If in coded language SHANKAR = 2016 NEERAJ = 2520 RAMESH = 144 Then RAJAT = ?

M4maths Previous Puzzles

28 Mar 2014 Coded language

If in coded language
SHANKAR = 2016
NEERAJ = 2520
RAMESH = 144
Then
RAJAT = ?

OPtion

1) 3640
2) 2640
3) 8096
4) 5760
5) 5040
6) 6760
7) 3600
8) 3024
9) 5760
10)None of these

Solution

A(1), B(2), C(3), D(4), E(5), F(6), G(7), H(8), I(9), J(10), K(11), L(12), M(13), N(14), O(15), P(16), Q(17), R(18), S(19), T(20), U(21), V(22), W(23), X(24), Y(25) ,Z(26)
SHANKAR = 19 8 1 14 11 1 18 = 8*14*18 = 2016 (Multiplication of even)
NEERAJ = 14 5 5 18 1 10 = 2520
RAMESH = 18 1 13 5 19 8 = 144
Similarly
RAJAT = 18 1 10 1 20 = 3600

Option 7)

Correct Option: 7 Best Solution (16)

Dr.Dipin Singh   10 years AGO

Product of positional value of letters having even positional value in English Alphabets.
Like B=2; ;D=4; F=6..
So RAJAT = 18(R)*10(J)*20(T) =3600

Like? Yes (18) | No (6)  

Akanksha Mishra   10 years AGO

Given
SHANKAR = 2016
NEERAJ = 2520
RAMESH = 144

A(1),B(2),C(3)................,Y(25),Z(26)

1].SHANKAR
S(19),H(8),A(1),N(14),K(11),A(1),R(18)
Multiply the even position values
= 8*14*18
= 2016

Similarly
RAJAT
R(18),A(1),J(10),A(1),T(20)
Multiply the even position values
= 18*10*20
= 3600

SO Answer will be 3600(option 7)

Like? Yes (12) | No (6)  

RAKESH   10 years AGO

multiply only even no.s assigned to alphabets

Like? Yes (9) | No (8)  

Santosh Vishwakarma   10 years AGO

A(1),B(2)............Z(26)
1) S H A N K A R
(18)(8)(1)(14)(11)(1)(18)
multiplication of even numbers(18*8*14)=2016
note:take one number only one time in multipy
R(18)A(1)J(10)A(1)T(20)....18*10*20=3600.

Like? Yes (1) | No   

Udhaya kumar   10 years AGO

product of even alphanumerics...
RAJAT = R * J * T = 18*10*20=3600.....

Like? Yes (4) | No (5)  

P.Selva Dhasni   10 years AGO

the ans is 7) 3600

multiply the even numbers

SHANKAR => 19 8 1 14 11 1 18 =>8*14*18 => 2016

NEERAJ => 14 5 5 18 1 10 => 14*8*10 =>2520

RAMESH => 18 1 13 5 19 8 => 18*8 =>144

RAJAT =>18 1 10 1 20 =>18*10*20 =>3600

Like? Yes (3) | No (6)  

Ragaven   10 years AGO

product of even alpha numerics...
RAJAT = R * J * T = 18*10*20=3600.....

Like? Yes (2) | No (5)  

J.DHANDAPANI   10 years AGO

EVEN NOS ARE MULTIPLIED
ANS:18X10X20=3600

Like? Yes (1) | No (4)  

Mithra MR   10 years AGO

EVEN NOS ARE MULTIPLIED
ANS:18X10X20=3600

Like? Yes (1) | No (4)  

Satish Zod   10 years AGO

Consider A=1, B=2,............Z=26.
Multiply even numbers corresponding to alphabets in name.

Like? Yes (1) | No (4)  

Ann Theressa   10 years AGO

write the numbers corresponding to alphabets.ie
A = 01
B = 02
C = 03
.
.
.
Z =26
and multiply the even numbers
SHANKAR
19, 08, 01, 14, 11, 01, 18
8*14*18 = 2016

NEERAJ
14, 05, 05, 18, 01, 10
14*18*10 = 2520

RAMESH
18, 01, 13, 05, 19, 08
8*18 = 144

RAJAT
18, 01, 10, 01, 20
18*10*20 = 3600

Like? Yes (3) | No (7)  

ASHISH MITTAL   10 years AGO

if a=1,b=2,c=3 and so on....
in given word answer is obtained by multiply the digit which is even
so for rajat the even no is 18,10,20 and their multiplication will be 3600...so answer will be option (7)

Like? Yes (1) | No (5)  

azharshahid01@gmail.com   10 years AGO

In coded Language,
A=1,
B=2,
...
...
z=26.
Multiply all even numbers in a word.
SHANKAR = 19,8,1,14,11,1,18 => 8*14*18= 2016
NEERAJ = 14,5,5,18,1,10 => 14*18*10 = 2520
RAMESH = 18,1,13,5,19,8 => 18*8 = 144
Similarly,
RAJAT = 18,1,10,1,20 => 18*10*20 = 3600
Thus answer is option 7) 3600

Like? Yes (1) | No (5)  

ADVAITA BASAK   10 years AGO

R=18, A=1, J=10, A=1, T=20

Multiplying the even numbers.....

18*10*20=3600

Like? Yes (1) | No (5)  

hanamant k   10 years AGO

multiply only even digit of letters sum is th result
exmple
R-18 A-1 J-10 A-1 T-20

so
18*10*20=3600

Like? Yes (1) | No (5)  

muni   10 years AGO

36 first two digits are perfect square and divisible by 4 and 9

Like? Yes (1) | No (5)