The upper and lower part radius of a bucket is 30 cm. and 20 cm. Its height is 60 cm. How much water

Kushagra Tiwari   10 years AGO

Vol of bucket = (1/3)*pi*h(R1^2+R1*R2+R2^2).

so vol in this case = (1/3)*pi*60 ( 900+400+600)/1000 = 38 Pi litres = 120 litres(Approx)

which is in option no 10

Like? Yes (22) | No (5)  

Surit Datta   10 years AGO

The Bucket according to the question can be referred as a Frustum of a Right Circular Cone

A frustum may be formed from a right circular cone by cutting off the tip of the cone with a cut perpendicular to the height, forming a lower base and an upper base that are circular and parallel. The problem can be generalized to other cones and n-sided pyramids but for the moment consider the right circular cone.

Let h be the height, R the radius of the lower base, and r the radius of the upper base.

Given R, r, and h, find the volume of the frustum.

Here R is 30cm
r is 20 cm
h is 60 cm

volume formula is

V = {(pi * h) * (R square + R*r + r square) }/ 3

so according to this volume is almost 120 litre.
So the answer is 120 litre.
That's it.

Like? Yes (7) | No (3)  

Ashwin Dinesh   10 years AGO

formula:
[ pi x h x ( R^2 + r^2 + Rxr ) ] / 3
= 119380.52 cm^3
= 119.38 L ~ 120 L
which is option 10.

Like? Yes (5) | No (1)  

RAKESH   10 years AGO

Vol of frustum = pi *h/3 (R^2 +r^2 + R*r)

V = 3.14 * 60/3 * (900 + 400 + 600) / 1000 litre

= 119.43
~ 120 litre

Like? Yes (3) | No (1)  

Sanu Panji   10 years AGO

The upper and lower part radius of a bucket is R and r. Its height is h

Volume of that bucket
V = Pi*h*(R^2+r^2+R*r)/3 cm^3
= 3.14*60*(30^2+20^2+30*20)/3 cm^3
=119320 cm^3
=120 Litre (approx)

For derivation follow the link
http://www.mathalino.com/reviewer/derivation-of-formulas/derivation-of-formula-for-volume-of-a-frustum

Like? Yes (4) | No (2)  

Vijay Menaria   10 years AGO

volume of frustum = (3.14*h(R1^2 + R2^2 + R1*R2))/3
3.14*60( 20^2 + 30^2 +20*30 ) / 3
119320 cm^3
119.3 litre

Like? Yes (2) | No   

BHASKAR MANDAL   10 years AGO

volume of frustrum is (pi*h) * (R^2 + r^2 + Rr) /3
= 3.14*60*(30^2 + 20^2 + 30*20 ) / 3
= 119320 cm^3
= 119.32 l
= 120 l approx
so the option is 10

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prem kumar   10 years AGO

shape of the bucket is truncated cone
vol of truncated cone=(pi/3)h(a^2+ab+b^2)
so vol=120

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sachin   10 years AGO

volume of frustum is = (1/3) * pi * H * (r1^2 + r2^2 + r1 * r2)
so r1 =20
r2=30
h=60

answer in cm= 119528.578 cm^3
so In ltr it will be= 119528.578/1000
= 119.52 = 120 ltr approx
= 120 approx

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MINTU KUMAR GUPTA   10 years AGO

22/7*60*[(20)^2+{(30)^2-(20)^2}/2]

Like? Yes (3) | No (1)  

SOURABH   10 years AGO

vol. of frustum=22/7*h(r*r+R*R+R*r)/3

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Chirag Ranjan Lahiri   10 years AGO

Vol of bucket = (1/3)*pi*h(R1^2+R1*R2+R2^2).

so vol in this case = (1/3)*pi*60 ( 900+400+600)/1000 = 38 Pi litres = 120litres

Like? Yes (2) | No   

Shreya Tiwari   10 years AGO

Vol of bucket = (1/3)*pi*h(R1^2+R1*R2+R2^2).

so vol in this case = (1/3)*pi*60 ( 900+400+600)/1000 = 38 Pi litres = 120 litres

Like? Yes (2) | No (1)  

Abhishek Vishwakarma   10 years AGO

vol = 1/3 * pi* 60 ( 30^2+20^2+ 30*20)/1000 = 38*22/7 = 119.42 litres

Like? Yes (1) | No   

Amit Kumar Pal   10 years AGO

Vol of bucket = (1/3)*pi*h(R1^2+R1*R2+R2^2).

so vol in this case = (1/3)*pi*60 ( 900+400+600)/1000 = 38 Pi litres = 120 litres

Like? Yes (1) | No   

Arijit Acharyya   10 years AGO

water can be filled in the bucket = volume of bucket
V= 1/3*pi*h*(R^2+r^2+R*r) = 1/3*22/7*60*(30^2+20^2+30*20) cm^3 = 119428 cm^3 /1000 litre =120 litre (approx)

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Anand   10 years AGO

vol = 1/3 * pi* 60 ( 30^2+20^2+ 30*20)/1000 = 38*22/7 = 119.42 litres

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Gitanjali K   10 years AGO

approx 120 lit

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Udhaya kumar   10 years AGO

pie * h /3 (r1^2+r1r2+r2^2)........

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NAVEEN KUMAR   10 years AGO

volume of bucket=h.Pi(R1^2+R2^2+R1*R2)/3
put, h=60,R1=30,R2=20
=119320 cm^3=119320/1000=120 lit(approx)
option(10)

Like? Yes (2) | No (1)  

nikhil pogale   10 years AGO

volume = (PI*(r1^2+ r2^2 +r1*r2)*h)/3
volume= 3.14*(30*30+20*20+30*20)*60/3
v=119380cm^3
ans=119380/1000=119.38=120 lt

Like? Yes (1) | No   

Supriya Mondal   10 years AGO

We know that volume of a bucket is=v=(1/3)*h*pi*(r1^2 + r2^2 + r1r2)
here, h=60cm
r1=20cm
r2=30cm
So after putting the values in the formula we will get v=119380.52 cm^3.
that is 119.38 lit=120 lit(approx)

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Arijit Das   10 years AGO

(3.14/3)*60*((30)^2 + 30*20 + (20)^2)

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MRITUNJAY   10 years AGO

volume of frustum=h*pi*(r1^2+r2^2+r1*r2)/3
=60*22*(30^2+20^2+30*20)/21
=120 litre

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Devendra Marghade   10 years AGO

If we extend the height of bucket to form a cone, then height of a cone upto radius of 20 cm = 20*60/(30-20)= 120 &
Total height =60+120= 180 cm.
Volume of bucket= Total Volume of a cone - Volume of a cone upto radius 20 cm.
=(1/3)*Pi*30^2*180 - (1/3)*Pi*20^2*120
=(1/3)*Pi*(900*180 - 400*120)
=119428.57 cm^3
=119428.57/1000 Litre ~ 120 Litre

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vishwa   10 years AGO

3.14 x 60/3[30*2 x 30x20 x 20*2]
=120

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sandeep kumar   10 years AGO

r1= 30cm


r2= 20cm



h= 60cm




V= 1/3*3.14*(R1^2+R2^2+R1*R2)*H


V=119320CM^3


S0,

V= 120 LITRE

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VIKAS KUMAR THAKUR   10 years AGO

r1=30,r2=20,l=60
volume=3.14/3*l*(r1^2+r1*r2+r2^2)=119320cm^3~120 lit

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swasthika   10 years AGO

formula:
3.14 * h(r1+r2+r1*r2)/3
therfore on substituting the values we get,
119.320 => 120 litres

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bharat deep rastogi   10 years AGO

volume of frustum= 3.14H/3(R*R+R*r+r*r)
=(62.8)*(900+600+400)
=62.8*1900
=120

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Akshay Jadhav   10 years AGO

volume of frustum
V= 1/3*pi*h(R2+Rr+r2)
R=30
r=20
h=60

Like? Yes (2) | No (1)  

ARUN KUMAR   10 years AGO

volume=[(1/3)pi*h*(r1^2+r2^2+r1*r2)]

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gouthamdaneti   10 years AGO

the volume of frustum of cone is (πh/3)*(R2+Rr+r2), where R = radius of the lower base, r = radius of the upper base and h = height.

Like? Yes (1) | No   

Parag Wagh   10 years AGO

calculated the lateral area, surface area and volume

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Karthick Raja   10 years AGO

volume=1/3*3.14*h(r1^2+r1r2+r2^2)
=1/3*3.14*60(30*30+30*20+20*20)
=119320
to make litre
119320/1000
=119.32=120

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Anubhav jain   10 years AGO

1/3*22/7*60(30*30+30*20+20*20)
=120

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aman   10 years AGO

Formula for the volume of a bucket: 1/3*pi*h*
(r1^2 +r1r2 +r2^2). Where r1 and r2 are the
radii, h is the height.
1/3*3.14*60*(20^2+20*30+30^2) = 38000 pi
38000/1000=38pi
38*3.14=120

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BINAY PRASAD YADAv   10 years AGO

let upper radius be R and lower radius be r
therefore volume of the bucket = {3.14285*h(R*R+r*r+R*r)}/3 cm^3
volume= {3.14285*60(30*30+20*20+30*20)}/3=119434 cm^3
now convert it in litre by dividing 1000
119.434 litre which is nearly equal to 120 litre
option 10) 120 litre is correct answer

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Dinesh Kumar   10 years AGO

vol. of frustum=3.14*h/3(R^2 +rR +r^2)
putting the values and get ans. is
120 litre

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ganesh babu   10 years AGO

volume of = pi /3 * h * (r1^2+r1*r2+r2^2)
=((22*60)/7*3 ) *(30^2+30*20+20^2)
= 63* 1900
=119700
water can fill in bucket = 119700/100
=120 liter (approx)

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Aparna Bhattacharya   10 years AGO

The capacity of the bucket=πh/3 *(r1^2+r2^2+r1*r2)=119320
=119320
=119.32 litre
=120 litre
here, π=3.14, h=60cm, r1=30cm, r2=20cm.
option: 10

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Rishikesh Ranjan   10 years AGO

1/3*pi*30*30*180 - 1/3*pi*20*20*120 = 120litres

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dhanaseelan   10 years AGO

volume of bucket is (1/3)*pi*h*(R^2+r^2+Rr)
volume=119.42 lits
~120 LITRES

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sanjeev kumar   10 years AGO

ans 120

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Yogeshkumar   10 years AGO

THE RADIUS INBETWEEN 20 AND 30 IS 25. SO RADIUS=25cm. HEIGHT=60cm. VOLUME OF CYLINDER=3.14*r^2*h=3.14*25*25*60=120000cm^3 =120000/1000litres=120litres.

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Sahil Nagpal   10 years AGO

bucket is a type of cone that has no end point like a typical cone. so its formula is V=(3.14*h(r1+r2)^2)/3
so by calculating V=119320 cm^3

therefore v=119.32=120ltr (nearest to option)

Like? Yes (1) | No