Jinping decides to randomly tweet a 3 letter word from English alphabets (without repetition of any alphabet). What is the probability that he will tweet LIE?

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29 Apr 2020 Probability Jinping decides to randomly tweet a 3 letter word from English alphabets (without repetition of any alphabet). What is the probability that he will tweet LIE?: OPtion
1) 1/17576
2) 1/17076
3) 1/17596
4) 1/17516
5) 1/12600
6) 1/13600
7) 1/14600
8) 1/15680
9) 1/15600
10) None of these; Correct Option: 9 Best Solution (4)

Dr.Dipin Singh 5 years AGO

Total possible 3 lettered words without repetition = 26x25x24= 15600

Like? Yes (1) | No

Devendra Marghade 5 years AGO

Required probability=(1/26)*(1/25)*(1/24)=1/15600
Option 9)

Like? Yes | No

RAMADURAI NATESAN 5 years AGO

ans. = 1/26 * 1/25 * 1/24 = 1/15600

Like? Yes | No

Varun 5 years AGO

There are three letters
Choices for first letter = 26
Without repetition
For second letter = 25
For 3rd letter = 24
So possible choices = 26*25*24 = 15600
And probability is needed for just one word = 1/15600
= Option (9)

Like? Yes | No (1)

Dimple

India

Punjab

Time: 00:01:33

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Jinping decides to randomly tweet a 3 letter word from English alphabets (without repetition of any

M4maths Previous Puzzles

29 Apr 2020 Probability