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Maths Quotes

mathematic is the door and key to the science

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The essence of mathematics is not to make simple things complicated, but to make complicated things simple.

S. Gudder

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Vipul Chavan 3 years ago

Thanks m4 maths for helping to get placed in several companies.
I must recommend this website for placement preparations.

yash mittal 4 years ago

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(4 years ago) "Other"

Gold is 19 times as heavy as water and copper is 9 times as heavy as water. In
what ratio should these be mixed to get an alloy 15 times as heavy as water.

Reply Like? Yes (1) | No

(4 years ago)

Required ratio = (15-9)/(19-15) = 6/4 = 3/2
Therefore, these should be mixed in the ratio 3:2.

Like? Yes | No

(4 years ago) "Other"

Does anyone think that the prize system of today's puzzle needs to be changed and it needs to return the earlier system of distribution of prize amount. Whoever wants to win the prize needs to compete with other candidates. Otherwise there is no benefit of becoming topper of the week again if you already won a prize in a month.

Reply Like? Yes (3) | No (1)

(4 years ago) "Other"

In what respective ratio must water be mixed with juice costing Rs 16 per litre to
obtain a mixture worth Rs 12 per litre ?

Reply Like? Yes (1) | No

(4 years ago)

Water. Juice
0 -------------------------- 16
12
(16-12). ---------------- (12-0)
=4 =12
Therefore, ratio of water & juice = 4 : 12 = 1 : 3

Like? Yes (3) | No

to (4 years ago) "Other"

22000 is correct

Reply Like? Yes | No

(4 years ago) "Other"

Select the right option from the given alternativesKPQR:LRTV:DGHY:?
1 point
A) EIKC
B) ETKC
C) EJKD
D) EHKD

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(4 years ago)

Answer is : EIKC (Option A)

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(4 years ago) "Other"

20% of the people own only two cars each, 40% of the remaining, own three cars each and the remaining members own only one car each. Which statement is true ?

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(4 years ago) "Other"

Vedik ganit
https://youtu.be/YzFMYk4s2JE

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(4 years ago) "Other"

For today's puzzle,
CP comes out to be Rs. 28000.
Sp is Rs. 5000.
Loss= Rs. 23000..nobe of given options
But answer has been accepted by calculating loss difference of two selling prices.
What a murder of maths!

Why to calculate cp, if not required to calculate loss.
Please think, think and think if pissible.

Reply Like? Yes (6) | No

(4 years ago)

Good observation.
I think Site administrators are busy somewhere else due to lockdown.
or
Puzzles are being checked by Kirana merchants who are inable to open shops and they compare loss with max sale price (MSP).

Please check and respond .

Like? Yes (3) | No

(4 years ago)

Good observation.
I think Site administrators are busy somewhere else due to lockdown.
or
Puzzles are being checked by Kirana merchants who are unable to open shops and they compare loss with max sale price (MSP) to be expected or max gain possible.

Please check and respond .

Like? Yes (4) | No

(4 years ago)

Answer should be Rs. 23000/-
option 10. None of these

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(4 years ago) "Other"

best placement questions ...thank u m4maths

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(4 years ago) "Other"

In a class if 1 is absent the rest of them can be divided into 6 equal groups and if two are absent can be divided into 7 equal groups. Find the minimum number of students in the class

Reply Like? Yes | No

(4 years ago)

6*6=36
If we assume the number is 37 then
37-1=36 divisible by 6
And 37-2=35 divisible by 7

Like? Yes | No (1)

(4 years ago)

Let the number of students be 'x' then x-1=6y and x-2=7z
=> 6y+1 = 7z+2 or 6y - 7z = 1
Which is true for y=6, z=5
So, minimum number of students=6y+1 or 7z+2 = 37

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(4 years ago) "Other"

Find the largest 2- digit number which when divided by 2,3 and 5 leaves remainder 1, 2 and 4....Any short trick please.

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(4 years ago)

Calculate the l. C. M
That is 30 , 30+4=34 when divisible by 3 gives one remainder but does got go with 2,5 . So the next number can be 37. It helds all the option

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(4 years ago) "Other"

https://en.m.wikipedia.org/wiki/File:FCOC.jpg

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(4 years ago) "Other"

https://en.m.wikipedia.org/wiki/File:FCOC.jpg

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(4 years ago) "Other"

MADAN=CODPC
REENA=.....?

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(4 years ago)

MADAN=CODPC
REENA=.....?=GTECP

Like? Yes | No (1)

to (4 years ago) "Other"

Please help with this problem.
If two numbers are divided by a dividor produce remaindes 3 and 4, but then the sum of the numbers is divided by that divisor gives remainder 2. Find the divisor.

Reply Like? Yes (1) | No

(4 years ago)

Ans=5

Let the divisor be a, first no. be x and second no. be y, then in given 3 conditions
X = ak + 3 —(i)
y = al + 4 —(ii)
x+y = am + 2 —(iii)
Adding (i) & (iii), and Substituting x+y in (iii), we get (ak+3) + (al+4) = am+2
a(m-k-l) = 5
Prime factorization gives a=5 or 1
As divisor cannot be 1 in above given conditions, so divisor a=5.

Like? Yes | No (1)

(4 years ago) "Other"

BIHAR=SDMPK
PATNA=.....?

Reply Like? Yes (1) | No

(4 years ago)

answer tell me please

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(4 years ago) "Other"

NUMBER =UIGSBY
SECOND=......?

Reply Like? Yes (1) | No

(4 years ago) "Other"

DISTURB=FRANTIC
DTWVUKF=.......?

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(4 years ago) "Other"

where should i start to prepare for aptitude?

Reply Like? Yes (2) | No

(4 years ago) "Other"

Please give solution.
जब कोई व्यक्ति 60 km/hr की गति से चलता है तो वह सुबह 11:00 am बजे घर पहुंचता है . जब वह 32 km/hr की गति से चलता है तो वह दोपहर 12:00 pm बजे घर पहुंचता है. 46 km/hr की सवारी करने पर वह किस समय घर पहुंचेगा, यदि दिया गया है कि वह प्रत्येक दिन सुबह 9:00 am बजे अपनी यात्रा शुरू करता है
1)11:30 am 2)11:45 am 3)11:24 am 4)11:36 am

Reply Like? Yes | No (2)

(4 years ago) "Other"

How can we express a rational number as a sum of an integer and a rational number?

Reply Like? Yes (1) | No

(4 years ago)

5/4 = 1 + 1/4
where 5/4 and 1/4 are rational numbers, and 1 is integer

Like? Yes (2) | No (1)

to (4 years ago) "Other"

Reply Like? Yes | No

to (4 years ago) "Other"

Please explain, assistant pipe ha ya admi ?

A barrel full of beer has 2 taps one midway, which draws a litre in 6 minutes and the other at the bottom, which draws a litre in 4 minutes. The lower tap is normally used after the level of beer in the barrel is lower than midway. The capacity of the barrel is 36 litres. A new assistant opens the lower tap when the barrel is full and draws out some beer, As a result the lower tap has been used 24 minutes before the usual time. For how long was the beer drawn out by the new assistant?
Ans 16

Reply Like? Yes (1) | No (1)

(4 years ago) "Other"

if y = log x(1+x), then x = ?

Reply Like? Yes | No (1)

(4 years ago) "Other"

The price of sugar increases by 20%, by what % should a housewife reduce the consumption of sugar so that expenditure on sugar can be same as before?

Reply Like? Yes (1) | No

(4 years ago)

16.66%

Let initial consumption=100 & price=100, then expenditure=100*100=10000
If new consumption=x & price=120, then for same expenditure, 120x=10000
=> x=83.33
So, % reduction=100-83.33=16.66

Like? Yes (1) | No (1)

to (4 years ago) "Other"

the students of a class appeared for an exam which had 200 questions. Each correct answer was awarded 2 Marks and for each wrong answer one-third of a mark was deducted. two student answered all the question in it. the first student got the maximum possible marks and the second student got 175 marks less than him. find the number of questions correctly answered by the second student. 1)115 2)125 3)135 4)145 ) none of.
Please solve

Reply Like? Yes | No

(4 years ago)

2) 125

Maximum possible marks, 1st student got = 2*200 = 400
.'. Marks of 2nd student = 400 - 175 = 225
Let for 2nd student, correct answers=x and wrong answers=y
Then, x + y = 200 ---(i) and 2x - y/3 = 225 ---(ii)
Solving equation (i) & (ii), we get x=125, y=75
Hence, 2nd student solved 125 correct answers.

Like? Yes (3) | No

(4 years ago)

In a game of 80 points, A can give B 5 points and C 15 points. then how many points B can give C in a game of 60?
Devendra can you give brief Sol for this

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to (4 years ago) "Other"

Two cars starts from point A and B to B and A respectively. They cross each other in 1.2 hour and the first car reaches A at 1 hour before the second car reaches B. If the distance between A and B is 50 km, what is the speed of the slower car? 1)20km/hr 2) 10km/hr 3)15km/hr 4)25km/hr........ Which is correct questions in both of. Please solve if any is correct please 🙏😊

Reply Like? Yes | No

(4 years ago)

Speed of the slower car=16.66 km/hr

Let the speed of the car starting from point A and B be a and b km/hr.
Given, car starting from B reaches A, 1 hour early => Car starting from A is slower, so we have to find 'a'
As car cross each other in 1.2 hrs => 50/(a+b) = 1.2 => a+b = 125/3 ---(i)
Time difference of cars reaching B and A = 50/a - 50/b = 1 ---(ii)
Now substituting, b=125/3 - a from eqn. (i) into (ii), we get 3a² - 425a + 6250 = 0 ---(iii)
(3a-50) (a-125) = 0
a=50/3, a=125, (Ignoring a=125 as with this speed two cars cann't cross each other in 1.2 hrs)
Therefore, speed of slower car=50/3=16.66 km/hr and faster car=25 km/hr.

Like? Yes (2) | No

to (4 years ago) "Other"

Two cars starts from point A and B to B and A respectively. They cross each other in 1 hour and the first car reaches A at 5/6 hour before the second car reaches B. If the distance between A and B is 50 km, what is the speed of the slower car? 1)20km/hr 2) 10km/hr 3)15km/hr 4)25km/hr

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to (4 years ago) "Other"

Sheela, Sandhya and jyotsna can type a page in in 10, 15 and 18 minutes respectively. they decided to work together for equal time to type a document which contains 980 pages. how many pages are typed by jyotsna ? 1)280 2)275 3)245 4)350 5)none

Reply Like? Yes | No

(4 years ago)

3) 245

In 1 min, individually Sheela, Sandhya and Jyotsna can type 1/10, 1/15, 1/18 pages respectively.
Together in 1 min they can type 1/10 + 1/15 + 1/18 = 2/9 page.
For 980 pages time required = 980/(2/9) = 4410 min.
So, pages typed by Jyotsna in 4410 min = (1/18)*4410 = 245

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to (4 years ago) "Other"

vimal alone can do a piece of work in 36 days. the time taken by vimal in completing 1/6th of the work equals the time taken by Gopi to complete 2/5th of the same work. in how many days can they both complete the work if they work together?

Reply Like? Yes | No

(4 years ago)

10 (10/17) days

Days required by Vimal=36. So Vimal can complete 1/6 of the work in (1/6)*36=6 days.
If Gopi takes 'x' days for same work, then days required for 2/5 of work=2x/5=6
=> x=15
Thus 1 day's work of Vimal & Gopi = 1/36 + 1/15 = 17/180
Hence, required days = 180/17 = 10 10/17

Like? Yes (2) | No

to (4 years ago) "Other"

, Q, R and S are four friends and they are working independently on a work. R can do the work in M days, whereas S can do the same work in 2M days. R started the work and worked for only 144/7 days. then, he was replaced with S, who completed the remaining work in the same time as P and Q working together would finish the entire work. the efficiency ratio of P and Q is 4:3. if P and Q are working on alternate days, with P being first, the work will finished in 41 days.

1)in how many days can R individually complete the total work?

Reply Like? Yes | No

(4 years ago) "Other"

P, Q, R and S are four friends and they are working independently on a work. R can do the work in M days, whereas S can do the same work in 2M days. R started the work and worked for only 144/7 days. then, he was replaced with S, who completed the remaining work in the same time as P and Q working together would finish the entire work. the efficiency ratio of P and Q is 4:3. if P and Q are working on alternate days, with P being first, the work will finished in 41 days.
1)in how many days can R individually complete the total work?

Reply Like? Yes | No

(4 years ago)

216/7 days

Given R takes M days, so 1 day's work of R = 1/M
Similarly S takes 2M days, so 1 day's work of S = 1/(2M)
Work completed by R in 144/7 days = (1/M)*(144/7) = 144/(7M) and remaining work = 1 - 144/(7M)

Given, efficiency ratio of P and Q is 4:3.
Days required is inversely proportional to efficiency. Let P & Q can complete the work in x/4 & x/3 days respectively.
Given, P and Q are working on alternate days, with P being first, the work will finished in 41 days.
=> P works for 21 days whereas Q works for 20 days to complete the work.
=> 21*P's 1 day work + 20*Q's 1 day work = 1
21*4/x + 20*3/x = 1
=> x=144
Thus, P takes 144/4=36 days and Q takes 144/3=48 days to complete the work individually.
Now (P+Q)'s 1 day work = 1/36 + 1/48 = 7/144
.'. Together P & Q require 144/7 days = Days required by S to complete remaining work
=> (144/7)*1/(2M) = 1 - 144/(7M)
72/(7M) = (7M - 144)/7M
7M = 216
M = 216/7 = Days required by R individually to complete the work.

Like? Yes (3) | No (1)

to (4 years ago) "Other"

If 36 persons are engaged on a piece of work, the work can be completed in 40 days. After 32 days, only 3/4 th of the work was completed. How many more persons are required to complete the work on time?
A)10
B)8
C)9
D)12

Reply Like? Yes (2) | No

(4 years ago)

D)12

Work completed by 36 persons in 32 days=3/4
1 person's 1 days work = (3/4)/(32*36) = 1/1536
Now remaining work=1/4 and remaining days=40-32=8
So, required work in 1 day = (1/4)/8 = 1/32
Total persons required = (1/32)/(1/1536) = 48
Hence, additional persons = 48 - 36 = 12

Like? Yes (2) | No (1)

(4 years ago) "Other"

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(4 years ago) "Other"

The ratio of difference between Compound interest and simple interest at 2 year and 2.5 year is 9:17 then rate of compound interest? 1)22.22% 2)11.11% 3)18.18% 4)22.5%

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to (4 years ago) "Other"

The ratio of difference between Compound interest and simple interest at 2 year and 2.5 year is 9:17 then rate of compound interest? 1)22.22% 2)11.11% 3)18.18% 4)22.5%

Reply Like? Yes | No

to (4 years ago) "Other"

A man borrows a sum of rs 96,000 at 5% p.a. interest compounded annually. At the end of one year, he repays a certain amount and he repays the balance amount of rs 70,980 at the end of the second year. What amount does he repays at the end of the first year?

Reply Like? Yes | No (2)

(4 years ago)

Rs. 33200

Amount after 1 year = 96000*(1 + 5/100) = 100800
Let he repays Rs. x after 1 year, then amount to be paid after 2nd year=(100800 - x)*(1 + 5/100) = 70980
100800 - x = 67600
=> x=33200

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(4 years ago) "Other"

For Today's puzzle, options 3 and 5 are same as 246.
Please check.

Reply Like? Yes (1) | No

(4 years ago) "Other"

Anyone plz send me the model papers of amcat.. mail id kousalya97r@gmail.com

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(4 years ago) "Other"

Plz send me the model papers of amcat...

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(4 years ago) "Other"

How many ports will be allocated to a new emulator?

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(4 years ago) "Other"

H17, B11, P79, G16, L48, ?

Reply Like? Yes (45) | No (5)

(4 years ago) "Other"

problem statement:

you are given an array a[],and you need to find out the combination of array element which has same different.print the count of combinations

SAMPLE INPUT: SAMPLE OUTPUT:
5
4
27
37
47
57
EXPLANATION:

the possible comnibation are with 10 difference(27,37),(37,47),(47,57) -3 with 20 difference (27,47),(37,57)-2 total 3+2=5

E

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(4 years ago) "Other"

Anyone tell me the pattern of Amcat

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to (4 years ago) "Other"

In a election between two parties P and Q, Q is loser. If Q get 25% more votes then he win by the thrice the majority then that of P. If the total number of votes are 4250. How many vote did P get? 1)2250 2)1125 3)2000 4) 1525.. please give solution

Reply Like? Yes (4) | No

(4 years ago)

3) 2250

Total votes = P + Q = 4250 ---(i)
When Q is loser, majority of P = (P - Q)
When Q gets 25% more votes, then votes of Q = Q + 0.25Q = 1.25Q and votes of P = (P - 0.25Q)
According to given condition, 1.25Q - (P - 0.25Q) = 3*(P - Q)
=> 4P - 4.5Q = 0 ---(ii)
On solving equations (i) & (ii), Q=2000, P=2250

Like? Yes (4) | No

(4 years ago)

As per given ststement, Q is the looser.
From given options, only 2250 votes for P satisfies this condition.
No need to waste time to solve in detail while appearing for multiple choice questions test in limited time.

Like? Yes (1) | No

to (4 years ago) "Other"

In a local election, 2400 people were to vote for Party A or Party B. Party A was bound to win the election. However, on Election Day, 33% of the voters of Party A were kidnapped. Party B was also able to influence the remaining Party A voters and thus double the strength of its voters. In this way, Party A lost by a majority which was half of that by which it would have won had the elections been fair. How many people finally voted for Party A and Party B?

Reply Like? Yes | No

(4 years ago)

Final voters of party A=1029, B=1371

In fair election, party A voters=1542, party B voters=858, majority of A=684
After 33% and some voters of A shifted to B, Party A voters=1029, party B voters=1371, majority of B=342

Like? Yes (3) | No

(4 years ago) "Other"

Reply Like? Yes | No

(4 years ago) "Other"

Reply Like? Yes | No (1)

(4 years ago)

As per given statement, Q is the loser.
From given options, only 2250 votes for P satisfies this condition.
No need to waste time to solve in detail while appearing for multiple choice questions test in limited time.

Like? Yes | No

(4 years ago) "Other"

Pls check on site.
May answer is 5 which is correct as per site only .
But marks .. -1.
Any reason ?

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(4 years ago) "Other"

Regarding 'Today's puzzle'dated 30.01.2020, it is to inform you that result displayed at site is incomplete.
I have submitted same answer ( option) in first 10 minutes, but same is not displayed here.
Please check.

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