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Anchal 12 years ago

There are 45 cans out of them one is poisoned. If a person tastes very little of this he will die within 14 hours. So they decided to test with mice. Given that a mouse dies in 24 hours and you have 24 hours in all to find out the poisoned can, how many mice are required to find the poisoned can?
(a) 44
(b) 29
(c) 6
(d) 5

Reply Like? Yes (1) | No

ABHISHEK CHANDEL 12 years ago

6 mice we need. let first assign each can a unique no from 1 to 45.
now for representing 45 in binary we need 6 digit . so let take 6 mice nd assign 1 digit to each mice now taste from can to mice in binary sequence,i.e if suppose 16 no can contain poison then there corresponding, mice will be dead so we can find it easily..

Like? Yes (4) | No

SOURAV GANGULY 12 years ago

nopz i dnt think in dat way we can find it out..

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ABHISHEK CHANDEL 12 years ago

y couldnt find out can you explain.. itz the perfect way..

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mani kumar 12 years ago

let us 45 cans split into 22,23 for testing of those cans we need one mouse
than splitting the 23 cans into 11, 11 we need one mosue
this processs is going on up to single can we require 6 mouses

Like? Yes (1) | No

RAFEEK AHAMED.H 12 years ago

nice explanation ABHISHEk ....Thank u...

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Krishnendu Lakshman 12 years ago

6 mice would be required

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Anchal 12 years ago

We have an equal arms two pan balance and need to weigh objects with integral weights in the range 1 to 40 kilo grams. We have a set of standard weights and can place the weights in any pan. . (i.e) some weights can be in a pan with objects and some weights can be in the other pan. The minimum number of standard weights required is:

a. 4 b. 10 c. 5 d. 6

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narasimharao 12 years ago

4 the weighing's are 3^0, 3^1, 3^2,3^3

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Anchal 12 years ago

I didn't understand
Can you please explain it properly

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Anchal 12 years ago

A thank giving banquet at no. 2 Rictor Street has 49 guests which consisted of 6 statesmen 26 relatives and their families. At the end of the banquet 14 people shake hands with each other, some of which were between the statesmen alone, some between relatives alone and some were between the statesmen and relatives. How many hands shakes were there in total.

1. 84.50
2. 91.00
3. 98.00
4. 182.00

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Anchal 12 years ago

can anyone help in me in finding the solution of this question???

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Anchal 12 years ago

Abhishek starts to paint a fence on one day. On the second day, two more friend of Abhishek joins him. On the third day 3 more friends of him join him and so on. If the fence is completely painted this way in exactly 20 days, then find the number of ways in which 10 girls painting together can paint the fence completely. Given that every girl can paint twice as fast as Abhishek and his friends (Boys)? (Assume that the friends of Abhishek are all boys).
(a) 20
(b) 40
(c) 45
(d) 77

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bhagyashri mandlik 12 years ago

77 is the ans tell me is this correct

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sushant kumar 12 years ago

77 days will be the answer.

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Anchal 12 years ago

If f(1)=4 and f(x+y)=f(x)+f(y)+7xy+4,then f(2)+f(5)=?

Reply Like? Yes (1) | No

rohit kumar 12 years ago

ans is 125
f(1+1)=f(1)+f(1)+7*1*1+4=4+4+7*1*1+4=19=f(2)
f(2+2)=f(2)+f(2)+7*2*2+4=19+19+28+4=70=f(4)
f(5)=f(1+4)=f(1)+f(4)+7*1*4+4=4+70+7*1*4+4=106
f(2)+f(5)=125

Like? Yes (9) | No

Anchal 12 years ago

One day Eesha started 30 min late from home and reached her office 50 min late while driving 25% slower than her usual speed. How much time in min does eesha usually take to reach her office from home?

Reply Like? Yes (1) | No

Abhilash Mishra 12 years ago

60 min or 1 hr.

as,
let her usual speed be 's' and time be 't'.
then, on the day, her speed is = .75*s
and time is = t + (20/60) hr
so,
s*t = .75 s * (t+1/3)
implies t = 1 hr.

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sandhya 12 years ago

let her usual speed x and time taken for it is y
now his speed is x-(x/4)=3x/4 and time taken for it is y+20
:. x/(3x/4) = y+20/y
thrfr y =60 min

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Rashmi bharti 12 years ago

she usually takes 60 min to reach her office.
In actual Esha reached her office 20 min late due to her slow speed because she already left home 30 min late that day.
50-30=20
let her usual speed is x and her usual time taken to reach office is y.then on that very day her speed reduces by 25% i.e, her speed is 3x/4 and she takes (y+20)min
so, we get y=60 min.

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Rohan Goyal 12 years ago

Let y be the distance from home to office
Let x be the usual time taken
Let u be the usual speed
therefore new speed= u-u/4=3u/4
u=y/x.......eq1
new time x'=x+20
so 3u/4=y/x+20.......eq2
Substituting eq1 and 2
3x+60=4x
therefore, x=60 answer

Like? Yes (1) | No

Anchal 12 years ago

A snail covered 3mm in the frst sec and 4 mm each in each successive sec,for a certain number of sec.However if it had covered 1mm in the 1 st sec and 8 mm more in each successive sec for some secs, then the difference between the length of the path it would have covered during the same time and the actual path that it actually took would have been more than 6 mm but less than 30 mm.find the time for which the snail moved?

Reply Like? Yes | No

Rohan Goyal 12 years ago

4,5,6,7 seconds.....any 1 is possible

Like? Yes | No (1)

aakash 12 years ago

Is it 2 < n < 8

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Anchal 12 years ago

with explanation

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