Out of three given numbers, the first one is twice the second and three times the third. If the aver

Supriya Mondal   9 years AGO

Sum of three number is=88*3=264
Let three numbers are a, b,c and a is the highest and c is the lowest
Then,
2b=a so b=a/2 and 3c=a so c=a/3
we can write,
a+b+c=264
a+a/2+a/3=264
11a/6=264
a=144
So, c=144/3=48
So there difference is=144-48
=96
So, option 5)96 is the right answer

Like? Yes (14) | No (5)  

varsha   9 years AGO

x1=2.x2=3.x3
(x1+x2+x3)/3=88
x1=144
x3=48
x1-x3=96

Like? Yes (8) | No (2)  

sai   9 years AGO

sum=274
first =144
third =48
difference 96

Like? Yes (7) | No (4)  

SANTOSH   9 years AGO

let numbers be 6x,3x,2x
average 11x/3=88
then x=24
Numbers 144,72,48
difference 144-48=96

Like? Yes (4) | No (2)  

MRITUNJAY   9 years AGO

x y z
6 3 2
difference between x and z be 4.
so 88*3/11*4=96

Like? Yes (5) | No (3)  

neha gupta   9 years AGO

Let a ,b and c be three numbers
then acc to ques a=2b=3c
therefore b=a/2
and c=a/3

a+b+c=88*3=264
a+(a/2)+(a/3)=264
11a=264*6
a=144
c=144/3=48

a-c=144-48=96

Like? Yes (3) | No (1)  

Chandrima Goswami   9 years AGO

Let 1st= 6a, 2nd= 3a and 3rd no= 2a
Average, 11a/3=88 => a=24
Therefore 1st no=144 and 3rd no=48
Difference between 1st and 3rd is 96

Like? Yes (2) | No   

vignesh   9 years AGO

since the first number be x and second be x/2 and third be x/3 by given avg is 88 so (x+x/2+x/3)/3=88 on solving we get x as 144 then the second number is 72 and the third is 48 now the difference is 96

Like? Yes (2) | No   

Rhul Sharma   9 years AGO

Let the numbers be
X
X/2
X/3
(X X/2 X/3)/3. =88
6X 3X 2X = 1584
X= 144
144. - 48 = 96

Like? Yes (1) | No   

Mehul D Parmar   9 years AGO

(x+x/2+x/3)/3=88

11x/18=88
x=144

thn x/3=144/3
x/3=48

thn 144-48=96

Like? Yes (1) | No   

Surendhar Ramanujam   9 years AGO

let x be the third number
Then the three numbers are 3x, 1.5x and x
since the average is 88 we get x=48
Thereby the difference between 1st and 3rd number is
3x-x=2x
2x=2*48=96

Like? Yes (1) | No   

Urvashi Jain   9 years AGO

according to the question a=2b,a=3c
a+b+c/3=88
a+b+c=264.....(i)
b=a/2,c=a/3
put in equation (i)
a+a/2+a/3=264
6a+3a+2a=6*264
11a=6*264
a=6*24
a=144
c=a/3,144/3=48
a-c=144-48=96

Like? Yes (1) | No   

Divyansh jaiswal   9 years AGO

(6x+3x+2x)/3=88

x=24

first no=48
third=144
diff.=96

Like? Yes (1) | No   

Hemalatha   9 years AGO

On calculating, the first no is 144, the next is 96, and the third is 72. The average of the three nos results to 88 as per the question.

Like? Yes (1) | No   

anuj kumar singh   9 years AGO

let the first no. be n
then 2nd no. be n/2
third no. be n/3

thn,
(n+n/1+n/3)/3=88
calculate it...and you'll get the answer

Like? Yes (1) | No   

Deepak   9 years AGO

let three numbers be x,y,z
second number y=x/2,
third number, z = x/3
average, x + x/2 + x/3 = 88, x = 144 and z = 48
thus difference is x-z = 96

Like? Yes (1) | No   

swetha   9 years AGO

x,x/2,x/3
(x+x/2+x/3)/3=88
x=144
x-x/2=72

Like? Yes (1) | No   

RAVAL   9 years AGO

according to given data,
x=2y=3z
& (x+y+z)/3=88
by solving the above equation,
x=144
y=72
z=48
difference x-z=96

Like? Yes (1) | No   

Debraj Ghosh   9 years AGO

numbers are 6x,3x,2x
so (6x+3x+2x)=(88*3)
=>11x=(88*3)
=>x=24
so difference between first and third is 4x=96

Like? Yes (1) | No   

Jyothi C Allapur   9 years AGO

let the three numbers be a,b,c
given :
a = 2b and a = 3c
i.e., b = a/2 and c = a /3
and average is 88
( a+ b + c ) / 3 = 88
substituting b and c in above eqn, we get a = 144
and b = 72 and c = 48
and difference between a and c is 144 - 48 = 96

Like? Yes (1) | No   

Shiva Sharma   9 years AGO

2A,A,B
2A = 3B
3A+B = 3*88
11B/2 = 3*88
B=8*3*2=48
A=3*48/2=72
first Number = 2*A=2*72=144
last number = 48
difference(2A-B)=144-48=96

Like? Yes (1) | No   

Parvathi.R   9 years AGO

Lets take the no.s as x, x/2, x/3
Now
(X+(x/2)+(x/3))/3= 88
On solving , we get x=144
1st no s 144
2nd no s 72
3rd no s 48
Diff bw 1 & 3 is 96

Like? Yes (1) | No   

ravi singh   9 years AGO

let, no. are X1, X2, X3
then, X1=2*X2=3*X3 ......eq(1)

and (X1+X2+X3)/3 = 88 .......eq(2)

from eq(1) and eq(2)

X1 = 144 and X3 = 48

hence difference us 96

Like? Yes (1) | No   

kush nigam   9 years AGO

x=2y, x=3z, x+y+z= 88*3=264, => 3z+3/2z + z= 11/2z =264 => z= 48=> difference x n z= 3z-z = 2z

= 96

Like? Yes (1) | No   

KARAN SHARMA   9 years AGO

a=2b , a=3c
(a+b+c)/3=88
solve dis we get a=144 and c= 3*144
required ans. is a-c = 96

Like? Yes (1) | No   

Divya Obilishetti   9 years AGO

let numbers are a,b ,c
a=2b and a=3c
i.e b=a/2 and c=a/3
average of a+b+c is 88
(a+a/2+a/3)/3=88
you will get the vcalues

Like? Yes (1) | No   

RAKESH ARYA   9 years AGO

if 1st no = x
then , (x + x/2 + x/3 ) / 3= 88
=> 11x/6 = 88*3
=> x= 144

then x - x/3 = 144 - 48
=96

Like? Yes (1) | No   

Pranesh S   9 years AGO

let the second number be x.
then the first number will be 2x.
if let the third number be y
then first number will be 3y.
therefore 2x=3y and y =(2/3)x
given (2x +x+(2/3)x)/3=88.
solving this ,we get x=72.
therefore the 2x-(2/3)x=2(72)-2/3(72)=96

Like? Yes (1) | No   

MUKESH   9 years AGO

let x be the 1st value,y be the 2nd value,z be the 3rd value
from given x=2y=3z
(i.e) (x+x/2+x/3)/3=88
on solving this we get x=144,y=72,z=48
difference of 1st and 3rd is 96

Like? Yes (1) | No   

K.M.AYESHA SHARMIL JAHAN   9 years AGO

let the 3 no. be x,y,z
x=2y
x=3z
x+y+z/3=88
by solving,
x =144
z =48
x-z=96

Like? Yes (1) | No   

Priyanka Kumari   9 years AGO

a=2b=3c
(a+b+c)/3=88
by solving we get
a=144
b=72
c=48

Like? Yes (1) | No   

santhosh   9 years AGO

X+1/2x+1/3X=88
X(1+1/2+1/3)=88
(11/6 )X=88
X=144
(1/3)X=48
144-48=96

Like? Yes (1) | No   

chanchal kumar choudhary   9 years AGO

let 1st no=x,2nd=x/2,3rd=x/3,
(x+x/2+x/3)/3=88
x=144;
1st=144;
3 rd=48;
diff=144-48=96

Like? Yes (1) | No   

naveen v   9 years AGO

take series as 2a, a, 2a/3 then u will get 144,72,48 ..
144-48= 96

Like? Yes (1) | No   

Kamlesh Kumar   9 years AGO

6x+3x+2x=3*88
11x=264
x=264/11
x=24
6*24-2*24
=> 96

Like? Yes (1) | No   

Vinith Mahendran   9 years AGO

The values are 3y,3y/2,y
Therefore 11y/2/3=88
11y/6=88
Y=48
Then 48(3-1)=96

Like? Yes (1) | No   

Lavanya Rajendran   9 years AGO

X=2y,
x=3z,
(x+y+z)/3=88
(x+x/2+x/3)/3=88
on solving x=144
144/3=48
144-48=96

Like? Yes (1) | No   

ENABOTHULA MOUNIKA   9 years AGO

Let x,y,z are 3 numbers
Given x=2y, x=3z and x +y +z/3=88
(X+x/2+x/3)/3=88
11x/18 =88
X=144 ==> y=72 and z=48
X-Z = 144 - 48 =96

Like? Yes (1) | No   

SHEELA S   9 years AGO

x+y+z/3=88
x+x/2+x/3=264
11x=1584
x=144 so y=72,z=48
x-z=96

Like? Yes (1) | No   

vimal tiwari   9 years AGO

let no be x y z
y=x/2
z=X/3

avg=(x+y+z)/3
88=(x+x/2 + x/3)/3
x=144
y=72
z=48

x-z =144-48=96

Like? Yes (1) | No   

bipro biswas   9 years AGO

x=2y=3z
(x+y+z)/3=88
solving:x=144
thereforex-z=x-(x/3)=2/3*x=96

Like? Yes (1) | No   

v v shyam kumar   9 years AGO

let the three no.s be :
x,x/2,x/3.
average of these is given as 88.
(x+x/2+x/3)/3=88,
therefore x=144.
The difference between first and third no.is = 144-48=96.

Like? Yes (1) | No   

UDIT   9 years AGO

x=2y=3z and x+y+z=264 so solving, x=144 z=48 x-z=96 (option 5)

Like? Yes (1) | No   

TUSHAR CHHABRA   9 years AGO

let second be x, first=2x, third=y,but y=2x3

Like? Yes (1) | No   

Subashini Nagarajan   9 years AGO

x,y,z are three nos....then x=2y; x=3z; so ...x+y+z / 3 = 88
so.... (x+(x/2)+(x/3))= 88*3 ........ x = 144 and z = 48 then x- z = 96

Like? Yes (1) | No   

Gadupudi Ramakrisna   9 years AGO

a=2b
a=3c
((a+b+c)/3)=88
(a+(a/2)+(a/3))/3=88
11a=88*6*3
a=144
b=77
c=48
a-c=96

Like? Yes (1) | No   

pratap kumar sahoo   9 years AGO

x=2y=3z;
(x+y+z)/3=88;
putting,
x=3Z,y=(3Z)/2;
z=48;
x-z=z*(3-1)=48*2=96

Like? Yes (1) | No   

GADUPUDI RAMAKRISHNA   9 years AGO

Let me take the three numbers are a,b,c
then
a=2b
a=3b
average of the numbers=(a+b+c)=88*3
(a+(a/2)+(a/3))=88*3
6a+3a+2a=88*3*6
11a=88*3*6
a=144
b=a/2=72
c=a/3=48
so a-b=144-48=96

Like? Yes (1) | No   

ADERU CHENCHU NITHISH   9 years AGO

let the numbers be x,x/2,x/3
(x+x/2+x/3)/3=88
(11x/(3*6))=88
x=8*18
x-x/3=x(1-1/3)=2x/3=2*8*18/3=96

Like? Yes (1) | No (1)  

Devendra Marghade   9 years AGO

If three numbers are x,y & z, then
x=2y=3z, so y=x/2 and z=x/3
As the average of these three numbers is 88,
(x+y+z)/3= 88 or [x+(x/2)+(x/3)]/3=88, so x=144 & z=48
So difference between x & z=144-48=96
Answer is option (5)

Like? Yes (1) | No (1)  

aman aditya   9 years AGO

6x+3x+2x=11x
average of three no is 88 so total is=88*3=264
264/11x
so x=24
so numbers are: 144,72,48

Like? Yes (1) | No (1)  

ABHINAV PUSHPAM   9 years AGO

Let 1st no. be x, 2nd = x/2, 3rd= x/3

=> x+x/2+x/3 = 3*88

=> 11x/6=264

so, x= 144

Hence difference = 144 - 1/3*144 = 96
option 5)

Like? Yes (1) | No (1)  

Swetha   9 years AGO

(3x+(3x/2)+x)/3=88
(6x+3x+2x)/2=264
11x=528
X=48

So, difference btw 1st n 3rd no.'s is (48*3)-48=96

So the ans is option 5 i.e., 96

Like? Yes (1) | No (1)  

Math Lovers   9 years AGO

let numbers are x,y,z
=> x=2y=3z
now,
(x+y+z)/3 =88
=> x+y+z = 88*3

now, z=x/3, y=x/2
=> x + x/2 + x/3 = 88*3
=> x = 88*3*6/11 = 8*3*6
now x-z = x - x/3 = 2x/3 = 96

Like? Yes (1) | No (1)  

virendra tiwari   9 years AGO

(a+a/2+a/3)/3=88
a=144
c=48
difference=96

Like? Yes (1) | No (1)  

shivaprabhu   9 years AGO

Let X be the number

Given three numbers in the ratio X:X/2:X/3

and also (X+X/2+X/3)/3=88

solving X=144

Hence difference between 1st and 3rd number is

X-X/3=144-144/3
=144-48
=96

Ans:-96

Like? Yes (1) | No (1)  

kishor Mali   9 years AGO

let the no be 6x,3x,2x
so avg is 11x/3=88
now x=24
so diiference is 6*24-2*24=96

Like? Yes (1) | No (1)  

mohita verma   9 years AGO

let 3 no be x,y,z
As per question,
y=x/2 and z=x/3
(x+x/2+x/3)/3=88
x=144
so, y=72
z=48
x-z=144-48=96

Like? Yes (1) | No (1)  

lokesh   9 years AGO

let the numbers be x , x/2 ,x/3

so (x + x/2 + x/3)3 = 88
=> x= 144

now , 144 - 144/3 = 96

Like? Yes (1) | No (1)  

POOJA YADAV   9 years AGO

Let 2nd no =x 3rd no=y
1st no = 2x = 3y
x=3y/2
(3y+3y/2+y)/3=88
y=48
x= 72
2x=144
so, 144-48=96 ans

Like? Yes (1) | No (1)  

asim   9 years AGO

let 3 given numbers be a , b , c
=> a = 2b ...........................(i)
and a = 3c ........................(ii)

given avg = 88
=> a + b + c = 88 * 3
=> a + (a/2) + (a+3) = 88 * 3 ................(from eq i and eq ii )
=> a(11/6) = 88 * 3
=> a = 48 * 3
=> c = a / 3 = 48*3 / 3 = 48

i.e. a - c = 48 * 3 - 48
= 48 ( 3 - 1 ) = 48 * 2 = 96 ans

Like? Yes (1) | No (1)  

ISHITA UPADHYAY   9 years AGO

Let the numbers be : 3x, 3x/2, x resp.
(3x+3x/2+x)/3 = 88
x=48
Difference = 144 - 48 = 96 Ans

Like? Yes (1) | No (1)  

Ayan Patra   9 years AGO

Let the 3 numbers be a, b and c.
Now, a = 2b = 3c.
So their average can be expressed as:
(2b + b + c) / 3 = 88.
or, 3b + c = 264.
We know that 2b - 3c = 0, from the given condition.
Solving the equations we get b = 72.
So, a = 2b = 144 and c = a / 3 = 48.
Therefore, a - c = 144 - 48 = 96.

Like? Yes (1) | No (1)  

Chirag Jindal   9 years AGO

x=2y=3z
and x+y+z/3=88
substituting from above relations we get
x=144
y=72
z=48
therefore x-z=96

Like? Yes (1) | No (1)  

Thanakkumar T   9 years AGO

Three No's be a b and c...if b=a/2,then c=a/3...if a+b+c=88*3....then a=144,c=48 then a-c=96

Like? Yes (1) | No (1)  

poojasaisri   9 years AGO

x=2y=3z
(x+y+z)/3=88
2y+y+(2/3)y=264
y=72
x=144
z=48
x-z=96

Like? Yes (2) | No (2)  

Yathiraj   9 years AGO

(x+(x/2)+(x/3)) / 3 = 88
Hence, x=144
x/3 = 48
x - (x/3) = 96

Like? Yes (2) | No (2)  

viswambher   9 years AGO

let the three numbers be a,b,c
and a=2b=3c
and average of three numbers is 88 therefore a+b+c= 264
solving the equations we get c= 48 and since a=3c difference b/w those two is 2c = 96

Like? Yes (2) | No (2)  

Mahesh   9 years AGO

Let X be the first number
Then
(X+X/2+X/3)/3 = 88
11X/6 = 88*3
11X = 88*3*6
X = 1584/11
X = 144

Then Second number is 144/3 = 48
So 144 - 48 = 96

Like? Yes (1) | No (1)  

Prayani Singh   9 years AGO

Let a,b,c be two number
a=2b and a=3c
and (a+b+c)/3=88
=> (a+a/2+a/3)/3=88
(11a/6)/3=88
a=(3*6*88)/11=144
hence, a=144 and c=a/3=144/3=48
difference is a-c=144-48=96

Like? Yes (1) | No (3)