work = 1/48

(Ajay+Bhuvanesh) 's 1 day work = (1/80 + 1/48) = 1/30.

Hence Ajay and Bhuvanesh will together complete the work in 30 days

Like? Yes (1) | No (2)