The cost of 4 pens is same as that of 1 note book. The total cost of x pens and x/2 note books is 150 rupee. The maximum possible cost of the pen will be (in rupee)
according to the given condition
x pen = x/4 note book
so x/4 + x/2 = 3x/4 note book costs 150 rupee
so cost of 1 note book = 150*4/3x = 200/x
and that of pen = 50/x
now there are x/2 note books so minimum value of x will be 2
so minimum cost of pen = 50/2 = 25
There are 2 bags. The first contains 8 white, 4 red and 6 green balls whereas second contains 6 white, 8 red and 4 black balls. One ball from both the bag is selected, then probability to get the balls of same colour will be
If white is selected from both the bags then probability = 8/18*6/18
if red is selected from both the bags then probability = 4/18*8/18
sum of these two will be the answer.
The sum of three positive real numbers x, y and z is 9. If the largest positive difference between any 2 of the 3 numbers is 5 and these 3 numbers are in arithmetic progression then the product of these 3 numbers will be
x+y+z = 9
and the three are in AP so y = 3
so x+z = 6
and z-x = 5 consider that z is the greatest and x is least number
on solving these 2 equations we get x = 1/2, y = 3, z = 11/2
Ratio of 3 positive numbers x, y and z is 2:3:4 and the ratio of 3 positive numbers p, q and r is 1:2:3. By using these 2 ratios a new ratio is formed as 13:j:31. j will be