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Placement Papers with Solutions

(#M40039110) SELF QUESTION integration Keep an EYE

integration of
2x^12 + 5x^9/(x^5 + x^3 +1)

Akanksha Mishra (11 years ago)

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(#M40038496) SELF QUESTION intregation Keep an EYE

slove it
intregation of (cos5x+ cos4x )/(1 - 2cos2x)

Akanksha Mishra (11 years ago)

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(#M40037963) SELF QUESTION Keep an EYE

please slove it as early as possible
x^1/2 + y = 7
x + y^1/2 = 11

prove that x = 9 and y = 4

Akanksha Mishra (11 years ago)

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(#M40037835) MATHS QUESTION Slope Keep an EYE

Find the maximum slope of the curve
f(x) = 2x + 3x^2 - x^3 - 27

Asked In Maths Akanksha Mishra (11 years ago)

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(#M40037438) MATHS QUESTION logic Keep an EYE

what is the definition of infinitive related to maths?????

Asked In maths Akanksha Mishra (11 years ago)

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(#M40034069) SELF QUESTION Codded language Keep an EYE

codded language
NIDHI = 38
SHANKAR= 30
NANDINI= 59
then:
ANKITA = ?

Akanksha Mishra (11 years ago)

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(#M40033112) OTHERS QUESTION Information Keep an EYE

can someone suggest me.. how can I get the question of Last Week which had asked in Today Puzzle?

Solution

Dear Akanksha Mishra,

Kindly don't get confused between our "Discussion Board" and "Placement Puzzles" section.

In "Placement Puzzles" section, post your questions and we will provide you the answers immediately whereas discuss your issues and problems with your fellow mates in our "Discussion Board" segment.

Don't mix the two, because sometimes it become little difficult for us to answer your questions on time in the puzzle section.

Regard
Team M4maths.

Like manish sir answer on facebook.

Asked In Others Akanksha Mishra (11 years ago)

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(#M40032924) SELF QUESTION Trigonometry Keep an EYE

Prove that :
tan70 = tan20 + 2tan50

Akanksha Mishra (11 years ago)

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(#M40032912) SELF QUESTION Combination Keep an EYE

Find the number of 4- letter words,that can be formed from the letters of the word "ALLAHABAD"

Akanksha Mishra (11 years ago)

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(#M40032911) SELF QUESTION Permutations Keep an EYE

There are n person sitting round a table
find the number of different ways in which 3 person can be selected so that no two are neighbors...
Answer hint : 1/6*n(n-4)(n-5)

Akanksha Mishra (11 years ago)

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