How may iron rods, each of length 7 m and diameter 2 cm can be made out of .88 cubic metre of iron?

M4maths Previous Puzzles

06 Aug 2014 Volume and Surface Areas How may iron rods, each of length 7 m and diameter 2 cm can be made out of .88 cubic metre of iron?: OPtion
1) 100
2) 200
3) 300
4) 350
5) 390
6) 420
7) 460
8) 400
9) 460
10)None of these; Correct Option: 8 Best Solution (102)

sudhakar 10 years AGO

Convert the diameter value centimeter into meter=0.02m

Consider the iron rod (Cylinder) volume v=πr^2 h
v=3.14*(1/100)*7
v =0.2198

The number of iron rods in 88 cubic meter=(88/0.2198)
=400.3

Total number of iron rods is 400

Like? Yes (14) | No (6)

PAWAN KUMAR 10 years AGO

Firstly, convert everything to cm
7m=700cm,
0.88m^3= 0.88*100*100*100 cm^3= 88 *10,000 cm^3
Also, volume of one iron rod=pi*r*r*h= 22/7*1*1*700 cm^3
Therefore,
no. of iron rods= volume of iron/ volume of one rod
= (88*100*100)/(22/7*1*1*700)
= 400 Ans.

Like? Yes (5) | No

anandhakumar 10 years AGO

volume of cylinder=pi*r^2*h
no:of cylinders=88/(pi*(1*10^-2)7)
=88/0.2198
=400.36
=400

Like? Yes (11) | No (6)

Ramesh Sriram 10 years AGO

0.88/(22/7(.01*.01)*7)=400

Like? Yes (5) | No

Samrat Adhikari 10 years AGO

Given data,
L=7m, D=2cm=2/100m
V=.88 cum
Let, 'n' be the no. of rods can be made.
Now,
V=n*(π/4)(D*D*L)
putting the values & solving yields
n=400

Like? Yes (4) | No

Rahul shaw 10 years AGO

Radius = 2/2 cm = 1 cm = 0.01 cm.
Length = 7 m.
let x be the no. of iro rods can be made.
therefore, volume = (22/7)*(1/10000)*(7)*x = 88/100
x=400.

Like? Yes (2) | No

Sumit Ranjan 10 years AGO

volume of 1 iron rod=pi*r*r*h
i.e. (22*7)/(7*10000)cubic meter=22/10^4cubic meter
no of rods in 0.88 cubic mtr=0.88/[22/10^4]=400
hence ans=400

Like? Yes (1) | No

GOKULARAMANAN 10 years AGO

rods volume=pi*r^2*l=3.14*0.01^2*7=2.2*10^-3;
cube volume=0.88;
no.of rods=cube volume /rods volume;
ans=400;

Like? Yes (1) | No

JANARTHANAN RAM 10 years AGO

rod's volume=pi*r^2*l=3.14*0.01^2*7=2.2*10^-3;
cube's volume=0.88;
no.of rods=cube's volume /rod's volume=0.88/2.2*10^-3;
ans=400;

Like? Yes (3) | No (2)

prakash kumar 10 years AGO

volume of iron rod=22/7*1/100*1/100*7=22/10000 m^3

hence no of iron rods=0.88*10000/22=400

Like? Yes (1) | No

AKASH ROY 10 years AGO

no of rods = total cubic metre of iron/volume of 1 rod=400

Like? Yes (1) | No

Ayushi Gaur 10 years AGO

diameter=1m=1/100=.01cm
volume of iron rod=pi*(r2)*h=22/7*(.01)*(.01)*7
=.0022 meter cube
no of iron rods can made from .88 cubic meter of iron=.88/.0022=400

Like? Yes (1) | No

Sandip Dutta 10 years AGO

88/(100*(22/7)*7/10000)=400

Like? Yes (1) | No

MRITUNJAY KUMAR 10 years AGO

no of iron rods =0.88/3.14*(10^(-2))^2*7=400.

Like? Yes (1) | No

Sneha Goel 10 years AGO

no of cubes= volume of iron/volume of 1 bar

Like? Yes (1) | No

Tania Mondal 10 years AGO

vol of each iron rod=(22*7)/(7*100*100)=11/5000 m^3
so no of rods= 0.88*5000/11= 400

Like? Yes (1) | No

Manikumar R 10 years AGO

=0.88/pi*r^2*h
=0.88/2.34*1cm^2*7m
=400

Like? Yes (1) | No

Ravi Kumar 10 years AGO

volume of rod = (22/7)*7*.01*.01= .0022cubic metre

no of iron rods made = volume of iron/ volume of iron rod
=>.88/.0022 = 400

Like? Yes (1) | No

prabhat kumar 10 years AGO

88/(22/7*7*(1/100))

Like? Yes (1) | No

Arijit Acharyya 10 years AGO

V=22/7*r^2*h
let n number of iron rods can be made...
0.88=22/7*(2/200)^2*7*n
by solving
n=400
option 8)

Like? Yes (1) | No

ankit shw 10 years AGO

vol of cylinder 3.14*.01^2*7
no.of rods=.88/vo, of cylinder

Like? Yes (1) | No

NIRAJ KUMAR 10 years AGO

0.88/(pi*0.01^2*&)=400

Like? Yes (1) | No

manohar 10 years AGO

n*22/7*1cm^2*7=88
so n=400

Like? Yes (1) | No

RISHAV ANAND 10 years AGO

volume of one rod= (22/7)*0.01*0.01*7= 22/10000 cubic metre
total volume of iron = 0.88 cubic metre
no of rods= 0.88/0.0022= 400

Like? Yes (1) | No

Ravi Kumar Kodari 10 years AGO

0.88/(22/7(.01*.01)*7)=400

Like? Yes (1) | No

A.nagu 10 years AGO

0.88/((22/7)0.0001*7)

Like? Yes (1) | No

T.VIGNESWARA REDDY 10 years AGO

Volume of sphere is 4pir*r*h so volume of each iron rod is 4*(22/7)0.1*0.1*7=0.0022 so total volume is 0.88 so 0.88/0.0022=400

Like? Yes (1) | No

suman 10 years AGO

x=.88*(7/22)*(1/7)*(100*100)

Like? Yes (1) | No

PRIYANK BHARGAVA 10 years AGO

volume of cylindrical rod = 22/7 *1*700= 2200cm^3
so given volume of iron = 88*(100)^3=880000 cm^3

on dividing 880000/2200 = 400

Like? Yes (1) | No

Bittu 10 years AGO

volume of 1 rod = 3.14*7*0.01*0.01
no of rods=0.88/0.002198=400

Like? Yes (1) | No

shiv pujan 10 years AGO

vol of 1 rod=((22/7)*(1/100)*(1/100)*7)=11/5000 cubic m
vol of iron =.88 cu m
no of rods=.88/(11/5000)=400

Like? Yes (1) | No

Udhaya kumar 10 years AGO

V = X(A*L)
A = PI/4(D)^2
A = 3.14 * 10^-4
0.88 = X(A*7)
X = 400.16.............

Like? Yes (2) | No (1)

Rayapureddy V Sai Kiran 10 years AGO

volume of cylinder=pi*r^2*h=pi*0.01^2*7=2.199*10^-3
no of rods=0.88/volume of cylinder=400.16

Like? Yes (1) | No

gouthamdaneti 10 years AGO

find the volume and divide .88 with volume

Like? Yes (1) | No

Mounica Kakarlapudi 10 years AGO

volume of each rod =(3.14*7*0.01*0.01)
no. of rods = 0.88/(volume of each rod)

Like? Yes (1) | No

SAYAN CHATTERJEE 10 years AGO

volume of a rod=(22/7)r^2*h
so, 88*10^(-2)*10^6 = x*22/7*1^2*700
=> x= 400 -------------(8).

Like? Yes (1) | No

yagnik pandya 10 years AGO

According to volume of cylinder
Pi*r*r*h
We cn get 400

Like? Yes (1) | No

Arun Kumar Prasad 10 years AGO

volume of one rod=3.14*(.01)^2*7
=0.002198 cubic metre
no. of rods =.88/0.002198
=400 rods ANSWER

Like? Yes (1) | No

Anoop 10 years AGO

volume of rode is=
(22/7)*(.01)*(.01)*7=.0022
no of rods in .88 is -
0.88/0.0222 =400

option 8)

Like? Yes (1) | No

Aman Abhilash 10 years AGO

Since you have taken... 7 m and 2 cm so radius is 0.01 m...

Now we have: n*pi* l*r^2=88

We get n=40016

Like? Yes (1) | No

Pushpendra singh chundawat 10 years AGO

volume of single rod-
volume is given by-pi*r^2*h
given-r=1 cm,here centimeter to be converted into meter
length-7 meter
v=3.14*(1/10000)*7=.0022 m^3
hence no of rods-
0.88/.0022=400

Like? Yes (1) | No

Sandeep Negi 10 years AGO

Total volume /volume of rod

Like? Yes (1) | No

Dheeraj Kumar 10 years AGO

(.88*1000000)=n*22/7*1*1*7*100
n=400
where n= no. of iron rods

Like? Yes (1) | No

anubhav 10 years AGO

volume of cylinder=n*pi*r^2*h=0.88 cubic centimeter
(pi=3.14)find value of n
where n will be no of rods
NOTE:make sure abount units
r=0.01m h=0.07m
n=pi*r^2*h/0.88
=400

Like? Yes (1) | No

puja agarwal 10 years AGO

.88/22*0.01*0.01

Like? Yes (1) | No

Shamir kumar 10 years AGO

n*(22/7)*(.01*.01)*7=.88
n=400 ans

Like? Yes (1) | No

T.Aravinth kumar 10 years AGO

88/π{(0.01)^2*7}=400

Like? Yes (1) | No

VIVEK VICTOR 10 years AGO

volume of iron=0.88 m3
length of iron rod=7 m
diameter of iron rod=2 cm=0.02m
Radius of iron rod=0.01 m
So, Volume of cylinder=3.14*0.01*0.01*7=0.002198 m3
No. of iron rods=volume of iron / volume of one iron rod
=0.88/0.002198=400

Like? Yes (2) | No (2)

Devendra Marghade 10 years AGO

For each rod, here r=0.01m ,h=7m
Volume of each rod= Pi*r^2*h=(22/7)*0.0001*7=0.0022
Number of iron rods that can be made out of 0.88 m^3
= 0.88/0.0022=8800/22=400

Like? Yes (3) | No (3)

Abhishek Mitra 10 years AGO

the volume of the iron rod will be ((22/7)* (0.01)^2 )*7 cubic metre
and the total amount of iron available is .88 cubic metre.

so the numbers of rod can be made will be
0.88 / {(22/7)*(0.01)^2)*7}
i.e. =400
option 8

Like? Yes (2) | No (2)

nigarashraf 10 years AGO

vol. of cylinder=22/7*r*r*h
no. of rod =.88/vol. of cylinder
=400

Like? Yes (1) | No (1)

Datla Kanthi 10 years AGO

Volume of 1 rod = (( 22/7) x (1/100) x (1/100) x 7 ) cu.m = 11/5000 cu.m
Volume of iron = 0.88 cu. m.
Number of rods = (0.88 x 5000/11) = 400.

Like? Yes (1) | No (1)

prem kumar 10 years AGO

volume of 1rod=(22/7*1/100*1/100)=11/5000 cu.mt
volume of iron (given)=0.88cu.mt
no of rods=(0.88*5000/11)=400
so option 8

Like? Yes (3) | No (3)

HARISHCHANDRA RAIKWAR 10 years AGO

area of rod=length of rod*Pi*r^2 = 0.0022 m^2

no. of rods = 0.88/0.0022 = 400

Like? Yes (1) | No (1)

ABHOY KUMAR 10 years AGO

let n no. of rods can be made out.
so, volume of n rods = volume of iron
n*(volume of rod)=0.88
n*(3.14*r^2*h)=0.88 ...... (r=.01m , h=7m)
n=400

Like? Yes (1) | No (1)

D.RANJITHKUMAR 10 years AGO

Volume of 1 rod = [22/7 * 1/100 * 1/100 * 7] cu. m = 11/5000 cu.m.
Volume of iron = 0.88 cu. m.
Number of rods = [0.88 * 5000/11] = 400

Like? Yes (1) | No (1)

chauhan dhara vinayakkumar 10 years AGO

volume=0.88
0.88/3.14*0.01*0.01*7
=400

Like? Yes (1) | No (1)

vartika 10 years AGO

Volume of iron = .88 cubic metres
radius of required iron rods= d/2 = 2/2=1cm= .01m
height of 1 rod = 7m
volume of 1 iron rod= pi*(.01)*(.01)*7 cubic metres
therefore, total no of iron rods = .88 /[(22/7*7)*.01*.01]
= 400

Like? Yes (1) | No (1)

manish kumar b 10 years AGO

volume of each rod=7*pi*(0.01)^2............(1)
available volume of iron=.88.........................(2)
now for no of rods we must divide eqn (2) by (1)...then we get 400. .....option 8.

Like? Yes (1) | No (1)

Ananth 10 years AGO

Volume of 1 rod = (( 22/7) x (1/100) x (1/100) x 7 ) cu.m = 11/5000 cu.m
Volume of iron = 0.88 cu. m.
Number of rods = (0.88 x 5000/11) = 400

Like? Yes (1) | No (1)

Sneha 10 years AGO

Volume of 1 rod=(22/7 * 1/100 * 1/100 * 7)cubic metre=22/10000 cubic metre
Volume of iron=0.88 cubic metre
Number of rods=(0.88 * 10000/22)=400

Like? Yes (1) | No (2)

Ravi Bhalani 10 years AGO

volume of 1 rod=(22/7*1/100*1/100*7)=11/5000 cu.m
volume of iron=0.88 cu.m
number of rods=(0.88*5000/11)=400

Like? Yes (1) | No (2)

raj ranjan verma 10 years AGO

no. of iron rod=.88*10000/3.14*1*7=400

Like? Yes (1) | No (2)

Asha Praveena 10 years AGO

Volume of 1 rod = (( 22/7) x (1/100) x (1/100) x 7 ) cu.m = 11/5000 cu.m
Volume of iron = .88 cu. m.
Number of rods = (.88 x 5000/11) = 400

Like? Yes (1) | No (2)

Surya Rajitha 10 years AGO

volume of one rod= pi*(1*10^-2)^2*7 cubic meters

whole volume= 0.88 cubic meters

0.88= n* volume of each rod

n= 0.88/volume of each rod
= 0.88/(pi*(1*10^(-4))*7)=400.16~400 rods

Like? Yes (1) | No (2)

krishna kanth 10 years AGO

total volume is 880000 cubic centimetre
volume of each rod is 22*1*1*700/7=2200
no.of rods=880000/2200=400

Like? Yes (1) | No (2)

Tark Patel 10 years AGO

Let l=7 m , d=2 cm so r=1 cm = 10^(-2) m
Volume of 1 rod = (22/7) * ( ( 10^(-2) ) ^2 ) * 7
= 22/10000 cu. m

Rods = (0.88) / (22/10000) = 400

Like? Yes (1) | No (2)

HARDIP BHALANI 10 years AGO

volume of 1 rod=(22/7*1/100*1/100*7)=11/5000 cu.m
volume of iron=0.88 cu.m
number of rods=(0.88*5000/11)=400

Like? Yes (1) | No (2)

Dipak Singh 10 years AGO

x=400.16

Like? Yes (1) | No (2)

Navneet Kaur 10 years AGO

volume of cylinder=pi*r^2*h
here given volume of iron rod=.88 cubic meter
length of iron rod=7m
diameter of iron rod=2cm
so radius=1cm =1/100m

.88=n*22/7*1/100*1/100*7
on solving it we get
n=(.88*100*100*7)/(22*1*7)
so n=400

Like? Yes (1) | No (2)

Harshad 10 years AGO

volume of 1 rod=(22/7*1/100*1/100*7)=11/5000 cu.m
volume of iron=0.88 cu.m
number of rods=(0.88*5000/11)=400

Like? Yes (2) | No (3)

sivaramakrishna 10 years AGO

N*pi*r*r*h=0.88
N*3.14*0.01*0.01*7=0.88
N=400.

Like? Yes (2) | No (3)

Pranshu Chaurasia 10 years AGO

0.88=(22/7)*(0.01)^2*7*N
N=400

Like? Yes (1) | No (2)

Shashi nath jha 10 years AGO

Rod=πr2h=22
8800÷22=400

Like? Yes (1) | No (2)

Avinash Gupta 10 years AGO

Given volume = .88 cubic metre

& given length=7m diameter=2cm=0.01m

So volume of rod = 22/7 * 0.01*0.10 *7=22/10000
so number of rod = volume of cube/volume of rod
=0.88/22*10000
=400

Like? Yes (3) | No (4)

madanpal vishwakarma 10 years AGO

volume of one rod=((22/7)*(1/100)*(1/100)*7)cu.m=11/5000 cu.m
volume of iron=0.88 cu.m
Number of rods=(0.88*5000/11)=400
so option 8) 400 is correct

Like? Yes (1) | No (2)

Saraswathy 10 years AGO

Diameter = 2cm
Radius = 2/2 = 1 cm => 1/100 m
length = 7 m
Volume = pi*r^2*h
=> pi * 1/100 * 1/100 * 7

No. of iron rods made can be => 0.88*100*100/(pi*7)

= 400.36
= 400 approximately

Ans : 400 (Option 8)

Like? Yes (1) | No (2)

vadthyavath 10 years AGO

v=n*pi*r^2*h
0.88=n*3.14*1*10^-4*7
n=8800/3.14*7
n=400.36
so 400 is the answer

Like? Yes (1) | No (2)

sanju kumari 10 years AGO

volume of 1 rod =(22/7*1/100*1/100*7)=11/5000 cu. m.

volume of iron=0.88 cu. m.
number of rods=(0.88*5000/11)=400

Like? Yes (1) | No (2)

RAJEEV KUMAR 10 years AGO

.88=22/7*0.01*0.01*7*n
n=number of rods.
n=400

Like? Yes (1) | No (2)

aditya wargis 10 years AGO

n*(22/7*0.02*0.02*7/4)=88
n=400

Like? Yes (1) | No (2)

Aravinth kumar 10 years AGO

iron? Sol.Volume of 1 rod = (( 22/7) x (1/100) x (1/100) x 7 ) cu.m = 11/5000 cu.m
Volume of iron = 0.88 cu. m.
Number of rods = (0.88 x 5000/11) = 400

Like? Yes (1) | No (3)

Ajay Kumar Gupta 10 years AGO

volume=(pi)*r^2*h
height=7m
radius=0.01m
so,
0.88=n*(pi)*0.01^2*7
i.e,n=400

Like? Yes (1) | No (3)

ANKUR ANAND 10 years AGO

length=7m
radius=.01m
total volume of cylinder=0.88 m^3
so,n=0.88/pi*0.01*0.01*7
so, n=400

Like? Yes (1) | No (3)

Saurabh Kumar 10 years AGO

no of rod required= (.88*10000)/(3.14*7*1*1)

Like? Yes (1) | No (3)

ANSHIKA JAIN 10 years AGO

as diameter is 2cm
so radius=diameter/2
i.e. radius=1cm=.01 m
given vol. of iron be .88 cubic metre
so vol. of rod=pi*r*r*h
=(22*.01*.01*7)/7
=22/10000
total no. of rods=vol. of iron / vol. of 1 rod
=.88/(22/10000)
=400
so total no. of iron rods will be 400

Like? Yes (1) | No (3)

surendra singh 10 years AGO

no of iron rod = ( .88*7*100*100/22*7*1)
= 400

Like? Yes (1) | No (3)

deepesh singh panwar 10 years AGO

the velocity of one iron roads= 22*0.01*0.01*7/7
total iron velocity= 0.88 cubic meter
no. of iron rods= 0.88*7/22*0.01*0.01*7=400

Like? Yes (1) | No (3)

surya 10 years AGO

Volume of 1 rod = (( 22/7) x (1/100) x (1/100) x 7 ) cu.m = 11/5000 cu.m
Volume of iron = 0.88 cu. m.
Number of rods = (0.88 x 5000/11) = 400

Like? Yes (1) | No (3)

AMAN KUMAR 10 years AGO

volume of rod 22/7*(1/100)^2*7= 22/10000 cubic meter
no of rod=.88*10000/22=400

Like? Yes (1) | No (3)

Rajat sadhu 10 years AGO

diameter of each rod=2cm
=>radius=2/2=1cm=0.01m=r
length of each rod=7m=l
volume of each rod v=pi*r^2*l
total volume of iron given=0.88cubic meter
let x no. of rods are formed den
x*pi*r^2*l=0.88
x*(22/7)*(0.01^2)*7=0.88
on solving,we get
x=400

Like? Yes (2) | No (4)

Sourojit Dhua 10 years AGO

3.14*.01*.01*7=0.002198 cubic meter
therefore toal no. of iron rods= 0.88/0.002198 ~ 400

Like? Yes (1) | No (3)

saira fatma 10 years AGO

VOLUME OF IRON=.88M^3
VOLUME OF 1 IRON ROD=22*10^-4*7/7=22*10^-4
NO=88*10000/22*100=400

Like? Yes (1) | No (3)

sai naveen vanapalli 10 years AGO

pi*r*r*h=3.14*0.01*0.01*7=0.0022

400*0.0022=0.88

Like? Yes (1) | No (3)

Narendra Jadon 10 years AGO

Volume of Iron rod = 22/7*1*7 = 22 cubic cm.

No. of required rods = .88 x 10000/22 =400

Like? Yes (1) | No (3)

prashant kumar 10 years AGO

convert all parameter in meter
radious of rods=(2/2)=1 cm =(1/100)=0.01
volume of rod=pi*r^2*h=(22/7)*(0.01)^2*7=22*0.01*0.01
so no. of rod=volume off iron/volume of rod =0.88/22*0.01*0.01 =8800/22 =400

Like? Yes (1) | No (3)

PRATIK SINHA 10 years AGO

Vol of iron available .88 cubic meter and vol of one rod will be =3.14 ×.01×.01×7 as vol of cylinder that is rod is (22÷7)×r^2×h so number of rod = volume of iron available ÷ vol of one rod .thus we get no of rod=400

Like? Yes (1) | No (3)

BHANU KUMAR 10 years AGO