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PRABHAT KUMAR

India

Bihar

Time: 00:01:20

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Maths Quotes

MATHEMATICS is the key of every problem.

vivek .R

amcat ques , guys help me what is the value of these log0.2 base 5

amcat

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Placed in Infosys With Help for M4Maths
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Ankush Bansal 3 years ago

I got successfully placed in TCS pool drive. Thank you M4 Maths

Naveen Kumar 3 years ago

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(1 Month ago) "Other"

Find the product of all the factors of 3^16

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(1 Month ago) "Other"

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(1 Month ago) "Other"

Buy High Quality Counterfeits Bank notes, Real/Fake Passports, Drivers license, Id cards, Visas, Etc... jayroy011@hotmail.com or Whatsapp +27639356786

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to (1 Month ago) "Other"

i got answer 1:1 but there is no option

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to (1 Month ago) "Other"

thank u sir can u please solve remaining problems?

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(1 Month ago) "Other"

Two alloys contain zinc and copper in the ratio of 2 : 1 and 4 : 1. In what ratio the
two alloys should be added together to get as new alloy having zinc and copper in
the ratio of 3 : 1

Reply Like? Yes (1) | No

(1 Month ago)

Let the ratio is x:y
(2x+4y):(x+y)=3:1
2x+4y=3x+3y=>x=y
Now x:y=1:1

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(1 Month ago) "Other"

How many Kg ot wheat @ Rs. 14 per kg should be mixed with 32 kg of wheat @ Rs
22 per kg so that there is a profit of 25% by selling the mixture @ Rs 23.90 per kg

Reply Like? Yes | No

(1 Month ago)

Ans: 18 kg

Let x kg of wheat costing Rs. 14/kg is mixed, then (x*14 + 32*22)/(x+32) = 23.9*(100/125)
(14x + 704) / (x+32) = 19.12
14x + 704 = 19.12x + 611.84
5.12x = 92.16
x = 18

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(1 Month ago) "Other"

Two types of rice (type 1 and type 2) were mixed in the respective ratio of 1 : 3.
The mixture was then sold @ 75.60 per kg to gain a profit of 20%. If the price of
type 1 rice is Rs. 75 per kg, what is the price of type 2 rice per kg

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(1 Month ago) "Other"

Gold is 19 times as heavy as water and copper is 9 times as heavy as water. In
what ratio should these be mixed to get an alloy 15 times as heavy as water.

Reply Like? Yes (1) | No

(1 Month ago)

Required ratio = (15-9)/(19-15) = 6/4 = 3/2
Therefore, these should be mixed in the ratio 3:2.

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(1 Month ago) "Other"

Does anyone think that the prize system of today's puzzle needs to be changed and it needs to return the earlier system of distribution of prize amount. Whoever wants to win the prize needs to compete with other candidates. Otherwise there is no benefit of becoming topper of the week again if you already won a prize in a month.

Reply Like? Yes | No (1)

(1 Month ago) "Other"

In what respective ratio must water be mixed with juice costing Rs 16 per litre to
obtain a mixture worth Rs 12 per litre ?

Reply Like? Yes (1) | No

(1 Month ago)

Water. Juice
0 -------------------------- 16
12
(16-12). ---------------- (12-0)
=4 =12
Therefore, ratio of water & juice = 4 : 12 = 1 : 3

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to (1 Month ago) "Other"

22000 is correct

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(2 Months ago) "Other"

Select the right option from the given alternativesKPQR:LRTV:DGHY:?
1 point
A) EIKC
B) ETKC
C) EJKD
D) EHKD

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(1 Month ago)

Answer is : EIKC (Option A)

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(2 Months ago) "Other"

20% of the people own only two cars each, 40% of the remaining, own three cars each and the remaining members own only one car each. Which statement is true ?

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(2 Months ago) "Other"

Vedik ganit
https://youtu.be/YzFMYk4s2JE

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(2 Months ago) "Other"

For today's puzzle,
CP comes out to be Rs. 28000.
Sp is Rs. 5000.
Loss= Rs. 23000..nobe of given options
But answer has been accepted by calculating loss difference of two selling prices.
What a murder of maths!

Why to calculate cp, if not required to calculate loss.
Please think, think and think if pissible.

Reply Like? Yes (6) | No

(2 Months ago)

Good observation.
I think Site administrators are busy somewhere else due to lockdown.
or
Puzzles are being checked by Kirana merchants who are inable to open shops and they compare loss with max sale price (MSP).

Please check and respond .

Like? Yes (3) | No

(2 Months ago)

Good observation.
I think Site administrators are busy somewhere else due to lockdown.
or
Puzzles are being checked by Kirana merchants who are unable to open shops and they compare loss with max sale price (MSP) to be expected or max gain possible.

Please check and respond .

Like? Yes (4) | No

(2 Months ago)

Answer should be Rs. 23000/-
option 10. None of these

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(2 Months ago) "Other"

best placement questions ...thank u m4maths

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(2 Months ago) "Other"

In a class if 1 is absent the rest of them can be divided into 6 equal groups and if two are absent can be divided into 7 equal groups. Find the minimum number of students in the class

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(2 Months ago)

6*6=36
If we assume the number is 37 then
37-1=36 divisible by 6
And 37-2=35 divisible by 7

Like? Yes | No (1)

(2 Months ago)

Let the number of students be 'x' then x-1=6y and x-2=7z
=> 6y+1 = 7z+2 or 6y - 7z = 1
Which is true for y=6, z=5
So, minimum number of students=6y+1 or 7z+2 = 37

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(2 Months ago) "Other"

Find the largest 2- digit number which when divided by 2,3 and 5 leaves remainder 1, 2 and 4....Any short trick please.

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(2 Months ago)

Calculate the l. C. M
That is 30 , 30+4=34 when divisible by 3 gives one remainder but does got go with 2,5 . So the next number can be 37. It helds all the option

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(2 Months ago) "Other"

https://en.m.wikipedia.org/wiki/File:FCOC.jpg

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(2 Months ago) "Other"

https://en.m.wikipedia.org/wiki/File:FCOC.jpg

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(3 Months ago) "Other"

MADAN=CODPC
REENA=.....?

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(3 Months ago)

MADAN=CODPC
REENA=.....?=GTECP

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to (3 Months ago) "Other"

Please help with this problem.
If two numbers are divided by a dividor produce remaindes 3 and 4, but then the sum of the numbers is divided by that divisor gives remainder 2. Find the divisor.

Reply Like? Yes | No

(3 Months ago)

Ans=5

Let the divisor be a, first no. be x and second no. be y, then in given 3 conditions
X = ak + 3 —(i)
y = al + 4 —(ii)
x+y = am + 2 —(iii)
Adding (i) & (iii), and Substituting x+y in (iii), we get (ak+3) + (al+4) = am+2
a(m-k-l) = 5
Prime factorization gives a=5 or 1
As divisor cannot be 1 in above given conditions, so divisor a=5.

Like? Yes | No (1)

(3 Months ago) "Other"

BIHAR=SDMPK
PATNA=.....?

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(3 Months ago)

answer tell me please

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(3 Months ago) "Other"

NUMBER =UIGSBY
SECOND=......?

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(3 Months ago) "Other"

DISTURB=FRANTIC
DTWVUKF=.......?

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(3 Months ago) "Other"

where should i start to prepare for aptitude?

Reply Like? Yes (1) | No

(3 Months ago) "Other"

Please give solution.
जब कोई व्यक्ति 60 km/hr की गति से चलता है तो वह सुबह 11:00 am बजे घर पहुंचता है . जब वह 32 km/hr की गति से चलता है तो वह दोपहर 12:00 pm बजे घर पहुंचता है. 46 km/hr की सवारी करने पर वह किस समय घर पहुंचेगा, यदि दिया गया है कि वह प्रत्येक दिन सुबह 9:00 am बजे अपनी यात्रा शुरू करता है
1)11:30 am 2)11:45 am 3)11:24 am 4)11:36 am

Reply Like? Yes | No (2)

(3 Months ago) "Other"

How can we express a rational number as a sum of an integer and a rational number?

Reply Like? Yes (1) | No

(3 Months ago)

5/4 = 1 + 1/4
where 5/4 and 1/4 are rational numbers, and 1 is integer

Like? Yes (2) | No (1)

to (3 Months ago) "Other"

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to (3 Months ago) "Other"

Please explain, assistant pipe ha ya admi ?

A barrel full of beer has 2 taps one midway, which draws a litre in 6 minutes and the other at the bottom, which draws a litre in 4 minutes. The lower tap is normally used after the level of beer in the barrel is lower than midway. The capacity of the barrel is 36 litres. A new assistant opens the lower tap when the barrel is full and draws out some beer, As a result the lower tap has been used 24 minutes before the usual time. For how long was the beer drawn out by the new assistant?
Ans 16

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(4 Months ago) "Other"

if y = log x(1+x), then x = ?

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(4 Months ago) "Other"

The price of sugar increases by 20%, by what % should a housewife reduce the consumption of sugar so that expenditure on sugar can be same as before?

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(4 Months ago)

16.66%

Let initial consumption=100 & price=100, then expenditure=100*100=10000
If new consumption=x & price=120, then for same expenditure, 120x=10000
=> x=83.33
So, % reduction=100-83.33=16.66

Like? Yes (1) | No (1)

to (4 Months ago) "Other"

the students of a class appeared for an exam which had 200 questions. Each correct answer was awarded 2 Marks and for each wrong answer one-third of a mark was deducted. two student answered all the question in it. the first student got the maximum possible marks and the second student got 175 marks less than him. find the number of questions correctly answered by the second student. 1)115 2)125 3)135 4)145 ) none of.
Please solve

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(4 Months ago)

2) 125

Maximum possible marks, 1st student got = 2*200 = 400
.'. Marks of 2nd student = 400 - 175 = 225
Let for 2nd student, correct answers=x and wrong answers=y
Then, x + y = 200 ---(i) and 2x - y/3 = 225 ---(ii)
Solving equation (i) & (ii), we get x=125, y=75
Hence, 2nd student solved 125 correct answers.

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(3 Months ago)

In a game of 80 points, A can give B 5 points and C 15 points. then how many points B can give C in a game of 60?
Devendra can you give brief Sol for this

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to (4 Months ago) "Other"

Two cars starts from point A and B to B and A respectively. They cross each other in 1.2 hour and the first car reaches A at 1 hour before the second car reaches B. If the distance between A and B is 50 km, what is the speed of the slower car? 1)20km/hr 2) 10km/hr 3)15km/hr 4)25km/hr........ Which is correct questions in both of. Please solve if any is correct please 🙏😊

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(4 Months ago)

Speed of the slower car=16.66 km/hr

Let the speed of the car starting from point A and B be a and b km/hr.
Given, car starting from B reaches A, 1 hour early => Car starting from A is slower, so we have to find 'a'
As car cross each other in 1.2 hrs => 50/(a+b) = 1.2 => a+b = 125/3 ---(i)
Time difference of cars reaching B and A = 50/a - 50/b = 1 ---(ii)
Now substituting, b=125/3 - a from eqn. (i) into (ii), we get 3a² - 425a + 6250 = 0 ---(iii)
(3a-50) (a-125) = 0
a=50/3, a=125, (Ignoring a=125 as with this speed two cars cann't cross each other in 1.2 hrs)
Therefore, speed of slower car=50/3=16.66 km/hr and faster car=25 km/hr.

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to (4 Months ago) "Other"

Two cars starts from point A and B to B and A respectively. They cross each other in 1 hour and the first car reaches A at 5/6 hour before the second car reaches B. If the distance between A and B is 50 km, what is the speed of the slower car? 1)20km/hr 2) 10km/hr 3)15km/hr 4)25km/hr

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to (4 Months ago) "Other"

Sheela, Sandhya and jyotsna can type a page in in 10, 15 and 18 minutes respectively. they decided to work together for equal time to type a document which contains 980 pages. how many pages are typed by jyotsna ? 1)280 2)275 3)245 4)350 5)none

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(4 Months ago)

3) 245

In 1 min, individually Sheela, Sandhya and Jyotsna can type 1/10, 1/15, 1/18 pages respectively.
Together in 1 min they can type 1/10 + 1/15 + 1/18 = 2/9 page.
For 980 pages time required = 980/(2/9) = 4410 min.
So, pages typed by Jyotsna in 4410 min = (1/18)*4410 = 245

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to (4 Months ago) "Other"

vimal alone can do a piece of work in 36 days. the time taken by vimal in completing 1/6th of the work equals the time taken by Gopi to complete 2/5th of the same work. in how many days can they both complete the work if they work together?

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(4 Months ago)

10 (10/17) days

Days required by Vimal=36. So Vimal can complete 1/6 of the work in (1/6)*36=6 days.
If Gopi takes 'x' days for same work, then days required for 2/5 of work=2x/5=6
=> x=15
Thus 1 day's work of Vimal & Gopi = 1/36 + 1/15 = 17/180
Hence, required days = 180/17 = 10 10/17

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to (4 Months ago) "Other"

, Q, R and S are four friends and they are working independently on a work. R can do the work in M days, whereas S can do the same work in 2M days. R started the work and worked for only 144/7 days. then, he was replaced with S, who completed the remaining work in the same time as P and Q working together would finish the entire work. the efficiency ratio of P and Q is 4:3. if P and Q are working on alternate days, with P being first, the work will finished in 41 days.

1)in how many days can R individually complete the total work?

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(4 Months ago) "Other"

P, Q, R and S are four friends and they are working independently on a work. R can do the work in M days, whereas S can do the same work in 2M days. R started the work and worked for only 144/7 days. then, he was replaced with S, who completed the remaining work in the same time as P and Q working together would finish the entire work. the efficiency ratio of P and Q is 4:3. if P and Q are working on alternate days, with P being first, the work will finished in 41 days.
1)in how many days can R individually complete the total work?

Reply Like? Yes | No

(4 Months ago)

216/7 days

Given R takes M days, so 1 day's work of R = 1/M
Similarly S takes 2M days, so 1 day's work of S = 1/(2M)
Work completed by R in 144/7 days = (1/M)*(144/7) = 144/(7M) and remaining work = 1 - 144/(7M)

Given, efficiency ratio of P and Q is 4:3.
Days required is inversely proportional to efficiency. Let P & Q can complete the work in x/4 & x/3 days respectively.
Given, P and Q are working on alternate days, with P being first, the work will finished in 41 days.
=> P works for 21 days whereas Q works for 20 days to complete the work.
=> 21*P's 1 day work + 20*Q's 1 day work = 1
21*4/x + 20*3/x = 1
=> x=144
Thus, P takes 144/4=36 days and Q takes 144/3=48 days to complete the work individually.
Now (P+Q)'s 1 day work = 1/36 + 1/48 = 7/144
.'. Together P & Q require 144/7 days = Days required by S to complete remaining work
=> (144/7)*1/(2M) = 1 - 144/(7M)
72/(7M) = (7M - 144)/7M
7M = 216
M = 216/7 = Days required by R individually to complete the work.

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to (4 Months ago) "Other"

If 36 persons are engaged on a piece of work, the work can be completed in 40 days. After 32 days, only 3/4 th of the work was completed. How many more persons are required to complete the work on time?
A)10
B)8
C)9
D)12

Reply Like? Yes (1) | No

(4 Months ago)

D)12

Work completed by 36 persons in 32 days=3/4
1 person's 1 days work = (3/4)/(32*36) = 1/1536
Now remaining work=1/4 and remaining days=40-32=8
So, required work in 1 day = (1/4)/8 = 1/32
Total persons required = (1/32)/(1/1536) = 48
Hence, additional persons = 48 - 36 = 12

Like? Yes (2) | No (1)

(4 Months ago) "Other"

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(4 Months ago) "Other"

The ratio of difference between Compound interest and simple interest at 2 year and 2.5 year is 9:17 then rate of compound interest? 1)22.22% 2)11.11% 3)18.18% 4)22.5%

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to (4 Months ago) "Other"

The ratio of difference between Compound interest and simple interest at 2 year and 2.5 year is 9:17 then rate of compound interest? 1)22.22% 2)11.11% 3)18.18% 4)22.5%

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to (4 Months ago) "Other"

A man borrows a sum of rs 96,000 at 5% p.a. interest compounded annually. At the end of one year, he repays a certain amount and he repays the balance amount of rs 70,980 at the end of the second year. What amount does he repays at the end of the first year?

Reply Like? Yes | No (1)

(4 Months ago)

Rs. 33200

Amount after 1 year = 96000*(1 + 5/100) = 100800
Let he repays Rs. x after 1 year, then amount to be paid after 2nd year=(100800 - x)*(1 + 5/100) = 70980
100800 - x = 67600
=> x=33200

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(4 Months ago) "Other"

For Today's puzzle, options 3 and 5 are same as 246.
Please check.

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(4 Months ago) "Other"

Anyone plz send me the model papers of amcat.. mail id kousalya97r@gmail.com

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(4 Months ago) "Other"

Plz send me the model papers of amcat...

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(4 Months ago) "Other"

How many ports will be allocated to a new emulator?

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(5 Months ago) "Other"

H17, B11, P79, G16, L48, ?

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