The sum of 3 different non-zero single digit integers is 11. What will be the probability for the gr

BHANU KUMAR   10 years AGO

sample space= 1,2,3
1,3,7
1,4,6
2,3,6
2,4,5
n(s)=5
event =6,1,4
6,2,3
n(e)=2
p=n(e)/n(s)
p=2/5

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Ravi Kumar Kodari   10 years AGO

Possibilities are 8 1 2
731
623
641
542

in this only two are having 6 as greatest number.

2/5

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Ramesh Sriram   10 years AGO

8 1 2
7 3 1
6 2 3
6 4 1
5 4 2

there r two possibilities with Greatest number as 6

2/5

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Ann Theressa   10 years AGO

possible outcomes are - (1,2,8) , (1,3,7),(1,4,6),(2,3,6) and (2,4,5)

required outcome - (1,4,6) , (2,3,6)

probability = 2/5

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KRISHNA CHANDRA UPADHYAY   10 years AGO

no. of event=2
total no. of sample points in a sample space=5
therefore, required probability=no. of event/total no. of sample points in a sample space
=2/5

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BITU KUMAR NIRALA   10 years AGO

Event Space=2,
Sample Space=5,
so p=2/5

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Harshad    10 years AGO

1+2+8=11
1+3+7=11
1+4+6=11
2+3+6=11
2+4+5=11
total 5 combinations,
Out of which 2 has "6" as greatest digit,so probability is 2/5

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paaredi muthyam reddy   10 years AGO

8 1 2
7 3 1
6 2 3
6 4 1
5 4 2
there are two possibilities with 6 as greatest number among 5 possibilities

2/5

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HARDIP BHALANI   10 years AGO

1+2+8=11
1+3+7=11
1+4+6=11
2+3+6=11
2+4+5=11
total 5 combinations,
Out of which 2 has "6" as greatest digit,so probability is 2/5

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GOKULARAMANAN   10 years AGO

POSSIBLE SOLUTION IS 6+1+4,6+2+3,8+2+1,7+1+2,5+4+2
FROM ABOVE POSSIBLE TWO POSSIBLES ARE SATISFIES THE CONDITION .PROBABILTY IS 2/5,

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sandhya rani   10 years AGO

{6,4,1},{5,4,2},{6,2,3},{4,4,3},{5,3,3}
is are possible combinations
among them probability for the greatest integer to be 6 is 2/5

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sompon temtheerakij   10 years AGO

1 2 8
1 3 7
1 4 6
2 3 6
2 4 5

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RANJAN KUMAR PANDIT   10 years AGO

1 2 8
1 3 7
1 4 6
2 3 6
2 4 5
so possibility is : 2/5

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Jeniffer.D   10 years AGO

Let the three different non-zero single digit integers be
1 2 8
1 3 7
1 4 6
2 3 6
2 4 5
The probability that the greatest number is 6 is 2/5

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krishna kanth   10 years AGO

numbers will be 812,713,623,614,542,

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Raghvendra Pratap Singh   10 years AGO

All possible cases are:
1,2,8
1,3,7
1,4,6
2,3,6
2,4,5
Hence pblty of 6 being the greatest is : 2/5

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NEHA AGRAWAL   10 years AGO

since only 641,632 are favorable ourcomes from possibilities including 542,731,821 so 2/5.

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suman kumar pan   10 years AGO

The possible combinations are
8,2,1
7,1,3
6,1,4
6,2,3
5,2,4
So the probability is ..... 2/5

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sahil kumar jain   10 years AGO

total of 5 solutions are there ...but only 2 solutions are possible if 6 is
greatest number

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Sundar Kumar   10 years AGO

The sum of 3 different non-zero single digit integers is 11.
so possibles are 1+2+8=11, 1+3+7=11, 1+4+6=11, 2+3+6=11, 2+4+5=11.
And probability for the greatest integer to be 6. so here 2 (i.e 1+4+6=11, 2+3+6=11)

Answer 2/5 (i.e: probability for the greatest integer to be 6 /The sum of 3 different non-zero single digit integers is 11).

Answer : option 9) 2/5

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vibhu raj gupta   10 years AGO

by solving it's find that only 5 pairs are created for sum 11 which are 632,641,731,821,542. for 6 highest integer probability is 2 out of 5

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sangita kumari   10 years AGO

n(S)=(1,4,6),(1,2,8),(1,3,7),(2,3,6),(2,4,5)=5
n(E)=(1,4,6),(2,3,6)=2

p(E)=n(E)/n(S)=2/5

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Ashwin Dinesh   10 years AGO

All possible combinations to get 11 are:
1 + 2 + 8
1 + 3 + 7
1 + 4 + 6 BINGO!
2 + 3 + 6 BINGO!
2 + 4 + 5
So, You have 2 out of 5 combinations where you have largest integer as 6.
So probability would be 2/5
Which is option 9) 2/5.

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T.Aravinth kumar   10 years AGO

6/15

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Pranshu Chaurasia   10 years AGO

146,326 have 6,6 combinations and rest 173,128,524 also have 6 combinations each.so total outcome=30 and favorable=12.
probability=12/30=2/5

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vimal   10 years AGO

2/5+2/5+2/5=6/5
In this highest integer is 6 and the sum of both number is 11.
So,answer will be 2/5(option 9)

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naina   10 years AGO

the possilble pairs can be 8,2,1
7,3,1
6,4,1
5,4,2
6,3,2
Total no of cases =5
req cases in which 6 is the greatest integer of all=2
probability=2/5

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shabih abbas   10 years AGO

the combinations formed are
(1,2,8)
(1,3,7)
(1,4,6)
(2,3,6)
(2,4,5)
so the total combination is 5 and the combination which contain greatest integer 6 are (1,4,6) & (2,3,5)
so the probabilty is 2/5

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Varunraj Reddy   10 years AGO

probability=12/30=2/5

Option 9)

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Saraswathy   10 years AGO

Total no. of ways that gives a sum 11 is
(1,2,8)
(1,3,7)
(1,4,6)
(1,5,5)
(2,3,6)
(2,4,5)
Totally 5 ways [since nos should be different... (1,5,5) is not allowed]
No. of combinations having the greatest integer 6 => 2
(1,4,6) nd (2,3,6)

Probability ll be 2/5

Ans : 2/5 (Option 9)

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Ravi Bhalani   10 years AGO

1+2+8=11
1+3+7=11
1+4+6=11
2+3+6=11
2+4+5=11
total 5 combinations,
Out of which 2 has "6" as greatest digit,so probability is 2/5

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Sneha Goel   10 years AGO

there are 5 possibilities: (6,3,2)
(6,4,1)
(8,2,1)
(7,3,1)
(5,4,2)
hence, probability= 2/5

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DILEEP KUMAR   10 years AGO

5 2 4
6 4 1
6 3 2
7 3 1
8 1 2

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JANARTHANAN RAM   10 years AGO

options are (6,4,1),(7,3,1),(8,2,1)(6,3,2)(5,4,2)
so 2/4=2/5

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Tark Patel   10 years AGO

Using 5 summations,
1+2+8
1+3+7
1+4+6
2+3+6
2+4+5

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venkatesh   10 years AGO

(1,2,8) (1,3,7) (1,4,6) (2,3,6) (2,4,5) only two possibilities are there
so the answer is 2/5

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Rakesh Kumar Jangam   10 years AGO

(1,2,8) (1,3,7) (1,4,6) (2,3,6) (2,4,5)

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uma nath jha   10 years AGO

total possibility : 8,2,1
7,3,1
6,4,1
6,3,2
5,4,2

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LOKESH SAMANT   10 years AGO

2/5

(1,2,8) (1,3,7) (1,4,6) (2,3,6) (2,4,5)

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MRITUNJAY KUMAR   10 years AGO

The total possibilities to get sum of three digit to be 11.
7+3+1
6+3+2,
6+4+1
5+2+4
2+8+1
the probability for the greatest integer to be 6.=2/5.
option 9).

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siddhant   10 years AGO

Considering 6 as a solution...the remaining values come as (7,-2),(8,-3),(9,-4),(-2,7),(-3,8),(-4,9),(1,4),(2,3),(3,2),(4,1).

Therefore 6 is greatest in 4 cases out of 10... Therefore 2/5

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RAHUL RANJAN   10 years AGO

we have the the sample space
(1,2,8)
(1,3,7)
(1,4,6)
(2,4,5)
(2,3,6)
so..n(s)=5
andn(E)=2
so,probablity=2/5

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pulkit goyal   10 years AGO

following possibilities are:
1+2+8
1+3+7
1+4+6
2+3+6
2+4+5
therefore,probability is 2/5

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Ajay Meena   10 years AGO

8+2+1=11
7+3+1=11
6+4+1=11
6+3+2=11
5+4+2=11

then 2/5 (6 coming twice)

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Jasmine Khan   10 years AGO

total number of words=10
total possible numbers having 6 as the greatest number=2
P(6 is the largest number)=4/10=2/5

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Rahul Pandey   10 years AGO

8+2+1=11
7+3+1=11
6+4+1=11
6+3+2=11
5+4+2=11
total 5 cases... out of which in 2 cases 6 is the greatest.
hence p=2/5

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Bishwajeet kumar   10 years AGO

sum of 11 will be formed using combination: (128)=6ways,(236)=6ways,(245)=6ways,(173)=6ways,(164)=6ways
so total possible=30
& total favourable will be(236),(164)=12
so prob.=12/30=2/5

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