Two pipe M and N can fill a cistern in 24 minute and 32 minute respectively. If both the pipes are o

Divyanshu Gupta   10 years AGO

Since M remained open for 18 min.
so ,amount of work completed by M in 18 min is 18/24=3/4
Work remaining 1-3/4=1/4
N should be opened for= 32*1/4=8 Minutes is the answer

Like? Yes (23) | No (1)  

Saraswathy   10 years AGO

Let the pipe N is closed after x minutes
18/24 + x/32 = 1
Solving, we ll get x = 8

Ans : 8 (Option 6)

Like? Yes (28) | No (9)  

piyush ranjan behera   10 years AGO

M works for 24min and N works for 32 min.
LCM (24,32)= 96
both M and N together work for 96 unit to complete the total work
M can do 96/24=4 unit per min
N can do 96/32=3 unit per min
both can do (4+3)= 7 unit per day
so in 18min they can do 18*7= 126 unit
but we need only 96 unit so we have to reduce 126-96= 30 unit that will be not performed by N

so 30/3( N's Unit work) = 10 min
N not work for 10 min
so After 8 min N pipe should be closed.

Like? Yes (21) | No (11)  

Sourojit Dhua   10 years AGO

In 18 mins. M can fill 3/4th of the tank.
So, time taken by N to fill remaining 1/4th= 8 mins.

Like? Yes (15) | No (8)  

SAURADIPTA SADHU   10 years AGO

M does (1/24) part in one minute. So he will do (18/24)=(3/4) part of the work in 18 minutess.
So for remaining (1/4) part, N has to remain open for (32/4)=8 minutes

Like? Yes (6) | No (2)  

Kataria Deepak   10 years AGO

M 1 min work = 1/24
N 1 min work = 1/32
suppose N closed after x minutes
then

part filled by M & N in x min + part filled by M in (18-x) min = 1

x(1/24 + 1/32) + (18-x) *1/24 = 1
7x/96 + (18-x)\\\\24 = 1
7x + 4(18-x) = 96
7x-4x = 96-72
3x = 24
x =8


hence N closed after 8 min

Like? Yes (9) | No (5)  

KRISHNA CHANDRA UPADHYAY   10 years AGO

M and N in 1 Min can fill=(1/24) + (1/32) =7/96

in 8 minute M and N can fill=(7/96) * 8 =7/12

Like? Yes (6) | No (3)  

sompon temtheerakij   10 years AGO

rate of pipe M+N = 1/24+1/32 = 7/96 cis./min
Let X = the time of M+N
7/96X+1/24(18-X) = 1
7X - 4X = 96-72
X = 8
So,in 8 mins. N should be closed so that the tank is full in 18 minute

Like? Yes (1) | No   

Sailaja   10 years AGO

LCM of 24 and 32 is 96. Let tank is of 96 litres. M fills with 4ltrs/min and N with 3ltrs/min. If x is time for which both are open. Then x*(3+4) + (18-x)*4 = 96. This implies x as 8

Like? Yes (3) | No (2)  

amit baranga   10 years AGO

(18/24)+(x/32)=1
X=8

Like? Yes (3) | No (2)  

Rammohana rao Balaga   10 years AGO

let the capacity of cistern is X
then M can fill X/24 in 1 min.
N can fill in X/32 in 1 min.

as M is continuous..
M will fill 18* X/24 part in 18 mins.
and remaining X - (18*(X/24)) = X/4 part.
N need to be open for filling this X/4 part only.
so. N * X/32 = X/4 ==> 8 mins.

after 8 mins N should be closed.

Like? Yes (3) | No (2)  

Kaushlesh Kumar   10 years AGO

M is opened for 18 minutes,since it fills the tank (100%) in 24 mins,in 18 mins it will fill 18/24*100=75%
The remaining 25% is filled by N,it fills the tank(100%) in 32 mins,it will fill the tank 25% in 25/100*32=8 mins

Hence N must be closed after 8 mins

Like? Yes (3) | No (2)  

swarupa nuggu   10 years AGO

X (1/24+1/32)+(18-x)(1/24)=1
X=8

Like? Yes (2) | No (2)  

Grishma Shah   10 years AGO

x/24 + x/32 + (18-x)/24 = 1
7x - 4x - 72 = 96
3x - 72 = 96
3x = 24
x = 8

Like? Yes (3) | No (3)  

natuva aditya   10 years AGO

x(1/24+1/32)+(18-x)*1/24)=1
by solving the above equation,
we get x=8 minutes. pipe N should be closed after 8 minutes

Like? Yes (1) | No (2)  

Priya Dharshini   10 years AGO

work done by M in 1 min=1/24;
work done by N in 1 min=1/32;
therefore (M+N) work done in 1 min=(1/24+1/32);
let N has closed after x min;
totally cistern is filled in 18 mins;
so,(M+N)x+(18-x)M=1;
((1/24+1/32)x)+((18-x)1/24)=1;
solving this equation we get x=8 mins;
hence N have been closed after 8 mins;

Like? Yes (1) | No (2)  

amit vijayvargiya   10 years AGO

x(1/24+1/32)+(18-x)1/24=1
7x+4(18-x)=96
3x=24
x=8

Like? Yes (1) | No (2)  

srujan   10 years AGO

M can fill in one minute: 1/24
N can fill in one minute ;1/32
in 18 min M can fill ;18*1/24=3/4
and in 18 min N can fill :18*1/32=9/16
but 3/4+9/16=21/16
21/16-5/16=1
hence 5/16 is over flowing
so N should stop it so 5/16*32=10
hence 18-10=8

Like? Yes (1) | No (2)  

dheeraj   10 years AGO

after x min N pipe turned off

x(1/24+1/32)+(18-x)(1/24)=1
by solving x=8

Like? Yes (1) | No (2)  

usha   10 years AGO

Let B is closed after x min
x(1/24)+(18-x)*1/24=1
x=8

Like? Yes (1) | No (2)  

Aravinthkumar   10 years AGO

In 18 min M fill the 3/4 of tank
and * min N fill the 1/4 of tank
so N off in 8 min.

Like? Yes (1) | No (2)  

Aravinth kumar   10 years AGO

In 18 min M fill the 3/4 of tank
and 8 min N fill the 1/4 of tank
so N off in 8 min.

Like? Yes (1) | No (2)  

RANJAN KUMAR PANDIT   10 years AGO

work done by m in 1 min= 100/24=4.25%
work done by n in 1 min= 100/32%
work done by m in 18 min=4.25*18=75%
so remaining 25% done by n in 8 minutes

Like? Yes (1) | No (2)  

ananthavalli   10 years AGO

Let N closed be x minute
x(1/24+1/32)+(18-x)*1/24=1
7x+4(18-x)=96
then x=8
N should be closed in 8 minute
so option 6) is correct

Like? Yes (1) | No (2)  

Madan   10 years AGO

let after x mins n should be closed
so
x/32+18/24=1
x=8

Like? Yes (1) | No (2)  

Shaik Riyaz   10 years AGO

Let N be closed after x minutes.
(M+N) in x min+(18-x)min=1min

Like? Yes (1) | No (2)  

suman kumar pan   10 years AGO

M fills 3/4 part & N fills 1/4 part ..so N is opened for (32*1/4)= 8

Like? Yes (1) | No (2)  

Nikhil chavan   10 years AGO

18/32+x/24=1
and x=8

Like? Yes (1) | No (2)  

Yamuna Muthusamy   10 years AGO

Let B must be closed in x minutes.
part filled by (A+B) in x min + part filled by A in (18-x) min =1
x((1/24)+(1/32))+(18-x)(1/24)=1
(7x/96)+((18-x)/24)=1
7x+4(18-x)=96
x=8
ans= 8 minutes

Like? Yes (3) | No (4)  

goli kiranmaye   10 years AGO

7x+(18-x)*4=96
x=8
96 is the lcm of 24 and 32

Like? Yes (3) | No (4)  

shree   10 years AGO

x/32+18/24=work done (1)
therefore x= 8

Like? Yes (1) | No (2)  

asish bidurendra chhotaray   10 years AGO

after 6 min N should be closed

Like? Yes (1) | No (2)  

Raghvendra Pratap Singh   10 years AGO

time taken by by both pipes together = (24*32)/(24+32)=96/7 mins
Suppose after x minutes second pipe was closed: then

7x/96 + (18-x)/24 = 1
Solve for x = 8.

Like? Yes (1) | No (2)  

MANU   10 years AGO

in 1 min M fill 1/24
in 1 min N fill 1/32
in 18 min M fill 18/24=3/4 part
remaining 1/4 part will fill by N IN 4/32=1/8
So N should be closed in 8 min.

Like? Yes (1) | No (2)  

saira fatma   10 years AGO

because M's i min work=1/24
N's 1min work=1/32
M's 18 min work+N's min work=1
18/24+x/32=1
x=8

Like? Yes (1) | No (2)  

Udhaya kumar   10 years AGO

8(1/24+1/32)+10(1/24)=1...........

Like? Yes (1) | No (2)  

Rajamohan Raju   10 years AGO

Both M & N can complete the work in 96/7 min.
In 8min both can finish 7/12th part of work.
The remaining 5/12th work can be completed by M in 10min.

Like? Yes (1) | No (2)  

azharshahid01@gmail.com   10 years AGO

M can fill in 1 minute= 1/24 part of cistern
M will fill cistern in 18 minute= 18*(1/24)= 3/4

Remaining empty part of cistern= 1/4.

N can fill in 1 minute= 1/32 part of cistern
N can fill in x minute= 1/4 part of cistern

on calculating, x=8

So, N should be closed on 8 minutes.

Like? Yes (3) | No (5)  

vinusha reddy   10 years AGO

let n be closed after x minutes
part filled m and n in x min=x(1/24+1/32)
part filled by m in 18-x min=1/24(x-18)
then x(7/96)+(18-x)/24=1
x=8 min

Like? Yes (2) | No (4)  

AMIT KUMAR ANAL   10 years AGO

Let N takes xmin
In 1 min, Cistern filled by M and N be 1/24 and 1/32 respectively.
Therefore, in 18 min M fills 18/24
Therefore, 18/24+x/32=1
Solving this eqn
We get x= 8

Like? Yes (1) | No (3)  

Devendra Marghade   10 years AGO

If both the pipes are open, then
1 min. filling=(1/24)+(1/32)=7/96
If both the pipes are open for 'x' min.,then N is closed after 'x' min. or only M is open for (18-x) min.
So, x*(7/96) + (18-x)*(1/24)= 1
On solving, x=8

Like? Yes (1) | No (3)  

Tark Patel   10 years AGO

M = 1/24 , N = 1/32
1/24*18 + 1/32*(18-M)=1
->18-M = 8
->M=10
so N,
18-10 =8
Answer is 8

Like? Yes (1) | No (3)  

RAVI RANJAN   10 years AGO

in 18 mins pipe M can fill 3/4th of the tank.
therefore, 1/4th can be filled by pipe n in 8 mins.
since,
8/32 = 1/4

Like? Yes (1) | No (3)  

naina   10 years AGO

M = 1/24 N =
1/32
1/24*18 + 1/32*
(18-M)=1
18-M = 8 M=10
so 18-10 =8

Like? Yes (1) | No (3)  

Satyaki    10 years AGO

pipe A will work for 18 minutes. suppose pipe B is closed after x minutes than
we have 18/24+x/32=1
x=8 minute.

Like? Yes (1) | No (3)  

Saranjit Singh   10 years AGO

If N is closed after x minutes , then
18/24 +x/32=1
x/32=1/4
x=8 mins

Like? Yes (2) | No (4)  

Palash Malani   10 years AGO

volume=v
speed of m=v/24
speed of n =v/32

together
18m+xn=v
18v/24 +xv/32 = v
x=8

Like? Yes (3) | No (5)  

Asha Praveena   10 years AGO

N is closed after x min..
Part fill by (M+N) in x min+Part filled by M in (18-x) min=1
x(1/24+1/32) + (18-x)(1/24)=1

7x+4(18-x)=96

3x=96-72

x=24/3

x=8 min

After 8 min N should be closed..

Like? Yes (1) | No (3)  

abhilasha   10 years AGO

M = 1/24 N = 1/32
1/24*18 + 1/32*(18-M)=1
18-M = 8 M=10 so 18-10 =8 B

Like? Yes (1) | No (3)  

Varunraj Reddy   10 years AGO

Let N closed after x min.
Then
1 part filled by M and N in x min+ another part filled by M in (18-x) min=1
=>(1/24+1/32)x+1/24(18-x)=1
By solving we get,
x=8

Option 6)

Like? Yes (2) | No (4)  

krishna kanth   10 years AGO

let total units be 96
Tap M fills it in 24 min i.e 4 units/min
Tap N fills it in 32 min i.e 3 units/min
if both opened together it fills 7 units/min
we say after x min we are closing tap N
7*x+4*(18-x)=96
3*x = 24
x=8min

Like? Yes (1) | No (3)  

Jigyasa Kumar   10 years AGO

M = 1/24 N = 1/32
1/24*18 + 1/32*(18-M)=1
18-M = 8 M=10 so 18-10 =8 B

Like? Yes (1) | No (3)  

Deepak Kumar   10 years AGO

1/24 *(18)+1/32*(n)=1
n=8

Like? Yes (1) | No (3)  

SAHIL DIWAN   10 years AGO

here pipe M is used for 18 minutes. so part of tank filled by =(1/24)*18=3/4
so remaining tank is to be filled by n i.e=(1-3/4)=(1/4)
so let n is open for x minutes
then x*(1/32)=1/4
x=8
so n must be closed after 8 minutes

Like? Yes (1) | No (3)  

nageshwarnk   10 years AGO

1/24 *(18)+1/32*(n)=1
n=8

Like? Yes (1) | No (3)  

Dharmendra   10 years AGO

1/24 *(18)+1/32*(n)=1
n=8

Like? Yes (1) | No (3)  

vimal   10 years AGO

Let N be close after x minute.
Then cistern filled by both M and N in x min
so, (1/24+1/32)*x=7x/96
Then certain is to be filled by M in (18-x)min
so, (18-x)*(1/24)=(18-x)/24
So,
(7x/96)+(18-x)/24=1
by solving x=8
So,N should be close after 8 minutes

Like? Yes (1) | No (3)  

shabih abbas   10 years AGO

M = 1/24 N = 1/32
1/24*18 + 1/32*(18-M)=1
18-M = 8 M=10 so 18-10 =8 B

Like? Yes (1) | No (3)  

Arijit Acharyya   10 years AGO

pipe M->in 24 units can fill the cistern
pipe N->in 32 units can fill the cistern
let,total work =HCF of 24 & 36 i.e, 96 units
now M->96/24=works 4 units/minute
N->96/32=works 3 units/minute
Together they work 4+3=7 units/minute
if N stop working after 8 minutes
they both work 8*7=56 units and rest of the work will be done by M
rest of work=96-56=40
M->4 units/minute so 40 units of work will be done in 10 minutes
total time they take to fill the cistern is 8+10=18 minutes
Ans:-option 6)

Like? Yes (1) | No (3)  

NUGGU SINDHURI   10 years AGO

Let both the tanks should be open for x min and the tank m should be open for 18-x min to full the tank

So he equ is
X (1/24+1/32)+(18-×) (1/24)=1

By solving this we ll get x=8

Like? Yes (1) | No (3)  

Sneha Goel   10 years AGO

part filled by M in 18 mins= 18/24
remaining= 1/4
remaining filled by N in 32*1/4 min= 8mins

Like? Yes (2) | No (4)  

potani manikumar   10 years AGO

here meaning M worked for 18 minutes and he completed 3/4th of work
one minute work of M is 1/24 th part then 18 minutes work is (1/24)18=3/4
N has to complete remaining 1/4th of work and he takes 8 minutes to complete 1/4th of work
(1/32)*8=1/4.

Like? Yes (1) | No (3)  

paaredi muthyam reddy   10 years AGO

18(1/24)+(18-x)(1/32)=1

where (18-x) is the actual time N is open

by solving above eqn we will get x=10

so ans is 8 mins

Like? Yes (2) | No (4)  

Ravi Kumar Kodari   10 years AGO

18(1/24)+(18-x)(1/32)=1

where (18-x) is the actual time N is open

by solving above eqn we will get x=10

so ans is 8 mins

Like? Yes (2) | No (4)  

avinash   10 years AGO

Let after x hrs the pipe b is closed... Then (7x/96)+((18-x)/24)=1

Like? Yes (1) | No (3)  

Satishbabu   10 years AGO

Work done by M in 1min=1/24, N=1/32,
=> work done by M&N in 1min=1/24+1/32=7/96,
the work done by both M&N in 8 mins=8*(7/96)=7/12,
If we close the pipe N now, M has to fill the remaining 5/12,
=> M can fill 1/24 in 1 min,
=> 5/12 can fill in 10 mins,
Therefore total time taken is 8+10=18 min,
Therefore we have to close N after 8 mins, Option is (6).

Like? Yes (1) | No (3)  

Ramesh Sriram   10 years AGO

18(1/24)+(18-x)(1/32)=1

where (18-x) is the actual time N is open

by solving above eqn we will get x=10

so ans is 8 mins

Like? Yes (2) | No (4)  

MRITUNJAY KUMAR   10 years AGO

The part of water tank filled by both the pipe in 1 min M&N=1/24+1/32= 7/96.
after 18 min work done by the pipe is 18*7/96=21/16.
the extra work done=21/16-1=5/16
the time taken by the N to fill that part=10min.
so the time after which N should be closed=18-10=8 min.
option 6)

Like? Yes (1) | No (3)  

gouthamdaneti   10 years AGO

(7x/96)+(18-x/24)=1
x is the time

Like? Yes (2) | No (4)  

Liti   10 years AGO

both pipe can work in 1 min= 7/96
both pipes in 8 min = 56/96
m in rest 10 min= 40/96

Like? Yes (2) | No (4)  

Navpreet Singh   10 years AGO

1/24*18 + 1/32*(18-M)=1
18-M = 8 M=10 so 18-10

Like? Yes (1) | No (3)  

guddu   10 years AGO

Let N be turned off after x minutes. Then,

Part filled by (M + N) in x min. + Part filled by M in (18 -x) min. = 1.
x(1/24+1/32)+(18-x)1/24=1
x=8

Like? Yes (1) | No (3)  

Ravi Bhalani   10 years AGO

M remains on for 18 min.
So,portion filled by M will be 18/24=3/4.
Remaining portion =1/4
So, N needs to be opened for 8 min.

Like? Yes (1) | No (3)  

JANARTHANAN RAM   10 years AGO

(18/24*100)+(8/32*100)=100%

Like? Yes (1) | No (3)  

Nilesh Dattatraya Veer   10 years AGO

In 8 minute work done by M and N=(1/24+1/32)*8=7/12
remain work =5/12
M took 24 min for 1
so x require for 5/12
x=(5/12)*24
x=10
so x+8=18 minutes

Like? Yes (2) | No (4)  

Harshad    10 years AGO

M remains on for 18 min.
So,portion filled by M will be 18/24=3/4.
Remaining portion =1/4
So, N needs to be opened for 8 min.

Like? Yes (1) | No (3)  

HARDIP BHALANI   10 years AGO

M remains on for 18 min.
So,portion filled by M will be 18/24=3/4.
Remaining portion =1/4
So, N needs to be opened for 8 min.

Like? Yes (1) | No (3)  

DIPAK TIWARI   10 years AGO

Let N should be closed after 'x' minutes.
Work done in x minute by N=x/32
Therefore remaining work=1-(x/32)
And work done by M in 18 minutes=18/24
Hence, 1-(x/32)=18/24
x/32=6/24
x=8minutes.

Like? Yes (1) | No (3)  

SRI MEENAKSHI   10 years AGO

Let N be turned off after x minutes.

Then Part filled by (M+N) in x min + Part filled by M in (18-x) min = 1

x (1/24+1/32) + (18-x)1/24 = 1

7x/96 + (18-x)/24 =1

7x +72 - x = 96

6x = 96- 72

x = 8

Therefore, N must be closed after 8 minutes.

Like? Yes (1) | No (3)  

Dark Knight   10 years AGO

Let the time be 'x' min when both M and N was working together.
then the equation comes as
x(1/24+1/32)+(18-x)*1/24=1
So after equating we get
7x+72-4x/96=1
3x+72=96
3x=24
x=8

Like? Yes (1) | No (3)  

samir kumar das   10 years AGO

M = 1/24 N = 1/32
1/24*18 + 1/32*(18-M)=1
3M=30
M=10 so 18-10 =8

Like? Yes (1) | No (3)  

Amrita priyadarshi   10 years AGO

m will fill 1/24 part in 1 minute and n will fill 1/32 part in 1 minute.
for 8 minutes both will work together and fill 7/12 part after that m will alone fill the tank. hence m will fill 10/24 part in next 10 minutes.
thus pipe n should be closed after 8 minutes.

Like? Yes (1) | No (3)  

VIMALRAJ V   10 years AGO

M = 1/24 N = 1/32
1/24*18 + 1/32*(18-M)=1
18-M = 8 M=10 so 18-10 =8
Therefore answer is 8(option 6)

Like? Yes (1) | No (3)  

Brijesh Rawat   10 years AGO

in 18 min. M will fill 18*(1/24)=3/4
rest part filled by N = 1/4
temi taken by N to fill 1/4 part= (1/4)*32= 8 min.

Like? Yes (1) | No (3)  

Udai Pratap Singh   10 years AGO

m=24minute n=32minute ---alone
LCM=96 UNIT total capacity
M can fill in one minute =4(96/24) unit of tank ,N can fill in one minute =3(96/32) unit of tank .
suppose after x minute n will close.
so, 18*4+x*3=96
x=8 minute
Ans -option =6

Like? Yes (2) | No (4)  

Pankaj Yogi   10 years AGO

using unitary method: M in 1 minute can fill 1/24 th of cistern and N in 1 minute can fill 1/32 th. in total if both are opened work done per minute will be 1/24+ 1/32. but as question says N is stopped after t minutes and M alone was open for full 18 minutes till the cistern is filled. therefore we can write:
1/24 * 18 + 1/34 * t = 1 (refers full cistern)
after solving you would get t= 8 mins.

Like? Yes (1) | No (3)  

Ashwin Dinesh   10 years AGO

its simple...

Like? Yes (1) | No (3)  

RAHUL RANJAN   10 years AGO

m is opened for entire 18 min
so it wiil fill 18/24=3/4 part
so remaining part is 1/4.
hence opening time for n is
(1/4)32=8 min ans

Like? Yes (1) | No (3)  

Anish Mathur   10 years AGO

M = 1/24 N = 1/32
1/24*18 + 1/32*(18-M)=1
18-M = 8 M=10 so 18-10 =8

Like? Yes (1) | No (4)  

BITU KUMAR NIRALA   10 years AGO

M and N in 1 Min can fill=(1/24) + (1/32) =7/96

in 8 minute M and N can fill=(7/96) * 8 =7/12

left to fill = 5/12

after N closed M can be fill in =(5/12)*24
= 10 Min

so, total Min =10+8
=18
so after 8 Min N should be closed

Answer:- 8 Min (option 6)

Like? Yes (1) | No (4)  

BHANU KUMAR   10 years AGO

one min work of M and N=(1/24)+(1/32)=7/96
let after x minutes N is closed.
then we have...
x*(7/96)+(18-x)*(1/24)=1
(7x+72-4x)/96=1
3x=24
so x=8 (option 6)

Like? Yes (1) | No (4)