What is the next number of the following sequence 11, 15, 51, 87, 312, 348,........

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28 Apr 2014 Sequence What is the next number of the following sequence 11, 15, 51, 87, 312, 348,........: OPtion
1) 384
2) 400
3) 436
4) 472
5) 476
6) 548
7) 573
8) 648
9) 701
10)None of these; Correct Option: 7 Best Solution (38)

Pradeep 10 years AGO

573 {11;1+1=2;11+2^2=15;;15+6^2=51;;51+6^2=87 SIMILARLY 348+(3+4+8)^2=573}

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llamar 10 years AGO

11+(1+1)^2=15
15+(1+5)^2=15+36=51
51+(5+1)^2=51+36=87
87+(8+7)^2=87+225=312
312+(3+1+2)^2=312+36=348
348+(3+4+8)^2=348+225=573

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Hanish 10 years AGO

11,15,51,87,312,348,.........
11=(1+1)=2
15=(11+2^2)
15=(1+5)
51=(15+6^2)
similarly,
348=(3+4+8)
therefore required no. is:-n=(348+15^2)=573

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sravanibatchu 10 years AGO

348+square(3+4+8)=573

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nirmal kumar saini 10 years AGO

11+(1+1)^2=15;
15+(1+5)^2=51;
51+(5+1)^2=87;
87+(8+7)^2=312;
312+(3+1+2)^2=348;
348+(3+4+8)^2=573;
so 573 is the answer

Like? Yes (3) | No (3)

SriS 10 years AGO

11,15,51,87,312,348..
11-15=4(1+1=2,2*2=4)
15-51=36(1+5=6,6*6=36)
51-87=36(5+1=6,6*6=36)
312-87=225(8+7=15,15*15=225)
348-312=36(3+1+2=6,6*6=36)
so answer is 3+4+8=15...15*15=225
348+225=573

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ANUP KUMAR 10 years AGO

11+(1+1)^2 = 15
15+(1+5)^2 = 51
87+(8+7)^2 = 312
312+(3+1+2)^2 = 348
348+(3+4+8)^2 = 573

Like? Yes (3) | No (4)

ABHOY KUMAR 10 years AGO

ANSWER:573
11+2^2=15;(2^2 BECOZ 11 IS WRITTEN AS (1+1)^2)
15+6^2=51;(6^2 BECOZ 15 IS WRITTEN AS (1+5)^2)
51+6^2=87;(6^2 BECOZ 51 IS WRITTEN AS (5+1)^2)
87+15^2=312;(15^2 BECOZ 87 IS WRITTEN AS (8+7)^2)
312+6^2=348;(6^2 BECOZ 312 IS WRITTEN AS (3+1+2)^2)
348+15^2=573(15^2 BECOZ 348 IS WRITTEN AS (3+4+8)^2)

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subramani 10 years AGO

11
11+(1+1)^2=15
15+(1+5)^2=51
51+(5+1)^2=87
87+(8+7)^2=312
312+(3+1+2)^2=348
like that..
348+(3+4+8)^2=573
So the Answer is "573" Option 7)

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OM PRAKASH JHA 10 years AGO

11
15=11+(1+1)*(1+1)
51=15+(1+5)*(1+5)
87=51+(1+5)*(1+5)
similarly,348+(3+4+8)+(3+4+8)=573

Like? Yes (1) | No (2)

Ann Theressa 10 years AGO

next number = previous number + square of sum of digits of previous number

11 + (1+1)^2 = 15
15 + (1+5)^2 = 51
51 + (5+1)^2 = 87
87 + (8+7)^2 = 312
312 + (3+1+2)^2 = 348
348 + (3+4+8)^2 = 573

Like? Yes (3) | No (5)

Devendra Marghade 10 years AGO

11+(1+1)^2=11+4=15
15+(1+5)^2=15+36=51
51+(5+1)^2=51+36=87
87+(8+7)^2=87+225=312
312+(3+1+2)^2=312+36=348
348+(3+4+8)^2=348+225=573

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Nitesh Joshi 10 years AGO

348+(3+4+8)^2= 348+225= 573
next no= no + (sum of digits)^2

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Md Shahid Akhter 10 years AGO

11+(1+1)^2 = 15
15+(1+5)^2 = 51
87+(8+7)^2 = 312
312+(3+1+2)^2 = 348
348+(3+4+8)^2 = 573

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AJAY KUMAR 10 years AGO

3+4+8=15
348+(15^2)=573

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Grishma Shah 10 years AGO

11
11+ (1+1)^2 = 15
15+ (1+5)^2 = 51
51+ (5+1)^2 = 87
87+ (8+7)^2 = 312
312+ (3+1+2)^2 = 348
348+ (3+4+8)^2 = 573

Like? Yes (1) | No (3)

Varunraj Reddy 10 years AGO

Given sequence 11,15,51,87,312,348,...

Take 1st number in the sequence 11=>1+1=2=>2^2=4
11+4=15(2nd number)

Take 2nd number 15=>1+5=6=>6^2=36
15+36=51(3rd number)
.........
.........
similarly,
348=>3+4+8=15=>15^2=225
348+225=573 option 7)

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Gitanjali K 10 years AGO

1+1=2
11+2^2=15
1+5=6
15+6^2=51
5+1=6
51+6^2=87
8+7=15
87+15^2=312
3+1+2=6
312+6^2=348
3+4+8=15
348+15^2=573 is the answer

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DHIRENDRA 10 years AGO

Given
11, 15, 51, 87, 312, 348,........
first term
11=11+(1+1)^2=11+4=15
15=15+(1+5)^2=15+36=51
51=51+(5+1)^2=51+36=87
same as
348=348+(3+4+8)^2=348+225=573

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Satish Zod 10 years AGO

Add square of sum of individual digits of a number to same number.

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Mahalakshmi 10 years AGO

11
11+(1+1)^2=15
15+(1+5)^2=51
51+(5+1)^2=87
87+(8+7)^2=312
312+(3+1+2)^2=348
348+(3+4+8)^2=573
so ans is 7)573

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harshal agrawal 10 years AGO

11 + (1+1)^2 = 15
15 + (1+5)^2 = 51
51 + (5+1)^2 = 87
87 + (8+7)^2 = 312
312 + (3+1+2)^2 = 348
348 + (3+4+8)^2 = 573

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Aman 10 years AGO

Next term is the sum of previous term and the square of the sum of its digits.
11, 15, 51, 87, 312, 348,.......
15= 11+(1+1)^2
51= 15+(1+5)^2
..

next no will be 348+(3+4+8)^2= 348+15^2= 348+225=573

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Dr.Dipin Singh 10 years AGO

11+(1+1)^2=11+4=15
15+(1+5)^2=15+36=51
..
..
so 348+(3+4+8)^2=573 .. option 7

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DILEEP KUMAR 10 years AGO

11 + (1+1)^2 = 15,
15 + (1+5)^2 = 51
51 + (5+1)^2 = 87.
.....
348 + ( 3+ 4+8)^2 = 573

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Govind raj 10 years AGO

(sum of digit)^2 then add to next...as
11=(1+1)^2=4..11+4=15
15=(1+5)^2=36..36+15=51
51=(5+1)^2=36..36+51=87
87=(8+7)^2=225..225+87=312
312=(3+2+1)^2=36..312+36=348
lly (3+4+8)^2=225+348=573

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indrajeet yadav 10 years AGO

11+(1+1)^2=11+4=15
15+(1+5)^2=15+36=51
51+(5+1)^2=51+36=87
87+(8+7)^2=87+225=312
312+(3+1+2)^2=312+36=348
348+(3+4+8)^2=348+225=573

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Anantharaman 10 years AGO

Formula:
Add the previous number square of sum of digits in previous number in sequence
11
11+(1+1)^2=11+(2)^2=11+4=15
15+(1+5)^2=15+(6)^2=15+36=51
51+(5+!)^2=51+(6)^2=51+36=87
87+(8+7)^2=87+(15)^2=87+225=312
312+(3+1+2)^2=312+(6)^2=312+36=348
348+(3+4+8)^2=348+(15)^2=348+225=573

Answer Option 7

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TUSHAR 10 years AGO

573

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adarsh yadav 10 years AGO

15-11=4,which is the square of 1+1 i.e 2,
51-15=36,which is the square of 1+5 i.e 6,
87-51=36,which is the square of 5+1 i.e 6,
312-87=225,which is the square of 8+7 i.e 15,
348-312=36,which is the square of 3+1+2 i.e 6,
similarly,573-348=225,which is the square of 15,
and hence the answer is 573

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OM PRAKASH JHA 10 years AGO