A train 220 m long is running with a speed of 60 kmph. In what time will it pass a man who is runnin

Speed of the Train = 60Kmph
Speed of the Man = 6Kmph
Relative Speed =60 + 6 = 66Kmph (Opposite Direction)
Speed per Second = (66 * 5)/18
= 55/3
Time taken to cross each other = (Length of the Train)/Speed per Second = 220 / (55/3)
= (220*3)/55
= 4 * 3 = 12
Hence the right choice is 5.

we know the basic formula:- distance=speed*time.
now, here length of the train=220 m
speed of the train=60 kmph
speed of the man=6 kmph
since, the man is running in opposite direction to that of the train. so, speed gets added. thus, speed becomes 66 kmph.
we convert this speeed into m/s. since the options are in seconds. we know the convresion rule of converting kmph into m/s. so, 66 kmph=66*5/18 that results 55/3 m/s.
now, putting it into the formula d=s*t
we have, length of the train=220 m
and speed=55/3 m/s.
thus, after putting these values in formula and calculating..we get the time as 12 seconds which is the required answer.
and speed

relative speed of man w.r.t train = 6+60 = 66 kmph
time = distance/speed
hence time = 220/(66*(5/18))= 12 sec

relative speed of train and man is (60+6)=66 kmph
=(55/3) m/s
train length=distance=220 m
man pass the train at= 220/(55/3)
=12 sec (option 5)

66000 m is travelled in 60*60 sec
1 m " " " 3600/66000 s
220 M " " " 3600*220/66000 s = 12 sec

ans= 12 sec
relative speed=60+6km/h
=66*5/18
=55/3
time taken= 220*3/55
=12 sec

Since boh running in the opposite direction so using relativity speed will be added
i.e. speed=60+6 kmhr
=66×5/18 ms

total distance = 220
time =distance / speed
= 220/(66×5/18)
= (220×18)/(5×66)
= 12 sec

using relative speed concept
net speed = 60+6 = 66kmph = 55/3 m/s
hence time = distance/speed = 220/(55/3)=12 seconds

Distance =220m
Net speed = 60 + 6 = 66kmph i.e. 330/18mps
So time taken to cross = 220/330*18 =12s

SPEED IS IN OPPOSITE DIRECION SO 60KMPH+6KMPH=66KMPH ,IN MPS 18.33MPS. TIME=DISTANCE/SPEED.SO T=220/18.33=12S

D=S*T
they are moving in opposite direction so speed= 66 kmph
220= 66*1000/3600 *t
on solving T=12 sec

total relative velocity=(60+6)*5/18(m/s)
total distance =220m
time = dist/speed=12secs

relative speed=66km
=66×60×60secs
time=220×1/66×6×6
=12secs

relative speed=60+6=66kmph OR 66*5/18=55/3
t=d/s
t=220/55/3=12sec

speed of train in m/s=60*(5/18)=50/3m/s
speed of man in m/s=6*(5/18)=5/3m/s
net speed of train=50/3-(-5/3)=55/3m/s
so,time =d/s=220/(55/3)=12s

since train is moving in opposite direction
its speed is added 60+6kmph=in meter/sec it become
55/3
apply formula t=d/s=( 220/(55/3))

S1 = 60KM/H = 50/30M/SEC
S2 = 6KM/H = 5/3M/SEC
L1 = 220MTR
L2 = 0
T = ?
S2+S2 = L1+L2/T
50/3+5/3 = 220/T
55/3 = 220/T
=> T = 220*3/55
T = 660/55
T = 12SEC.

total speed= 60+6 km/hr (because, moving in opposite direction)
=66*5/18 m/sec =55/3 m/sec
time= distance/ total speed
=220*3/55
=12 sec

distance covered by train in passing the man=220m
relative speed=60+6=66kmph=110/6 mps
time taken=220/110*6=12sec

length to be covered=220m,
relative velocity=60+6 kmph=55/3mps
time=220/(55/3)+12 sec

use relative speed and give the speed of man to train in opposite direction. THan simply use speed * time = distance.
Convert the speed into m/s.

distance = 220kmph
relative speed =60+6=66kmph=110/6mps
time=distance/speed
=220/(110/6)
=12sec

relative speed =(60+6)kmph
66kmph=66*(5/18)m/sec=55/3 m/sec
velocity=displacement/time
time=displacement /relative velocity
i.e time=220/(55/3)sec
=12sec

Relative Speed between train and man= 60+6=66 kmph=(66*5)/18=55/3 m/sec
Time taken to pass the man= (220*3)/55= 12 sec.
So, the answer is Option 5) 12 sec.

distance = 220m
speed of the train = 60+6 kmph
66000m = 60*60 seconds
1m = 60*60/66000
220m = (60*60/66000)*220
=12

60kmph=50/3 mpsec
6kmph=5/3 mpsec
adding this two we get 55/3
220*3/55=12secs

speed=60+6
=66kmph
=66*5/18 mps
=55/3 mps

time=length/speed
=220/(55/3)
=12 sec

relative speed = 60+6 = 66kmph
=66*5/18 mps
time=distance /speed
= 220*18/(66*5)

=12 sec

speed of the train relative to man=(60+6)km/h=66km/h
66*5/18=(55/3)m/sec
time taken to pass the man=(220*3/55)=12sec

time= train length / train speed + man speed

time= 220 / (60+6 )*5/18 = 220*18 / 66*5 = 12 sec

speed of train relative to man=(60+6)km/hr=66km/hr
=[66*5/18]m/s=55/3 m/sec
Time taken to pass the man=220*3/55
=660/55 m/sec
=12

opposite direction=60+6=66kmph
66*5/18=18.33m/s
220/18.33=12 sec

Here train and men going opposite then its velocity 60+6 and then put it in time=distance/velocity

time = distance/speed
distance = 220 m
speed = (60+6)*5/18=18.333
time = 220/18.33
= 12 sec

Relative speed = 60+6 = 66km/hr

66km/hr*(5/18) m/s

=55/3 m/s

T=D/S
T=220/(55/3)
T=12 sec

d/s=t
opposite direction so +
convert km/hr into m/sec
t=220/(66*5/18)
t=12 sec

length of train/relative speed of both=220/66*(5/18)=12 sec
convert km to m multiply by 5/18(convert to same unit)

total distance to be covered is 220m
total speed is 66kmph we will convert this in ms and then divide total distance by total speed

Speed of the train relative to man is,
=(60+6)kmph = 66kmph
time in m/sec
= (66*5/18) m/sec
= 55/3 m/sec
Time when train cross the man is,
= 220/(55/3) = 220*3/55
= 12 sec
ans is 5) 12sec

Relative speed will be 60+6=66 (opposite direction)
distance 220 meter
convert relative speed to meter/second as distance given in meter
66 * (5/18) = 55/3
now time= distance/speed
220/(55/3) =12 sec.
so ans will be 12 sec.

the speed of train wrt man will be =speed of train +speed of man .
so time taken =length of train/speed.

The relative speed of train and man =60+6=66 kmph
In m/sec=66*(5/18)=55/3 m/sec
T=220/(55/3)=12sec

relative speed = 66kmph*5/18=55/3mps
time = 220/(55/3)=12

The speed of train and the man=66 kmph
In m/sec=55/3
T=220/(55/3)=12 s

Relative speed of the train when person is stop=66km/h
and it convert it in to m/s
55/3m/s
then time taken to cover this 12 sec

as the train i s passing with a speed of 60 kmph at a distance of 220 m so first time is calculated s=d*t

lenght of train=220m(l1)
speed of train=60kmph(s1)
speed of man=6kmph(s2)
so time taken to meet =l1/s1+s2
as they are moving in opposite direction add the speeds
if they are moving in same direction then substract

T=distance/speed
Relative speed=60+6=66kmph=66*5/18=55/3
T=220*3/55=12 sec

Speed of train relative to man=60+6=66km/hr
Speed in m/s= 66*(5/18)=55/3m/s
time taken=220*3/55=12sec Ans

Speed (train+man)= 60+6=66kmph
66*(5/18) =(55/3)m/sec
time=distance/speed
t=220/(55/3)
=12sec

Use relative speed.
S1+S2=L1/t (We add speed becoz of both are moving in oppostie direction).
convert speed in ms.

relative speed is 66kmph converting it into m/s we get 18.333 m/s substituing these in speed = distance /time we get 12sec as answer.

opposite direction so relative speed=60+6=66km/hr
=66*1000/3600m/secs
time=distance/speed
=12 secs

relative speed=66kmph(opposite direction)
speed=distance/time;
time=220/66*(5/18) 1kmph=5/18 m/s
time = 12sec

60+6=66kmph=66*5/18mps11*5/3mps
220/(11*5/3)m=12m

opposite direction 60+6=66. den by convertn to m/s ans= 55/3 m/s. den time taken= 220×(3/55)= 12 sec

d=220 m
since both run in opposite directions, so total speed gets added s=60+6=66 kmph
t=d/s
t=220/(66*5/18)
=12 sec

as man is moving in opposite direction so speed will be 60+6kmph=66kmph i e 66*5/18=110/6
we know that speed=dist/time
t=220*6/110
=12sec

relative speed=60+6=66
time=distance/time
=220m/66kmph
=12s

total speed =60+6kmph=66kmph=55/3ms
time=distance/speed
=(220*3)/55
=12sec

speed of the train relative to man=(60+6)=66km/hr
=(66*5/18)m/sec
=55/3 m/sec
time taken to pass the man=(220*3/55)sec
=12sec.

Speed of train relative to man=(60+6)kmph
=(66*5/18)mpsec= (55/3)mpsec
time taken by the train to cross the man= time taken by it to cover 220 m at(55/3)mpsec = ( 220*3/55) sec = 12 sec

relative speed=60+6=66kmph=110/6 m per sec
time=220*6/110=12

First convert the given speeds into m/sec by multiplying with 5/18
now we have speed of train =50mps
speed of man=5mps
time taken =220/(50/3+5/3)
=12 sec

travelling in oppositedirection so speeds get added and hange it into m/sec...then solve it by distance/speed

hence both the speed aree in opposite dir
relative speed =(60+6) km/hr
now time= distance/speed
=(220/(1000*66))*60*60 sec
=12 sec

relative speed of train w.r.t man =60+6 = 66kmph
speed in m/s = 66*5/18=55/3 m/s.

time = (220*3)/55 = 12seconds.

The speed of the train is 60*5/18=50/3 m/sec and that of the man is 6*5/18= 5/3 m/sec. In 12 seconds the train will traverse a distance of 50*12/3=200 m and the distance covered by the man will be 5*12/3=20 m, which adds up to 220 m , which is same as the length of the train. Therefore the answer is 12 seconds.

Distance=220m
as train and man moves in opposite direction
so,
relative speed=60kmph+6kmph=66kmph=66*5/18m/sec
Time=Distance/Speed
= 12sec

total distance= 220
total velocity= 60+6
velocity in m/s = 18.33m/s
so time taken to pass the man = 220/18.33= 12 sec

Relative speed = 60+6= 66 km/hr= 55/3 m/sec
Time taken to cover distance of 220mtrs = 220*3/55 = 12 secs

relative speed=(60+66)*5/18=(50/3)m/sec
Time=220/(55/3)=12sec
Option 5)

Time taken to pass the man = 220/{(60+6)*(5/18)}
= (220*18)/(66*5)
= 12 seconds

Relative speed=60+6 =66 kmph= 66*5/18= 55/3 m/s
Time taken to pass a man=220/(55/3)=12 sec.

Speed of train relative to man=(60+6)km/hr=66km/hr
={66x5/18}m/sec
=(55/3)m/sec
Therefore Time taken to pass the man={220*3/55}sec
=12 sec
Ans is 12 sec
Option is (5)

trains speed =60*(5/18)=50/3 m/s
man speed =6*(5/18)=5/3 m/s
relative speed=(50/3)+(5/3)=55/3 m/s
so time=(220*3)/55=12 sec.

Relative speed = 60+66 = 66 kmph or 330/18 m/s
Time taken to pass the man:
Length of the train/relative speed
220*(18/330) = 12 sec.

Option 5)