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Devendra Marghade

India

Maharashtra

Time: 00:04:10

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Maths Quotes

without maths no can't live in this world

k ravikumar

How many times can you subtract 7 from 83, and what is left afterwards? You can subtract it as many times as you want, and it leaves 76 every time.

Unknown

Placed User Comments

Placed in Infosys With Help for M4Maths
Thank you :) :)

Ankush Bansal 3 years ago

I got successfully placed in TCS pool drive. Thank you M4 Maths

Naveen Kumar 3 years ago

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(3 Days ago) "Other"

MADAN=CODPC
REENA=.....?

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(3 Days ago)

MADAN=CODPC
REENA=.....?=GTECP

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to (3 Days ago) "Other"

Please help with this problem.
If two numbers are divided by a dividor produce remaindes 3 and 4, but then the sum of the numbers is divided by that divisor gives remainder 2. Find the divisor.

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(3 Days ago)

Ans=5

Let the divisor be a, first no. be x and second no. be y, then in given 3 conditions
X = ak + 3 —(i)
y = al + 4 —(ii)
x+y = am + 2 —(iii)
Adding (i) & (iii), and Substituting x+y in (iii), we get (ak+3) + (al+4) = am+2
a(m-k-l) = 5
Prime factorization gives a=5 or 1
As divisor cannot be 1 in above given conditions, so divisor a=5.

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(3 Days ago) "Other"

BIHAR=SDMPK
PATNA=.....?

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(3 Days ago)

answer tell me please

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(3 Days ago) "Other"

NUMBER =UIGSBY
SECOND=......?

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(3 Days ago) "Other"

DISTURB=FRANTIC
DTWVUKF=.......?

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(19 Days ago) "Other"

where should i start to prepare for aptitude?

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(20 Days ago) "Other"

Please give solution.
जब कोई व्यक्ति 60 km/hr की गति से चलता है तो वह सुबह 11:00 am बजे घर पहुंचता है . जब वह 32 km/hr की गति से चलता है तो वह दोपहर 12:00 pm बजे घर पहुंचता है. 46 km/hr की सवारी करने पर वह किस समय घर पहुंचेगा, यदि दिया गया है कि वह प्रत्येक दिन सुबह 9:00 am बजे अपनी यात्रा शुरू करता है
1)11:30 am 2)11:45 am 3)11:24 am 4)11:36 am

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(21 Days ago) "Other"

How can we express a rational number as a sum of an integer and a rational number?

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(18 Days ago)

5/4 = 1 + 1/4
where 5/4 and 1/4 are rational numbers, and 1 is integer

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to (26 Days ago) "Other"

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to (28 Days ago) "Other"

Please explain, assistant pipe ha ya admi ?

A barrel full of beer has 2 taps one midway, which draws a litre in 6 minutes and the other at the bottom, which draws a litre in 4 minutes. The lower tap is normally used after the level of beer in the barrel is lower than midway. The capacity of the barrel is 36 litres. A new assistant opens the lower tap when the barrel is full and draws out some beer, As a result the lower tap has been used 24 minutes before the usual time. For how long was the beer drawn out by the new assistant?
Ans 16

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(1 Month ago) "Other"

if y = log x(1+x), then x = ?

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(1 Month ago) "Other"

The price of sugar increases by 20%, by what % should a housewife reduce the consumption of sugar so that expenditure on sugar can be same as before?

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(1 Month ago)

16.66%

Let initial consumption=100 & price=100, then expenditure=100*100=10000
If new consumption=x & price=120, then for same expenditure, 120x=10000
=> x=83.33
So, % reduction=100-83.33=16.66

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to (1 Month ago) "Other"

the students of a class appeared for an exam which had 200 questions. Each correct answer was awarded 2 Marks and for each wrong answer one-third of a mark was deducted. two student answered all the question in it. the first student got the maximum possible marks and the second student got 175 marks less than him. find the number of questions correctly answered by the second student. 1)115 2)125 3)135 4)145 ) none of.
Please solve

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(1 Month ago)

2) 125

Maximum possible marks, 1st student got = 2*200 = 400
.'. Marks of 2nd student = 400 - 175 = 225
Let for 2nd student, correct answers=x and wrong answers=y
Then, x + y = 200 ---(i) and 2x - y/3 = 225 ---(ii)
Solving equation (i) & (ii), we get x=125, y=75
Hence, 2nd student solved 125 correct answers.

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(1 Month ago)

In a game of 80 points, A can give B 5 points and C 15 points. then how many points B can give C in a game of 60?
Devendra can you give brief Sol for this

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to (1 Month ago) "Other"

Two cars starts from point A and B to B and A respectively. They cross each other in 1.2 hour and the first car reaches A at 1 hour before the second car reaches B. If the distance between A and B is 50 km, what is the speed of the slower car? 1)20km/hr 2) 10km/hr 3)15km/hr 4)25km/hr........ Which is correct questions in both of. Please solve if any is correct please 🙏😊

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(1 Month ago)

Speed of the slower car=16.66 km/hr

Let the speed of the car starting from point A and B be a and b km/hr.
Given, car starting from B reaches A, 1 hour early => Car starting from A is slower, so we have to find 'a'
As car cross each other in 1.2 hrs => 50/(a+b) = 1.2 => a+b = 125/3 ---(i)
Time difference of cars reaching B and A = 50/a - 50/b = 1 ---(ii)
Now substituting, b=125/3 - a from eqn. (i) into (ii), we get 3a² - 425a + 6250 = 0 ---(iii)
(3a-50) (a-125) = 0
a=50/3, a=125, (Ignoring a=125 as with this speed two cars cann't cross each other in 1.2 hrs)
Therefore, speed of slower car=50/3=16.66 km/hr and faster car=25 km/hr.

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to (1 Month ago) "Other"

Two cars starts from point A and B to B and A respectively. They cross each other in 1 hour and the first car reaches A at 5/6 hour before the second car reaches B. If the distance between A and B is 50 km, what is the speed of the slower car? 1)20km/hr 2) 10km/hr 3)15km/hr 4)25km/hr

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to (1 Month ago) "Other"

Sheela, Sandhya and jyotsna can type a page in in 10, 15 and 18 minutes respectively. they decided to work together for equal time to type a document which contains 980 pages. how many pages are typed by jyotsna ? 1)280 2)275 3)245 4)350 5)none

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(1 Month ago)

3) 245

In 1 min, individually Sheela, Sandhya and Jyotsna can type 1/10, 1/15, 1/18 pages respectively.
Together in 1 min they can type 1/10 + 1/15 + 1/18 = 2/9 page.
For 980 pages time required = 980/(2/9) = 4410 min.
So, pages typed by Jyotsna in 4410 min = (1/18)*4410 = 245

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to (1 Month ago) "Other"

vimal alone can do a piece of work in 36 days. the time taken by vimal in completing 1/6th of the work equals the time taken by Gopi to complete 2/5th of the same work. in how many days can they both complete the work if they work together?

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(1 Month ago)

10 (10/17) days

Days required by Vimal=36. So Vimal can complete 1/6 of the work in (1/6)*36=6 days.
If Gopi takes 'x' days for same work, then days required for 2/5 of work=2x/5=6
=> x=15
Thus 1 day's work of Vimal & Gopi = 1/36 + 1/15 = 17/180
Hence, required days = 180/17 = 10 10/17

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to (1 Month ago) "Other"

, Q, R and S are four friends and they are working independently on a work. R can do the work in M days, whereas S can do the same work in 2M days. R started the work and worked for only 144/7 days. then, he was replaced with S, who completed the remaining work in the same time as P and Q working together would finish the entire work. the efficiency ratio of P and Q is 4:3. if P and Q are working on alternate days, with P being first, the work will finished in 41 days.

1)in how many days can R individually complete the total work?

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(1 Month ago) "Other"

P, Q, R and S are four friends and they are working independently on a work. R can do the work in M days, whereas S can do the same work in 2M days. R started the work and worked for only 144/7 days. then, he was replaced with S, who completed the remaining work in the same time as P and Q working together would finish the entire work. the efficiency ratio of P and Q is 4:3. if P and Q are working on alternate days, with P being first, the work will finished in 41 days.
1)in how many days can R individually complete the total work?

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(1 Month ago)

216/7 days

Given R takes M days, so 1 day's work of R = 1/M
Similarly S takes 2M days, so 1 day's work of S = 1/(2M)
Work completed by R in 144/7 days = (1/M)*(144/7) = 144/(7M) and remaining work = 1 - 144/(7M)

Given, efficiency ratio of P and Q is 4:3.
Days required is inversely proportional to efficiency. Let P & Q can complete the work in x/4 & x/3 days respectively.
Given, P and Q are working on alternate days, with P being first, the work will finished in 41 days.
=> P works for 21 days whereas Q works for 20 days to complete the work.
=> 21*P's 1 day work + 20*Q's 1 day work = 1
21*4/x + 20*3/x = 1
=> x=144
Thus, P takes 144/4=36 days and Q takes 144/3=48 days to complete the work individually.
Now (P+Q)'s 1 day work = 1/36 + 1/48 = 7/144
.'. Together P & Q require 144/7 days = Days required by S to complete remaining work
=> (144/7)*1/(2M) = 1 - 144/(7M)
72/(7M) = (7M - 144)/7M
7M = 216
M = 216/7 = Days required by R individually to complete the work.

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to (1 Month ago) "Other"

If 36 persons are engaged on a piece of work, the work can be completed in 40 days. After 32 days, only 3/4 th of the work was completed. How many more persons are required to complete the work on time?
A)10
B)8
C)9
D)12

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(1 Month ago)

D)12

Work completed by 36 persons in 32 days=3/4
1 person's 1 days work = (3/4)/(32*36) = 1/1536
Now remaining work=1/4 and remaining days=40-32=8
So, required work in 1 day = (1/4)/8 = 1/32
Total persons required = (1/32)/(1/1536) = 48
Hence, additional persons = 48 - 36 = 12

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(1 Month ago) "Other"

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(1 Month ago) "Other"

The ratio of difference between Compound interest and simple interest at 2 year and 2.5 year is 9:17 then rate of compound interest? 1)22.22% 2)11.11% 3)18.18% 4)22.5%

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to (1 Month ago) "Other"

The ratio of difference between Compound interest and simple interest at 2 year and 2.5 year is 9:17 then rate of compound interest? 1)22.22% 2)11.11% 3)18.18% 4)22.5%

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to (1 Month ago) "Other"

A man borrows a sum of rs 96,000 at 5% p.a. interest compounded annually. At the end of one year, he repays a certain amount and he repays the balance amount of rs 70,980 at the end of the second year. What amount does he repays at the end of the first year?

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(1 Month ago)

Rs. 33200

Amount after 1 year = 96000*(1 + 5/100) = 100800
Let he repays Rs. x after 1 year, then amount to be paid after 2nd year=(100800 - x)*(1 + 5/100) = 70980
100800 - x = 67600
=> x=33200

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(1 Month ago) "Other"

For Today's puzzle, options 3 and 5 are same as 246.
Please check.

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(1 Month ago) "Other"

Anyone plz send me the model papers of amcat.. mail id kousalya97r@gmail.com

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(1 Month ago) "Other"

Plz send me the model papers of amcat...

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(2 Months ago) "Other"

How many ports will be allocated to a new emulator?

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(2 Months ago) "Other"

H17, B11, P79, G16, L48, ?

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(2 Months ago) "Other"

problem statement:

you are given an array a[],and you need to find out the combination of array element which has same different.print the count of combinations

SAMPLE INPUT: SAMPLE OUTPUT:
5
4
27
37
47
57
EXPLANATION:

the possible comnibation are with 10 difference(27,37),(37,47),(47,57) -3 with 20 difference (27,47),(37,57)-2 total 3+2=5

E

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(2 Months ago) "Other"

Anyone tell me the pattern of Amcat

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to (2 Months ago) "Other"

In a election between two parties P and Q, Q is loser. If Q get 25% more votes then he win by the thrice the majority then that of P. If the total number of votes are 4250. How many vote did P get? 1)2250 2)1125 3)2000 4) 1525.. please give solution

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(2 Months ago)

3) 2250

Total votes = P + Q = 4250 ---(i)
When Q is loser, majority of P = (P - Q)
When Q gets 25% more votes, then votes of Q = Q + 0.25Q = 1.25Q and votes of P = (P - 0.25Q)
According to given condition, 1.25Q - (P - 0.25Q) = 3*(P - Q)
=> 4P - 4.5Q = 0 ---(ii)
On solving equations (i) & (ii), Q=2000, P=2250

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(2 Months ago)

As per given ststement, Q is the looser.
From given options, only 2250 votes for P satisfies this condition.
No need to waste time to solve in detail while appearing for multiple choice questions test in limited time.

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to (2 Months ago) "Other"

In a local election, 2400 people were to vote for Party A or Party B. Party A was bound to win the election. However, on Election Day, 33% of the voters of Party A were kidnapped. Party B was also able to influence the remaining Party A voters and thus double the strength of its voters. In this way, Party A lost by a majority which was half of that by which it would have won had the elections been fair. How many people finally voted for Party A and Party B?

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(2 Months ago)

Final voters of party A=1029, B=1371

In fair election, party A voters=1542, party B voters=858, majority of A=684
After 33% and some voters of A shifted to B, Party A voters=1029, party B voters=1371, majority of B=342

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(2 Months ago) "Other"

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(2 Months ago) "Other"

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(2 Months ago)

As per given statement, Q is the loser.
From given options, only 2250 votes for P satisfies this condition.
No need to waste time to solve in detail while appearing for multiple choice questions test in limited time.

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(2 Months ago) "Other"

Pls check on site.
May answer is 5 which is correct as per site only .
But marks .. -1.
Any reason ?

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(2 Months ago) "Other"

Regarding 'Today's puzzle'dated 30.01.2020, it is to inform you that result displayed at site is incomplete.
I have submitted same answer ( option) in first 10 minutes, but same is not displayed here.
Please check.

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(2 Months ago) "Other"

i want questions on TCS nqt

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(2 Months ago) "Other"

a student asked to get the combined sum of three individual series but due to his laziness he wrote all three 1 series in the combined form as 3+2+4+8+3+a+27+ . then he realizes that some of the terms merged and converted to new term. what will be the exact sum if he suppose to find the sum of first 36 terms a)6812 b)9812 c)6914 d)6912

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(2 Months ago) "Other"

No. Of zero?
1/2(6+10).

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(2 Months ago) "Other"

The ratio of A and B’s income last year was 4:3 the ratio of their own incomes of last year and this year individually, it’s 3:4 and 5:6 respectively. If the total sum of their present income is ₹8.04 lakh, then what is the last year income of b? Please give solution

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(2 Months ago)

2.7 lakh

Let the income of A & B last year was 4x and 3x.
Given ratio of their last year to this year income individually are 3:4 and 5:6 respectively.
Then income this year of A = 4x*(4/3) = 16x/3 and income of B = 3x*(6/5) = 18x/5
Sum of the incomes this year = 16x/3 + 18x/5 = 804000
=> x = 90000
Therefore, last year income of B = 3x = 3*90000 = 270000 = 2.7 lakh

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(2 Months ago) "Other"

How to learn python

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(2 Months ago) "Other"

consulting firms nj

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(2 Months ago) "Other"

I have aptitude question solution

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(2 Months ago) "Other"

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(2 Months ago) "Other"

I am a Staff Author at https://www.fieldengineer.com a Marketplace for On Demand telecom workforce, ranging from telecom field engineers to high-level network engineers,
project managers and Network Architects in 146 countries.
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to (2 Months ago) "Other"

hiiii can u plz share infosys papers madam

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(2 Months ago) "Other"

Mumbai¤¤Pune¤¤,91–8426924404 Black magic to kill enemy

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(2 Months ago) "Other"

Ibm written papers

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(3 Months ago) "Other"

near by a yard which is 225 meters long 26 papaya tree are planted at equal distance one tree being at each end of the yard what is the distance between two consecutive trees?

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(2 Months ago)

9 meters
225/(26-1)= 225/25= 9 meters

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