M4maths Previous Puzzles

12 Apr 2012 Bhoomi

The date of birth of Bhoomi is 4th may 2010 at 1:00 PM. Her exact age at the time of the release of the puzzle today will be

OPtion

1) 1y-10m-07d-22h
2) 1y-11m-23d-20h
3) 1y-11m-07d-22h
4) 1y-10m-27d-12h
5) 1y-10m-17d-02h
6) 1y-11m-17d-22h
7) 1y-10m-17d-12h
8) 1y-11m-07d-02h
9) 1y-11m-07d-12h
10)none of these

Solution

2012 04 12 11
2010 05 04 13

after conversion we can write

2011 16 11 35
2010 05 04 13

1 11 07 22

Correct Option: 3 Best Solution (12)

Shiv Kumar   12 years AGO

by April 4th 2012 at 1PM it will be 1 year 11 months.

Her age on 5th April 2012 at 11AM is 1 Year 11 Month 22 Hours

from 5 th to 12th, there are seven complete days
So her age on 12th at 11AM is 1 Year 11 Months, 07 Days and 22 Hours

Like? Yes (4) | No   

Balakrishnan M   12 years AGO

Year-Month-Day-Hours
2012- 04 - 12 - 11
2010- 05 - 04 - 13
--------------------
Subtract
==> 2011 - 16 - 11 - 35
==> 2010 - 05 - 04 - 13
--------------------
1y - 11m - 07d - 22h

Like? Yes (2) | No   

prithviraj sanningannavar   12 years AGO

from 4-5-2010 to 4-4-2012 it ll be 1 year 11 months.
from 4-4-2012 1:00 pm to 12-4-2012 11:00am it will be 7 days 22 hours

Like? Yes (2) | No   

nithya   12 years AGO

4th may 2010 to 4th april 2012 is 1 year 11 months completed. then calculate the days, after 4th apr to yesterday(11th) -7 days then calculate the time, from yesterday after 1.00p.m to today 11.ooa.m - 22hrs. so ans: ,1year 11 months 7 days 22 hrs is her age.

Like? Yes (1) | No   

Rakesh Kumar Kohli   12 years AGO

Year - Month - Day - Hour
2012 - 04 - 12 - 11
2010 - 05 - 04 - 13
........................
1 - 11 - 7 - 22
........................

Like? Yes (1) | No   

raja   12 years AGO

=>(2010/5/4 at 1.00pm)-(2012/4/12 at 11.00 am)
=>(1yr/11m/7d at 22.00)
=> Option : 3

Like? Yes (1) | No   

J.P.Raja Suresh   12 years AGO

=>(2010/5/4 at 1.00pm)-(2012/4/12 at 11.00 am)
=>(1yr/11m/7d at 22.00h)
=> Option : 3

Like? Yes (1) | No   

J.P.Anitha   12 years AGO

=>(2010/5/4 at 1.00pm)-(2012/4/12 at 11.00 am)
=>(1yr/11m/7d at 22.00)
=> Option : 3

Like? Yes (1) | No   

vignesh waran A   12 years AGO

yy mm dd hh
today => 2012 - 04 - 12 11 (-)
b.day => 2010 - 05 - 04 13
------------------
01 - 11 - 07 22

Like? Yes (1) | No   

prem kumar.s   12 years AGO

2012-4-12-11
2010-5-04-13
so
1y-11m-07d-22h

Like? Yes (1) | No   

Selva Narayanan A J   12 years AGO

For 4th May 2011 at 1PM it will be 1yr,
For 4th April 2012 at 1PM it will be 1yr-11m,
For 11th April 2012 at 1PM it will be 1yr-11m-07days
Today at 11AM, the exact age will be,
1yr-11m-07days-22hrs

Like? Yes (1) | No   

Shamsu   12 years AGO

The answer is 3, because puzzle starts every day at 11. therefore, 22hr and remaing and todays day would be 7 days.

Like? Yes (1) | No   

11 Apr 2012 arrangement

Arrange 9 integers from 1 to 9 without repetition in a 3*3 size square box (total 9 small boxes) in such a manner that sum of 3 integers (S) of 3 horizontal , 3 vertical and 2 diagonal lines are same. S will be

OPtion

1) 9
2) 10
3) 12
4) 14
5) 15
6) 18
7) 21
8) 25
9) 28
10) 30

Solution

sum of all 9 integers = 45
so sum S = 45/3 = 15

Correct Option: 5 Best Solution (8)

Balakumaran N.A   12 years AGO

Its nothing but a Concept of "Magic Square"...
we can arrange by Matrix(3*3): 6 1 8
7 5 3
2 9 4

S=15...

Like? Yes (3) | No   

Datla Kanthi   12 years AGO

One way to get equal sum numbers can be arranged as below:
+---+---+---+
| 2 | 9 | 4 |
+---+---+---+
| 7 | 5 | 3 |
+---+---+---+
| 6 | 1 | 8 |
+---+---+---+
sum of 3 integers (S) of 3 horizontal , 3 vertical and 2 diagonal lines is 15 so option 5

Like? Yes (2) | No   

Balakrishnan M   12 years AGO

Sum of the 3 integers S=15,
3 horizontal lines,
6+1+8=15,7+5+3=15,2+9+4=15
3 vertical lines,
6+7+2=15,1+5+9=15,8+3+4=15
2 diagonal is
6+5+4=15,8+5+2=15.
3*3 Square is
6 1 8
7 5 3
2 9 4

Like? Yes (2) | No   

anil kumar reddy   12 years AGO

8 1 6
3 5 7
4 9 2 the sum will be 15 if you add in all direction it is a magic square

Like? Yes (1) | No   

sumanth jayam   12 years AGO

4 3 8
9 5 1
2 7 6

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Sikandar chouhan   12 years AGO

2 | 9 | 4
7 | 5 | 3
6 | 1 | 8

Like? Yes (1) | No   

Viru Sihag   12 years AGO

2 | 9 | 4
7 | 5 |3
6 | 1 | 8

Like? Yes (1) | No   

Vignesh   12 years AGO

Following are 3*3 matrix with sum of 15 in horizontal(3), vertical(3) and diagonal(2)

2 9 4
7 5 3
6 1 8

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10 Apr 2012 reminder

On diving 223^224 by 25 reminder will be

OPtion

1) 4
2) 6
3) 9
4) 12
5) 16
6) 19
7) 20
8) 21
9) 23
10) none of these

Solution

223 and 25 are co prime.
so 223^[25*{1-(1/5)}] will give 1 as reminder on dividing by 25.Here 5 is the only factor of 25.
so {223^20}^11 will give 1 as reminder on dividing by 25.
so remaining powers of 223 = 4
223 = 200+23
so we have to divide 23*23*23*23 by 25
or 529*529 by 25
or 4*4 by 25 so reminder = 16

Correct Option: 5 Best Solution (11)

Balakrishnan M   12 years AGO

(223)^224/25=(225-2)^224/25
by using binomial expansion,
(225-2)^224/25=(225^224-224*225*2+......+2^224)/25
=[(multiples of 25)+2^224]/25
=(reminder 0+2^224)/25
=(2^7)^32/25
2^7 divides 25 leaves a reminder is 3
=(3)^32/25
=(3^3)^10*3^2/25
3^3 divides 25 leaves a reminder is 2
=9*2^10/25
=(2^7*2^3*9)/25
=3*8*9/25
=27*8%25
=2*8
=16

Like? Yes (5) | No (1)  

Tijo Jose   12 years AGO

By Euler's Theorem, 223^phi(25) mod 25 = 1
phi(25) = 20
So, 223^20 mod 25 = 1
223^224 mod 25
= (223^220)mod25 * 223^4mod 25
= (223^20mod25)^11 * 223^4mod 25
= 223^4mod 25
= (223mod25)^4mod 25
= (-2)^4 mod 25
= 16 mod 25
= 16

Like? Yes (2) | No   

Sikandar chouhan   12 years AGO

223^4=2472973441
223^8=..............41
.
.
.

223^224=......................................41

so divide first term by 25 will give remainder 16
which is same for other terms ..

Like? Yes (2) | No (2)  

sumanth jayam   12 years AGO

=(223^224)%25
=(223^24)%25 as 224 % 25 = 24
Reminder will be of ( 223^ 24 ) % 25 = 16

Like? Yes (2) | No (2)  

edwin jebakumar   12 years AGO

223^224mod 25
(223^7mod 25)32
(.88*25)*32
704/25=remainder 16

Like? Yes (1) | No (1)  

Rakesh Kumar Kohli   12 years AGO

The last two digits of 223 are 23. When we will take powers of 223 we will find that after power 20 , the last two digits of 223 i.e 23 starts repeating.It means after every 20 power, the last two digits i.e 23 repeats. So power 221 will have last two digits as 23. So the last two digits of 223^224 will be the same as last two digits of 223^4 i.e 41. So when it is divided by 25, the reminder will be 16. So on dividing 223^224 by 25, reminder will be 16.

Like? Yes (2) | No (3)  

raja   12 years AGO

=> 223^224=1.047826367387420645198347729516e+526
=> 1.047826367387420645198347729516e+526\25
=> 16
=> Ans :16 (Option : 5)

Like? Yes (1) | No (3)  

J.P.Raja Suresh   12 years AGO

=> 223^224=1.047826367387420645198347729516e+526
=> 1.047826367387420645198347729516e+526\25
=> 16
=> Ans :16 (Option : 5)

Like? Yes (1) | No (3)  

Srivass   12 years AGO

(223^224)%25=(1.047826367387420645198347729516e+526)%25=16

Like? Yes (1) | No (3)  

J.P.Anitha   12 years AGO

=> 223^224=1.047826367387420645198347729516e+526
=> 1.047826367387420645198347729516e+526\25
=> 16
=> Ans :16 (Option : 5)

Like? Yes (1) | No (3)  

Trav   12 years AGO

Other than setting it up in a calculator, I have no reason. Am looking forward to reading the reason(s).

Like? Yes (1) | No (3)  

09 Apr 2012 sequence

next number of the sequence
6, 16, 52, 186, 784, .............. will be

OPtion

1) 3240
2) 3420
3) 3560
4) 3670
5) 3830
6) 3970
7) 4390
8) 4430
9) 4520
10) none of these

Solution

6
(6+10)*1 = 16
(16+10)*2 = 52
(52+10)*3 = 186
(186+10)*4 = 784
(784+10)*5 = 3970

Correct Option: 6 Best Solution (0)

06 Apr 2012 powers

4^(1/3) * 8^(4/15) * 16^(1/20) * 32^(1/15) = ?
here ^ is for powers

OPtion

1) 1
2) 2
3) 4
4) 8
5) 16
6) 2^(1/2)
7) 8^(1/2)
8) 32
9) 32^(1/2)
10) none of these

Solution

on solving we will get
2^(2/3) * 2^(12/15) * 2^(4/20) * 2^(5/15)
= 2^(2/3 + 4/5 + 1/5 + 1/3)
= 2^2 = 4

Correct Option: 3 Best Solution (16)

Dr.Dipin Singh   12 years AGO

4^(1/3) * 8^(4/15) * 16^(1/20) * 32^(1/15)
= 2^(2/3) * 2^(12/15) * 2^(4/20) * 2^(5/15)
= 2^(2/3) * 2^(4/5) * 2^(1/5) * 2^(1/3)
= 2^(2/3) * 2^(1/3)* 2^(4/5) * 2^(1/5)
= 2^1*2^1 = 2*2=4 ... option 3

Like? Yes (6) | No   

dineshv   12 years AGO

2^(2/3)*2^(12/15)*2^(4/20)*2^(5/15)

2^((2/3)+(4/5)+(1/5)+(1/3))

2^2

4

Like? Yes (3) | No   

Shiv Kumar   12 years AGO

2^(2/3)*2^(12/15)*2^(4/20)*2^(5/15)
=2^(2/3+4/5+1/5+1/3)
=2^(1+1)
=4

Like? Yes (3) | No (2)  

Viru Sihag   12 years AGO

convert all these in power of 2.
then 2^(2/3)*2^(4/5)*2^(1/5)*2^(1/3) = 2^2 = 4

Like? Yes (3) | No (2)  

Arneet   12 years AGO

4^(1/3) * 8^(4/15) * 16^(1/20) * 32^(1/15) =
2^( 2/3 +12/15 + 4/20 + 5/15) = 2^2 =4

Like? Yes (1) | No   

Suresh Varma P   12 years AGO

4 = 2^2
8 = 2^3
16 = 2^4
32 = 2^5
2^(2/3)*2^(4/5)*2^(1/5)*2^(1/3)
2^(2/3+4/5+1/5+1/3) = 2^2 = 4
Ans: option 3

Like? Yes (1) | No   

prithviraj sanningannavar   12 years AGO

4^(1/3) * 8^(4/15) * 16^(1/20) * 32^(1/15)
=2^(2/3) * 2^(12/15) * 2^(4/20) * 2^(5/15)
=2^[(2/3)+(12/15)+(4/20)+(5/15)]
=2^2
=4

Like? Yes (1) | No   

J.P.Anitha   12 years AGO

=> 4^(0.333)*8^(0.2666)*16^(0.05)*32^(0.066) => 1.58666*1.74085*1.14869*1.25701 => 3.99 (or) 4 => Ans : 4 (Option : 3)

Like? Yes (2) | No (1)  

gurumoorthy   12 years AGO

2^(2/3) * 2^(4/5) * 2^(1/5) * 2^(1/3)
2^1 * 2^1= 4

Like? Yes (1) | No   

parul mishra   12 years AGO

option (3) all the values in eq are in the base of 2
2^2^1/3=4^1/3
2^3^4/15=8^4/15
2^4^1/20=16^1/20
2^5^1/15=32^1/15
now base is same as 2 powers can be added so
2^(2/3+4/5+1/5+1/3)=2^2=4

Like? Yes (1) | No   

vignesh waran A   12 years AGO

Convert all the numbers into powers of 2 by simplification we get ans. As 4

Like? Yes (1) | No   

SEDHUPATHY S   12 years AGO

4^(1/3) * 8^(4/15) * 16^(1/20) * 32^(1/15)
-> (2*2)^(1/3)*(2*2*2)^(4/15)*(2*2*2*2)^(1/20)*(2*2*2*2*2)^(1/15)
-> (2^2)^(1/3)*(2^3)^(4/15)*(2^4)^(1/20)*(2^5)^(1/15)
-> 2^(2/3+4/5+1/5+1/3)
-> 2^2
-> ANS: 4 , option:3

Like? Yes (1) | No   

Balakrishnan M   12 years AGO

4^(1/3)*8^(4/15)*16^(1/20)*32^(1/15)
=(2^2)^(1/3)*(2^3)^(4/15)*(2^4)^(1/20)*(2^5)^(1/15)
=2^(2/3)*2^(12/15)*2^(4/20)*2^(5/15)

Like? Yes (1) | No   

Amit kumar   12 years AGO

2^(2/3)*2^(4/5)*2^(1/5)*2^(1/3)
=2^(1+1)
=2^2
=4

Like? Yes (1) | No   

Vivek Yadav   12 years AGO

convert all base into 2...
2^(2/3)*2^(4/5)*2^(1/5)*2^(1/3)=2^(2/3+4/5+1/5+1/3) =2^2=4.

Like? Yes (2) | No (1)  

sridhar reddy   12 years AGO

on simplifying
2^[(2/3)+(4/5)+(1/5)+(1/3)]
=2^2
=4

Like? Yes (2) | No (1)  

05 Apr 2012 book and notebook

Total cost of 4 books and 3 notebooks is 150 rupee. If cost of note book is more than that of book. Then possible number of ordered pair for the cost of note book and book will be
Given that the cost of note book is a multiple of 5 rupee and cost of book is more than 5 rupee.

OPtion

1) 1
2) 2
3) 3
4) 4
5) 5
6) 6
7) 7
8) 8
9) 9
10) more than 9

Solution

possible cost of note book = 25, 30, 35, 40

Correct Option: 4 Best Solution (9)

Dr.Dipin Singh   12 years AGO

possible pairs of cost of Note book and book are
Rs. 25 and Rs. 18.75
30 and 15
35 and 11.25
40 and 7.5

Like? Yes (6) | No (2)  

dineshv   12 years AGO

let cost of notebooks = N,cost of books = B
From given condition
4B + 3N = 150,
N>B,
N=5*X,B=5+Y
for the above coditions to satisfy the value of N starts from 25
There fore the values of N would be 25,30,35,40.
and values of B correspondigly would be 75/4,15,45/4,30/4

Like? Yes (5) | No (4)  

sajal jain   12 years AGO

suppose cost of one book = x
and cost of one note book = y

so,
4x + 3y = 150
but y>x and y=5*m , x = 5+n
4x=150-3y
4x=150-15*m
x = 15(10-m)/4
m can be 0,1,2,3,4,5,6,7,8,9
but at 9 x will be less then 5
and at 0,1,2,3,4 y will be less then x
so number of ordered pair for the cost of note book and book will be 4 (when m = 5,6,7,8)

Like? Yes (2) | No (3)  

Viru Sihag   12 years AGO

Let the cost of book is 5+y and cost of notebook is 5x. 4(5+y)+15x=150
then hit and trial method.

Like? Yes (2) | No (4)  

Datla Kanthi   12 years AGO

Possible values of book and notebook are
(18.75,25),
(15,30),
(11.25,35),
(7.5,40) so 4 pairs are possible

Like? Yes (1) | No (4)  

shiv vaishnav   12 years AGO

put cost of notebook = 5,10,15,20

Like? Yes (1) | No (4)  

Rakesh Kumar Kohli   12 years AGO

The possible ordered pairs for the cost of note book and book are (25,18.75),(30,15),(35,11.25),(40,7.50).
Thus possible number of ordered pair for the cst of note book and book will be 4.

Like? Yes (1) | No (4)  

Komal Jain   12 years AGO

Notebook cost is multiple of 5 and book cost is greater than 5.
And the expression is 4B+3N=150
for N=5 ... B > N same way for N=10,15,20
For N=25,B=18.75 .....(1)
For N=30,B=15 .....(2)
For N=35,B=11.25 .....(3)
For N=40,B=7.5 .....(4)
For greater values of N , B becomes less than 5
So therefore there are in all 4pairs
(N,B)={(25,18.75),(30,15),(35,11.25),(40,7.5)}

Like? Yes (1) | No (4)  

sridhar reddy   12 years AGO

notebook = n
book = b
4b+3n=150 & n>b & b>5 R.s
n is a multiple of 5
ordered pairs (notebook, book)
(25,18.75),(30,15),(35,11.25),(40,7.50) are 4

Like? Yes (1) | No (4)  

04 Apr 2012 integral pair

if 1/x + 1/y = 1/205 then possible no. of integral pairs of (x,y) will be. where x and y are positive integer.

OPtion

1) 1
2) 2
3) 3
4) 4
5) 5
6) 6
7) 7
8) 8
9) 9
10) none of these

Solution

1/x + 1/y = 1/205
on solving we get y = 205x/(x-205),
note that factor of 205 are 1, 5, 41, 205
now possible values of x for getting integral y are
205+1, 205+5, 205+41, 2*205, 6*205, 42*205, 206*205

Correct Option: 7 Best Solution (1)

Viru Sihag   12 years AGO

First of all assume that the value of x=410 and put in the equation xy/205=x+y then the value of y=410
Trick is that first multiply 205 by n+1 and divide by n is equal to integer then this is a solution. So first i take n=1 then this is an integer and then n=2 then its not an integer so its not an answer of this. n=1,n=5,n=41 these are the 5 ans.
The pair of (x,y) is (410,410),,(1230,246),,(246,1230),,(8610,210)& (210,8610) and 2 more solutions are- (206,42230) & (42230,206)

Like? Yes (5) | No (3)  

03 Apr 2012 x and y

x + 2y = 9, x and y are non negative integers.
Possible no. of solution pairs are

OPtion

1) 1
2) 2
3) 3
4) 4
5) 5
6) 6
7) 7
8) 8
9) 9
10) more than 9

Solution

Possible pairs are (1,4), (3,3), (5,2), (7,1), (9,0)

Correct Option: 5 Best Solution (26)

Shiv Kumar   12 years AGO

Possible Values of (x,y) are
1) (9,0)
2) (7,1)
3) (5,2)
4) (3,3)
5) (1,4)

Like? Yes (5) | No   

Vignesh   12 years AGO

Possible x and y values are
(x=1;y=4)
(x=3;y=3)
(x=5;y=2)
(x=7;y=1)
(x=9;y=0)

Like? Yes (4) | No   

B.Senthil Kumar   12 years AGO

possible solutions are
x=1, y=4
x=3, y=3
x=5, y=2
x=7, y=1
x=9, y=0

Like? Yes (3) | No   

Viru Sihag   12 years AGO

using hit and trial method.

Like? Yes (2) | No   

~Sandeep~   12 years AGO

Following 5 non negative integral values of y would satisfy the equation 0,1,2,3,4

Like? Yes (2) | No   

sridhar reddy   12 years AGO

given quadratic equation x+2y=9
x and y are non negative integers
if x=1=>y=4 ordered pair (1,4)
x=3=>y=3 ordered pair (3,3)
x=5=>y=2 ordered pair (5,2)
x=7=>y=1 ordered pair (7,1)
x=9=>y=0 ordered pair (9,0)
possible number of solution pairs are 5

Like? Yes (2) | No   

Datla Kanthi   12 years AGO

Possible pairs are (1,4),(3,3),(5,2),(7,1) and (9,0)

Like? Yes (1) | No   

saurabh middha   12 years AGO

only 5 pairs:
(7,1)
(5,2)
(3,3)
and
(1,4)
(9,0)

Like? Yes (1) | No   

Balakrishnan M   12 years AGO

x + 2y = 9, x and y are non negative integers.
i.e) 1≤x≥9, 0≤y≥4,
Possible no. of solution pairs are 5,
Solution Pairs are (1,4),(3,3),(5,2),(7,1)&(9,0)

Like? Yes (1) | No   

nithya   12 years AGO

(1,4) (3,3) (7,1) (9,0) (5,2)

Like? Yes (1) | No   

Gunaseelan   12 years AGO

Possible no of solution pairs are {(9,0),(1,4),(3,3),(5,2),(7,1)}

Like? Yes (1) | No   

Rakesh Kumar Kohli   12 years AGO

The possible pairs of solution are
(1,4),(3,3),(5,2),(7,1),(9,0) as shown below
1+2*4 = 9
3+2*3 = 9
5+2*2 = 9
7+2*1 = 9
9+2*0 = 9

Like? Yes (1) | No   

pathan   12 years AGO

The pairs are
(1,4)
(3,3)
(5,2)
(7,1)
(9,0)

Like? Yes (1) | No   

muthu   12 years AGO

=5 possibilities
so......option5

Like? Yes (1) | No   

sumanth jayam   12 years AGO

1,4
3,3
5,2
7,1
9,0 will be the values of x and y to satisfy the equation

Like? Yes (1) | No   

Mohammed Farook.S   12 years AGO

x+2y=9;
x=9-2y, and y=9-x/2;
so the ans is option 5)5

Like? Yes (1) | No   

parul mishra   12 years AGO

no of possible pairs will be 5.
(1,4)
(3,3)
(5,2)
(7,1)
(9,0)
all these pairs are satisfying the eqn value x+2y=9.
so option (5)

Like? Yes (1) | No   

yazar   12 years AGO

x=9, y=0
x=7, y=1
x=5, y=2
x=3, y=3
x=1, y=4

Like? Yes (1) | No   

enchantress   12 years AGO

x will be odd numbers since only then 2y divides 9-odd=odd. this can be x=1,3,5,7,9 and corresponding y values .

Like? Yes (1) | No   

Bharat Kul Ratan   12 years AGO

just put the value in x from 0 to 9. You'll get only 5 such pairs which satisfy the given equation.

Like? Yes (1) | No   

Venmathi Raj   12 years AGO

x+2y=9
1+2(4)=9
3+2(3)=9
5+2(2)=9
7+2(1)=9
9+2(0)=9
if x i even number cannot get the solution

Like? Yes (1) | No   

malar   12 years AGO

x=9,y=0
x=1,y=4
x=2,y=5
x=3,y=3
x=7,y=1

Like? Yes (1) | No   

edwin jebakumar   12 years AGO

1,4
3,3
5,2
7,1
9,0

Like? Yes (1) | No   

suryambika   12 years AGO

as (x,y) can be(9,0),(1,4),(3,3),(5,2),(7,2)
satisfies the eq. so possible no. of pairs=5

Like? Yes (1) | No   

Abinaya   12 years AGO

(1,4),(3,3),(5,2),(7,1),(9,0).

Like? Yes (1) | No   

Guruprasath   12 years AGO

To get non-negative and integral values for X and Y the possible combinations are :

(X,Y) = (7,1), (9,0), (5,2), (1,4), (3,3)

Like? Yes (1) | No   

02 Apr 2012 Complete the series

Find the next number
9, 16, 21, 24, ?

OPtion

1) 25
2) 27
3) 30
4) 26
5) 36
6) 40
7) 28
8) 32
9) 50
10) none of these

Solution

product of number where number sum is 10
1 X 9
2 X 8
3 X 7
4 X 6
5 X 5 = 25

Correct Option: 1 Best Solution (49)

Viru Sihag   12 years AGO

first of all find the common difference of these given numbers. And that common diff are 7,5,3. This is the AP of common diff -2 so the next common diff is 1 so the value is 25.

Like? Yes (7) | No   

Balakumaran N.A   12 years AGO

Differences of sequences decreasing by 7,5,3,1...
9+7 = 16;
16+5= 21;
21+3= 24;
24+1= 25;

Like? Yes (7) | No   

Jeevan   12 years AGO

9, 16, 21, 24, ?
Diff in numbers is 7,5,3,1

9+7=16
16+5=21
21+3=24
24+1=25 .... option 1

Like? Yes (5) | No   

sumanth jayam   12 years AGO

Diff between first and second is 7
Diff between second and third is 5
Diff between third and fourth is 3
and in the same way
Diff between fourth and fifth should be 1
So 9,16,21,24,25 is the right answer

Like? Yes (4) | No   

Dr. Divya   12 years AGO

Keeping the difference in numbers in decreasing order of odd numbers as 7,5,3,1

24+1=25

Like? Yes (4) | No   

Datla Kanthi   12 years AGO

Differences of numbers are in AP 7,5,3,... diff -2
son next number is 24+1 = 25

Like? Yes (3) | No   

Shiv Kumar   12 years AGO

difference between the numbers is 7,5,3,1....

So Next number will be 25

Like? Yes (3) | No   

saurabh middha   12 years AGO

16=9+7;
21=16+5;
24=21+3;
so next number 25=24+1;

Like? Yes (3) | No   

Gunaseelan   12 years AGO

9+7=16
16+5=21
21+3=24
24+1=25

Like? Yes (3) | No   

Mullaji Zubair Dawood   12 years AGO

the Difference is reducing as 7,5,3 &Then considering Common difference as 2,next difference Is 1,therefore 25 so ans.1

Like? Yes (3) | No   

Komal Jain   12 years AGO

The difference in numbers is 7 (16 -9) , 5 (21 -16), 3 (24 -21) . this way next difference will be 1 .
So, 24 + 1 = 25 is the answer

Like? Yes (3) | No   

sai naresh   12 years AGO

9+7=16
16+5=21
21+3=24
24+1=25

Like? Yes (3) | No   

sridhar reddy   12 years AGO

9
9+7=16
16+5=21
21+3=24
24+1=25

Like? Yes (3) | No   

bharatkavali   12 years AGO

has the difference between the numbers decreases in the order of 7,5,3 so the difference between the numbers must be 1 so, the answer ids 25

Like? Yes (3) | No   

B.Senthil Kumar   12 years AGO

16-9=7, 21-16=5, 24-21=3, x-24=1
so x=25

Like? Yes (3) | No   

anil kumar reddy   12 years AGO

odd numbers decreasing series difference between 9 and 16 is 7 next is 5 and so on

Like? Yes (3) | No   

Balakrishnan M   12 years AGO

9, 16, 21, 24, ?
difference betweenthe sequence is -2.
(i.e)7,5,3,1.

Like? Yes (3) | No   

raja   12 years AGO

=> 9, 16, 21, 24, ...
=> 16-9=7 ,21-16=5 , 24-21=3 , 25-24=1
=> Sequence will Be : 7 , 5 , 3 , 1,....
=> Sequence Will Be : 1 , 3 , 5 , 7.....
=> 9 , 16 , 21 , 24 , 25
=> Ans : 25 ( Option : 1 )

Like? Yes (3) | No   

sugumar   12 years AGO

9,16,21,24 so the difference is 7,5,3,1 this numbers are add to the next number24+1=25

Like? Yes (2) | No   

Vignesh   12 years AGO

In the series, every term increased by consecutive prime number in reverse order from 7.

Therefore,

9 +7 = 16
16 +5 = 21
21 +3 = 24

24 +2 = 26

Like? Yes (1) | No   

J.P.Raja Suresh   12 years AGO

=> 9, 16, 21, 24, ...
=> 16-9=7 ,21-16=5 , 24-21=3 , 25-24=1
=> Sequence will Be : 7 , 5 , 3 , 1,....
=> Sequence Will Be Reversing : 1 , 3 , 5 , 7.....
=> 9 , 16 , 21 , 24 , 25
=> Ans : 25 ( Option : 1 )

Like? Yes (2) | No (1)  

J.P.Anitha   12 years AGO

=> 9, 16, 21, 24, ...
=> 16-9=7 ,21-16=5 , 24-21=3 , 25-24=1
=> Sequence will Be : 7 , 5 , 3 , 1,....
=> Sequence Will Be : 1 , 3 , 5 , 7.....
=> 9 , 16 , 21 , 24 , 25
=> Ans : 25 ( Option : 1 )

Like? Yes (1) | No   

Mohammed Farook.S   12 years AGO

16-9=7;
21-16=5;
24-21=3;
so the above series is odd number
25-24=1;
so the ans is option 1)25

Like? Yes (1) | No   

vignesh kumar   12 years AGO

9+7=16,16+5=21,21+3=24,24+1=25 so the number is 25

Like? Yes (1) | No   

vignesh waran A   12 years AGO

Ans: 25

becoz., 9,16,21,24.25 their differences with neighbours are 7, 5, 3, 1 respectively

Like? Yes (1) | No   

Parikshit   12 years AGO

9 + 7 = 16
16 + 5 = 21
21 + 3 = 24
24 + 1 = 25

Like? Yes (1) | No   

parul mishra   12 years AGO

The following series in increasing with the interval of 7,5,3,1.
so the next term will be 25
option(1)

Like? Yes (1) | No   

sudarshan sahu   12 years AGO

add by odd number 7,5,3,1

Like? Yes (1) | No   

Harmandeep Kaur   12 years AGO

b'coz 16-9=7
21-16=5
24-21=3
25-24=1
so there is a odd integer difference b/w numbers so
answer is 1.

Like? Yes (1) | No   

Pratik Goyal   12 years AGO

the difference between first two numbers is of 7
and between the next two no. is 5
and the next two no is 3
then the difference between next two no. is 1
then final no. would be 25

Like? Yes (1) | No   

pathan   12 years AGO

The series is: +7, +5, +3, +1 ....

Like? Yes (1) | No   

vineet shirdhonkar   12 years AGO

difference b/w 9 and 16 is 7
difference b/w 16 and 21 is 5
difference b/w 21 and 24 is 3
difference b/w 24 and 25 is 1
since in each step diffecnce is decersed by 2 hence 25 is correct answer

Like? Yes (1) | No   

NOBLE RAJKUMAR   12 years AGO

its ODD number series
9+7=16,
16+5=21,
21+3=24,
24+1=25...

Like? Yes (1) | No   

Rajeev Kumar   12 years AGO

16-9=7
21-16=5
24-21=3
25-24=1
All are odd numbers with diff of two

Like? Yes (1) | No   

mayank garg   12 years AGO

there is a decrement of 2 as for eg. in 9 we add 7 that gives 16 then we add with a decrement of 2 that is we add 5 now so it will become 21 and so on....

Like? Yes (1) | No   

sajal jain   12 years AGO

9, 16, 21, 24, --

9*1, 8*2, 7*3, 6*4, --

we can make two series
one is = 9*1, 7*3, --
second is = 8*2, 6*4, --

in both series one digit is decreasing by 2 and another in increasing as 9 to 7 / 1 to 3

so another number will be 5 to 5, it means 5*5 =25

so series is 9, 16, 21, 24, 25

Like? Yes (1) | No   

Sonesh Goindani   12 years AGO

diference between the two nos is decreasing by 2 every time
9,16 - 7
16,21 - 5
21,24 - 3......next shud be 1 so add 1 to 24..=25

Like? Yes (1) | No   

M.Sakthivel   12 years AGO

the number order ll be increase by.. 7,5,3,1 so 24+1=25

Like? Yes (1) | No   

edwin jebakumar   12 years AGO

9,16,21,24,?
16-9=7
21-16=5
24-21=3
all these are odd numbers starting in reverse from 7. therefore the next difference must be 1

24+1=25

Like? Yes (1) | No   

arunraj   12 years AGO

Different b/w two no are prime no in decreasing way from 7

Like? Yes (1) | No   

anand gautam   12 years AGO

9 to 16 decrease 7 ,16to 21 dec 5 and 21to 24 dec 3 so dec by 7,5,3,and 1 so ans is 25

Like? Yes (1) | No   

mridula nahata   12 years AGO

ans : 25
9 16 21 24 25
diff= 7 5 3 1

Like? Yes (1) | No   

akhileshwar reddy g   12 years AGO

9+7=16
16+5=21
21+3=24

7-5=5-3=2 so difference will be 2
then next number will be 24+(3-2)=25

Like? Yes (1) | No   

Avinder Singh   12 years AGO

difference between two consecutive number is decreasing by 2 every time.
let see 16-9=7
21-16=5
24-21=3
so
25-24=1

Like? Yes (1) | No   

suryambika   12 years AGO

as 16-6=7, 21-16=5, 24-21=3
so x-24=1
solving this x=25

Like? Yes (1) | No   

Ayyappan   12 years AGO

Decremental of 2..
+7,+5,+3,+1

Like? Yes (1) | No   

Shubham   12 years AGO

differe between follow a series of odd number

Like? Yes (1) | No   

Bharat Kul Ratan   12 years AGO

Successive difference between numbers is 7, 5, 3, hence next term should be 1 which will lead to number 25

Like? Yes (1) | No   

Nidhi Srivastava   12 years AGO

9+7=16
16+5=21
21+3=24
24+1=25

Like? Yes (1) | No   

30 Mar 2012 Positive integer

A positive integer n less than 7000 is such that the H. C. F. of n and 7000 is 14. Total number of possible values of n are

OPtion

1) 20
3) 50
3) 80
4) 100
5) 120
6) 150
7) 200
8) 250
9) 300
10) none of these

Solution

7000 = 14 * 2^2 * 5^3
it means to get hcf as 14, 2 and 5 multiple of 14 are non possible cases
now 7000/14 = 500
7000/14*2 = 250
7000/14*5 = 100
7000/14*2*5 = 50
so possible values = 500 - 250 - 100 + 50 = 200

Correct Option: 7 Best Solution (3)

Vignesh   12 years AGO

H.C.F of n and 7000 is 14 means, values of n will divisible by 14.

So, for first 5 divisible value of 14, there is 2 possible values of n and 7000 which H.C.F is 14.
(i.e, n= 14 and n=42)

First 5 Divisible value of 14 = 2 possibles of n.
Multiply 100 on both sides,
Therefore,

5 *100 = 2 *100
First 500 divisible value of 14 = 200 possibles of n

Where 500*4 = 7000(N is lesser than 7000)

Like? Yes (4) | No   

sridhar reddy   12 years AGO

70000=7*2*2*2*5*5*5
n=7*2*x
where x is any natural number except 2 & 5
such that (n,7000)=14
7000/14=500 and n

Like? Yes (1) | No   

Datla Kanthi   12 years AGO

1 to 500 numbers multiplied with 14 we get 7000
7000 = 14*2*2*5*5*5
In 1 t0 500
Numbers divisible by 2 are 250
Numbers divisible by 2 & 5 are 100
Only by 5 are 50
possible values of n are = numbers not divisible by either 2 or 5
= 500 -(250+50) = 200 so option 7

Like? Yes (1) | No (2)