M4maths Previous Puzzles

28 Feb 2020 Probability

In a class, there are 20 males and 15 females. Three students are selected at random. The probability that 1 female and 2 males are selected, is:

OPtion

1) 21/47
2) 22/25
3) 19/46
4) 23/45
5) 21/44
6) 19/49
7) 20/47
8) 53/60
9) 42/92
10) None of these

Solution

Total Outcomes = 35C3 = 6545

Positive Outcome = 20C2 * 15C1 = 2850
Probability =
570/1309

Correct Option: 10 Best Solution (0)

27 Feb 2020 Permutation

In how many ways a team, consisting of 5 boys and 6 girls can be formed from 8 boys and 10 girls?

OPtion

1) 11160
2) 11260
3) 11360
4) 11460
5) 11560
6) 11660
7) 11700
8) 11860
9) 11760
10) None of these

Solution

Required number of ways = (8C5 x 10C6)
= (8C3 x 10C4)
= 11760.

Correct Option: 9 Best Solution (3)

26 Feb 2020 Partnership

Amar, Akbar and Anthony jointly thought of engaging themselves in a business venture. It was agreed that Amar would invest Rs. 6500 for 6 months, Akbar, Rs. 8400 for 5 months and Anthony, Rs. 10,000 for 3 months. Amar wants to be the working member for which, he was to receive 5% of the profits. The profit earned was Rs. 7400. Calculate the share of Akbar in the profit.

OPtion

1) 2280
2) 2820
3) 2630
4) 2840
5) 2660
6) 2800
7) 2880
8) 2440
9) 2580
10) None of these

Solution

For managing, Amar received = 5% of Rs. 7400 = Rs. 370.

Balance = Rs. (7400 - 370) = Rs. 7030.

Ratio of their investments = (6500 x 6) : (8400 x 5) : (10000 x 3)

= 39000 : 42000 : 30000

= 13 : 14 : 10

Akbar's share = Rs. 7030 x (14/37) = Rs. 2660.

Correct Option: 5 Best Solution (3)

25 Feb 2020 RANK of the word

Rank of the word FEBRUARY in the dictionary of words formed by the letters of the word FEBRUARY?

OPtion

1) 8361
2) 8365
3) 8362
4) 8363
5) 8364
6) 8360
7) 8359
8) 8358
9) 8366
10) None of these

Solution

7560 + 720 + 60 + 12 + 12 + 0 + 0 + 0 + 1 = 8365

Correct Option: 2 Best Solution (5)

24 Feb 2020 Series

Find the next term of the series: 8, 20, 38, 62, 92

OPtion

1) 108
2) 112
3) 118
4) 124
5) 126
6) 128
7) 132
8) 136
9) 138
10) None of these

Solution

Series is formed with following formula:
nth term = (n+1)^3 - n^3 + 1
So 6th term = (6+1)^3 - 6^3 + 1 = 128

Correct Option: 6 Best Solution (4)

21 Feb 2020 Prime Number

What is the product of two largest three digit prime numbers which have 3 in their unit place?
Note: Two largest = Largest and second largest

OPtion

1) 936733
2) 936719
3) 936729
4) 936739
5) 936749
6) 936769
7) 936799
8) 936789
9) 936779
10) None of these

Solution

Two largest three digit prime numbers with 3 at unit place are 983 and 953
953 x 983 = 936799

Correct Option: 7 Best Solution (0)

20 Feb 2020 Profit and Loss

888 Oranges are bought for Rs. 2424 and sold at the rate of Rs. 18 per half dozen. The percentage of profit or loss is:

OPtion

1) 13.89 % Profit
2) 12.89 % Loss
3) 11.89 % Profit
4) 10.89 % Profit
5) 9.09 % Profit
6) 8.89 % Profit
7) 7.89 % Profit
8) 9.89 % Profit
9) 5.89 % Profit
10) None of these

Solution

Cost of 1 Orange = 2424/888 = 2.73
Selling price of 1 Orange = 18/6 = Rs. 3

As SP > CP so its profit
So Profit % = (3.00 - 2.73 )*100/2.73 = 9. 89%

Option 8)

Correct Option: 8 Best Solution (4)

19 Feb 2020 Stocks

The market value of a 8% stock, in which an income of Rs. 660 is derived by investing Rs. 2200, brokerage being 3/4 %, is:

OPtion

1) 25.00
2) 25.75
3) 25.95
4) 25.25
5) 26.25
6) 25.92
7) 26.67
8) 26.46
9) 27.62
10) None of these

Solution

For an income of Rs. 660, investment = Rs. 2200

For an income of Rs. 8, investment = Rs. (2200/660) * 8 = 26.67
For a Rs. 100 stock, investment = Rs. 26.67

Market value of Rs. 100 stock = Rs. 26.67 - 0.75 = Rs. 25.92

Correct Option: 6 Best Solution (0)

18 Feb 2020 Divisor

What should be added to 664352
so that it is exactly divisible by 243?

OPtion

1) 11
2) 12
3) 10
4) 13
5) 14
6) 233
7) 231
8) 234
9) 235
10) None of these

Solution

Dividing 664352 with 243 we get 2733 as quotient and 233 as reminder.
243-233 = 10

Correct Option: 3 Best Solution (2)

17 Feb 2020 Average

The average of Pappu's marks in 6 subjects is 44. If his average in five subjects excluding Maths is 49, how many marks he obtained in Maths?

OPtion

1) 10
2) 20
3) 30
4) 40
5) 12
6) 21
7) 19
8) 27
9) 39
10) None of these

Solution

Total Marks Obtained in 6 subjects= 6*44
Marks Obtained in 5 subjects = 5*49

Marks of maths = 19

Correct Option: 7 Best Solution (2)