A mixture contains sugar solution and colored water in the ratio 7 : 9. If 13 liters of colored water is added to the mixture, the ratio becomes 4 : 7. Find the initial quantity of sugar solution in the given mixture (in liters).
The initial ratio is 7 : 9.
Let ‘k’ be the common ratio.
=> Initial quantity of sugar solution = 7 k
=> Initial quantity of colored water = 9 k
=> Final quantity of sugar solution = 7 k
=> Final quantity of colored water = 9 k + 13
Final ratio = 7 k : 9 k + 13 = 4 : 7
=> k = 4
Therefore, initial quantity of sugar solution in the given mixture (in liters) = 7 k = 28 liter
A is 7 years older than B who is two times as old as C. The total of the ages of A, B and C is 222 years. What is the value when the age of B is multiplied to the difference between ages of A and C ?
The present age of a brother is 6 years more than four times the age of his sister. Six years hence, brother’s age will be four years more than thrice the age of the sister. Find the present age of the brother.
Let the sister’s present age be ‘n’ years.
=> brother’s present age = (4n + 6) years
So, according to the question
(4n + 6 + 6) = 3 (n + 6) + 4
=> 4n + 12 = 3n + 22
=> n = 10
Hence, brother’s present age = (4n + 6) = 46 years