M4maths Previous Puzzles

13 Dec 2019 Profit & Loss

Mallya bought a mobile from a shop. If he sells it at Rs. 18400 to Mukesh and earns a profit of 28%, find the price at which Mallya bought the mobile.

OPtion

1) 17375
2) 16375
3) 15375
4) 14315
5) 13375
6) 14375
7) 12375
8) 11375
9) 18375
10) None of these

Solution

CP = (18400)*100/128 = 14375

Correct Option: 6 Best Solution (5)

12 Dec 2019 Average

What is the average of all multiples of 12 lying between
424 and 530

OPtion

1) 476
2) 472
3) 470
4) 480
5) 468
6) 466
7) 464
8) 462
9) 478
10) None of these

Solution

432
444
456
468
480
492
504
516
528
Average = 4320/9 = 480

Correct Option: 4 Best Solution (7)

11 Dec 2019 Area

The ratio of length and breadth of a rectangular park is 6:3. If a squirrel running along the boundary of the park at the speed of 24 km/hr completes one round in 12 minutes, find the area of the park in square meters.

OPtion

1) 1260000
2) 1270000
3) 1280800
4) 1290000
5) 1200000
6) 1210000
7) 1280000
8) 1230000
9) 1208000
10) None of these

Solution

One round of the park is equal to the perimeter of the park.

So, by completing one round, the squirrel covers a distance equal to the perimeter of the park.

Now, Distance or perimeter = speed * time
= 24 * (12/60)
= 4.8 km or 4800 meters

Let Length = 6x and breadth = 3x

So, Perimeter: 2 (6x + 3x) = 4800
18x = 4800

x= 4800/18

So, Length = 6*(4800/18) = 1600 meters

And, Breadth = 3*(4800/18) = 800 meters

Area = Length * Breadth
= 1600 * 800
= 1280000 sq. m.

Correct Option: 7 Best Solution (1)

10 Dec 2019 Age

The present ages of A,B and C are in proportions 3:6:8. Five years ago, the sum of their ages was 70. What is the product of their present ages?

OPtion

1) 7500
2) 12960
3) 3840
4) 12096
5) 18000
6) 24000
7) 43740
8) 42000
9) 19440
10) None of these

Solution

Answer: 18000 years

Five years ago sum of Ages of A, B and C = 70
Five years later i.e. sum of current ages of A, B and C =
70 + 3*5 = 85

Present Age of A = 85*3/(3+6+8) = 15 years

Present Age of B = 85*6/(3+6+8) = 30 years
Present Age of C = 85*8/(3+6+8) = 40 years

Product of their ages = 18000

Option 4)

Correct Option: 5 Best Solution (5)

09 Dec 2019 Probability

The tickets numbered from 99 to 116 are mixed up and then a ticket is drawn at random. What is the probability that the ticket has a number which is a multiple of 3 or 5?

OPtion

1) 7/16
2) 9/16
3) 7/17
4) 8/17
5) 9/17
6) 10/17
7) 1/2
8) 8/18
9) 7/18
10) None of these

Solution

Multiple of 3: 99, 102, 105, 108, 111, 114
Count = 6
Multiples of 5 which are not multiples of 3 = 100, 110, 115
Count = 3
Total = 6+3 = 9

Total numbers between 99 and 116 = 18

Probability = 9/18 = 1/2

Correct Option: 7 Best Solution (2)

06 Dec 2019 Probability

What is the probability of picking up an alphabet card from a 52 card deck?

OPtion

1) 11/52
2) 3/13
3) 5/13
4) 7/13
5) 6/13
6) 4/13
7) 3/13
8) 2/13
9) 1/13
10) None of these

Solution

Alphabet cards are A, J, Q and K
Each of this would have 4 suites
So total number of alphabet cards =16
Probability = 16/52 = 4/13

Correct Option: 6 Best Solution (1)

05 Dec 2019 Solve

Given,
3+9+5 = 43
4+6+7 = 71
1+6+5 = 32
then
4+8+3 = ?

OPtion

1) 21
2) 23
3) 31
4) 33
5) 41
6) 43
7) 51
8) 35
9) 39
10) None of these

Solution

3+9+5 = 3^2 + 9 + 5^2 = 43
4+6+7 = 4^2 + 6 + 7^2 = 71
1+6+5 = 1^2 + 6 + 5^2 = 32

Then
4+8+3 = 4^2 + 8 +3^2 = 33

Correct Option: 4 Best Solution (0)

04 Dec 2019 Code Decode

If
GABBAR = 126
MOGAMBO = 195
SHAKAAL = 228

KAANCHA = ?

OPtion

1) 281
2) 285
3) 289
4) 193
5) 119
6) 211
7) 11
8) 141
9) 111
10) None of these

Solution

A=1, B=2, C=3....Z=26

Multiplication of value of first alphabet and last letter of each alphabet

So for KAANCHA
=> K = 11, A =1
=> 11x1 = 11

Correct Option: 7 Best Solution (2)

03 Dec 2019 Arithmetic

The sum of squares of three successive integers is 6629. Sum of these integers is?

OPtion

1) 121
2) 122
3) 123
4) 131
5) 113
6) 103
7) 102
8) 101
9) 141
10) None of these

Solution

(a-1)^2 + a^2 + (a+1)^2 = 6629
=> a^2 -2a + 1 + a^2 + a^2 + 2a + 1 = 6629
=> 3a^2 + 2 = 6629
=> a^2 = (20174-2)/3 = 2209
=> a = 47
So the 3 numbers are 46, 47 and 48 and their sum is 141

Correct Option: 9 Best Solution (3)

02 Dec 2019 Missing Number

Find the missing number:

17, 31, 65, 127, 257, ?

OPtion

1) 551
2) 557
3) 537
4) 531
5) 521
6) 511
7) 517
8) 524
9) 527
10) None of these

Solution

Each number is twice the previous one with 3 added or subtracted alternatively.

Correct Option: 6 Best Solution (0)