yerra anitha   8 years AGO

dif of given years is (5-3.5)=1.5
ie.., for 1.5interst is 288
that menas let x as sum
x*1.5*15/100=1280
soo, sum=1280

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shivangi rastogi   8 years AGO

i1=(p*15*7)/(100*2)
i2=(p*15*5)/100
i2-i1=288
hence p= 1280

Like? Yes (1) | No   

madanpal vishwakarma    8 years AGO

let assume each sum is m

so according to question

diff of interest = (interest for 5 year) - (interest for 7/2 year)
288 = ((m*15*5)/100)- ((m*15*3.5)/100)
after calculation m=1280
so option 8 is correct

Like? Yes (1) | No   

G.S.Kantharao   8 years AGO

Here the rate of Intrest is same.
Hence the difference of intrest for 1 1/2 years = Rs.288
Let the priciple = X
(X * 15 * 1.5)/(100) =288
X = (288 *100)/(22.5)
= Rs.1280
Hence the right choice is 8.

Like? Yes (1) | No   

DEVANSH SUBNANI   8 years AGO

Let each amount be Rs.100
SI1=(100*15*(7/2))/100=Rs.52.5
SI2=(100*15*5)/100=Rs.75
Difference=22.5
If diff is 22.5,each amount=Rs.100
If diff is 288,each amount=(100/22.5)*288=Rs.1280
Option 8)

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sruthi pujari   8 years AGO

amount 288 is the interest for 1.5 years(5-(7/2)) at 15% per annum.so 288=(x*1.5*15)/100.
on solving x=1280

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uttam kumar   8 years AGO

let p be x
si 1=0.525x
si 2=0.75x
si 2 - si 1=288
x=1280

Like? Yes | No   

Nikita Punia   8 years AGO

let x be the amount
then by SI formula, SI=PRT/100
288=15x(7/200-5/100)
x=1280

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Mukund Manohar   8 years AGO

Let each sum be Rs P
(P*15*5)/100 - (P*15*7)/(100*2) = 288
P = (288*40)/9 = 1280
Each Sum is Rs 1280

Like? Yes | No   

VISHAL.MORI   8 years AGO

28800=p*15*5-p*15*3.5
so,
28800=22.5p
p=1280

Like? Yes | No   

Ravali Dasari   8 years AGO

I=ptr/100
let p1=p2=x then interest 1=x*(7/2)*15/100 and interest 2 = x*5*15/100
Given difference between their interests is 288
=> 3x/4 - 21x/40 =288
9x= 11520
X= 1280

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PRUDHVI RAJ   8 years AGO

difference between years is 5 - 3.5 = 1.5 years
so interest for these 1.5 years is 288.
SI = (PTR)/100
P = (SI*100)/(T*R)
SI = 288, T=1.5, R=15
P = (388*100)/(1.5*15)
p = 1280

Like? Yes | No   

Manish   8 years AGO

x-y=288
[{P*(7/2)*15}/100]/{(p*15*5)/100}]=X/y
10*x=7*y
put the value into eqn.
x=672
y=960
put the any value in above 1st eqn and get the value of p
p=1280 Rs.

Like? Yes | No   

Rishabh Bhardwaj   8 years AGO

Diff of SI = S2-S1 = ((p*5*15)/100) - ((p*(7/2)*15)/100) = 280
:: Solve for P, P=1280

Like? Yes | No   

kondapuram tirumalreddy   8 years AGO

let sum =x
according to given question sum willl be calculated as follows
[(x*5*15)/100]-[(x*7*15)/(2*100)] = 288
then we will get x=1280

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Maholleshwari Nekkanti   8 years AGO

I2-I1=288
(p*5*15/100)-(p*7*15/200)=288
p=1280

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sanjeet kumar   8 years AGO

Let intrest be I1 and I2 and principle be x.
Then I1 = x*15*7/100*2
and I2 = x*15*5/100
And I2-I1= 288 (given)
Therfore from three equation, we get x = 1280

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NISHANT KUMAR   8 years AGO

let sum be x
SI2-SI1=288
(x*5*15/100) - (x*7*15/200) =288
x =1280

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Satyendra Singh   8 years AGO

si1 - si2 = 288

p1*r1*t1 - p2*r2*t2 = 288 * 100

since p1 = p2 = p
and r1 = r2 = 15

p*15*(5-3.5) = 288 * 100

p = 288 * 100 / 15 * 1.5 = 1280

Like? Yes | No   

aakash singhal   8 years AGO

let's total amount is=x
x×7/2×15÷100-x×5×15÷100=288
so x=1280

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anamika singh   8 years AGO

Si=p×r×t/100
Difference between si =288
(P×15×5)/100-(p×15×7/2)/100 =288

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Devendra Marghade   8 years AGO

For Sum=P and Rate=R, for period N1, N2
Difference in interest=(PR/100)(N2-N1)
Here R=15, N2=5, N1=3.5
So,(P*15/100)(5-3.5)= 288
P= 288*100/(15*1.5)=1280

Option 8)

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Somasekhar   8 years AGO

let the equal sum be x,and i=ptr/100;given i1-i2=288
hence x*15*5/100-x*15*3.5/100=1280

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VIKAS NAIN   8 years AGO

As per given data,
rate = 15%
difference in interest = 288
difference in time = 5-7/2 = 5-3.5=1.5
sum = difference in interest*100
___________________________= 288*100/1.5*15 = 1280
difference in time*rate

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suburbs basireddy   8 years AGO

1.5 yrs-->288
5yrs-->960
then sum=1280 from I=PTR/100

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Priyanka devi E   8 years AGO

difference between interest for 7/2years and 5 years is RS.288.
that is interest for 1.5 years is Rs.288.
so interest for 1 year will be Rs.192.
15% of X = 192. (15/100)xX=192;
X=(192x100)/15;
X=1280; the amount is Rs1,280.

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Lakshmi Narayanan.k   8 years AGO

Let the amount be X.
(15*X*7)/200=(15*X*5)/100.
X=1280.(option 8)

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tejaswi A   8 years AGO

let x be the amount then as per the given conditions,
x*(15/100)*(5-7/2)=288
hence x=1280

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AVINASH KUMAR SINGH   8 years AGO

let the sum be x then
((x*15*5)/100)-((x*15*3.5)/100)=288
x=1280

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vijay   8 years AGO

the difference between two interests is 288 we found interests individually by taking initial amount is x and subtracted from one another and equated to 288 hence we got x value

Like? Yes | No   

Siva   8 years AGO

X*(15/100)((5-(7/2))=288
X*(15/100)(3/2) = 288
=> X= 1280.

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AMAR KUMAR REDDY   8 years AGO

so principle is same in both cases
let us assume as "p"
now difference between is given as 288
(p*15/100)*((7/2)-5)=288
after calculating
p=1280

Like? Yes | No   

Gaurav negi   8 years AGO

SI=PRT/100
SI1-SI2=(PR1T1/100 ) - PR2T2/100
on solving
288=((3/4) -(21/40))P
P=1280
Thi problem is MEDIUM

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Poulami Dey   8 years AGO

Difference of the duration is (5-3.5}=1.5
Therefore d amt is 1280×15%×1.5=288

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hari vishnu   8 years AGO

si1=p*15*7/(100*2)=21p/40
si2=p*15*5/(100)=3p/4
si2-si1=288
solving the above equations
we get 9p=11520
p=1280

Like? Yes | No   

KAVITHA N   8 years AGO

Sum = Difference in Interest*100/Rate of Interest*Difference B/w 2 years.

Sum = 288*100/15*1.5 = 1280

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Sandip Das   8 years AGO

let the deposited amount is p
hence,
((p*15*5)/100)-((p*15*(7/2))/100)=288
((p*15)/100)*(3/2)=288
p=(288*2*100)/(15*3)
=1280 (option 8)

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Dashrath Yadav   8 years AGO

[(5-3.5)*15*x]=288*100
after solved....
we got x=1280 ans

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Dinesh kumar sah   8 years AGO

Simply, given that difference of SI For 5 and 7/2 years is 288.
so 15p[5-7/2]/100=288
or, p=1280 Ans
Hence option (8) is the right answer.

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Mridula Shaw   8 years AGO

Principal=P(Let)
Thus,
ATP,
(P*15*5/100)-(P*15*7/(100*2)=288
=>P=Rs.1280

Like? Yes | No   

sachin soni   8 years AGO

Formula for S.I. = P*R*T/100
let each sum of money be x
then (x*15*(5-7/2))/100 = 288
hence x= 1280
hence option 8 is correct

Like? Yes | No   

brijesh tripathi   8 years AGO

let x be the amount which is deposited in two different banks
then by formula of si=(p*r*t)/100
[(x*15*5)/100]-[(x*15*7/2)/100]=288 here 288 is the difference of interest
by solving above statement we found x=1280
which is my answer

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sharumathydeivasigamani   8 years AGO

since the simple interest formula is given by the relation

SI=P*N*R/100.

(P*(7/2)*15/100)~(p*5*15)/100)=288

P*(105/200)-P*(75/100)=288

P*(45/200)=288

so P=288*200/45

hence P=Rs.1280

Like? Yes | No   

devayani   8 years AGO

I1-I2 =288
(x*5*15)/100 - (x*7/2*15)/100 =288
(x*15)/100[5-7/2] =288
(x*15)/100[3/2] =288
Solving x=1280

Like? Yes | No   

gulshan   8 years AGO

288=p(1+15*5/100)-p(1+7/2*15/100)
288=p[(1+3/4)-(1+21/40)]
288=p[(7/4)-(61/40)]
288=p[(70-61)/40]
288=p*9/40
p=1280

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KANISHKA SINHA   8 years AGO

(Intrest for 5 years)-(intrest for 3 years + intrest for half a year)= 288

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himabindu   8 years AGO

Given that R =15% T = 7/2 and 5 years
Let us take P is x because the amount in two banks is same
The difference between interests is 288 i.e

288 = x*5*15/100 - x*3.5*15/100
288 = 9x/40
x = 11520/9
x=1280

Like? Yes | No   

Garrepally Gopikrishna   8 years AGO

apply si=ptr/100
therefore,x*5*15/100-x*3.5*15/100
then x=1280

Like? Yes (1) | No (1)  

Samjukta Das   8 years AGO

Let each sum be Rs P. Then,
P*15*5/100-P*15*7/100*2=288
3P/4-21P/40=288
=Rs 1280

Like? Yes | No   

snehita dey   8 years AGO

difference between both the sums is 288. let one amount is x+(x*15*7/100*2) and the other is x+(x*15*5/100). so by 61x/40-7x/4=288 we get 1280

Like? Yes | No   

kanik   8 years AGO

if amount 100
interest after 3.5 year at 15% is 52.5
interest after 5 year at 15% is 75
difference is 22.5
if differ is 22.5 amount 100
if differ is 288 amount 100*288/22.5= 1280

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Rahini B   8 years AGO

pnnr/100 - pnr/100 = 288
(p×7/2×15)/100 - (p×5×15)/100=288
105p/200 - 75p/100 = 288
p=57600/45
p=1280

Like? Yes | No   

Aakash Beniwal   8 years AGO

let sum is 'x'
then solve
(x * 15)/100[ 5 - 7/2) = 288
find 'x' which is 1280

Like? Yes | No (1)