product of the positional number of all the letters of the word TWINKLE will be {for example posi

IQBAL MEHDI   11 years AGO

As positional number of A=1
similarly,
T=20,W=23,I=9,N=14,K=11,L=12,E=5.
Hence,
product of the positional number of all the letters of the word TWINKLE=20*23*9*14*11*12*5=38253600 ans.

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S.NANDHINI   11 years AGO

T=20,W=23,I=9,N=14,K=11,L=12,E=5
so=>20*23*9*14*11*12*5=38253600

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PARAG KAMRA   11 years AGO

t-20
w-23
i-9
n-14
k-11
l-12
e-5
20*23*9*14*11*12*5=38253600

Like? Yes (2) | No (1)  

Jagat   11 years AGO

20*23*9*14*11*12*5 = 180*23*154*60 = 38253600

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prashanthi   11 years AGO

20*23*9*14*11*12*5

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Shiv Kumar   11 years AGO

TWINKLE
20*23*9*14*11*12*5=38253600

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Ajay Kashyap   11 years AGO

TWINKLE = 20*23*9*14*11*12*5 = 38253600

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Balakrishnan M   11 years AGO

TWINKLE
T-20,W-23,I-9,N-14,K-11,L-12,E-5.
so,20*23*9*14*11*12*5=38253600

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satyaprakash vengala   11 years AGO

20*23*9*14*11*12*5=38253600

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Devendra Marghade   11 years AGO

Positional Number are T(20),W(23),I(9),N(14),K(11),L(12),E(5)
The product 20*23*9*14*11*12*5=38253600

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Gulshan Kumar   11 years AGO

Positional numbers for the following: TWINKLE as
t 20
w 23
i 9
n 14
k 11
l 12
e 5
= 38253600
Option 3 is correct

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Vivek Tiwari   11 years AGO

The positional values of T,W,I,N,K,L,E are 20,23,9,14,11,12,5 and just multiply u will get the answer

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Muhammad Ahmed   11 years AGO

T = 20
W = 23
I = 9
N = 14
K = 11
L = 12
E = 5

The product of all is:
20 x 23 x 9 x 14 x 11 x 12 x 5 = 38253600

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phani   11 years AGO

20*23*9*14*11*12*5=38253600

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R.K   11 years AGO

positional number ARE
T=20, W=23, I=9, N=14, K=11, L=12 AND E=5
Product of these number will be
20*23*9*14*11*12*5=38253600

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ranganna   11 years AGO

T=20,W=23,I=9,N=14 ,K=11,L=12, E=5
TWINKLE=20*23*9*14*11*12*5
=38253600

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ajitha   11 years AGO

The posoitions of letters in ALPHA oreder
T=20
W=23
I=9
N=14
K=11
L=12
E=5

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Showvhick Nath   11 years AGO

T - 20
W - 23
I - 9
N - 14
K - 11
L - 12
E - 5

Then Product is - 20*23*9*14*11*12*5 = 38253600

Like? Yes (1) | No   

J.P.Raja Suresh   11 years AGO

=> positional number of A=1 , B=2....Z=26,
=> TWINKLE =20*23*9*14*11*12*5=38253600
=> Ans :38253600 (Option : 3)

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kishan vaghasiya   11 years AGO

t=20,w=23,i=9,n=14,k=11,l=12,e=5. i.e.20*23*9*14*11*12*5=38253600

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Sujata Bamuriya   11 years AGO

in twinkle position value of...
t-20 w-23 i-9 n-14 k-11 l-12 e-5
product of these values
20*23*9*14*11*12*5=38253600

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KOLLI APPALA NAIDU   11 years AGO

T*W*I*N*K*L*E
20*23*9*14*11*12*5=38253600

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shashidhar   11 years AGO

just multiply the positions using a calculator. as simple as that !

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Jayashree   11 years AGO

t-20,w=23,i=9,n=14,k=11,l=12,e=5. product=38253600

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Reema khan   11 years AGO

20*23*19*14*11*12*5=38253600

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jyotish r   11 years AGO

5*9*11*12*14*20*23=38253600

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sagar arora   11 years AGO

the positional values of various letters come out to be 5,11,12,9,14,20,23
and their product is 38253600

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siddhant das   11 years AGO

twinkle=20*23*9*14*11*12*5

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GIRISH TYAGI   11 years AGO

T*W*I*N*K*L*E=20*23*9*14*11*12*5=38253600

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vamsi krishna   11 years AGO

20*23*9*14*11*12*5=38253600

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roshan kumar   11 years AGO

twinkle=20*23*9*14*11**12*5=38253600 that is option 3

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Vignesh   11 years AGO

20*23*9*14*12*13*5= 38253600

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DANISH EQUBAL   11 years AGO

As positional number of A=1
Hence,
product of the positional number of all the letters of the word TWINKLE=20*23*9*14*11*12*5=38253600 ans.

Like? Yes (1) | No (1)  

Jamil Ahmed   11 years AGO

T=20, W=23, I=9, N=14, K=11, L=12, E=5
So, T*W*I*N*K*L*E=20*23*9*14*11*12*5
=38253600

Like? Yes (1) | No (1)