Total no. of methods for selecting 2 letters out of 4 which has to be posted correctly = 4*3/2*1 = 6
No. of methods in which remaining 2 letters are posted wrongly is 1 only.
Hence total methods = 6*1 = 6
Let the numbers are x and y
According to the given conditions
(1/x) + (1/y) = 0.45
And (1/x2) + (1/y2) = 0.1025
On solving these two equations , we get the two values 4 and 5
No. of methods for selecting 6 cards out of 52 are 52*51*50*49*48*47/6*5*4*3*2*1
Similarly no. of methods for selecting 2 cards out of 48 after selecting 4 kings are
48*47/2*1
Hence probability is (48*47/2*1)/( 52*51*50*49*48*47/6*5*4*3*2*1)
= 3/54145
6 boys and 8 men get a total wage of Rs 8000 in 4 days. 8 boys and 6 men get a total of Rs 6000 in 3 days.
The efficiency ratio of boy and a man respectively?
The upper and lower part radius of a bucket is 30 cm. and 20 cm. Its height is 60 cm.
How much water can be filled in the bucket ?
It is given that: 1 litre = 1000 cm.^3
On increasing the slant sides of the bucket, a cone can be obtained, whose height is obtained by the formula h/(h-60) = 30/20
On solving h = 180
Think that: two cones can be formed by increasing the slant height, their radii and heights are 30 cm.,
20 cm. and 180 cm., 120 cm.
Volume of the cone is πr^2/3
Therefore volume of the bucket is π(30)^2*180/3 – π(20)^2*120/3
= 38000π cm.^3
= 38π litre
Original price of the object = 95/1.2
On selling the object in 75 rupee amount received = 75/(95/1.2)
= 94.74 %
Hence % loss = (100 – 94.74) % = 5.26 %