After 5 years a man\'s age will be three times his son\'s age and 5 years ago he was seven times as

Akanksha Mishra   10 years AGO

Consider the age of father in present = x year
Consider the age of father in present = y year

after five year age of father will be = (x+5) year
after five year age of father will be = (y+5) year

five year ago age of father = (x - 5)year
five year ago age of son = (y - 5)year

according to question;
5 years a man's age will be three times his son's age

(x + 5) = 3(y + 5)
you will get
x - 3y -10 = 0 ---------(1)

5 years ago he was seven times as old as his son
(x - 5) = 7(y - 5)
you will get equation;
x - 7y + 30 = 0--------------(2)

according to equation (1) and (2)
x = 40
y = 10
so
the age of father in present = x = 40 year
the age of father in present = y = 10 year
option 7

Like? Yes (30) | No (5)  

Harsh Poddar   10 years AGO

let son age =x
five years after=x+5
after 5 years father's age=3(x+5)
before five years son age=x-5
before five years fathers age =7(x-5)
present father age=3(x+5)-5 and 7(x-5)+5
equation
3(x+5)-5=7(x-5)+5
solve
x=10
present son age =10years
father age =3(10+5)-5
=45-5=40years
so present ages=40,10 years
option 7

Like? Yes (15) | No (1)  

SAM   10 years AGO

Let Man\'s age=x;son\'s age=y.
x+5=3(y+5)
x-5=5(y-5)
now solve it....

Like? Yes (7) | No   

saurabh   10 years AGO

The dad(d) is 40, and the son(s) is 10.
d=7s (the dad and son five years ago)
and
d+10=3(s+10) (the dad and son five years from now)
d+10=3s+30
substitute in the value of d from the first equation
7s+10=3s+30
rearrange
7s-3s=30-10
4s=20
s=5
Note this is the son five years ago...
so the son is now 10
the dad five years ago = 7s = 35, so the dad is now 40

((((((((now if you want to check your answer,
then
five years ago, the son was 5 and dad was 35
5*7=35 Check :)
Five years from now, the don is 15, and the dad is 45
15*3=45)))))))))

Like? Yes (4) | No   

shilpi   10 years AGO

suppose the age of father is =x
and the age of son is =y

acc to equation 1
x+5=3(y+5)
and acc to equation 2
x-5=7(y-5)

on solving the above equation
x(age of father)=40
y(age of son)=10

Like? Yes (4) | No   

Kaustubh karekar   10 years AGO

let their current ages be x,y
so, after 5 yrs, it will be x+5,y+5
now, x+5=3(y+5), then x+5=3y+15
also, 5 yrs ago the age will be x-5, y-5
now, x-5=7(y-5), then x-5=7y-35
solving the equations we get,
x=40 and y=10
so, option 7 is correct

Like? Yes (4) | No   

S.SHAFI   10 years AGO

After 5 years,
Lets son's age = x, then
Mans's age is three times his son's age = 3x

5 years ago,
son's age will be x-5-5 = x-10
Man's age will be 3x-5-5 = 3x-10
Man's age was seven times his son = 7(x-10)
so,
3x-10 = 7(x-10)
3x-10 = 7x-70
4x = 60
x = 15

Son's age after 5 years is 15 years and Man's age is 3x = 45 years.
Their Present Ages are 10 and 40.

Like? Yes (4) | No (1)  

Hariom   10 years AGO

let, man's present age is X
and son is y.
After 5 years their age will be x+5 and y+5.

x+5=3(y+5)...eqn 1
neo 5 years ago, their age was x-5 and y-5.
therefor acc. to the question,
x-5=7(y-5)...eqn 2
on solving 1 and 2, we get x=40 and y=10.

Like? Yes (4) | No (1)  

Leelanand Kumar Yalla   10 years AGO

Let the present Ages of Man and his son is M,S;
So according to statement M+5=3(s+5);------>(1)
M-5=7(5-5);------->(2)
M-3S-10=0---->(1)
M-7S+30=0---->(2)
By Solving These two Equations we will get Son's age is 10 years;
and Man's Age is 40 Years.... This is The answer...

Like? Yes (4) | No (1)  

shamma mohammad   10 years AGO

son=x
man=7x after 5years
option cheking:7
40,10
40-5=35
10-5=5
7x=7(5)=35

Like? Yes (5) | No (2)  

ANUP KUMAR   10 years AGO

x=present age of father;
y=present age of son;
given,
x+5=3*(y+3)
x-3y=10---(1)
&
x-5=7*(y-5)
x-7y=-30----(2)

solve (1)-(2)=>y=10;put the value of y in eqn (1)
then x=40;
present age of father is 40
& present age of son is 10

Like? Yes (3) | No   

Sajal Garg   10 years AGO

Let father's age = x; son's =y
Condition 1) (x+5)=3(y+5) =>x-3y=10...(1)
condition 2) (x-5)=7(y-5) =>x-7y=-30...(2)
solving 1 & 2) x=40 & y=10..
Answer=7) 40,10 years

Like? Yes (2) | No   

Devendra Marghade   10 years AGO

If present age of man=x, son=y
3(y+5)=(x+5), x-3y=10 ---(i) &
7(y-5)=(x-5), x-7y=-30 ---(ii)
Solving (i) & (ii), x=40, y=10

Like? Yes (2) | No   

Jigyasa Kumar   10 years AGO

the option 40, 10 is correct.because,
5 years ago, man will be 35 years old and son's age will be 5 years.So, man's age is 5 times his son's age.

Like? Yes (2) | No   

Sukanya   10 years AGO

after 5 years the ages will be
father - 45 son - 15(15*3=45)
before 5 years the ages will be
father-35 son-5(5*7=35)

Like? Yes (2) | No   

R.RAVIKUMAR   10 years AGO

Let's assume that father's present age is 'x' yrs and son's present age is 'y' yrs..
As per the given instructions,
x+5=3(y+5) => x-3y=10
x-5=7(y-5) => x-7y=-30
by solving those eqns, we get x=40 and y=10..

Like? Yes (2) | No   

Venkatesh KK   10 years AGO

Let the present ages of father and son be F and S respectively. After 5 years their age will be (F+5) and (S+5) respectively...
Therefore,
(F+5) = 3(S+5) ...(1)

5 years ago,
(F-5) = 7(S-5) ...(2)

Solving equations (1) and (2) we get S = 10 and F=40... i.e., father's age = 40 and son's age = 10.. (Option 7)

Like? Yes (3) | No (1)  

Aarush Singh   10 years AGO

Answer is 40, 1o.Because,
5 years ago, man will be 35 years old and son\'s age will be 5 years.So, man\'s age is 5 times his son\'s age.

Like? Yes (2) | No   

Rajasekhar Reddy   10 years AGO

M+5 = 3*(S+5)
M-3S = 10 -------> 1
M-5 = 7*(S-5)
M-7S = -30 ---------> 2
SOLVING ABOVE TWO EQUATIONS
WE GET
S = 10 YEARS
M = 40 YEARS

Like? Yes (2) | No   

Subhash chandra pal   10 years AGO

Let present ages are as follows:
Father=x
Son=y
After 5 year:
Father's age=x+5
Son's age=y+5
According to problem:
x+5=3(y+5)..............(i)
5 years ago:
Father's age=x-5
Son's age=y-5
According to problem:
x-5=7(y-5)...................(ii)
Now solving equation (i)and (ii)
We have x=40 and y=10.

Like? Yes (2) | No   

abhilasha   10 years AGO

the option 40, 10 is correct.because,
5 years ago, man will be 35 years old and son\'s age will be 5 years.So, man\'s age is 5 times his son\'s age.

Like? Yes (2) | No   

aviral bhargava   10 years AGO

let father's age be x and son's age be y
first equation would be formed as,
(x+5)=3(y+5)
Second equation would be formed as,
(x-5)=7(y-5)
On solving the above equations we get,
x=40 years and y=10 years
father's age is 40 years and son's age is 10 years .

Like? Yes (2) | No   

Mahalakshmi   10 years AGO

from above question we can form equations
x-5=7(y-5)
x+5=3(x+5)

solving this equation will get
x=40,
y=10
so fathers age 40 and sons age 10

Like? Yes (2) | No   

RAKESH   10 years AGO

x+5=3(y+5)
x-5=7(y-5)
=> x=40,y=10

Like? Yes (3) | No (1)  

Saidinesh   10 years AGO

five years back son age =5;
father's age =35;
i.e 7 times
now their age is 10,40
after five years
their age is 15, 45
i.e son age is trice as father age

Like? Yes (2) | No   

Pallekonda Rajesh   10 years AGO

today both years lets a and b
after 5 years b+5=3*(a+5)
before 5 years b-5=7*(a-5)
if we solve above two equations we will get
the ans:a=10 b=40

Like? Yes (2) | No   

TRIMURTULU   10 years AGO

man+5=3(son+5)
man-5=7(son-5)
2 equation 2 unknowns solve
man=40
son=10

Like? Yes (2) | No   

ranu   10 years AGO

let assume sons age is x year and father age is y year
5 year ago
7(x-5)=y-5
7x-35=y-5
7x-y=30 equation1
after 5 year
3(x+5)=y+5
3x+15=y+5
3x-y=-10 equation2
solve eq1 and eq2
x=10 and y=40

Like? Yes (2) | No   

SIVA BALSUBRAMANIAN   10 years AGO

x present age of father, y present age of mother
so after 5years
x+5=3(y+5)
before 5 years
x-5=7(y-5)
by solving this equation
x=40,y=10

Like? Yes (2) | No   

Sanjay Bhatt   10 years AGO

Let the Father's Age be X years.
Let the Son's Age be Y years.


After 5 years...
X+5=3(Y+5)...(1)
Before 5 years...
X-5=7(Y-5)...(2)

Solving (1) and (2) simultaneously we get,
X=40
Y=10

Like? Yes (2) | No   

ASHISH MITTAL   10 years AGO

Let father present age is f and son age is s so
f+5=3(s+5)------1
f-5=7(s-5)------2
by solving equation 1 and 2 we get
f=40
s=10

Like? Yes (2) | No (1)  

Harshit Daga   10 years AGO

Let man current age = x
and let son current age = y

After 5 years,
x+5 = 3*(y+5)

and,
before 5 years..

(x-5) = 7*(y-5)

so from above equations..
x=40,
and
y=10

which means..
Man current age = 40 years.
and, son current age = 10 years..

i.e. option 7 is correct.

Like? Yes (1) | No   

NAGENDRA P   10 years AGO

let the age of man be M,let the age of his son be S..
M+5=3(S+5)
M=3S+10....(1)
M-5=7(S-5)
3S+5=7S-35...
40=4S
S=10..
M=40..
SO OPTION (7)

Like? Yes (1) | No   

magamutha   10 years AGO

5 yrs ago the age of the son and father is x and y respectively. The eqn is y=7x
after 5 yrs y+10=3(x+10)
x=5,y=35 present ages are 10 and 40

Like? Yes (1) | No   

Sudipta Mukherjee   10 years AGO

from options ..7 is r8....40+5=3(10+5)....(i)
7(10-5)=40-5...(ii)

Like? Yes (1) | No   

rajat joshi   10 years AGO

only this option fits best

Like? Yes (1) | No   

TANUSREE MAHAPATRA   10 years AGO

let,x=son's present age
y=father's present age
3(x+5)=y+5
7(x-5)=y-5
after solving we get,x=10,y=40

Like? Yes (1) | No   

Gudivada sunitha   10 years AGO

after 5 years 40 is 45 son age is a5 and 15*3 =45.
before 5 years father age is 35 , son age is 5, 5*7=35

Like? Yes (1) | No   

Lavankumar Reddy   10 years AGO

40,10 years that are after 5 years = 40+5 = 45 and 10+5 = 15 so age was 45/15 = 3 times
5 years ago age is = 40-5=35 and 10-5 = 5
S0 different is =35/5= 7 times

Like? Yes (1) | No   

Dhwan Lalwani   10 years AGO

Present man n son age be M & S
After 5yr, M+5=3(S+5)
Before 5yr, M-5=7(S-5)
solving them we get,
M=40yrs & S= 10yrs

Like? Yes (1) | No   

chandrappa   10 years AGO

x+5=3(y+5)

Like? Yes (1) | No   

pari   10 years AGO

father son
5yr ago 7x x
present age 7x+5 x+5
5yr after 7x+5+5 = 3(x+5+5) solve this eq.

we will get x=5
so ans is 40 and 10

Like? Yes (1) | No   

Rajat Goyal   10 years AGO

Best Option

Like? Yes (1) | No   

Swathi   10 years AGO

Ans:7)40,10
F+5=3(X+5)
F-5=7(X-5)
by solving these two equations we will get F=40 and X=10

Like? Yes (1) | No   

rakesh   10 years AGO

son age father age
present x
after 5yrs x+5 3(x+5)
before 5yrs x-5 7(x-5)

3(x+5)-7(x-5)=10
3x+15-7x+35-=10
4x=40
x=10


man present age=40
son present age=10

Like? Yes (1) | No   

sravani   10 years AGO

let man's age =x
let son's age =y
x+5=3(y+5)
x-5=7(y-5)
are given
we get x+10=5y by solving the above eq
so option 7 only satisfies it.

Like? Yes (1) | No   

Sapan Suman   10 years AGO

two equation
M+5=3(S+5)
M-5=7(S-7)

Like? Yes (1) | No   

vijayanirmala   10 years AGO

x=father age y=sons age
(x-5)=7(y-5)so (x+5)=3(y+5)
(x-5) = 7(y-5)

(x+5) = 3(y+5)
--> x+5 = 3y+15
--> x-3y = 10

Like? Yes (1) | No   

Parthi Smith   10 years AGO

man's age = x
son's age = y
1.x+5=3(y+5) => x=3y+10
2.x-5=7(y-5) => x=7y-30
Therefore,y=10,x=40

Like? Yes (1) | No   

ARJYA HALDER   10 years AGO

Let, present father\'s age=x
present son\'s age=y
So, from question we can get,
x+5=3(y+5) &
x-5=7(y-5)

Solving the above equations we get, x=40 & y=10

Like? Yes (1) | No   

VIKASH RAY   10 years AGO

Let,the present age of the man is- 40 years.
& the age of his son is- 10 years.
so, 5 years ago, he was seven times as old as his son.
and after5 years,he will be three times his son's age

Like? Yes (1) | No   

MD NAZIR   10 years AGO

Ans: 7) 40, 10
Eliminating Answers will take lesser time.
(40+5)=3 (10+5)
(40-5)=7 (10-5)

Like? Yes (1) | No   

MADHU   10 years AGO

let father's age be F
son's age be S
after 5 yrs F+5=3(S+5)=> F=3S+10
ago 5 yrs F-5=7(S-5)=> F=7S-30
by equating we get F=40
S=10

Like? Yes (1) | No   

susmit   10 years AGO

f+5 = 3(s+5)
f-5 = 7(s-5)

Solving this f = 40
s = 10
hence option no. 7

Like? Yes (1) | No   

Sumit Kumar Dharmani   10 years AGO

let us assume that the present age of man be M and of his son be S
then according to given condition
(M+5) = 3(S+5)
and
(M-5) = 7(S-5)
so solving these 2 equations;
we get M = 40 and S = 10
hence the answer is option 7.

Like? Yes (1) | No   

Rituparna Chakraborty   10 years AGO

Let
Man's present age=x
Son's present age=y
After 5 years
Man's age=(x+5)
Son's age=(y+5)
Given,(x+5)=3(y+5)
=>x-3y=10 ---------
5 years ago
Man's age=(x-5)
Son's age=(y-5)
Given,(x-5)=7(y-5)
=>x-7y=-30 -----------
Solving & we obtain,
x=40
y=10
So,Man's present age=40
Son's present age=10

Like? Yes (1) | No   

sudipta sadhukhan   10 years AGO

suppose their age after 5 yrs X & 3X.
present age X-5 & 3X-5
age before 5yrs X-10 3X-10

A/Q 7X-70=3X-10

=> X=15

present age 10& 40

Like? Yes (1) | No   

suraj jha   10 years AGO

mans age=x;
son age=y;
after 5 years
x+5=3(y+5);
x-3y=10.....(1)
5 years ago;
x-5=7(y-5);
x-7y=-30...(2)
eq1-eq2
x=40 & y=10
mans age=40;
son age=10;

Like? Yes (1) | No   

Chithra   10 years AGO

Present ages 40,10
After 5 yrs
45=15
5 yrs ago
35=5

Like? Yes (1) | No   

AKASH KUMAR   10 years AGO

LET MAN\'S PRESENT AGE =X AND SON\'S AGE=Y
THEN X+5=3(Y+5)---1
X-5=7(Y-5)---2
SOLVE WE GET X=40 AND Y=10

Like? Yes (1) | No   

ramkumar   10 years AGO

a+5=3(b+5);-----1
a-5=7(b-5);-----2
a=7(b-5)+5;
a=7b-35+5;
a=7b-30;------3
put equ(3) in (1)
7b-30+5=3(b+5);
7b-25=3b+15;
7b-3b=+15+25;
4b=40;
b=10;
put b=10 in equ (3);
a=7*10-30;
a=40;
so ans is a=10
b=40

Like? Yes (1) | No   

ayush   10 years AGO

3(x+5)=y+5
7(x-5)=y-5

* x & y are present age of child and father

Like? Yes (1) | No   

techknowxpress   10 years AGO

m+5=3*(s+5)
m-5=7*(s-5)
Solving these 2 eqns , we get
m(man's age)=40yrs
s(son's age)=10yrs

Like? Yes (1) | No   

anubhav verma   10 years AGO

x+5=3(y+5)
x-5=7(y-5)

Like? Yes (1) | No   

karthik hariharan   10 years AGO

Father age is taken as X;
Son age is taken as Y;
X+5=3(Y+5);----1
X-5=7(Y-5);-----2
X=3(Y+5)-5;
X=3Y+15-5;
X=3Y+10;-----3
PUT EQU 3 IN 2
3Y+10-5=7Y-35;
3Y+5=7Y-35;
3Y-7Y=-35-5;
-4Y=-40;
Y=10;
PUT Y=10 IN EQU 1
X+5=3(Y+5);
X+5=3(10+5);
X+5=45;
X=40;

Like? Yes (1) | No   

DHAKAD NEETENDRA SINGH   10 years AGO

only this option satisfy the condition

Like? Yes (2) | No (1)  

madanpal vishwakarma    10 years AGO

assume that men current age is x year and his son is y year old

then
according to the question

After 5 years a man's age will be three times his son's age

x+5=3(y+5).....equation (i)
II conditon
5 years ago he was seven times as old as his son

x-5=7(y-5)... equation(II)

on solving
we get x=40 and y=10.
so option 7 is correct

Like? Yes (4) | No (4)  

D.HARINATH REDDY   10 years AGO

x+5=3(y+5)
x-5=7(y-5)
then x=40,y=10

Like? Yes (1) | No (1)  

SID PRASANTH KUMAR   10 years AGO

40+5=3*(10+5)

Like? Yes (2) | No (2)  

IFFAT IRAM   10 years AGO

let the present age of son be x and father be y.


after 5 years,
son's age= x+5
father's age=y+5
y+5=3(x+5)
y=3x+10.........(1)

5 years ago,
son's age=x-5
father's age=y-5
y-5=7(x-5)
y=7x-30...........(2)

3x+10=7x-30
4x=40
x=10

y=3*10+10
y=40
son's present age=10yrs
father's present age=40 yrs.

Like? Yes (1) | No (1)  

Prashasti Sharma   10 years AGO

f=father and s=son
f(+5):(s+5)=3:1---(1)
f(-5):s(-5)=7:1--(2)
ratio is unequal hence..
eq1 * 6 and eq2*2
f(+5):s(+5)=18:6
f(-5):s(-5)=14:2
diff is 4
s0 if 4--10
then 1-- 10/4 which is 2.5
present age of father= (18*2.5-5)=40 years
present age of son=(6*2.5-5)=10 years

or by eqn method
3x-10=7(x-10)
x=15
father's age= 3*15-5=40 yrs
son's age= 15-5=10 yrs

Like? Yes (1) | No (1)  

Chaitanya Singh   10 years AGO

x -> age of father
y -> age of son

2 equations are
(x-5) = 7(y-5)
(x+5) = 3(y+5)

on solving
x = 40
y = 10

Like? Yes (1) | No (1)  

Vikram Saini   10 years AGO

40,10

Like? Yes (1) | No (1)  

Dhruv Patel   10 years AGO

x+5=3(y+5)
x-5=7(y-5)

Like? Yes (1) | No (1)  

Shiv Kumar   10 years AGO

40*10 because before 5 year man age 35 son 7 or after 5 year 45 son 15

Like? Yes (1) | No (1)