Rajesh and Mohan working separately can do a piece of work in 9 days and 12 days respectively. If they work for a day alternately, Rajesh beginning, in how many days, the work will be completed?
(Rajesh+Mohan)'s 2 day's work = 1/9 + 1/12 = 7/36
Work done in 5 pair of days = (5*7/36) = 35/36
Remaining work = (1 - 35/36) = 1/36
On 11th days it is Rajesh's Turn
1/9 : 1/36 :: 1 : x
x = 1/36 * 1 * 9
= 1/4 days
Therefore
Total time taken 10 1/4 = 41/4 days