Rs.5625 are divided among Mohan, Raju, Chandan so that Mohan may receive one-half as mush as Raju an

G.S.Kantharao   8 years AGO

Let Mohan,Raju and Chandan's shares are = M,R and C respectively.
Given M = ( R + C )/2
2M - R = C Equation 1
and R = ( M + C )/4
4R - M = C Equation 2
From 1 and 2
2M - R = 4R - M
3M = 5R
M : R = 5 : 3
From R = (M + C)/2 substituting M = 5R/3
R = ( 5R + 3C )/12 {After Simplification}
12R = 5R + 3C
7R = 3C
R : C = 3 : 7
M : R : C = 5 : 3 : 7
The difference of Mohan and Raju's Share is =
(5625* 2)/(5+3+7) = 750.
Hence the right choice is 3.

Like? Yes (2) | No (1)  

Prateek khanna   8 years AGO

M+R+C=5625..........(1)
according to question,
M=1/2(R+C) so
R+C=2M
put it in equation 1
3M=5625 ->M=1875
and R=1/4(M+C)
4R=M+C
put it in equation 1
5R=5625
R=1125
so share of mohan is more than raju by 1875-1125=Rs.750

Like? Yes (1) | No   

madhulikadoggala   8 years AGO

consider M,R,C be the shares of mohan,raju and chandhan respectively.
so
M+R+C=5625-----(1)
from the conditions given in question
we get the following equations
M=(R+C)/2-------(2)
R=(M+C)/4--------(3)
solving (1) and (2) we get
M=1875
Substituting 'M' value in equations (2)and (3) we get
R+C=3750-----(4)
4R-C=1875-----(5)
Solving (4) and (5) we get
R=1125
So Share of Mohan more than Raju=1875-1125=750

Like? Yes | No   

Mridula Shaw   8 years AGO

M=1/2(R+C)
R=1/4(M+C)
ATP,
M+R+C=5625
=>1/2(R+C)+R+C=5625
=>(R+C)=3750
Thus,
M=1/2*3750=Rs.1875
Now,
R=1/4(1875+3750-R)
=Rs.1125
Thus,Difference between Mohan's And Raju's Share=Rs.(1875-1125)=Rs.750

Like? Yes (1) | No (1)  

sujit sinha   8 years AGO

M+R+C=5625
and , R+C=2M
therefore, M=1875.
and R+C=3750
also,4R=M+C
so, R=1125

hence,M-R=750

Like? Yes | No   

saiprakash   8 years AGO

m=r+c/2
r=m+c/4
m+r+c=5625
m=1875
r=1125
m-r=750;

Like? Yes | No   

DWARAKA   8 years AGO

M+R+C=5625

M=1/2(R+C) ===> 2M=R+C ===>M=1875

R=1/4(M+C) ===>4R=M+C ===>R=1125

M-R=1875-1125

Like? Yes | No   

upasana bisht   8 years AGO

mohan share = 1/2 [raju + chandan]' share...... (1)

raju share = 1/4[mohan + chandan]' share........(2)

m+r+c = 5625
m= 5625 - r-c..... (3)
putting (1) in (3)
r + c = 3750... ( 4)
similarly
r = 5625 - m -c ... (5)
putting (2) in (5)
m + c = 4500 ...(6)

solving (5) and (6)
m - r = 750
m = 750 + r ans

Like? Yes | No   

AYAN PAUL   8 years AGO

From Equation 1 we get Mohan=.5(Raju+Chandan)
From Equation 2 we get Raju=.25(Mohan+Chandan)
from solving these two equations we get Raju = 3*Chandan/7 and Mohan= 5*Chandan/7
We know Mohan+Chandan+Raju=5625
so 5*Chandan/7+3*Chandan/7+Chandan=5625
We will get the amount of chandan and rest of two from these then.

Like? Yes | No   

dipanwita Bishnu   8 years AGO

M=1/2 (R+C)
R=1/4 (M+C)
M:R:C=5:3:7
M= 1875/-
R =1125/-
M-R =750/-

Like? Yes | No   

MOHAMMAD AAQIB   8 years AGO

2m=r+c eqn1; 4r=+m+c eqn2;
m+r+c=5625 eqn3;

put eqn1 & eqn2 in eqn3,we get
m=1875;
r=1125;
required ans= m-r=1875-1125=750;
option no.3

Like? Yes | No   

Naveen Kesharwani   8 years AGO

1) 1/2M=R+C
2) 1/4R=M+C
After solving these equation mohan=1875,raju=1125,
Chandan=2625
So difference between Raju and mohan share is 750.
So the answer is 750.

Like? Yes | No   

sindhuja   8 years AGO

m+r+c=5625
r=5625-m-c & r=(m+c)/2.eqaute these 2.
also m=(r+c)/2 solve tis with 1st eqn nd ull gt m.sub it in 2nd which will result in c nd find r using 1st eqn.thus ull gt the result

Like? Yes | No   

Siva   8 years AGO

M+R+C=5625,
M=[R+C]/2
2M =[5625-M]
M=1875.
R=[M+C]/4
4R=5625-R
R=1125.
M-R= 750.

Like? Yes | No   

Sangeetha Chinnasamy   8 years AGO

M+R+C=5625
M=1/2(R+C)
R=1/4(M+C)
Find R,M
R is 1125
M is 1875
1875-1125=750
ans is 750

Like? Yes | No   

Jyoti Ranjan   8 years AGO

as m+r+c=5625,2m=r+c,4r=m+c....
so m=1875 and r=1125,therefore m-r=750

Like? Yes | No   

DEVMALLYA BANDYOPADHYAY   8 years AGO

mohan recieves rs 1875 where as raju recieves 1125 so the difference is 750

Like? Yes | No   

jyoti   8 years AGO

let mohan.raju.chandan receive x,y,z money respectively.
then x+y+z=5625
x=y+z/2
y+z=5625-x

x=y+z/2
5625-x/2=x
after solving this we get x =1875

now
y+z= 3750

y=3750-z

3750-z= x+z/4;

x=1875; so put in ek

after solving we get z =2625

so y= 1125

we can check it by

2625+1125/2=1875 whichvis the value of x . similarly we check second condition.

mohan receive money more than raju= 1875-1125=750 ans

Like? Yes | No   

Abhash Kumar   8 years AGO

Answer:

A + B + C = 5625

4B + B = 5625
   B = 1125


Also A + C = 4B = 4 x 1125 =Rs 4500


Also
  B = 2A - C
 2A - C = 1125
Now solving A+C = 4500 and 2A-C = 1125


Then A = 1875 and C = 2625


Therefore., A-B = 1875 - 1125 = Rs. 750

Like? Yes | No   

R.Jayaraman   8 years AGO

let x ,y andz be the share's of mohan ,Raju and chandan respectively.
x=(y+z)/2








2x=y+z

y=(x+z)/2
2y=x+z and
x+y+z=5625
solving
x=1875
y=1125
x-y=750

Like? Yes | No   

bikash baral   8 years AGO

mohan;s share =5625/3=1875
as one part for mohan and rest 2 for raju & chandan

raju 's share = 5625/5=1125
one for raju and rest 4 for mohan and chandan

ans =1875-1125
=750

Like? Yes | No   

Pranjal Shrivastava   8 years AGO

let M R C be shares of mohan raju and chandan resp.
M = (R+C)/2 ; R=(M+C)/4; M+R+C = 5625;
solving these equation M= 1875 ; R= 1125; C= 2625;
M-R=750

Like? Yes | No   

pallabi   8 years AGO

Raju 2x chandan 2y
By first condition mohan will have x+y
Thn second condition gives 2x=1/4 (x+y+2y)
7x -3y=0
x+y+2x+2y=5625
By solving with a trick....add these...10x=5625
2x=1125
We need to find mohan - Raju by the question
So x+y-2x means y-x
Form 7x-3y=0
y=7x/3
Put it in y-x to get ans 4x/3 means 2*1125/3 =750

Like? Yes | No   

surajthite3995@gmail.com   8 years AGO

Let mohan=x,raju=y,chandan=z
Then,eq.1) x=1/2(y+z)
2x=y+z
eq.2) y=1/4(x+z)
4y=x+z
Solving 1 and 2
We get 3x=5y
Hence mohan = 1875
Raju= 1125
Hence mohan get 750 shares more than Raju.

Like? Yes | No   

yerra anitha   8 years AGO

given equations are:M=1/2(R+C) AND R=1/4(M+C)
When we solve the equations we wil get 2M=R+C;(1)
4R=M+C;(2)
M=4R-C;
PUT M IN 1 EQUATION THEN
2(4R-C)=R+C;
7R=3C;
R/C=3/7;
NOW PUT R&C VALUES IN 1 EQAUTION WE WILL GET 5=M;
SOO SHARES ARE OF Devied in 5:3:7 =m:r:c then valu MOHAN=1875;
RAJU=1125 DIFF IS 750

Like? Yes | No   

Shiv Pandey   8 years AGO

m=1/2(r+c)
2m=r+c

r=1/4(m+c)
4r=m+c
solving this, m=5/3r
ad put in equation, c=7/3r
r+m+c=5625
r+5/3r+7/3r=5625
r=1125 and m=1875
m-r=750

Like? Yes | No   

Ramneet kaur bhutani   8 years AGO

Mohan has (x+y)/2
Raju has x
Chandan has y
together they had 5625
and also Raju has((x+y)/2+y)/4
solving these equations we get the ans

Like? Yes | No   

Ashok   8 years AGO

M=1/2(R+S)
R = 1/4(M+S)
From Second line 4R= M+S (Substitute M value to get ratio of R & S as =3:7)

Then From the First Line 2M = R+S (Substitute S=7R/3 from the last equation)
Then we will get 5:3
So that M : R : C=5 : 3 :7

15 --->5625
1 ------>375
Diff of M & R = (5-3= 2) 2---->2*375=750


or
---------------------------
4R= M+S
2M=R+S
M+R+S=5625
4R+R = 5625 ==> 5R =5625 =====> R =1125

M+R+S=5625
2M+M =5625 ===> 3M =5625 =====> M=1875

So M-R = 1875-1125=750

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Rucha   8 years AGO

Rajus share is 1125 and chandan is 2625 so we get mohans share as 1875 I e 750 more than raju

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Shagun Chaudhary   8 years AGO

M=1/2(R+C)
R=1/4(M+C)
M+R+C=5625
=>M=1875
=>R=1125
M-R=750₹

Like? Yes | No   

Santosh   8 years AGO

Value of m comes out as 5R/3 and value of ac comes out as 7R/3
Putting it in m+c+r=5625
We get value of m as 1875 and value of r as 1125

Like? Yes | No   

Akshat Mokashi   8 years AGO

let mohan raju and chandan share be m,r and c
so m+r+c=5625 also m=1/2*(r+c)
r=1/4*(m+c) its clear that r+c=2m and m+c=4r
substituting these values we get 3m=5625 and 5r=5625
So share of mohan is more than that of raju by 750

Like? Yes | No   

Datla Lakshmi Bhavani   8 years AGO

mohan:chandan:raju=5:7:3
mohan=5/15*5625=1875
raju=3/15*5625=1125
so 1875-1125
=750

Like? Yes | No   

Aayushi Aggarwal   8 years AGO

Let mohan receives rs. X, raju receives rs. Y,chandan receives rs Z,
Then since all get rs 5625
then, X+Y+Z=5625,
Mohan receives half of raju and chandan
Then X=1/2(Y+Z)
NOW raju receives one fourth of mohan &chandan
Then Y=1/4(X+Z)
Now solving all three eq.
We get X=1875
Y=1125
Z=2625
THEN SHARE WHICHH MOHAN GET MORE BY RAJU IS Rs. (X-Y)
1875-1125=750 RS.

Like? Yes | No   

saurabh chatterjee   8 years AGO

m=(r+c)/2...1
r=(m+c)/4...2
we equate for c and find the ratio of m and r,then also find the value of c by putting the value in any of the equations above. m:r:c=5:3:7

Like? Yes | No   

gayathri   8 years AGO

M+R+C=5625
As per given conditions
M=0.5(R+c)
R=0.25(m+c)
So,by solving
M=1875
R=1125
Sol:1875-1125=750

Like? Yes | No   

Prakash Jha   8 years AGO

x+y+z=5625 .............(1)
x=(1/2)(y+z)............(2)= 2x-y-z=0;
y=(1/4)(x+z)...........(3)=x-4y+z=0;

adding 2 and 3;
3x-5y=0;.... (4)
subtracting 1 & 3;
5y=5625......(5)

therefore, by substituting value of 5 in 4,
3x=5625
x=1875
y=1125;
x-y=750rs

Like? Yes | No   

Rajeev Ranjan   8 years AGO

mohan=1/2(raju+chandan)
raju=1/4(mohan+chandan)
=>raju=3/7(chandan); 5/7(chandan)=mohan
5/7(chandan)+3/7(chandan)+chandan=5625
=> mohan-raju=1875-1125=750

Like? Yes | No   

sanjeet kumar   8 years AGO

From the question we have
Let mohan share be x.
Raju be y and chandan be z.
Then x+y+z = 5625
2x = y + z and 4y = x+z
On solving we get 750 as required answer

Like? Yes | No   

Gokul Krishnan   8 years AGO

a+b+c=5625
b+c=2a
a+c=4b
a-b=Rs.750

Like? Yes | No   

deepa subramanian   8 years AGO

m=(r+c)/2 => 2m=r+c
r=(m+c)/4 => 4r = m+c
r+m+c= 5625
m+2m=5625
m=1875

r+4r=5625
r=1125

m-r = 1875-1125 => 750

Like? Yes | No   

shailendra singh    8 years AGO

as given M=1/2(R+C) , R=1/4(M+C)
R=3/5M , C=7/5 M
M+R+C=5625
M+3/5M+7/5M = 5625
M=1875
HENCE R=1125
1875-1125 =750 = M-R

Like? Yes | No   

NISHA AGARWAL   8 years AGO

From the question,
Mohan:(Raju+Chandan)=1:2
So,Mohan's share is Rs(5625*(1/3))=Rs 1875
and also,
Raju:(Mohan+Chandan)=1:4
So,Raju's share is Rs (5625*(1/5))=Rs 1125
Therefore,
Mohan's share is more than that of Raju's by Rs(1875-1125)=Rs 750.

Like? Yes | No   

JAGARLAMUDI MAYURI   8 years AGO

let amount received by Mohan=m
let amount received by Raju=r
let amount received by Chandan=c
given m=(r+c)/2
=>(r+c)=2m --->equation 1
given r=(m+c)/4
=>(m+c)=4r --->equation 2
given m+c+r=5625--->equation 3
by substituting equation 1 in equation 3 we get
2m+m=5625
3m=5625
m=1875
by substituting equation 2 in equation 3 we get
4r+r=5625
5r=5625
r=1125
m-r=1875-1125=750
so share of mohan is more than that of raju by 750 rupees

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muthukumar   8 years AGO

5625=x+y+z=>z=2625
x=(y+z)/2=(((x+z)/4)+z)/2=(5/7)z=>1875
y=(x+z)/4=(((5/7)z)+z)/4=(3/7)z=>1125
z=z=>2625
x-y=750

Like? Yes | No   

madhavan nair   8 years AGO

total amount in 3 parts and then in 5 parts - difference of these two gives the difference of mohan and raju - which is 5625/3 - 5625/5 = 750

Like? Yes (1) | No (1)  

Rohit Ritesh   8 years AGO

A + B + C = 5625
B=1/4(A+C) = A+C =4B

4B + B = 5625

B = 1125

Also A + C = 4B = 4 x 1125 = 4500

A=1/2(B+C)=B+C= 2A

B = 2A - C

2A - C = 1125

Now solving A+C = 4500 and 2A-C = 1125

Then A = 1875 and C = 2625

A-B = 1875 - 1125 = Rs. 750

Like? Yes | No   

Mukund Manohar   8 years AGO

M+R+C = 5625
R = 1/4(M+C)
=> M+C = 4R
So,4R+R = 5625
R = 1125
M+C = 4R
=>M+C = 4*1125 = 4500
Now,M = 1/2(R+C)
=> R = 2M-C
=> 2M-C = 1125
On Solving,M+C = 4500 AND 2M-C = 1125
We get,M = 1875 and C = 2625
So,M-R = 1875 - 1125 = 750
The share of Mohan is more than that of Raju by Rs 750

Like? Yes | No (1)  

RAHUL KUMAR   8 years AGO

Let Mohan =A
Raju = B and
Chandan = C
A/C to question,
A = (B + C)/2
? B + C = 2 A
? A + B + C = 3A
Thus 3A = 5625
? A = Rs. 1875

Again B = ( A + C )/4
? A + C = 4B
? A + B + C = 5B
? 5B = 5625
? B = Rs. 1125

Thus A's share is more than that of B by Rs. (1875-1125) I.e. Rs. 750.

Option (3)

Like? Yes | No (1)  

ABHINAV PUSHPAM   8 years AGO

Let Mohan =A
Raju = B and
Chandan = C
A/C to question,
A = (B + C)/2
⇒ B + C = 2 A
⇒ A + B + C = 3A
Thus 3A = 5625
⇒ A = Rs. 1875

Again B = ( A + C )/4
⇒ A + C = 4B
⇒ A + B + C = 5B
∴ 5B = 5625
∴ B = Rs. 1125

Thus A's share is more than that of B by Rs. (1875-1125) I.e. Rs. 750.
Option (3)

Like? Yes | No (1)  

DEVANSH SUBNANI   8 years AGO

Let Mohan's share be A
Raju's share be B
Chandan's share be C
A=(B+C)/2
B+C=2A
A+B+C=5625
A+2A=5625
3A=5625
A=Rs1875

B=1/4(A+C)
4B=A+C
A+B+C=5625
B+4B=5625
5B=5625
B=Rs.1125

A-B=1875-1125=Rs.750
Therefore,Mohan's share is more than Raju by Rs.750
Option 3)

Like? Yes | No (1)  

UMANG RASTOGI   8 years AGO

m+r+c=5625.......(1
(r+c)/2=m.............(2
(((m+c)/4)+c/2)=m..............(3
on solving equations 2 and 3,
c=7/5 m
r=3/5 m
putting in equation 1,
m = 1875
from r = 3/5 m
r= 1125
m-r = 750 ans.

Like? Yes | No (1)  

MRITUNJAY   8 years AGO

Let Mohan =A
Raju = B and
Chandan = C
A/C to question,
A = (B + C)/2
? B + C = 2 A
? A + B + C = 3A
Thus 3A = 5625
? A = Rs. 1875

Again B = ( A + C )/4
? A + C = 4B
? A + B + C = 5B
? 5B = 5625
? B = Rs. 1125

Thus A's share is more than that of B by Rs. (1875-1125) I.e. Rs. 750.
Option (3)

Like? Yes | No (1)  

Jaikumar Bhatia   8 years AGO

Let's
Mohan=A
Raju=B
Chandan=C
Now,
A+B+C=5625

B=1/4(A+C)
A+C=4B
Therfore,
4B+B=5625
B=1125
Also,
A+C=4b=4*1125=4500
also A=1/2(B+C)=>B+C=2A
B=2A-C
2A-C=1125
Now Solving
A+C=4500 and 2A-C=1125
We get A=1875 and C=2625
Therefore,
A-B=1875-1125=750
Ans is Mohan(A) is more than Raju(B) by Rs 750
Option is (3)

Like? Yes | No (1)  

Dinesh kumar sah   8 years AGO

According to the question,
M+R+C=Rs.5625.........(1)
and M=(R+C)/2.........(2)
and R=(M+C)/2.........(3)
if we solve the above equations (1) and (2)
then we get M=Rs.1875 and if we further solve the above equations (2) and (3) and put the value of M then we will get R=Rs.1125.
so the share of Mohan is more than that of Raju by 1875-1125=Rs.750 Ans
hence option (3) is the right answer.

Like? Yes | No (1)  

Vipul kumar   8 years AGO

Let
mohan gets = M
chandan gets = C
Raju gets = R

given that,
M + C + R = 5625....(1)
2M = R + C............ (2)
and 4R=M + C ............ (3)

we hv to find ,
M-R=?

now from (1)+(2)
3M = 5625
M = 1875

from (2) - (3)
3M - 5R = 0
5625 - 5R = 0
5R = 5625
R = 1125

so M - R = 1875-1125
= 750

Like? Yes | No (1)  

PILLI MEGHASAI   8 years AGO

3m=5625;5r=5625;;then
M>R....and is 1875_1125=750.
mohan have more money than raju

Like? Yes | No (1)  

Rahul Das   8 years AGO

m+r+c=5625 & 2m=r+c & 4r=m+c
solve this 3 equation we get m=1875 & r=1125
so,m-r=750

Like? Yes | No (1)  

Vipul Mayank   8 years AGO

let x y and z for the three person

x+y+z=5625 .........eq1
y=1/4(x+z) => 4y=x+z .........eq2
therefore from eq 1
4y+y=5625
=> y=1125

Also x+z=4y from eq2
therefore x+z=4*1125=4500 .....................eq3

Also x=1/2(y+z) => y+z=2x
=> y=2x-z
but y=1125
therefore 2x-z=1125 .............................eq4

from eq3 and eq4
we get x=1875 and z=2625

so x-y=1875-1125= Rs750

Like? Yes | No (1)  

Prabhleen   8 years AGO

1/2(r+c)+ r+c =5625
=>r+c =3750. Eq1
1/4(m+c)+ m +c =5625
=>m+c= 4500. Eq2
Eq2-eq1
=>m-r = 750

Like? Yes | No (1)  

shaik jasmin   8 years AGO

let mohan be m,raju be r,chandhan be c
total amount is 5625
i.e m+r+c=5625----->eq 1
from question m=1/2(r+c)
2m=r+c------>eq 2
and r=1/4(m+c)
4r=m+c------------>eq 3
substitute eq 2 in eq 1
m+r+c=5625
m+2m=5625 (r+c=2m)
3m=5625
m=1875
now substitute eq 3 in eq 1
m+r+c=5625
4r+r=5625 (m+c=4r)
5r=5625
r=1125
now difference between mohan and raju is 1875-1125
=750

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Vishnu Prakash   8 years AGO

m+r+c=5625
m=(r+c)/2
r=(m+c)/4
On solving above equations, we get
m=1875
r=1125
c=2625
Answer=m-r=750

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SANDEEP KUMAR MAHATO   8 years AGO

let Mohan, Raju and Chandan be denoted by M,R and C respectively.

so atq we have 2 equations as

M=1/2(R+C) .............(1)

R=1/2(M+C) .............(2)

by comparing above 2 equations we will get

C=7R/3 and M=5R/3

now, M+R+C=5625

=> (5R/3) + R + (7/3)R = 5625

=> R = 1125

so, M = 5R/3 = 1875

So share of Mohan than by Raju is given by

M-C= 1875-1125 = 750

so option (3) is the answer

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Sandip Das   8 years AGO

let say chandan share is x rs and raju share is y rs
total rs 5625
so mohan share is 5625-(x+y) rs
also from question we get mohon share is (x+y)/2
hence 5625-x-y=(x+y)/2
=>x+y=3750
so mohon share is (5625-3750)
=1875
again from question we get raju share is
(((5625-(x+y))+x)/4
hence
y=(5625-x-y+x)/4
=>y=1125
so the share of more than that of raju by (1875-1125)
=750 (option 3)

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Jagdeep   8 years AGO

let x be Raju and chandan's share and y be Mohan and chandan's share.
According to the given condition x+x/2=5625
it gives x= 1875
and
y+y/4= 5625 which gives y= 1125.

so x/2(mohan's) is 750 more than y/4(raju's)

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puneet mahawar   8 years AGO

R+C=5625-M
M+C=5625-R
M=1/2(R+C)=1/2(5625-M)
M=1875
same as this R=1125
M-R=750

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Ajay Barathula   8 years AGO

Given M+R+C=5625-----(1)

condition's are R+C=2M-----(2) and M+C=4R-----(3)

by substituting (2) in (1) we get M=1875

similarly substituting (3) in (1) we get R=1125

by subtracting R from M we get remaining share of mohan from raju

M-R=1875-1125=750

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