Find the next number of the following sequence log4(base2),log8(base2),log16(base2),.........

Abhilash Mishra   11 years AGO

log32(base2) = log 2^5(base 2)

as we know, log a^b = b log a
hence, log 2^5 = 5 log 2

thus, log 2^5(base 2) = 5*log 2(base 2)
= 5

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Sanjeewani Indurkar   11 years AGO

according to the series the next number will be log32(base2)=log2^5(base2)=5log2/log2=5

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Kripa Shankar Singh   11 years AGO

Because,
log4(base2)= 2
log8(base2)= 3
log16(base2)= 4
So,
log32(base2)= 5

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niti   11 years AGO

log 4 ,log8,log16
2log2,3log2,4log2 next number will be log32 so
5log2
hence option 5

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roushan   11 years AGO

log4(base2)=2
log8(base2)=3
log16(base2)=4

2,3,4 next one is 5

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thota mahendar   11 years AGO

log4(base2),log8(base2),log16(base2),.
=log2^2,log2^3,log2^4,(log2^5(base2))
=2,3,4,(5)

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RAHUL KUMAR   11 years AGO

5 because
log32(base2)=5 every time the value for log is multiplying by 2 in previous value...

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ankush rajput   11 years AGO

log8(base2)=log22^3=3,similarly log(base2)32=5

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AVINASH KUMAR   11 years AGO

log32(base2)=5

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Abhijeet Kumar   11 years AGO

next number is log32(base2)
so,
log32(base2)
=log(2^5)(base2)
=5 log(base2) 2
=5(1) = 5

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Soni   11 years AGO

log4(base2),log8(base2),log16(base2),.........
next number is
log32(base2) = 5 .. option 5
as 2^5=32

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D.Jagruthi   11 years AGO

log32(base2)
=log2^5(base2)
=5log2(base2)
=5

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dharmendra   11 years AGO

log4(base2)=2
log8(base2)=3
log16(base2)=4
log36(base2)=5
that is the answer

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MONIKA JAIN   11 years AGO

log4(base 2)=2
log8(base2)=3
log16(base2)=4
so,next number is 5,i.e log32(base2)
so,answer is option 5.

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anjul meid   11 years AGO

log 32 (base 2)

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ravindra   11 years AGO

the next number is log32(base2)
that is log2^5(base2)=5

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k sathya bhavyasri   11 years AGO

log(2^2)(base2)= 2
log(2^3)(base2)= 3
log(2^4)(base2)= 4
log(2^5)(base2)= 5
..............
..............
log(2^n)(base2)= n

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jatin patware   11 years AGO

2 3 4 next=5

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PRATHAM MEHROTRA   11 years AGO

log 32(base 2)

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ANAND KUMAR   11 years AGO

log2^5(base2)=5

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Rohit Agarwal   11 years AGO

log4(base2)=2
log8(base2)=3
log16(base2)=4
log32(base2)=5

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Sasmita Ojha   11 years AGO

log32(base2)=5

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kethevijitha   11 years AGO

log2^2(base)2,log2^3(base)2,log2^4(base)2
nxt seq
log2^5(base)2...
now
2log2(base)2,3log2(base)2,4log2(base)2,
5log2(base)2 as loga(base)a=1
=>2,3,4,5

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vibhor sharma   11 years AGO

2,3,4.....5 ap

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jomon v j   11 years AGO

log 4 (base2) =2
log 8(base2) =3
log16(base2) =4
log 32(base2) =5

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Rats   11 years AGO

the next term is
log32(base2)=5
(since 2^5=32)

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Devendra Marghade   11 years AGO

log32(base2)=5

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ArunKumar   11 years AGO

log4(base2),log8(base2),log16(base2),.........
2log2(base2),3log2(base2),4log2(base2)
2,3,4
Ans 5

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Balakumaran N.A   11 years AGO

next sequence: log32(base2)
=> log 2^5 (base2) = 5 log2(base2) = 5.

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jitendra singh   11 years AGO

log(base2)32

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Naeem Ahamad   11 years AGO

log32(base2)=log2^5(base2)=5

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Samik Mukherjee   11 years AGO

The log series follows in this way:
2^2 (=4),2^3 (=8),2^4 (=16),2^5 (=32).
Since log 32(base 2)=5,so 5 is the answer.

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Balakrishnan M   11 years AGO

log4(base2)=log2^2(base2)=2log2(base2)=2*1 = 2,
log8(base2)=log2^3(base2)=3log2(base2)=3*1 = 3,
log16(base2)=log2^4(base2)=4log2(base2)=4*1 = 4,
Next number of the sequence is
log32(base2)=log2^5(base2)=5log2(base2)=5*1 = 5.

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Shreyansh Jain   11 years AGO

log 2^5/log2
5 log2/log2

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Balasaheb Rathod   11 years AGO

log4(base)2)=2,log8(base2)=3,log16(base2)=4,log32(base2)=5 ...ans is 5

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jai prakaash   11 years AGO

log32(base2)
5log2(base2)
=5

Like? Yes (1) | No (5)