Solve following equations 3(2u+v) = 7uv (i) 3(u+3v) = 11uv (ii)

Ann Theressa   10 years AGO

3(2u+v) = 7uv ---(i)
3(u+3v) = 11uv --- (ii)

6u + 3V = 7uv ---(1)
3u +9v = 11uv ---(2)

multiply (2) by 2

6u +18v = 22uv---(3)

eqn (3) - (2)

15v = 15uv
==> u=1
v = 3/2

Like? Yes (27) | No (10)  

Sivanjali   10 years AGO

Given equations are
6u + 3v = 7uv --- (1)
3u + 9v = 11uv --- (2)
Multiplying eqn (2) by 2,
6u + 18v = 22uv --- (3)
After solving eqn (1) and (3)
15v = 15uv
u = 1 and v = 3/2

Like? Yes (13) | No (7)  

azharshahid01@gmail.com   10 years AGO

Given Equations
3(2u+v)=7uv--(1)
3(u+3v)=11uv--(2)
On solving,
6u+3v= 7uv---(1)
3u+9v= 11uv---(2)
On multiplying equation (2) by 2. We get,
6u+3v= 7uv---(1)
6u+18v= 11uv---(2)
On solving,
u=1 and v=3/2.
So, result is option 6)u=1, v=3/2.

Like? Yes (13) | No (8)  

saurabh agarwal   10 years AGO

6u+3v-7uv=0...(1)
3u+9v-11uv=0...(2)
solve 1 and 2 we get u=1,v=3/2.

Like? Yes (5) | No (2)  

D.Ragulkumar   10 years AGO

3(2u+v)=7uv
3(u+3v)=11uv
calculation
6u+3v=7uv
(*2)6u+18v=22uv
-15v=-15uv
u=1
u in above equation
3+9v=11v
v=3/2

Like? Yes (6) | No (3)  

Devendra Marghade   10 years AGO

3(2u+v) = 7uv (i)
3(u+3v) = 11uv (ii)
Simplifying (i),6u+3v=7uv ---(iii)
Simplifying (ii,3u+9v=11uv ---(iv)
Solving,(iii)&(iv),u=1, v=3/2

Like? Yes (3) | No (1)  

Surya Narayana K   10 years AGO

Given eqns are
6u+3v=7uv
3u+9v=11uv
after solving we get
u= 1, v = 3/2

Like? Yes (4) | No (2)  

SONU GUPTA   10 years AGO

6u+3v=7uv-----(1)
3u+9v=11uv-----(2)*2
6u+18v=22uv
-15v=-15uv
u=1; v=3/2

Like? Yes (3) | No (1)  

J.DHANDAPANI   10 years AGO

Dividing throughout by uv,we get
(6/v)+(3/u)=7.
(3/v)+(9/u)=11.
Solving gives u=1 and v=3/2.

Like? Yes (3) | No (1)  

Varunraj Reddy   10 years AGO

Multiply eq i) with 3 we get
18u+9v=21uv....i)

subtract eq ii)
18u+9v=21uv....i)
-3u-9v=-11uv....ii)
-----------------
15u=10uv
v=3/2
Put v value in eqn ii)we get u=1

Like? Yes (3) | No (1)  

nilu kumari   10 years AGO

GO through the option
and, option 6. satisfies both the conditions
ie. u=1, v=3/2

Like? Yes (4) | No (2)  

Deepa waswani   10 years AGO

6u+3v=7uv .....(1)
3u+9v=11uv ....(2)
from eqn (1) => uv=(6u+3v)/7
put the value of uv in eqn (2)
3u+9v=11[(6u+3v)/7]
solving this eqn, we get, 45u-30v=0....(3)
from eqn (3), u=2v/3
substituting the value of u in eqn (1), we get,
v=3/2
and then using the value of v , we obtain the value of u=1

Like? Yes (3) | No (1)  

muni   10 years AGO

substitute u and v values in given equations

Like? Yes (3) | No (1)  

Sudipta Mukherjee   10 years AGO

6/v+3/u=7
3/v+9/u=11
u=1,v=3/2

Like? Yes (5) | No (3)  

meghana   10 years AGO

given : 3(2u+v)=7uv ...........(1)
3(u+3v)=11uv............(2)
solve : eq(1)and eq(2) then we get
6u+3v=7uv................(3)
3u+9v=11uv................(4)
multiply eq(3) by 11 and eq(4) by 7 then equations become
66u+33v=77uv
21u+63v=77uv
By solving above 2 equations we get 45u-30v=0
=> 3u=2v-----------eq(5)
substitute eq-5 in eq-4 then we get "u=1".
substitute "u=1" in eq-(5) then we get "v=(3/2)".






.

Like? Yes (3) | No (1)  

K.Sumathi   10 years AGO

6u+3v=7uv ---1
3u+9v=11uv ---2
After solving 1 and 2
we get
u=1
v=3/2

Like? Yes (3) | No (1)  

ASHISH MITTAL   10 years AGO

by solving this equation we get
u=1, v=3/2

Like? Yes (3) | No (1)  

saikiran   10 years AGO

by solving two equations
we get u=1,v=3/2

Like? Yes (3) | No (1)  

S.SHAFI   10 years AGO

Given Equations are..

6u+3v = 7uv
3u+9v = 11uv

solving we get, u=1, v=3/2..

Like? Yes (4) | No (3)  

SHEREENA NISHAD   10 years AGO

6u + 3v = 7uv....(1)
3u + 9v = 11uv...(2)
Multiply eqn (2) by 2
6u + 18v = 22uv ....(3)
(3) - (1) gives
15v=15uv
Then
u=1
substitute u=1 in any eqn
we get v=3/2

Like? Yes (6) | No (5)  

Leelanand Kumar Yalla   10 years AGO

6U+3V=7UV--------->(1);
3U+9V=11UV---------->(2);
By solving these two equations we will get U=1, V=3/2;......

Like? Yes (3) | No (2)  

SAM   10 years AGO

6u+3v = 7uv......(1)*3
3u+9v = 11uv......(2)

on solving

u=1,v=3/2

Like? Yes (4) | No (3)  

Saidinesh   10 years AGO

solving equation 1 and 2
3u=2v;
u/v=2/3;
it happens for only 6th option

Like? Yes (2) | No (1)  

AVIJIT   10 years AGO

from 1st equation
3(2u+v)= 7uv
i.e 6u+3v=7uv
or, 6u-7uv= -3v
or, u = 3v/(7v-6)
now put the value of u in the 2nd equation
we will get 3[(3v/7v-6)+3v] = 11(3v/7v-6)v
or 3[21v^2 - 15v]=33v^2
or 10v^2 - 15v = 0
v= 3/2
put the value of v in the 1st equation well get u = 1
so u= 1,v=3/2

Like? Yes (2) | No (2)  

gopisetty utpala   10 years AGO

by solving above two equations
we get u=1,v=3\2

Like? Yes (2) | No (2)  

Sandeep Jadala   10 years AGO

3(2u+v)=7uv
3(u+3v)=11uv
6u+3v=7uv
3u+9v=11uv
solve both equations u=1 & v=3/2

Like? Yes (2) | No (2)  

B karthik   10 years AGO

u=1,v=3/2
by doing calculation

Like? Yes (1) | No (1)  

Pallekonda Rajesh   10 years AGO

6u+3v=7uv,3u+9v=11uv
equate uv from two equations we get u=(2/3)v
substitute in any above equation
we get ans u=1,v=3/2

Like? Yes (1) | No (1)  

avinash kumar   10 years AGO

6u + 3v = 7uv ... (I) ....
3u + 9v = 11uv ... (II) ....
Dividing uv in both sides of eqn (I) and (II) .....
6u + 3v = 7uv
---> 6u / uv + 3v / uv = 7uv / uv
---> 6 / v + 3 / u = 7 ... (III) ....
Also ....
3u / uv + 9v / uv = 11uv / uv
----> 3 / v + 9 / u = 11 ..... (IV) ...
multiplying 2 to eqn IV ....
we get :-
6 / v + 18 / u = 22 .... (V) ...
solving III and V :-
u = 1 ..... v = 3 / 2 ....
So, u = 1 .. (ans) ..
v = 3 / 2 ... (ans) ..

Like? Yes (1) | No (1)  

ANURAG VERMA   10 years AGO

6u + 3v = 7uv ... (I)
3u + 9v = 11uv ... (II)
Dividing uv in both sides of eqn (I) and (II)
6u + 3v = 7uv
---> 6u / uv + 3v / uv = 7uv / uv
---> 6 / v + 3 / u = 7 ... (III)
Also
3u / uv + 9v / uv = 11uv / uv
----> 3 / v + 9 / u = 11 ..... (IV)
multiplying 2 to eqn IV
we get :-
6 / v + 18 / u = 22 .... (V)
solving III and V :-
u = 1 ..... v = 3 / 2

Like? Yes (1) | No (1)  

ritika mehrotra   10 years AGO

6u+3v=7uv
3u+9v=11uv
divide the whole eq by uv
(6/v)+(3/u)=7
(3/v)+(9/u)=11
let (1/v)=x;(1/u)=y
6x+3y=7
3x+9y=11
thus x=(2/3);y=1
therefore;u=1;v=(3/2)

Like? Yes (1) | No (1)  

hanamant k   10 years AGO

on dividing (1)/(2)
we get
3u-2v=0
==>u=2/3v ----(3) put this value in equ (1)

so ,then u will get v=3/2

put this value in equ (3)
then u will get u=1

hence u=1,v=2/3

Like? Yes (1) | No (1)  

Abdullah Khilji   10 years AGO

3(2u+v) = 7uv (i)
3(u+3v) = 11uv (ii)
6u+3v = 7uv (i)
3u+9v = 11uv (ii)
now multiplying equation (ii) by 2, we get
6u+3v = 7uv (i)
6u+18v = 22uv (ii)
- - -
_______________
-15v = -15uv
dividing both sides by -15v, we get
1 = u
now putting value of u in eq. (i) we get
3(2u+v) = 7uv (i)
3(2+v) = 7v
6+3v = 7v
6 = 4v
v = 3/2
Q.E.D.

Like? Yes (1) | No (1)  

Sohar Lal Singh   10 years AGO

given equation are
3(2u+v)=7uv.........(i)
3(u+3v)=11uv.........(ii)
divide the equatuon (i) by (ii)
(2u+v)/(u+3v)=7/11
cross multiply
11*(2u+v)=7*(u+3v)
22u+11v=7u+21v
22u-7u=21v-11v
15u=10v
3u=2v
or
v=(3/2)*u.....(iii)
put this value in equation i
we get
3(2u+3/2*u)=7u*3/2u
21u=21u*u
u=1 ans
and from (iii)
v=3/2*u then
v=3/2
hence option 6

Like? Yes (1) | No (1)  

Rohit Agarwal   10 years AGO

from (1)
uv=(6u+3v)/7--------------->(3)
from (2)
uv=(3u+9v)/11-------------->(4)

comparing (3) and (4)

u=(2/3)v
putting value of u in equation (3)

v=3/2 so u=1

Like? Yes (1) | No (1)  

Rohit Singh Panwar   10 years AGO

6u+3v=7uv (i)
3u+9v=11uv (ii)

9u+18v=22uv (ii*2)

15v=15uv (ii*2-i)

u=1

from eq (i)

6+3v=7v
4v=6
v=3/2

Like? Yes (1) | No (1)  

Gudivada sunitha   10 years AGO

check all options and 6 th correct option.

Like? Yes (1) | No (1)  

himesh suthar   10 years AGO

6u + 3v = 7uv

---> 6u / uv + 3v / uv = 7uv / uv

---> 6 / v + 3 / u = 7 ... (III) ....

Also ....

3u / uv + 9v / uv = 11uv / uv

----> 3 / v + 9 / u = 11 ..... (IV) ...

multiplying 2 to eqn IV ....

we get :-

6 / v + 18 / u = 22 .... (V) ...

solving III and V :-

u = 1 ..... v = 3 / 2 ....

So, u = 1 .. (ans) ..

v = 3 / 2 ... (ans) ..

Like? Yes (1) | No (1)  

karthika kumar   10 years AGO

6u+3v=7uv ---- (1)
3u+9v=11uv ---- (2)
(2)*2 --> 6u+18v=22uv
(1)-----> 6u+3v=7uv (-)
15v=15uv
=> u=1
substitute u=1 in (1) we get, 6+3v=7v => v=6/4=3/2

Like? Yes (1) | No (1)  

jyoti   10 years AGO

6u/uv+3v/uv=7uv/uv=>6/v+3/u=7
3u/uv+9v/uv=11uv/uv=>3/v+9/u=11
solving the above equation we get u=1 and v=3/2

Like? Yes (1) | No (1)  

MD SOHAIL AKHTER   10 years AGO

multiply eqn1 by 11 and eqn2 by 7,on solving we get;
u=1 and v=3/2

Like? Yes (1) | No (1)  

Aakash Jain   10 years AGO

on solving both equations
we get u=1 and v=3/2

Like? Yes (1) | No (1)  

Kowshik Sarker   10 years AGO

(2u+v)/(u+3v)=7/11.solving this we get
u/v=2/3.
so,u=(2/3)*v
putting this value in 3(2u+v)=7uv we get v=3/2
thus u=1.which is option 6.

Like? Yes (1) | No (1)  

ADVAITA BASAK   10 years AGO

6u+3v=7uv
3u+9v=11uv

by solving u=1, v=3/2

Like? Yes (1) | No (1)  

Rahul Kesharwani   10 years AGO

Solve n simplify (i) equation, there u got
v = 7uv/3 - 2u
put this value in another one,
then solve again another one

Like? Yes (1) | No (1)  

Pooja LOhar   10 years AGO

6u + 3v = 7uv ... (I) ....
3u + 9v = 11uv ... (II) ....
Dividing uv in both sides of eqn (I) and (II) .....
6u + 3v = 7uv
---> 6u / uv + 3v / uv = 7uv / uv
---> 6 / v + 3 / u = 7 ... (III) ....
Also ....
3u / uv + 9v / uv = 11uv / uv
----> 3 / v + 9 / u = 11 ..... (IV) ...
multiplying 2 to eqn IV ....
we get :-
6 / v + 18 / u = 22 .... (V) ...
solving III and V :-
u = 1 ..... v = 3 / 2 ....
So, u = 1 .. (ans) ..
v = 3 / 2 ... (ans) ..

Like? Yes (2) | No (2)  

SUPROTIM PAUL   10 years AGO

by solving two equations we get the value of U & V

Like? Yes (1) | No (1)  

ram kiran   10 years AGO

substitute the options in equations

Like? Yes (1) | No (1)  

indu   10 years AGO

multiply equation (ii) with 2 and subtract from equation(i) then we will get
u=1,
by substituting u=1 in any of the two equations we will get
v=3/2.

Like? Yes (1) | No (1)  

P.Selva Dhasni   10 years AGO

Answer is 6) u=1, v=3/2

3(2u+v)=7uv => 6u+3v=7uv => i)
3(u+3v)=11uv => 3u+9v=11uv =>ii)

multiply 2nd equation with -2.we get,

-6u-18v=-22uv => ii)

now solve the two equations,

6u+3v = 7uv
-6u-18v= -22uv

the solutions are,

u=1 and v=3/2..........:)

Like? Yes (1) | No (1)  

Vivek Jain   10 years AGO

11*(i) - 7*(ii),we get
45u=30v
checking by option we get u=1,v=3/2

Like? Yes (1) | No (1)  

vishnuvardhan   10 years AGO

-5u=uv*-10/3
v=3/2,u=1

Like? Yes (1) | No (1)  

kedasu suresh   10 years AGO

from given equations

Like? Yes (1) | No (1)  

rahul   10 years AGO

by solving the equation u=1, v=3/2

Like? Yes (1) | No (1)  

karthik hariharan   10 years AGO

3(2u+v)=7uv *3
3(u+3v)=11uv *6

solve this equation in eliminating method..
u=1,v=3/2

Like? Yes (2) | No (2)  

Santosh Vishwakarma   10 years AGO

just put the values
u=1 and v=3/2.

Like? Yes (1) | No (1)  

R.RAVIKUMAR   10 years AGO

From given eqns,
6u+3v = 7uv
3u+9v = 11uv
By solving two eqns, we get u=1 and v=3/2

Like? Yes (1) | No (2)  

Rajasekhar Reddy   10 years AGO

6u+3v = 7uv
3u+9v = 11uv

solving above two equations we get
u = 1
v = 3/2

Like? Yes (1) | No (2)  

RAKESH   10 years AGO

3(2u+v) = 7uv => 2/v + 1/u = 7/3 ---(1)

3(u+3v) = 11uv => 1/v + 3/u = 11/3 ---(2)

(1)*3-(2)
v=3/2 & u=1

Like? Yes (1) | No (2)  

ChinnaChowdaiah   10 years AGO

6u+9v=21uv -->(1)*3
3u+54v=11uv--->(2)*6
18u+9v=21uv
18u+54v=66uv
by solving this u=1
v=3/2

Like? Yes (1) | No (2)  

Soumya   10 years AGO

3(2u+v)=7uv=>6u+3v=7uv=>eqn*3=>18u+9v=21uv...........(1)
3(u+3v)=11uv=>3u+9v=11uv=>*by 6=>18u+54v=66uv........(2)
Now solvin eqn 1&2 we get
U=1 and v=3/2 hence option 6 is the answer.

Like? Yes (2) | No (3)  

virendra dubey   10 years AGO

3(2u+v)=7uv.==>6u+3v=7uv..(i)
3(u+3v)=11uv==>3u+9v=11uv..(ii)
now multiplying eq2 by 2
we get
6u+18v=22uv..(iii)
now subtract equation 3 from eq1
we get u=1 and v=3/2 so correct option(6)

Like? Yes (1) | No (2)  

Rashmi bharti   10 years AGO

the equations are
(3/v)+(9/u)=11
(6/v)+(3/u)=7
on solving we get,u=1 & v=3/2

Like? Yes (2) | No (3)  

rajesh   10 years AGO

by data

Like? Yes (1) | No (2)  

Bharat Bhushan Jha   10 years AGO

Satisfy only option 6

Like? Yes (1) | No (2)  

Soham Dalwadi   10 years AGO

6u + 3v = 7uv (i)
3u + 9v = 11uv (ii)
(i)

Like? Yes (1) | No (2)  

pawan kumar chhipa   10 years AGO

6u+3v=7uv .....(i)
3u+9v=11uv .....(ii)

equation (ii) multiply by 2 and subtract from (i)

15= 15u
u=1
and get v=3/2

Like? Yes (1) | No (2)  

champavat jaydipsinh padamsinh   10 years AGO

6u + 3v = 7uv (i)
3u + 9v = 11uv(ii)

equ(i) multiply by 6
equ(ii)multiply by 3

so,
18u + 9v =21uv
18u + 54v=66uv

solve both equ than

u = 1

v = 3/2

Like? Yes (1) | No (2)  

Snehasis   10 years AGO

the equations can be made are :
6u+3v=7uv(i)
3u+9v=11uv(ii)
After solving the equations,
u= 1 and v = 3/2

Like? Yes (2) | No (3)  

sandip   10 years AGO

3(2u+v)/3(u+3v)=7/11
or,22u+11v = 7u+21v
or,u=2v/3
let put the value of u in any equation we can get the value of v.
so V=2/3 and U=1.
hence ans is option 6.

Like? Yes (1) | No (2)  

Baburaya   10 years AGO

solve the simultaneous eqn . . .

Like? Yes (1) | No (2)  

nikhil   10 years AGO

on solving equations we u=1
and putting this value in any one equation we get v=3/2.

Like? Yes (1) | No (2)  

sethupathi.p   10 years AGO

solving the equation

Like? Yes (1) | No (2)