let suresg age is x
then, 1894-x+1894-2x=3644;
after soln
3x=144;
x=48
and in 1899 suresh was 53.

let grandmothers age be x then suresh age is 2x
grandmother birth year is 1894-x
suresh birth year is 1896-2x
according to qn .
1894-x+1894-2x=3644
3x=144
x=48
year to be added = 1899-1894=5years
suresh age after 5 year is 48+5=53yrs
53years is the answer

The toys are different; The boxes are identical

If none of the boxes is to remain empty, then we can pack the toys in one of the following ways

a. 2, 2, 1
b. 3, 1, 1

Case a. Number of ways of achieving the first option 2 - 2 - 1

Two toys out of the 5 can be selected in 5C2 ways. Another 2 out of the remaining 3 can be selected in 3C2 ways and the last toy can be selected in 1C1 way.

However, as the boxes are identical, the two different ways of selecting which box holds the first two toys and which one holds the second set of two toys will look the same. Hence, we need to divide the result by 2.

Therefore, total number of ways of achieving the 2 - 2 - 1 option is = = 15 ways.

Case b. Number of ways of achieving the second option 3 - 1 - 1

Three toys out of the 5 can be selected in 5C3 ways. As the boxes are identical, the remaining two toys can go into the two identical looking boxes in only one way.

Therefore, total number of ways of getting the 3 - 1 - 1 option is 5C3 = 10 = 10 ways.

Total ways in which the 5 toys can be packed in 3 identical boxes

= number of ways of achieving Case a + number of ways of achieving Case b
= 15 + 10 = 25 ways.

3*2*2=12 factors

A can be 0 1 or 2 times in finding factors.
Similarly B can be 0 or 1 times
and C can be 0 or 1 times.
hence total no. of factors are 3*2*2=12

a^2,b^1,c^1
(2+1)*(1+1)*(1+1)=3*2*2=12
we are adding one to inform that zero is also included in the factors

257 is the ans. for this question

you will get 257 as one factor and 7^2*3 as another..
Out of these two 257 is the largest..
so ans is 257