Raghav scored below runs in his last 7 innings 13 ; 38 ; 3 ; 29 ; 14 ; 68 ; 17 Find population sta

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07 Jun 2017 Standard Deviation

Raghav scored below runs in his last 7 innings
13 ; 38 ; 3 ; 29 ; 14 ; 68 ; 17
Find population standard deviation for his score in last 7 innings?

OPtion

1) 21.76
2) 24.39
3) 24.89
4) 25.14
5) 25.39
6) 20.14
7) 24.81
8) 23.51
9) 25.81
10)None of these

Solution

Mean of 7 score = (13+38+3+29+14+68+17)/7 = 182/7 = 26
Sum of squared difference from mean for each number = (26-13)^2 + (26-38)^2 + (26-3)^2 + (26-29)^2 + (26-14)^2 + (26-68)^2 + (26-17)^2
= 2840

Average of Squared difference (Variance) = 2840/7 = 405.71
Standard Deviation = Square root of variance = 405.71^1/2 = 20.14

Correct Option: 6 Best Solution (10)

vishal   7 years AGO

mean is 13+38+3+29+14+68+17=182/7=26
calculate the deviations of each data point from the mean, and square the result of each: we get 169+144+529+9+144+1764+81=2840
now the variance is 2840/7=405.71
now SD is sq. root of 405.71 i.e 20.14 which is the option (6).

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ganesh chemanchula   7 years AGO

Average=(13+38+3+29+14+68+17)/7=26
deviation at each point=(13-26)^2=169
(38-26)^2=144
(3-26)^2=529
(29-23)^2=9
(14-26)^2=144
(68-26)^2=1764
(17-26)^2=81
Mean will be (169+144+529+9+144+1764+81)/7=2840
Population Variance= square root of 2840=20.14
So option 6.

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tumati koushik   7 years AGO

average=182/7=26
standard deviation =2840/7=405.714
population standard deviation=sqrt 405.714=20.14

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palak Jain   7 years AGO

mean value=13+38+3+29+14+68+17/7
mean value=26
variance=13^2+12^2+23^2+3^2+12^2+42^2+9^2/7
variance=405.714
standard deviation=under root of variance=20.14

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sameena   7 years AGO

mean(u)=(13+38+3+29+14+68+17)/7=26
variance=405.7
standard deviation=square of(variance)=20.14

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Gokul Krishnan   7 years AGO

s=sqrt(((sum x^2)/N)-(M)^2))
M=mean of 7 innings=26
M^2=676
x^2=sum of individual innings squared=7572
N=7
s=20.14

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Latha   7 years AGO

Standard Deviation σ =√(1/n)Σ(x-µ)²
n=7
µ = mean of all values =(13+38+3+29+14+68+17)/7 =182/7= 26
x = each value of 7 innings
Σ(x-µ)²=(13-26)²+(38-26)²+(3-26)²+(29-26)²+(14-26)²+(68-26)²+(17-26)²
= 169+144+529+9+144+1764+81
=2840
σ=√(1/n)Σ(x-µ)²= √(1/7)2840 =√405.714 = 20.14

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BHAVANA   7 years AGO

mean=(13+38+3+29+14+68+17)/7=26
variance=((13-26)^2+12^2+23^2+3^2+12^2+42^2+9^2)/7=405.7143
standard deviation=squre root (405.7143)=20.14

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Vishnu Prakash   7 years AGO

Population Standard Deviation =
((sum((item-mean)^2))/number of items)^1/2

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Mukund Manohar   7 years AGO

Population Standard Deviation = [Sq.Root of {Sum of (individual value - average value)^2}/Total Number of values]
Here, Average value = (13+38+3+29+14+68+17)/7 = 26
Now, Sum of (individual value - average value)^2
= (13-26)^2 + (38-26)^2 + (3-26)^2 + (29-26)^2 + (14-26)^2 + (68-26)^2 + (17-26)^2
= 169 + 144 + 529 + 9 + 144 + 1764 + 81
= 2840
Population Standard Deviation for Raghav's score in last 7 innings = Sq.Rt.(2840/7)
= 20.14

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