M4maths Previous Puzzles

24 Jul 2018 Age

A is 11 years older than B who is three times as old as C. The total of the ages of A, B and C is 123 years. What is the value when the age of B is added to the difference between ages of A and C ?

OPtion

1) 64 years
2) 77 years
3) 82 years
4) 85 years
5) 43 years
6) 90 years
7) 91 years
8) 84 years
9) 101 years
10)None of these

Solution

Let’s assume Age of B be B years
Age of A = B+11
Age of C = B/3

Total age = B + 11 + B + B/3 = 123
Solving 7B/3 = 112
B = 48
A = B+11 = 59
C = 48/3 = 16


Difference between ages of A and C = (59-16) = 43

Final Value = Age of B + Diff of Age of A and C = 48 + 43 = 91

Option 7)

Correct Option: 7 Best Solution (9)

G.S.Kantharao   6 years AGO

Let A,B,C=3x+11,3x,x
=7x+11=123=> x =16
A,B,C=59,48,16
(A-C)+B=(59-16)+48=91
My option is 7👈

Like? Yes (4) | No (1)  

Dr.Dipin Singh   6 years AGO

Ages are 3c+11, 3c and c.
C=16
Difference of ages of A and C =2c+11
Required value=5c+11=91

Like? Yes (3) | No (1)  

Rutika   6 years AGO

suppose, age of C= x, B=3x, C=3x+11,
as per given total =123,
x+3x+3x+11=123;
x=16

Age of B= 48, C= 16, A= 59

Ans= 48+(59-16)= 91 . option 7

Like? Yes | No   

Gourav Chakraborty   6 years AGO

Let C's age be X years
Then,B's age=3X years
and A's age=(3X+11) years
Then,sum of all ages=123 years
+>X+3X+(3X+11)=123
+>7X=112
+>X=16
Then C's age=16 years
B's age=(3x16) years
=48 years
A's age=(48+11) years
=59 years
Difference of A's age and C's age=(59-16) years
=43 years
When B's age is added to difference,
the value =(43+48)years
=91 years

Like? Yes | No   

kanimozhi kalimuthu   6 years AGO

let the age of C is X
Then age of B=3X , A=3X+11
SUM of ages (X+3X+3X+11)=123
X=16
(A-C)=59-16=43
(A-C)+B=43+48=91 YEARS

Like? Yes | No   

Devendra Marghade   6 years AGO

Let age of C be x, then ages A & B are (3x+11) and 3x respectively.
Sum of the ages of A, B & C = (3x+11)+3x+x = 123
=> x=16
So ages of A=59, B=48 & C=16 years.
Required value=B+(A-C)=48+(59-16)=91
Option 7)

Like? Yes | No (1)  

Varun   6 years AGO

Let the age of C be c
Then, B=3C, A=3C+11
Total of ages = 3c+11+3c+c = 123
=> c = 16
=> B = 48, A= 59
Asked = A-C+B = 59-16+48
= 91 = Option (7)

Like? Yes | No (1)  

ruby   6 years AGO

A+B+C=123
C=X; B= 3X; A = 3X+11;
3X+11+3X+X=123
Solving, X=16
Ages
A=59; B=48; C=16;
Required value = B+A-C = 48+59-16 = 91
Hence option 7

Like? Yes | No (1)  

SAYAN CHATTERJEE   6 years AGO

3c+11+3c+c= 123.
So, C= 16, B= 3*16= 48, A= 48+11= 59.
So,B+(A-C)= 48+(59-16)= 91 yes.
Option 7.

Like? Yes | No (1)