A man standing 5 metre away from the bottom of the pole in a gravity free space throws a stone to th

M4maths Previous Puzzles

22 Feb 2013 height

A man standing 5 metre away from the bottom of the pole in a gravity free space throws a stone to the pole and it touches 1/3 height of the pole and makes angle of elevation 45 degree. height of the pole is..

OPtion

1) 10m
2) 15m
3) 22m
4) 25m
5) 30m
6) 34m
7) 40m
8) 45m
9) 50m
10) None of these

Solution

tan45=(1/3)h/5 (In gravity free space)
h = 15...

Correct Option: 2 Best Solution (9)

Abhijeet Kumar   11 years AGO

tan 45 = height/bredth
=> 1 = height/5
=> height = 5
and this height is 1/3 of the pole
so height of the pole = 5*3= 15m

Like? Yes (8) | No (5)  

Anurag Arora   11 years AGO

tan 45 = per/base
p = 1/3x m
base = 5m
(1/3x)/5 = 1
hence, x = 15m

Like? Yes (4) | No (4)  

Vinay Sipani    11 years AGO

15 m

tan(45) = 1
=> 1/3 height of pole = Distance b/w man and pole foot.

=> h/3 = 5 => h = 15 m

Like? Yes (2) | No (3)  

kalaiarasan   11 years AGO

tan 45 deg=opp/adj=>x/3=5=>x=15.

Like? Yes (2) | No (3)  

MANOJ TIWARI   11 years AGO

tan 45=(h/3)/5
so h=15

Like? Yes (1) | No (3)  

Preetha Maniyalath   11 years AGO

A man is standing at a distance of 5m (adjacent side)
stone reaches 1/3rd the height of the pole=x m (opposite side)
it makes an angle of 45 degrees
so Tan 45= opposite side/Adjacent Side
1=x/5m
x=5m
x is 1/3rd the height
the total height= 3x=3*5=15m
option 2

Like? Yes (1) | No (3)  

SH   11 years AGO

tan45=(h/3)/5.
=>h=15.

Like? Yes (1) | No (3)  

Devendra Marghade   11 years AGO

If the pole height=p
then tan 45=(P/3)/5 =1
p=15

Like? Yes (1) | No (3)  

Rats   11 years AGO

Let height of pole=h
h=3*tan 45*5
h=15

Like? Yes (1) | No (3)