If in coded language MOHAN = 24 SALIM = 22 SURESH = 63 Then YASHAR = ?

M4maths Previous Puzzles

30 May 2014 Coded Language

If in coded language
MOHAN = 24
SALIM = 22
SURESH = 63
Then
YASHAR = ?

OPtion

1) 27
2) 32
3) 51
4) 54
5) 90
6) 29
7) 43
8) 36
9) 30
10)None of these

Solution

A(1), B(2), C(3), D(4), E(5), F(6), G(7), H(8), I(9), J(10), K(11), L(12), M(13), N(14), O(15), P(16), Q(17), R(18), S(19), T(20), U(21), V(22), W(23), X(24), Y(25) ,Z(26)
MOHAN = (M+O+H+A+N)-(M+N)
MOHAN = (13+15+8+1+14)-(13+14) = 51-27 = 24
SALIM = (19+1+12+9+13)-(19+13) = 54-32 = 22
SURESH = (19+21+18+5+19+8)-(19+8) = 90-27 = 63
Similarly
YASHAR = (25+1+19+8+1+18)-(25+18) = 72-43 = 29
Option 6)

Correct Option: 6 Best Solution (16)

Saraswathy   10 years AGO

MOHAN = O+H+A => 15+8+1 = 24
SALIM = A+L+I => 1+12+9 = 22
SURESH = U+R+E+S => 21+18+5+19 = 63
Then
YASHAR = A+S+H+A => 1+19+8+1 = 29

Ans : 29 (Option 6)

Like? Yes (5) | No (3)  

rajani   10 years AGO

By adding the sum except first and last letters
we will get the result.
15+8+1=24
ALI-->1+12+9=22
URES-->21+118+5+19=63
So for YASHAR,
ASHA-->1+19+8+1=29

Like? Yes (3) | No (3)  

Ann Theressa   10 years AGO

Add the number corresponding to the middle alphabets

MOHAN = 15+8+1 = 24
SALIM = 1+12+9 = 22
SURESH = 21+18+5+19 = 63
YASHAR = 1+19+8+1 = 29

ans: option 6) 29

Like? Yes (3) | No (3)  

Udhaya kumar   10 years AGO

sum of alphanumeric values except first & last..
in YASHAR A+S+H+A+R = 29............

Like? Yes (3) | No (3)  

Dada Khalandar   10 years AGO

MOHAN=13+15+8+1+14
in these eliminate first and last numbers and then add remaining nubers then we get 24.
similarly as SALIM&SURESH WE GET 22&63
THEN
YASHAR=25+1+19+8+1+18
in above series eliminate last and first number and then add remaining number as 1+19+8+1 we get ans:29

Like? Yes (2) | No (2)  

Akhil K Ashok   10 years AGO

It the sum of the number of alphabets in the middle

Like? Yes (2) | No (2)  

SAMRIDHI   10 years AGO

MOHAN= O+H+A+N=15+1+8=24
SALIM= A+L+I=1+12+9= 22
SURESH= U+R+E+S= 21+18+5+19=63
YASHAR= A+S+H+A= 1+19+8+1= 29

Like? Yes (2) | No (2)  

SREEVIDHYA P P   10 years AGO

A=1, B=2,c=3,.............
MOHAN=24
O+H+A=15+8+1=24
SALIM=22
A+L+I=1+12+9=22
SURESH=63
U+R+E+S=21+18+5+19=63
Then YASHAR=A+S+H+A=1+19+8+1=29
So answer is 29.option 6

Like? Yes (2) | No (2)  

Dinesh thatti   10 years AGO

exclude 1st letter & last letter add sum of remaining letters we get answer
mohan o+h+a=24
salim a+l+i=22
suresh u+r+e+s=63
yashar a+s+h+a=29

so answer is 29

Like? Yes (2) | No (2)  

pawan kumar chhipa   10 years AGO

we eliminate last character in the word
MOHAN became =OHA
put their weight (like A=1,B=2..)
15+8+1 =24
like that we do with our question
YASHAR = ASHA
A=1;S=19;H=8
1+19+8+1 = 29
Ans is 29
option 6) 29

Like? Yes (2) | No (2)  

susmit   10 years AGO

total of all letters except first and last.
taking A:=1 B:=2 AND SO ON

Like? Yes (2) | No (3)  

pankaj kumar   10 years AGO

MOHAN -> OHN -> 15+8+1 =24
SALIM -> ALI -> 1+12+9 =22
SURESH -> URES -> 21+18+5+19 =63
THEN YASHAR -> ASHA -> 1+19+8+1 =29

Like? Yes (2) | No (3)  

K Venkata Subba Rao   10 years AGO

sum all the characters except 1st & last chars
ans 29

Like? Yes (1) | No (3)  

srilakshmi   10 years AGO

sum of the corresponding letters except 1st and last
so,
Y A S H A R = (1+19+8+1) = 29
24 1 19 8 1 18
________

Like? Yes (1) | No (3)  

Varunraj Reddy   10 years AGO

MOHAN=24
Remove first and last alphabets and add remaining
alphabets
O+H+A=15+8+1=24
....
Similarly
YASHAR=A+S+H+A=1+19+8+1=29 [Option 6]

Like? Yes (1) | No (3)  

hareesh   10 years AGO

O+H+A+N=24
--
--
A+S+H+A=29

Like? Yes (1) | No (3)