MINTU KUMAR GUPTA   10 years AGO

(4C4) *(48C2)/(52C6)
=3/54145

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RAKESH   10 years AGO

p = 4c4 * 48C2 / 52C6 = 1128 / 52C2 = 3/ 54145

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Jayanta Dutta   10 years AGO

we can choose 4 kings as 4C4 and rest any two from 48 so 48C2


so the probability is

4C4*48C2/52C6



Ans-5) 3/54145

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pravin   10 years AGO

(4c4*48c2)/52c6

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sujata chakraborty   10 years AGO

probability of getting 6 cards out of a deck(4 kings+2 any card)=(4C4* 48C2)/(52C6)
=3/54145 (C Is combination)

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prem kumar chaudhary   10 years AGO

4c4*48c2/52c6=1128/20358520
so ans =3/54145

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Deepak prajapati   10 years AGO

(4c4*48c2)/52c6=3/54145
so option 5 is correct

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swati kunj   10 years AGO

card pack has 52 cards
so probability of getting 4cards of king=4c4
probability of getting rest 2 card =48c2
so final probability of getting 4cards and 2 any other card= ((4c4)*(48c2))/52c6
=3/54145
so ans 5) 3/54145 is right answer

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ARJUN PRASAD   10 years AGO

(4c4 *48c2)/52c6=3/54145

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BHASKAR MANDAL   10 years AGO

probability =( 48C2 * 4C4 ) / 52 C6 = 3 / 54145
option 5

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Arijit Das   10 years AGO

(4C4*48C2)/52C6

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Pankaj Modi   10 years AGO

4 kings=4c4
2 another=48c2
total=52c6
so probability=(4c4 * 48c2)/(52c6)=3/54145

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v pavan   10 years AGO

probability=(48C2*4C4)/(52C6)=3/54145

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Md.Sultan Khichi   10 years AGO

No. Of ways of choosing 4 king are 4c4..and any is 48c2
So probability is 4c4*48c2/52c6=3/54145
Ans. Ob 5

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ravi prakash   10 years AGO

6*5*4*3*2/2*52*51*50*49
=3/54145

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Manasa Dullur   10 years AGO

since 4 kings are already selected, we have to select other two cards, it can be done in 48 C 2 ways, selecting any six cards in a pack of cards is 52 C 6 ways, so answer is 48 C 2 / 52 C 6 = 3/ 54145

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kamal   10 years AGO

choosing way of 4 kings from 52 cards = 1
choosing way of rest 2 cards from rest 48 cards= 48 C 2
so prbablity= 1* 48 C 2 / 52C6=720/12994800= 3/54145

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Surit Datta   10 years AGO

The probability is (4C4*48C2)/(52C6) = 3/54145
That's it..

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Narasapu Hari prasad   10 years AGO

option 5 is correct
totoal possible ways of selecting 6 cards from 52 cards is 52C6=20358520
total number of ways selcting set of 4 king and any other 2 is 48C2=1128
so required probability is 1128/20358520=3/54145

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tirupathi reddy   10 years AGO

Propability of getting 6 cards out of 52 is 52C6
Probability of getting 4 kings and 2 cards (any of the remaining)is
4C4*48C2 = 1*48C2
( we have 4 kings in the pack of 52 cards)

The required probability is
= (48 C 2)/(52 C 6 )
= (48*47*1*2*3*4*5*6)/(52*51*50*49*48*47*1*2)
= 3/54145

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Anubhav jain   10 years AGO

48C2*4C4/52C6
=3/54145

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abhishek narayan   10 years AGO

ways to select 4 king=4c4.
and any of 2 card out of 48 cards=48c2.
Therefore, required probability is= (4c4*48c2)/52c6
=3/54145.

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Harsh Poddar   10 years AGO

no of posibility of choosing of cards=52!/(46!6!)=20358520
no of possibility of choosing 4 kings =1
no of possibility of chooing any other two cards=48!/(46!2!)=1128
possible outcome =1*1128=1128
probablity=1128/20358520
=3/54145
option 5

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Aparna Bhattacharya   10 years AGO

Let, S be the sample space and E be the event of choosing 4 kings and 2 other cards.
n(S)=52C6=20358520
n(E)=4C4 * 48C2=1128
The Probability will be=n(E)/n(S)=1128/20358520=3/54145
Option: 5

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nikhil goyal   10 years AGO

(4C4 * 48C2) / 52C6

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Sravanthi   10 years AGO

(4C4*48C2)/(52C6)

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A SIRISHA    10 years AGO

Total conditions = 52C2
and Favourable condition = 48C2
Because we have to choose only 2 cards out of 48 as we consider 4 kings complsary

P=(48C2) /(52C6)
=3/(54145)
ANSWER IS OPTION------------ 5

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E PAMULETI   10 years AGO

Probability of Getting 6 cards out of 52 cards = 52C6
Probability of Getting 4 Kings out of 4 kings from 52 cards = 4C4
Remaining cards = 48
Probability of Getting any 2 cards out of 48 cards = 48C2
==>
(4C4*48C2)/52C6 = 3/54145

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gouthamdaneti   10 years AGO

(48c2)/(52c6)

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Ravi nishad   10 years AGO

(4C4 * 48C2) / ( 52C6 )

=3/54145

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N.sravani goud   10 years AGO

9/162435

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Abhishek mani   10 years AGO

(4c4*48c2)/52c6
=3/54145

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vikash kumar   10 years AGO

4c4*48c2/52c6=3/54145

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ADARSH GAURAV   10 years AGO

3/54145 is the answer.

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Swagatam Kumar Das   10 years AGO

to select the 4 kings prb is 4c4
and to select the other 2 card is prb is 48c2
So ans would be (4c4*48c2)/52c6
=3/54145

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aayushi bhandari   10 years AGO

(4C4*48C2)/52C6

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Parag Wagh   10 years AGO

(52c4.48c2)/52c6

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shubham singh   10 years AGO

48c2/52c6

Like? Yes (1) | No (1)