Akanksha Mishra   10 years AGO

Given;
ARUN = 62
MOHIT = 75
UDITA = 65

Firstly find the position of letters;
A(1),B(2),C(3)...................X(24),Y(25),Z(26)


1] ARUN = A(1) + R(18) + U(21) + N(14)
ARUN = 54
Total no of letters of ARUN = 4
Multiply 2 with the no of letters = 4*2 = 8
ARUN = 54 + 8 = 62


2] MOHIT = M(13) + O(15) + H(8) + I(9) + T(20)
MOHIT = 65
Total no of letters of MOHIT = 5
Multiply 2 with the number of letters = 5*2 =10
SO add 10
MOHIT = 65 + 10 = 75

Similarly SoLve NIRAJ;

4] NIRAJ = N(14) + I(9) + R(18) + A(1) + J(10)
NIRAJ = 52
Total no of letters of NIRAJ = 5
Multiply 2 with the number of letters = 5*2 =10
SO add 10

NIRAJ = 52 + 10 = 62
SO answer will option 5

Like? Yes (53) | No (4)  

Dr.Dipin Singh   10 years AGO

ARUN = 62.....4 letters....1+8+21+14+4*2=62
MOHIT = 75
UDITA = 65
Then
NIRAJ =14+9+18+1+10+5*2=62 as there are 5 letters.

Like? Yes (6) | No (3)  

Snehasis   10 years AGO

ARUN = 1+8+21+14 = 54
Now, ARUN has 4 characters therefore 4*2=8
Then, 54 + 8 = 62
Similarly,
MOHIT = 13+15+8+9+20 = 65
Now, MOHIT has 5 characters therefore 5*2=10
Then, 65 + 10 = 75
Likewise,
UDITA = 21 + 4 + 9 + 20 + 1 = 55
Now, again UDITA has 5 characters therefore 5*2 = 10
Then, 55 + 10 =65

So, for NIRAJ we will have,
14 + 9 + 18 + 1 + 10 = 52
and, also NIRAJ had 5 characters therefore 5*2=10
Therefore the required answer is,
NIRAJ = 52 + 10 = 62

Like? Yes (6) | No (3)  

rajesh   10 years AGO

it is the best solution

Like? Yes (1) | No   

M.Sindhu Priya   10 years AGO

according to allocation of 26 numbers in alphatets.
arun=1+18+21+14=54,here 4 letters so *2 for each leteert will get 8 total 54+8=62;
mohit =13+15+8+9+20=65 and +10 =75;
udita =21+4+9+20+1=55 and add +10=65;
from this niraj=14+9+18+1+10=52 and +10 =62

Like? Yes (1) | No   

khushboo   10 years AGO

if character of name is one then add 2 to sum of character of name
so for 5 character add 10 to total no of character of name
if we take A=1,B=2,C=3......soon.
A+R+U+N=54
M+O+H+I+T=65
then N+I+R+A+J=52
then add 10+52=62

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srinivetha   10 years AGO

arun=1+18+21+4=54+twice the number of letters=54+8=62
mohit=13+158+9+20=65+twice the number of letters=75
udita=21+4+9+20+1=55+twice the number of letters=65
niraj=14+9+18+1+10=52+twice the number of letters=62

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Kaustubh karekar   10 years AGO

the sequence is
n=14, i=9, r=18, a=1,j=10
and no of letters in the name=5
so, 5*2=10
so the sequence is
14+9+18+1+10 =52*10=62

Like? Yes (1) | No   

TRIMURTULU   10 years AGO

Arrange english alphabets with corresponding number system,like
A1,B2,C3,D4,E5,F6,G7,H8,I9,J10,K11,L12,M13,N14,O15,P16,Q17,R18,S19,T20,U21,V22,W23,X24,Y25,Z26
ARUN=(1+18+21+14)+(2*NO.OF LETTERS IN WORD"ARUN")=62
MOHIT=(13+15+08+9+20)+(2*NO.OF LETTERS IN WORD"MOHIT")=75
UDITA=(21+4+9+20+1)+(2*NO.OF LETTERS IN WORD"UDITA")=65
THEN
NIRAJ=(14+9+18+1+10)+(2*NO.OF LETTERS IN WORD"NIRAJ")=62

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sravani   10 years AGO

arun=1+18+21+14=54+(2*4=8)=62 no.of letters in arun=4.
mohit=13+15+8+9+20=65
65+2(5=m,o,h,i,t)=75
uditha=21+4+9+20+1=55
55+2(5)=65so niraj=14+9+18+1+10=52
52+2(5)=62

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K.SASIBENINA   10 years AGO

because option 5 satisfies the condition

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ananthavalli   10 years AGO

N+I+R+A+J=14+9+18+1+10=52+10=62

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Vinay Sipani    10 years AGO

Let A=1 , B=2 , C=3 ... Z=26

ARUN = (A + R + U + N) + 2*(No. Of letters)
= 54 + 8 = 62

MOHIT = (M + O + H + I + T) + 2*(no. Of letters)
= 65 + 10 = 75

UDITA = (U + D + I + T + A) + 2*(No of letters)
= 55 + 10 = 65

=>NIRAJ = (N + I + R + A + J) + 10
= 52 + 10 = 62

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Sajal Garg   10 years AGO

A(1), B(2), C(3), D(4), E(5), F(6), G(7), H(8), I(9), J(10), K(11), L(12), M(13), N(14), O(15), P(16), Q(17), R(18), S(19), T(20), U(21), V(22), W(23), X(24), Y(25), Z(26)
ARUN=(1+18+21+14)+(no.ofalphabet*2)=54+(4*2)=62
MOHIT=(13+15+8+9+20)+(no.ofalphabet*2)=65+(5*2)=75
UDITA=(21+4+9+20+1)+(no.ofalphabet*2)=55+(5*2)=65
NIRAJ=(14+9+18+1+10)+(no.ofalphabet*2)=52+(5*2)=62

Answer= option 5 (62)

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imran   10 years AGO

Ans is 62

In ARUN, A=01; R=18; U=21; N=14;
Total=54. but take 54+(2*4)=62
4 is taken because ARUN has 4 characters. so add (2*4)

Similarly
for MOHIT, 13+15+8+9+20=55
and 55+(2*5)=65
Since MOHIT has 5 characters, add (2*5)

for NIRAJ=14+9+18+1+10=52
then 52+(2*5)=62

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Praveen Kumar Devendran   10 years AGO

The most useful tool is a substitution cipher where each letter of the alphabet is represented by a number which corresponds to that letter's position in the alphabet. In simplest terms, this can be written as A=1, B=2 ... Z=26. Since A is the first letter of the alphabet, it is represented by the number 1. B, the second letter, is represented by 2. Z, the last of the 26 letters in the alphabet, is represented by 26.
A+R+U+N = 1+18+21+14 = 54
total letter in the word is 4 by multipy the letter in 2 and will get 8 and adding the multiplied letter value to the summed value of letter will get 62
and similarly we get all the thing

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Parthi Smith   10 years AGO

A+R+U+N=1+18+21+14=54+(NO.of letters*2)=62
similarly
N+I+R+A+J=62

Like? Yes (1) | No (1)  

jayabharathy   10 years AGO

a=1,b=2,c=3,....z=26
(A+R+U+N)+num of letters *2
(1+21+18+14)=54+(4*2)
=62
so that NIRAJ
(14+9+18+1+10)+(5*2)=62

Like? Yes (1) | No (1)  

karthik hariharan   10 years AGO

n=14
i=9
r=18
a=1
j=10

14+9+18+1+10=52....
niraj is a5 letter word 5*2=10
52+10=62
so 5th option

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arun prakash singh   10 years AGO

niraj= 62

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Devendra Marghade   10 years AGO

If letters A,B,C,....,Z are numbered as 1,2,3,..,26 respectively
Coding=Sum of the letters+2(Number of letters in the word)
ARUN=(1+18+21+14)+2(4)=54+8=62
MOHIT=(13+15+8+9+20)+2(5)=65+10=75
UDITA=(21+4+9+20+1)+2(5)=55+10=65
NIRAJ=(14+9+18+1+10)+2(5)=52+10=62

Like? Yes (2) | No (3)  

Rajasekhar Reddy   10 years AGO

A-1,B-2,...............Z-26
NIRAJ = N+I+R+A+J+(2*NUMBER OF LETTERS) = 62

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nilu kumari   10 years AGO

WE ARE TAKING THE POSITIONS OF THE LETTERS IN THE ALPHABET.
ARUN = 1+18+21+14 + 2*no. of letters in ARUN
= 54+2*4
= 54+8
= 62
MOHIT =13+15+8+9+20 + 2*no. of letters in MOHIT
=65+2*5
=65+10
=75
UDITA =21+4+9+20+1 +2*no. of letters in UDITA
=55+2*5
=65
NOW FOR NIRAJ
NIRAJ =14+9+18+1+10 + 2* no. of letters in NIRAJ
=52 + 2*5
=62

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Priyanka   10 years AGO

ADD POSITION OF ALL THE ALPHABETS+10 GIVES THE ANSWER.SO THE ANSWER FOR NIRAJ IS 52+10=62.

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Lavankumar Reddy   10 years AGO

A=1,B=2,C=3,D=4,E=5,F=6,G=7,H=8,I=9,J=10, K=11,L=12,M=13,N=14,O=15,P=16,Q=17,R=18,S=19,T=20,U=21,V=22,W=23,X=24,Y=25,Z=26.

ARUN = 1+18+21+14 = 54+2*4 (count of Letters) =54+8=62
MOHIT = 13+15+8+9+20 = 65 + 2*5 = 65+10 = 75
UDITA = 21+4+9+20+1 = 55 + 2*5 = 55+10 = 65

NIRAJ = 14+9+18+1+10 = 52 + 2*5 = 52+10 = 62

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Varunraj Reddy   10 years AGO

ARUN=1+18+21+14=54
54+(4*2)=62

MOHIT=13+15+8+9+20=65
65+(5*2)=75
..........

Similarly,
NIRAJ=14+9+18+1+10=52
52+(2*5)=62 option 5)

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K Venkata Subba Rao   10 years AGO

ARUN=54+(4*2) /*4 CHAR'S*/==> 62
MOHIT=65+5*2=75
UDITA=55+5*2=65
NIRAJ=52+5*2=62

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SONU GUPTA   10 years AGO

ARUN=(1+18+21+14)=54+4*2=62;
MOHIT=(13+15+8+9+20)=65+5*2=75
then
NIRAJ=(14+9+18+1+10)=52+5*2=62

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khotha sireesha   10 years AGO

For ARUN = 1+18+21+14 = 54+(letters are four so 4*2=62).
MOHIT = 13+15+8+9+20 = 65+(5letters*2=10)=75
UDITA= 21+4+9+20 = 55+(5letter*2=10)=65
so ANSWER IS
NIRAJ = 14+9+18+1+10=52+(5letters*2=10)=62

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achyuth   10 years AGO

ARUN=1+18+21+14=54+8=62.
.....
....
NIRAJ=14+9+18+1+10=52+10(LETTERS*2)=62
ANS=62
OPT=5

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SID PRASANTH KUMAR   10 years AGO

mohit=13+15+8+9+20=65+10=75
14+9+18+1+10=52+10=62

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Murugan D   10 years AGO

answer is 4
Arun=54+8=62
mohit=65+10=75
udita=55+10=65
niraj=52+10=62
so the answer is 62(option :5)

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Sudipta Mukherjee   10 years AGO

position wise addition + (5*2)=52+10=62

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neeraj pandey   10 years AGO

sum of al letter and +10

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soundar   10 years AGO

sum all alphabet position's value... then add 8 to 4 digit name.... if the name is 5 digit add 10...

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Chithra   10 years AGO

NIRAJ=14+9+18+1+10+10=62

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Sapan Suman   10 years AGO

sum of all alphabet position value +10

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ANUP KUMAR   10 years AGO

ARUN=1+18+21+14=54+2*(NO. OF LETTERS)=54+2*4=62
MOHIT=13+15+8+9+20=65+2*5=75
UDITA=21+4+9+20+1=55+2*5=65
NIRAJ=14+9+18+1+10=52+2*5=62

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Komala.G   10 years AGO

Option 5
A(1) B(2) C(3) D(4) E(5) F(6) G(7) H(8) I(9) J(10) K(11) L(12) M(13) N(14) O(15) P(16) Q(17) R(18) S(19) T(20) U(21) V(22) W(23) X(24) Y(25) Z(26)
For every letter in a word add 2
A(1)+R(18)+U(21)+N(14) = 54+8 = 62 ARUN
M(13)+O(15)+H(8)+I(9)+T(20) = 65+10 = 75 MOHIT
U(21)+D(4)+I(9)+T(20)+A(1) = 55+10 = 65 UDITA
Similarly
N(14)+I(9)+R(18)+A(1)+J(10) = 52+10 = 62 NIRAJ

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priyanka   10 years AGO

13+9+17+1+10=62

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MD SOHAIL AKHTER   10 years AGO

n=14,i=9,r=18,a=1,j=10
niraj=14+9+18+1+10+2*no.of letters (i.e 5)= 62

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Inderjeet Singh   10 years AGO

i used a as x and b as x+1 and so on....
and using arun =65
i found out x=3
then i put x=3
x + x+17 +x+20 +x+13 = NIRAJ which comes out 62

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sivaji ragala   10 years AGO

ARUN=1+18+21+14=54+8(IT IS FOUR LETTER WORD SO ADD 8 i.e(4*2))
MOHIT=13+15+8+9+20=65+10(IT IS five LETTER WORD SO ADD 10 i.e(5*2))
UDITA=21+4+9+20+1=55+10(IT IS five LETTER WORD SO ADD 10 i.e(5*2))
NIRAJ=14+9+18+1+10=52+10=62(IT IS five LETTER WORD SO ADD 10 i.e(5*2))

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sowmya   10 years AGO

ans is 62

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