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Solved Question (6040) UnSolved Question (153842)
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(#M40033886) SELF QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

Calculate remainder when (10!+111) is divided by 143??

SONU GUPTA (6 years ago)
Unsolved
Is this Puzzle helpful?   (6)   (2) Submit Your Solution Number System

(#M40033885) SELF QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

The sum of all four-digit numbers without repetition using 3, 4, 5, 7 is ... .
a. 1111 (3! + 4! + 5! + 7!)
b. 1111 (3 + 4 + 5 + 7)
c. 4444 (3 + 4 + 5 + 7)
d. 5555 (3! + 4! + 5! + 7!)
e. 1111 (3 + 4 + 5 + 7) (3!)
(need explanation pls)

SONU GUPTA (6 years ago)
Unsolved Read Solution (1)
Is this Puzzle helpful?   (0)   (0) Submit Your Solution Area and Volume
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(#M40033884) SELF QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

If length of a body is increasing gradually 5cm in every 10 minute and if the length of the body is 10 m at 2 pm. then what will be its true length at 10 am morning?

SONU GUPTA (6 years ago)
Unsolved Read Solution (1)
Is this Puzzle helpful?   (3)   (1) Submit Your Solution Time and Work

(#M40033883) SELF QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

A person leaves his home at a time when hour hand is between 4-5 and minute hand between 5-6, and when he returns after some time, the hands exchanged their positions. What time did he leave at?

SONU GUPTA (6 years ago)
Unsolved
Is this Puzzle helpful?   (0)   (0) Submit Your Solution Time and Work

(#M40033882) SELF QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

Find the number of zeroes in 100^1! *99^2! *98^3! *..... 1^100

SONU GUPTA (6 years ago)
Unsolved
Is this Puzzle helpful?   (0)   (3) Submit Your Solution Sequence and Series

(#M40033881) SELF QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

Urn A contains 3 red and 2 white marbles, Urn B contains 2 red and 5 white, an Urn is selected at random, a marble is drawn and put into the other Urn, then a marble is drawn from the second Urn,, probability that both marbles drawn are of same colour is ????

SONU GUPTA (6 years ago)
Unsolved Read Solution (3)
Is this Puzzle helpful?   (0)   (2) Submit Your Solution Probability

(#M40033880) SELF QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

A can solve a problem is 6/7 and B solving the problem is 3/14. Assuming two events 'A can solve the problem' and 'B can solve the problem' r independent,,, probability that only one can solve the problem
Option
1. 3/28
2. 5/28
3. 9/28

SONU GUPTA (6 years ago)
Unsolved
Is this Puzzle helpful?   (0)   (0) Submit Your Solution Probability

(#M40033879) SELF QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

Each face of a cubical dice is numbered with a distinct no from among the first six odd no, such that the sum of the two no on any pair of opposite sides is 12, if ten such dices r thrown simultaneously, then find the probability that sum of no that turn up is exactly 55

SONU GUPTA (6 years ago)
Unsolved
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(#M40033878) SELF QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

What is the max. Possible integer value of p if
7*8*9*.........*135=n*720^p

1. 30
2. 31
3. 32
4. 33

SONU GUPTA (6 years ago)
Unsolved
Is this Puzzle helpful?   (0)   (0) Submit Your Solution Probability

(#M40033877) SELF QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

If s1= {1,2,3,4,.....,23} & s2={207,208,209,210,.....,691}, how many elements of the set s2 are divisible by at least four distinct prime numbers that are elements of the set s1?

1.9
2.8
3.11
4.12

SONU GUPTA (6 years ago)
Unsolved
Is this Puzzle helpful?   (2)   (1) Submit Your Solution Permutation and Combination
Keep an EYE (0)Interview Experience (245)
Solved Question (6040) UnSolved Question (153842)
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Challenger of the Day

AYAN PAUL
AYAN PAUL
India
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Time: 00:00:39
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Maths Quotes

How many times can you subtract 7 from 83, and what is left afterwards? You can subtract it as many times as you want, and it leaves 76 every time.

Unknown

The more you know, the less sure you are

Voltaire

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Vipul Chavan 5 Months ago

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I must recommend this website for placement preparations.

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