The average speed of a cyclist who covers first, second and third km at 20, 16 and 12 km/hr respecti

Kushagra Tiwari   10 years AGO

Since we know that Avarage Speed = Total diatance/Total time taken

Here total distace is 3km

SO putting in formula we get = 3/(1/20 + 1/16 + 1/12)

on solving = (3*20*16*12)/(192+240+230)

that is 15.32 km

Which is in option no 7

Like? Yes (18) | No (5)  

Sourojit Dhua   10 years AGO

Avg. speed= Total distance covered/ Total time taken
So,
S= 3/(1/20+1/16+1/12)= 15.32 km/hr

Like? Yes (9) | No (4)  

aman   10 years AGO

1km with 20 speed so time taken = 1/20
another 1 km with 16 speed so time taken = 1/16
and last 1 kmwith 12 speed so time taken = 1/12
total time taken = 1/20 + 1/16 + 1/12 = 47/240
total distance = 3 km
total time = 47/240
so speed = distance/time = (3*240)/47 = 15.319
speed = 15.32 km/hr

Like? Yes (4) | No   

CHANDAN KUMAR   10 years AGO

avg speed=3/(1/20)+(1/16)+(1/12)=3/0.1958=15.32

Like? Yes (2) | No   

ashok   10 years AGO

3xyz/xy+yz+xz

Like? Yes (5) | No (3)  

s.veeresh kumar   10 years AGO

avg. speed=harmonic mean of given speeds

Like? Yes (2) | No   

ravi prakash   10 years AGO

total dist/total time
=720/47=15.32

Like? Yes (1) | No   

Aishwarya Chandra   10 years AGO

Let first distance be x
Second be y
N third be z
Den.,
Time taken by first km is = 1/20 hr
Time taken by second km is = 1/16 hr
Time taken by third km is = 1/ 12 hr
The avg speed= total distance / total time
Therefore,
Avg speed = 3/(1/20 + 1/16 +1/12)
= 15.32
Correct option is = 7

Like? Yes (2) | No (1)  

ADARSH GAURAV   10 years AGO

15.32 is the answer

Like? Yes (1) | No   

saket saurav sahu   10 years AGO

here d is same in all three round ,
so, avg speed =total dist./total time taken
total d= 1+1+1= 3
total t = ( 1/20 +1/16 +1/12) = 47/240
therefore,avg. speed = (3*240)/47 = 15.32

Like? Yes (1) | No   

Ajinkya Kulkarni   10 years AGO

As we know Average speed = Total Distance / Total Time

Total Distance = 3 KM
Total Time (Time is distance upon velocity ) = (1/20)+(1/16)+(1/12)=0.1958 hr

So Avg Speed = 3/0.1958=15.32Kmph

Like? Yes (1) | No   

Anurag Dwivedi   10 years AGO

3/((1/20)+(1/16)+(1/12))= 15.316

Like? Yes (2) | No (1)  

Sushil Singh   10 years AGO

let each distance= x km and avg. speed =y
then,
((12x)+(15x)+(20x))/240=x/y
by solving we get
y=15.32

Like? Yes (2) | No (1)  

ganesh babu   10 years AGO

avarge =3 (20x16x12)/(20x16)+(16x12)+(20x12)
=11520/752
=15.319
=15.32

Like? Yes (2) | No (1)  

Devendra Marghade   10 years AGO

Average Speed=Total Distance/(Total Time)
=[1+1+1]/[(1/20)+(1/16)+(1/12)]=720/47=15.32

Like? Yes (1) | No (1)  

Jabez David   10 years AGO

If a cyclist travels three equal distances at a Speed of

S1=20 km/hr
S2=16 km/hr
S3= 12 km/hr

then average speed is 3*S1*S2*S3/(S1S2+S2S3+S3S1)

Answer: 15.31915-> 15.32

Like? Yes (1) | No (1)  

AAKANCHA SRIVASTAV   10 years AGO

avg speed= 3*x*y*z/(x*y+y*z+z*x)
where x,y and z are 20,16 and 12 respectively
so,
3*20*16*12/752 =15.319 i.e 15.32(approx)

Like? Yes (1) | No (1)  

Sagar Kumar Subudhi   10 years AGO

3xyz/(xy+yz+zx)=15.32

Like? Yes (1) | No (1)  

Pradeep Kumar   10 years AGO

3(xyz) 3*20*16*12
-----------------= -------------------------------
xy+yz+xz 20*16+16*12+20*12

Like? Yes (1) | No (1)  

vinit   10 years AGO

3xyz/xy +yz+ xz

Like? Yes (1) | No (1)  

Chandra chur anand   10 years AGO

time to cover first km=1/20 hr
time to cover second km=1/16 hr
time to cover third km=1/12 hr
so avg time=total dist/total time=3/(1/20+1/16+1/12)
so avg time ll be 720/47=15.319~15.32 hr ans

Like? Yes (1) | No (1)  

kishore muddada   10 years AGO

total distance = 3 kms
first, second and third km at 20, 16 and 12 km/hr respectively (in km/hr)
avg velocity = total distance/total time and
time= distance/velocity
=3/[(1/20)+(1/16)+(1/12)]
=3/[47/240]
=720/47
=15.32

Like? Yes (1) | No (1)  

Pallavi Verma   10 years AGO

distance covered in 1 km @20 km/hr=1/20,similarily for other two time taken will be 1/16 and 1/12
total time taken=1/20+1/16+1/12=0.195833
total distance=1+1+1=3kms
avg speed=total distance/total time=3/0.195833=15.3191=15.32(upto 2 decimal places)

Like? Yes (1) | No (1)  

manish kumar sharma   10 years AGO

first we should have to calculate total time taken by him.
time taken in completion of first km = 1/20 hr
time taken in completion of second km = 1/16 hr
time taken in completion of third km = 1/12 hr

total time = 1/20+1/16+1/12
= 47/240 hr

average speed = total distance/ total time
= 3/(47/240)
= 15.32 km/hr

Like? Yes (1) | No (1)  

Rashi Bansal   10 years AGO

avg. speed = total distance / total time taken
total distance = 3 km
total time taken = 1/20 + 1/16 + 1/12

Like? Yes (1) | No (1)  

dhanaseelan   10 years AGO

Ans is 15.32

Like? Yes (1) | No (1)  

falguni singh   10 years AGO

average speed =(total distance travelled)/(total time taken)

=(d1+d2+d3)/((d1/s1)+(d2/s2)+(d3/s3))
=(1+1+1)/((1/20)+(1/16)+(1/12))
=15.32

Like? Yes (1) | No (1)  

Pallab Das   10 years AGO

avg speed=3.xy7/(xy+yz+xz)
x=20
y=16
z=12
Ans.-15.32

Like? Yes (1) | No (1)  

abhinav singh   10 years AGO

3xyz/xy +yz+ xz
3*20*16*12/(20*16+16*12+12*16)=15.32
ans=15.32
option 7

Like? Yes (1) | No (1)  

himanshu jaiswal   10 years AGO

avg speed = 3*(20*12*16)/(20*12+12*16+16*20)
=15.32 km/hr

Like? Yes (1) | No (1)  

Prarthana Veda Priya   10 years AGO

average speed=total distance covered/time taken
=3/(1/20+1/16+1/12)
=2520/752
15.32

Like? Yes (1) | No (1)  

shekhar suman   10 years AGO

avg speed=(1+1+1)/(1/20+1/16+1/12)=3*240/47=15.32

Like? Yes (1) | No (1)  

Biswajit Saha   10 years AGO

let the avg speed is x km/hr.
1/20 + 1/16 + 1/12 = 3/x [Since total distance is 3]
x=15.319 ~ 15.32

Like? Yes (1) | No (1)  

Pinaki Ghosh   10 years AGO

let the avg speed is x km/hr.
1/20 + 1/16 + 1/12 = 3/x [Since total distance is 3]
x=15.319 ~ 15.32

Like? Yes (1) | No (1)  

Aastha   10 years AGO

av.speed=3xyz/xy+yz+zx
=15.32km/hr

Like? Yes (2) | No (2)  

satyam sharma   10 years AGO

avg time taken to cover the distance of 3 km is
(1/20+1/16+1/12) hr=47/240 hr
avg speed=distance/avg time=3/(47/240)=(3*240)/47= 15.32 km/hr
so correct option is 7) 15.32

Like? Yes (1) | No (1)  

SOURABH   10 years AGO

time taken in covering first km=1/20 hr
for second km=1/16
for third=1/12
total time =1/20+1/16+1/12=47/240
avg speed=total dist/total time
=3/(47/240)=15.32 kmhr

Like? Yes (1) | No (1)  

MRITUNJAY   10 years AGO

Average speed=total distance travelled/total time taken

Like? Yes (1) | No (1)  

stuti priyambda   10 years AGO

time taken to cover distance=((1/12)+(1/16)+(1/20))=47/240
avg.speed=(3/(47/240))=15.32

Like? Yes (1) | No (1)  

Devesh Gupta   10 years AGO

time taken to cover first km = 1/20 hr
time taken to cover first km = 1/16 hr
time taken to cover first km = 1/12 hr

total distance covered = 3Km
total time taken=(1/20)+(1/16)+(1/12)

avg. speed=total distance covered/total time = 15.32

Like? Yes (1) | No (1)  

SOURAV MUKHERJEE   10 years AGO

avg speed=avg distance/avg time
avg distance=3/3=1
avg time=((1/20+1/16+1/12)/3)=47/(240*3)
avg speed=15.32

Like? Yes (1) | No (1)  

prem kumar   10 years AGO

3xyz/xy+ yz+ xz
15.32

Like? Yes (2) | No (2)  

Kashish Aneja   10 years AGO

1/20+1/16+1/12 will give the time
and dividing this time by total distance will give average speed
i.e 3/(47/240)=15.32

Like? Yes (1) | No (1)  

Arijit Acharyya   10 years AGO

3xyz/(xy+yz+zx)

(3*20*16*12)/((20*16)+(16*12)+(12*20))

=15.32

Like? Yes (1) | No (1)  

GAURAV KUMAR   10 years AGO

Average speed =total distance / total time
=(d1+d2+d3)/(d1/s1+d2/s2+d3/s3)
= (1+1+1) /(1/20+1/16+1/12)
=(3*240)/47
=15.3 (answer)

Like? Yes (1) | No (1)  

Sanchit Kapoor   10 years AGO

Total time=1/20+1/16+1/12 km/h
Total distance=3 km
So average speed =Total distance/Total time = 15.32 km/h
Thus option 7 is correct

Like? Yes (2) | No (2)  

raja babu   10 years AGO

Avg Speed= total distace travelled/total time taken
=> ______3_______
1/20+1/16+1/12
=> (3*20*16*12)/(16*12+ 12*20+20*16)
=>1152/192+240+320
=>11520/752
=>15.32

Like? Yes (1) | No (1)  

RABI KR. SHAW   10 years AGO

speed=distance/time
avg speed=(1+1+1)/(1/20+1/16+1/12)=15.32

Like? Yes (1) | No (1)  

Dharampal   10 years AGO

Total distance =3km
Total time taken =1/20+1/16+1/12
Avg speed=3/total time taken
=15.32

Like? Yes (1) | No (1)  

abhishek kumar   10 years AGO

total distance=3 km
total time= 47/240 hrs
so av speed= 3*240/47 = 15.319 km/hr

Like? Yes (1) | No (1)  

Ramesh Sriram   10 years AGO

total distance /total time

Like? Yes (1) | No (1)  

abhishek   10 years AGO

Average speed=total distance/total time

Like? Yes (1) | No (1)  

Chirag Ranjan Lahiri   10 years AGO

Let, x, y and z be 20, 16 and 12 respectively
So the average speed of x, y and z will be,
= 3*x*y*z/(x*y+y*z+z*x)
by, putting the values of x, y and z, the average speed becomes = 15.319 i.e = 15.32approx(answer)

Like? Yes (1) | No (1)  

SADINENI RAGHAVENDRA BABU   10 years AGO

total distance=3k.m
time taken for 1 k.m= 1/20
2 k.m=1/16
3 k.m= 1/12
total avg speed= 3/((1/20)+(1/16)+(1/12))
= 15.31914894 ~ 15.32

Like? Yes (1) | No (1)  

ANKITA Burbure   10 years AGO

The avg speed can be calculated as tot distance/tot time.Now the tot distance is 3km (1st 2nd and 3rd km).This will come in numerator.Now in denominator we represent time in the form of dist/speed.So in denominator we have (1/20 +1/16 +1/12) . On solving we get the ans as 15.319 i.e 15.32 (option 7)

Like? Yes (1) | No (1)  

Udit Pathak   10 years AGO

Avg speed= total dist./total time
Let dist be x.
Therefore avg speed= x/(x/3*20 + x/3*16 + x/3*12)
Solving x gets cancelled.
Takimg LCM in denominator we get
3/(47/240) = 15.31 hence answer.

Like? Yes (1) | No (1)  

PRIYA JAIN   10 years AGO

total distance=3km
total time=1/20+1/16+1/12=47/240hr
average speed=3/(47/240)=15.32km/hr

Like? Yes (1) | No (1)  

saket    10 years AGO

the answer would be 3/ ( 1/20 + 1/16 + 1/12) = 15.32km/hr

Like? Yes (2) | No (2)  

Simranjit Singh   10 years AGO

Avg Speed= Total Distance/total Time
=3*60/11.75
=15.32 km/hr

Like? Yes (1) | No (1)  

SIDDHARTH KUMAR   10 years AGO

3/(1/20 +1/16+1/12)=15.32

Like? Yes (1) | No (1)  

harini   10 years AGO

let X=20km/hr,Y=16km/hr,Z=12km/hr
average speed =3XYZ/XY+YZ+ZX
average speed =15.32

Like? Yes (1) | No (1)  

RANDHIR KUMAR   10 years AGO

total distance/total time taken

Like? Yes (1) | No (1)  

Jyoti kumari   10 years AGO

time taken in covering 1st km(t1)= 1/20
t2= 1/16
t3= 1/12
total time taken in covering 3 kms= (1/20)+(1/16)+(1/12)
=0.19583
average speed = 3/0.19583
=15.32

Like? Yes (1) | No (1)  

surya   10 years AGO

15.32

Like? Yes (1) | No (1)  

Abhishek birkh   10 years AGO

3xyz/(xy+yz+zx)=15.32
here x=20,y=16,z=12

Like? Yes (1) | No (1)  

Anupam Banerjee   10 years AGO

Average speed = 3/(1/20 + 1/16 + 1/12) = 15.32 km/hr

Like? Yes (1) | No (1)  

NIVEDA SIVAPRAKASAM   10 years AGO

formula : 3xyz/xy+yz+zx

Like? Yes (1) | No (1)  

vivek prakash   10 years AGO

(3x)/(x/20+x/16+x/12)=15.32

Like? Yes (1) | No (1)  

NAVEEN KUMAR   10 years AGO

avg. speed=3xyz/(xy+yz+xz)=3*20*16*12/(20*16+16*12+20*12)
=

Like? Yes (1) | No (1)  

Gauraw   10 years AGO

Total Distance Traveled = 3km
Total Time taken to cover 3km = (1/20)+(1/16)+(1/12) = 47/240 hrs
So Average speed = 3/(47/240) = 15.32 km/hrs

Like? Yes (1) | No (1)  

Bhupendra Rana   10 years AGO

TOTAL TIME=1/20+1/16+1/12
SPEED=DISTANCE/TIME
=3/TOTAL TIME
15.32

Like? Yes (1) | No (1)  

AMREEN   10 years AGO

time=distance/speed
for 1st km, speed=20km/hr
t1=1/20hr
for 2nd km
t2=1/16hr
for 3rd km,
t3=1/12hr
total time=t1+t2+t3
t=47/240hr
total distance=3km
avg speed=total distance/total time
avg speed=3*240/47
=15.32km/hr

Like? Yes (1) | No (1)  

Bhanoj   10 years AGO

time taken by the vehicle to complete each km is 3,3.75,5 min respectively.
Average velocity = (3/11.75)*60 = 15.32 kmph

Like? Yes (2) | No (2)  

RISHABH SHARMA   10 years AGO

avg speed=total distance/total time=3/(1/16+1/20+1/12)=15.32

Like? Yes (1) | No (1)  

santosh kumar patel   10 years AGO

3abc/(ab+bc+ca)

(3*20*16*12)/(20*16+16*12+12*20)=15.32

Like? Yes (1) | No (1)  

AMIT AGARWAL   10 years AGO

3xyz/xy +yz+ xz

Like? Yes (1) | No (1)  

Keerthanaa R S   10 years AGO

Total cyclist=3
Now average can be find by using,

3xyz/xy+yz+xz = 3(20)(16)(12) / ((20*16) + (16*12) + (12*20))

= 11520/752
=15.3191
Answer = 15.32(approx)

Like? Yes (1) | No (1)  

Shreya Tiwari   10 years AGO

Average Speed = Total distance/Total time taken

Here total distance is 3km

SO putting in formula we get = 3/(1/20 + 1/16 + 1/12)

on solving = (3*20*16*12)/(192+240+230)

that is 15.32 km

Like? Yes (2) | No (3)  

Abhishek Vishwakarma   10 years AGO

Average Speed = Total distance/Total time taken

Here total distance is 3km

SO putting in formula we get = 3/(1/20 + 1/16 + 1/12)
= (3*20*16*12)/(192+240+230)
15.32 km

Like? Yes (1) | No (2)  

RAKESH   10 years AGO

3*20*16*12 / (20*12+20*16 +16*12) = 15.32

Like? Yes (1) | No (2)  

Sneha   10 years AGO

Average speed=total distance covered/total time taken
=3/(1/20+1/16+1/12)
=15.32

Like? Yes (1) | No (2)  

DIPAK TIWARI   10 years AGO

(1+1+1)/(1/20 +1/16 +1/12)
=>15.319=15.32

Like? Yes (2) | No (3)  

ABHILESH PURI GOSWAMI   10 years AGO

avg speed = total distance / total time
= 3 /((1/20)+(1/16)+(1/12))
=15.32
option 7)

Like? Yes (1) | No (2)  

pawan kumar   10 years AGO

Time for 1st km= 3min
time for 2nd km= 15/4min
time for 3rd km= 5min

Avg speed= [3/(47/4)]*60 km/h
= 15.32 km/h

Like? Yes (1) | No (2)  

BHASKAR MANDAL   10 years AGO

If a person or thing travel three equal distances at a speed of x,y and z km/hr respectively then the average speed during the whole journey is 3xyz/(xy+yz+zx) km/hr

= 3*(20*16*12)/(20*16+16*12+20*12)
= 3*5.106
=15.32
so option 7 is the answer

Like? Yes (4) | No (5)  

harshit gupta   10 years AGO

from the equation we can solve where x is avg speed
x=(3/((1/20)+(1/12)+(1/16))
x=15.321 km/hr

Like? Yes (1) | No (2)  

gouthamdaneti   10 years AGO

1km in 20km/hr and 16 km/hr and 12km/hr
1 divide by each speed we get time for each km and 3/(totaltime)

Like? Yes (1) | No (2)  

Akshay   10 years AGO

time to travel 1st km=1/20=0.05 hr
time to travel 2nd km=1/16=0.0625
time to travel 3rd km=1/12=0.08333
average speed=total distance/total time=3/0.196=15.31
so,approx average value=15.32

Like? Yes (1) | No (2)  

Anand   10 years AGO

15.32 3xyz/xy+ yz+ xz

Like? Yes (2) | No (3)  

SANU PANJI   10 years AGO

If a person travels 3 equal distance at a speed of X, Y& Z km/hr resppectively, then the avg speed during whole journey is
3*X*Y*Z/(X*Y+Y*Z+Z*X)
=3*20*16*12/(20*16+20*12+12*16)
=15.32

Like? Yes (1) | No (2)  

pritika singh   10 years AGO

Total dist.= 3 km
Total time taken = 1/20 + 1//6 + 1//2 = 47/240
Average speed = 3×240/ 47 = 15.32

Like? Yes (2) | No (3)  

Gitanjali K   10 years AGO

3xyz/(xy+yz+xz)=15.32

Like? Yes (1) | No (2)  

vatan singh   10 years AGO

av. speed is total distance / total time
each distance is 1km find time taken
i.e. 1/20, 1/16, 1/12
total distance 3km
total time is 1/20+1/16+1/12
divide both got 15.319 i.e 15.32 approx

Like? Yes (1) | No (2)  

K Sudharshan reddy   10 years AGO

The time taken to cover 1st km is 1/20
the time taken to cover 2nd km is 1/16
and the time taken to cover 3rd km is 1/12
so total time taken to cover entire distance is 1/20+1/16+1/12
=47/240
And the total distance is 3 km.
Average speed can be given by avg speed=total distance/total time taken
=3*240/47
=15.32 km/hr

Like? Yes (1) | No (2)  

TINKU MITTAL   10 years AGO

If a person or thing travel three equal distances at a speed of x,y and z km/hr respectively then the average speed during the whole journey is 3xyz/(xy+yz+zx) km/hr
so avg speed = (3*20*16*12)/(20*16+16*12+12*20)
= 15.32 km/hr

Like? Yes (1) | No (2)  

v pavan   10 years AGO

time taken for covering 1st km=(1/20)hr
time taken for covering 2nd km=(1/16)hr
time taken for covering 3rd km = (1/12)hr
total distance=3km
total time=(1/20)+(1/16)+(1/12)
average speed= total distance/total time
upon feedind data average speed comes to be 15.32km/hr

Like? Yes (1) | No (2)  

Dinesh thatti   10 years AGO

(xyz) / (xy*yz*zx)=15.32

Like? Yes (1) | No (2)  

Ashish Kumar   10 years AGO

time taken for 1st km = 1/20 hr
similarly for 2nd an 3rd km is 1/16 n 1/12 resp.
total time taken = 1/20+1/16+1/12=752/3840
avg.speed= (3*3840)/752=15.32

Like? Yes (1) | No (2)  

nandyala sandhya rani   10 years AGO

avg speed=(3xyz)/(xy+yz+zx)
= 15.32

Like? Yes (1) | No (2)  

Deepu Kumar   10 years AGO

A/Q option 7 is correct.

Like? Yes (1) | No (2)  

sanjeev kumar   10 years AGO

ans is 15.32

Like? Yes (1) | No (2)  

swarupa nuggu   10 years AGO

15.66

Like? Yes (1) | No (2)  

Tania Chatterjee   10 years AGO

avg speed is 15.32

Like? Yes (1) | No (2)  

lakshmi nalluri   10 years AGO

avg speed=total distance covered/total time taken
=3*abc/(ab+bc+ca)
=3*(20*16*12)/(20*16+16*12+12*20)
=15.32kmph

Like? Yes (1) | No (2)  

chaitanya lakshmi   10 years AGO

avg speed=total distance/total time
a.s= D+D+D/(D/20 +D/16 + D/12 )
a.s=720/47 = 15.32

Like? Yes (1) | No (2)  

PRANEETH   10 years AGO

so total distance is 3km. and total time is 1/20 + 1/16 + 1/12. then average speed is equal to total distance/ total time which is qual to 15.319 approximately 15.32

Like? Yes (1) | No (3)  

niraj   10 years AGO

let total distance be 240
240/20=12
240/16=15
240/12=20
720/47=15.32(ans)

Like? Yes (1) | No (3)