Advika's age is 1/6th of her father's age. Advika's father's age will be twice Rahul's age after 10

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31 Jul 2019 Age

Advika's age is 1/6th of her father's age. Advika's father's age will be twice Rahul's age after 10 years. If Rahul's eleventh birthdays was celebrated two years before, then what is Advika's present age.

OPtion

1) 8 years
2) 12 years
3) 11 years
4) 5 years
5) 6 years
6) 9 years
7) 10 years
8) 4 years
9) 7 years
10) None of these

Solution

Let Advika's present age = x

Then, her father's age = 6x


Given that Advika's father's age will be twice Rahul's age after 10 years.


Therefore, Rahul's age after 10 years = (1/2) * (6x + 10) = 3x + 5


Also given that Rahul's eleventh birthday was celebrated two years before. So Rahu;s present age = 11+2
Therefore, Rahul's age after 10 years = 11 + 2 + 10 = 23

3x+5 = 23
=> x = 6

Therefore, Advika's present age = 6 years

Correct Option: 5 Best Solution (2)

SAYAN CHATTERJEE   5 years AGO

A= F/6, (F+10)= (R+10),
R= 11+2= 13,
So, F= 36,
So, Advika's age is 36/6= 6.
Option 5.

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Devendra Marghade   5 years AGO

Let present ages of Advika=A, Father=F, Rahul=R, then
A=F/6 ---(i) and
(F+10)=2(R+10) ---(ii)
Given, Rahul was of 11 years, 2 years before so Rahul's present age=13 years.
Substituting R=13 in (ii), we get F=36
From (i), A=36/6=6
Hence, present age of Advika is 6 years.
Option 5)

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