ritu yadav   9 years AGO

let x be no. of passed students and y be failed students
then x+y=120
and 39x+15y=4200
solving these equations will yield x as 100

Like? Yes (59) | No (23)  

Chandrajeet Yadav   9 years AGO

let assume Number of passed candidates = x
Since the Number of total candidate= 120
Then Number of failed candidates = 120-x

Since Average Marks obtained by 120 Candidates = 35
So, Total Marks obtained by 120 Candidates = 35*120 = 4200

Total marks obtained by passed Candidates = 39*x
Total marks obtained by failed Candidates = 15*(120-x)

So, 39*x + 15*(120-x) = 120*35
So, 39*x + 1800-15*x = 4200
So, 39*x-15*x = 4200-1800
So, 24*x = 2400
So, x = 100

So, Number of passed Candidates = x = 100

Like? Yes (29) | No (1)  

Abhishek Anand   9 years AGO

Go thru the option pick 100 as no. of passed student
Then 39 x 100 = 3900
and for failed student = 15 x20 = 300
3900+300=4200 which is equivalent to avg of 120 students

Like? Yes (5) | No (1)  

Vivek   9 years AGO

Average of 120 students is 35
let x number of students pass the exam
therefore (120 - x) students fail the exam
so we have
39*x+15*(120-x)=35*120
solving this we get
x= 100
Hence the option is 4)

Like? Yes (3) | No   

ABHINAV PUSHPAM   9 years AGO

Let the no of passed candidate be 'x' the the failed candidates be '120-x'
x*39+(120-x)*15=120*35
39x+1800-15x=4200
x=100

Like? Yes (4) | No (1)  

Surit Datta   9 years AGO

Let the no of passed candidate be 'x' the the failed candidates be '120 - x'
x*39 + (120 - x) *15 = 120*35
39x + 1800 - 15x = 4200
x = 100
so option 4
that's it.

Like? Yes (2) | No   

Devendra Marghade   9 years AGO

If passed candidates are x, then failed=120-x
So 39x+(120-x)*15=120*35
On solving,x=100
Option 4)

Like? Yes (2) | No   

ishan chourishi   9 years AGO

total 120 students, average marks=35
total marks=120*35=4200
there are total 120 students so options which have values more than 120 nd also 120 will be ignored.
now we have 4th option 100,
so let no of students passed=100
marks of passed=100*39=3900
no of students failed=120-100=20
marks of failed=20*15=300
hence total marks of passed nd failed studentd=3900+300=4200
which is average of 35 of 120 students hence option 4.

Like? Yes (2) | No   

K. Vanisri   9 years AGO

let number of student passed=x and that of failed=120-x
therefore,
(39*x+15(120-x))/120=35
Answer will come x=100
So 100 candidates are passed.

Like? Yes (3) | No (1)  

Nikhil Gajjala   9 years AGO

let the passed candidates be x
then fail candidates be y
I.e, x+y=120
total marks = 120*35=4200
39*x+15*(120-x)=4200
x=100

Like? Yes (2) | No   

nipun   9 years AGO

let the no. of passed student be x
hence no. of failed student =120-x

x*39 + ((120-x)*15) = 120*35
39x - 15x + (120*15) = 120*35
24x = 120*20
x=100

Like? Yes (3) | No (1)  

sourav pal   9 years AGO

otal no.of candidates=120 and avg is 35
then total marks obtained by total candidates will be=120*35(hint:total/num=average)
let us consider passed candidates will be x
failed candidates will be120-x
so

120*35=x*39+(120-x)15

By solving the equation we will get x=100

So ans:100

Like? Yes (1) | No   

S R Y Farhan   9 years AGO

P+F / 120 = 35.
P/np = 39
F/nf= 15
39np + 15nf /120 =35
24np + 15*120 / 120 =35
np = 100 answer

Like? Yes (1) | No   

Deepak kumar kumawat   9 years AGO

let passed candidates is x
(39x+15*(120-x))/120=35
x=100

Like? Yes (1) | No   

Vishal   9 years AGO

let x be no of passed then 120-x is no of failed ones..
now 35*120=4200 is total marks...
39*x + 15*(120-x) = 4200
getting x = 100.

Like? Yes (1) | No   

Math Lovers   9 years AGO

Let Passed students = x and failed Students = y

=> x + y = 120
=> 39x + 15y = 120*35

Solving these equations, x=100

Like? Yes (1) | No   

SWARNADEEP BISWAS   9 years AGO

passed candidates=x
x*39+15*(120-x)=120*35
x=100

Like? Yes (1) | No   

kumar   9 years AGO

let pass students be x fail be 120-x;
so 39*x + (120-x)*15 /120 =35
24x=2400
x=100 so pass stuents =100

Like? Yes (1) | No   

rajat gupta   9 years AGO

39x+(120-x)*15=120*35;
solve for x which is the no of students who passed the examination is equal to 100

Like? Yes (1) | No   

umesh   9 years AGO

39*x+15*(120-x)=120*35
24x=120*20
x=100

Like? Yes (1) | No   

neha gupta   9 years AGO

Let x be the number of candidates who passed and y be the number of candidates who failed then:
x + y =120 ..................(i)
also (39 * x) + (15 * y) = 120 * 35 ..............(ii)
Solving (i) and (ii) we get
x=100 and y=20
so number of candidates who passed are 100.

Like? Yes (1) | No   

IYTHA VENKATA RAMAIAH   9 years AGO

bothe passed and failed studnets marks equals to toal marks of 120 students .i.e,39X+15Y=4200, and solving from weighted average we get x=5y now substitute this in first we get x=100.

Like? Yes (1) | No   

santosh kumar patel   9 years AGO

no.of pass=p
no.of fail=120-p
total marks=pass+fail
120*35=39p+(120-p)*15
solvng we get p=100

Like? Yes (1) | No   

G Mounika   9 years AGO

The average marks obtained by 120 students = 35.
The sum of marks of 120 students = 120*35 = 4200.
The average of passed candidates was 39.
Let no of passed candidates= a and sum of marks of passed candidates = x.
so x/a=39
x = 39a
The average of failed candidates was 15
so (4200-x)/(120-a) = 15
(4200 - 39a) = 15(120 - a)
4200 - 39a = 1800 - 15a
24a = 2400
a = 100.
The number of candidates passed is a = 100.

Like? Yes (1) | No   

Balaselvaraj M   9 years AGO

average mark obtained by 120 student is 35.
therefore total marks obtained by 120 student is 35*120=4200.
average mark of passed candidate is 39.
average mark of failed candidate is 15.

let us take 'x' is the no of passed candidates.
then '120-x' is the no of failed candidates.
therefore,
39x+15(120-x)=4200,we get x=100 candidates.

Like? Yes (1) | No   

Bairi Sowjanya Reddy   9 years AGO

let T be total marks obtained by all students & Tp, Tf be total marks of 'x' passed and 'y' failed students resp..
.'. x+y=120 ----> eq1
avg=T/120 ==> 35 =T/120 ==> T=4200
Tp = 39 * x and Tf = 15 * y
Tp + Tf = T i.e. 4200 = 39x + 15y --> eq2
solving both the equations we get x=100 and y = 20

Like? Yes (1) | No   

Deven Patidar   9 years AGO

let x is the no of passed student
then
(39x+120*(120-x))/120= 35
39x+1800-15x=4200
24x=2400
x=100

Like? Yes (1) | No   

Rahul gope   9 years AGO

let the number of passed candidate=x,and failed=y
average of 120 candidtes is 35.
then total 120 number got=120*35=4200
we cant write 39x+15y=4200
and x+y=120
by solving we get x=100

Like? Yes (1) | No   

lanka koundinya   9 years AGO

let x be no.of students passed
39x+(120-x)*15=35*120
x=100

Like? Yes (1) | No   

Manikandn   9 years AGO

go through the options to get the answer......
if i take 100 the average marks of passed students is = 3900
then 20 students is failed soavg. marks of failed students is = 300
then add two averages and divide total number of students we get 35.. so 100 is correct option

Like? Yes (1) | No   

ezhilane   9 years AGO

we can try and error method
if i take 100 the average marks of passed students is = 3900
then 20 students is failed soavg. marks of failed students is = 300
then add two averages and divide total number of students we get 35.. so 100 is correct option

Like? Yes (1) | No   

Siddharth Sinha   9 years AGO

Let x be the no. of passed students and 120-x the no. of failed students.

So, ATQ

35*120 = 39*x + 15*(120-x)

Solving it we get x = 100 thus required no. of students.

Like? Yes (1) | No   

Sanjeeb Chatterjee   9 years AGO

let passed candidates be x and failed candidates be y
therfore total no of candidates is x+y=120
and 39x+15y=120*35
solving we get x=100
hence passed candidates is 100

Like? Yes (1) | No   

pankaj daripa   9 years AGO

39*x +(120-x)*15=120*35
or,(39x-15x)=4200-1800
or,24x=2400
or,x=100

Like? Yes (1) | No   

keerthi   9 years AGO

let number of passed candidates is = x
x *39+(120-x)15=35
x=100

Like? Yes (1) | No   

PRABIR    9 years AGO

Let x be total passed candidates,
39*x + (120-x)=120*35
24x=2400
X=100

Like? Yes (1) | No   

Ajay Kumar Gupta   9 years AGO

{x*39+(120-x)*15}/120=35
so, x=100 and 120-x=20
passing candidate=x=100

Like? Yes (1) | No   

siddhi datri   9 years AGO

let the no of passed candidates =x
Number of failed candidates=120-x
total marks=120*35
hence,
x*39+(120-x)*15=120*35
24x=120*20
x=100

Like? Yes (1) | No   

Puja Dhar   9 years AGO

let, sum of marks of 120 students is p. then p/120=35
or,p=4200
now let t no of student passed the xm and the sum of their no is x.. so.
x/t=39 again let sum of the number obtained by filed student is y. so, y/(120-t)=15
now,39t+15*(120-t)=4200(as sum of all the marks obtained by all 120 students is 4200)
or,t=100

Like? Yes (1) | No   

Moumita Choudhury   9 years AGO

Let the no of passed candidate be 'x' the the failed candidates be '120-x'
x*39+(120-x)*15=120*35
39x+1800-15x=4200
x=100

Like? Yes (1) | No   

Sandip Shaw   9 years AGO

let pass- x
failed=120-x
120*35=39*x+(120-x)*15
therefore x=100

Like? Yes (1) | No   

Rupa Kumari   9 years AGO

Let, n is the number of students passed the exam
39 n+ 15 (120-n) = 35*120;
on solving,
n = 100

Like? Yes (1) | No   

Ganesh kumar   9 years AGO

let total students marks be T,
total pass students marks be P,
total failed students marks be F.
so T=P+F;
now what given is ( T/120)=35
so P+F=35*120.
now P/x=39. F/y=15
where x and y are passed and failed students.
also x+y=120 total students
so by calculation we can get 100.

Like? Yes (1) | No   

ganesh babu   9 years AGO

120*35=35x * (120-x)15
4200=24x+1800
x=100

Like? Yes (1) | No   

Suganya   9 years AGO

given average of 120 candidates =35
sum/120=35
sum=35*120=4200
let us take from option and compare
sum/100=39
sum =3900
4200-3900=300 gives the average of failed candidates =15
so option is 4

Like? Yes (1) | No   

venkatasubbareddy   9 years AGO

let the number of students passed=x
no of students failed=120-x

then

120*35=39*x+(120-x)15

solving this we get x=100
no of students passed =100

Like? Yes (1) | No   

Nairita   9 years AGO

Marks obtained by total candidate=120×35 let no. Of passed students be x marks obtained by passed candidates=39x marks obtained by failed candidates=15(120-x) So, 39x+15(120-x)=120×35 Solving x=100.

Like? Yes (1) | No   

RAJ KUMAR   9 years AGO

x=passed candidate
y=failed candidate
x+y=120
39x+15y=4200
so x=100 ans............

Like? Yes (1) | No   

abhinash   9 years AGO

let no of passed student=x thn total marks of passed =39x
so eqn now
39x+(120-x)15=120*35
after solve get x=100

Like? Yes (1) | No   

bhaskar   9 years AGO

p+f=120
39p+15f=35(p+f)
p=5f
from lines 1 and 3
p=100(no. of students passed)

Like? Yes (1) | No   

Rahul kumar   9 years AGO

let x be no of passed student
total marks =120*35..........eq1
total marks of passed student=x*39.......eq2
total marks of failed student(120-x)*15......eq3
eq1=eq2+eq3
solving we ger x=100 ie no of passed student

Like? Yes (1) | No   

sommya   9 years AGO

x/120= 35 x= 4200

39y+ 15(120-y)= 4200

y = 100

Like? Yes (1) | No   

KODEISWARAN ELANGOVAN   9 years AGO

cp+cf=120
sum of all=sum of failed total+sum of passed total
solving both equations we get the ans as cp=100

Like? Yes (1) | No   

Pranav Vankar   9 years AGO

(39*x)+ 15(120-x)=25*120 (x is the number of candidates who passed)
solving above equation will give x=100

Like? Yes (1) | No   

Dinni   9 years AGO

39x+15y=4200
x+y=120
By solving x=100 & y=20
Passed students=100

Like? Yes (1) | No   

SHARMILA BISWAS   9 years AGO

average marks of 120 candidates=35
so total marks of 120 candidates=35*120
=4200
average marks of passed candidates=39
let no of passed candidates is x
so total marks of passed candidates=39*x
so no of failed candidates=120-x
then total marks of failed candidates=(120-x)*15
so,39*x+(120-x)*15=4200
then x=100
therefore option 4

Like? Yes (1) | No   

jothi   9 years AGO

(39x+15y)/120=35
39x+15y=4200
39x+15(120-x)=4200
39x+1800-15x=4200
24x=4200-1800
24x=2400
x=100

Like? Yes (1) | No   

Hari singh mandral   9 years AGO

x+y=4200
39x+15y=1800
after solving the eqautions
x will be 100

Like? Yes (1) | No   

Sagar Wadjikar   9 years AGO

pass + fail =120
39*pass +15*fail = 35*120
so pass = 100

Like? Yes (1) | No   

Santosh Kumar   9 years AGO

let no of pass student be x and no of fail student =(120-x)
now,
39(x)+15(120-x)=120*35
===>24x=2400
hence x=100

Like? Yes (1) | No   

THUMMALA VINEESHA   9 years AGO

let x be the passed candidates
x*39+(120-x)*15=120*35
39x+1800-15x=4200
24x=2400
x=100

Like? Yes (1) | No   

anand vijay   9 years AGO

x = no of passed candidate (120-x)=no. of failed candidate
39*x+(120-x)*15=4200
on solving we get, x=100
no of passed candidate=100
option 4)

Like? Yes (1) | No   

rajesh kumar pal   9 years AGO

total marks=120*35=4200
marks of passed candidate=39x
marks of failed candidate=15(120-x)
therefore,
39x+(120-x)15=4200
solve the equation nd u will get ur answer

Like? Yes (1) | No   

vignesh   9 years AGO

39x + 15(120-x) = 120*35
by solving this equation

Like? Yes (1) | No   

kriti kankariya   9 years AGO

let passed students be x
therfore failed will be 120-x.
(39x+15(120-x))/120=35

Like? Yes (1) | No   

A.P.Singh   9 years AGO

If x number of students passed, then
39x+15*(120-x)= 120*35
x=100

Like? Yes (1) | No   

Mohit Shrivastava   9 years AGO

Let no. of students passes b "x" and failed b "y".
Total students=x+y=120
average marks of 120 students is 35.Hence they have a total of 120*35=4200 marks.
Now average of passed student is 39 and no of students is x,hence total marks of passed students is 39x.Similarly for failed students its 15x.
Now we have two equations.
x+y=120
and
39x+15y=4200.
Solve it and I'll get d answer.

Like? Yes (1) | No   

vikas kulshrestha   9 years AGO

39x+15(120-x)=4200
x=100
x is a passed students.

Like? Yes (1) | No   

KULDEEP KUMAR   9 years AGO

Let the number o f passed candidates x.
Then total marks = 1 2 0 x 3 5 = 39x + ( l 2 0 - x ) x l 5
4200 = 39*+1800-15*
24*x = 2400
x=100

Like? Yes (1) | No   

Archie   9 years AGO

Let number of students who passed be x.Then (120-x) students failed..
----> Total marks obtained=x*39+(120-x)*15
=120*35
Solving we get,
x=100 :) Option 4

Like? Yes (1) | No   

velmala gangadhar   9 years AGO

t.p passed students marks
t.f failed students marks
p.s passed students
f.s failed students...
avrg of 120 students marks is 35...total marks=35*120
i.e t.p+t.f=35*120
avg of passed students marks 39..t.p/p.s==39
and avg of failed students marks 15.... t.f/f.s==15
by solving t.p=3900,t.f=300 ..then no.of students passed in exam is..100

Like? Yes (1) | No   

Trinadh   9 years AGO

let pass students be x and failed students be y. then sum of x and y is 120. Therefore 39*x+15*y=35*120. By solving this we can get x=100.

Like? Yes (1) | No   

vivek   9 years AGO

total marks obtained by students= 35*120=4200
also let no. of passed student will be x and no of failled student be y. then,
x+y=120
39*x + 15*y=4200
By solving two equation we get x =100

Like? Yes (1) | No   

Manikanta   9 years AGO

given the average of 120 students is 35 = (total sum/120)
total sum=35*120=4200
the passed candidates avarege =39
the failed candidates average =15
there fore 39*100=3900 passed students is 100 and
failed students is 15*20=300
the total is 4200
so the answer is 100

Like? Yes (1) | No   

vivek kr. chatterjee   9 years AGO

Average marks = 35 , no. of students = 120, so total = 35*120 = 4200
by hit and trial method,
taking no. of passed students (must be less than 120) = 100, their average marks = 39, so in total = 39* 100 =3900, and remaining failed students =20, their avrg = 15, in total = 15* 20 = 3000

since, 39000 + 3000 = 42000 which satisfies the situation

hence answer = option 4 i.e 100

Like? Yes (1) | No   

tamilmani   9 years AGO

The total mark got by 120 students
in the class= (120*35)=4200
No of candidates passed = x
No of candidates failed = 120 - x
39(x) + (120-x)*15 = 4200
39 x +1800 - 15 x = 4200
24 x = 2400
x = 100
Number of candidates passed in the examination(x)=100

Like? Yes (1) | No   

poojasaisri   9 years AGO

35=(x/120) x=4200 =>sum of all candidates marks
passed candidates => 39=y/z =>y=39z
failed candidates => 15=p/(120-z) =>p=15*(120-z)
w.k.t p+y=x =>p+y=4200
15*(120-z)+39z=4200
=> z=100 =>passed candidates

Like? Yes (1) | No   

guru teja   9 years AGO

Lets take no of passed candidate be X the the failed candidates be 120-X
X*39+(120-X)*15=120*35
39X+1800-15X=4200
X=100

Like? Yes (1) | No   

Sharmila Alajangi   9 years AGO

given the average of 120 students is 35 = (total sum/120)
total sum=35*120=4200
the passed candidates avarege =39
the failed candidates average =15
there fore 39*100=3900 passed students is 100 and
failed students is 15*20=300
the total is 4200
so the answer is 100

Like? Yes (1) | No   

shahida   9 years AGO

as avg of 120 students is 35...
let the no of students who passed be x..
so, the no of students who fail will be..120-x..
so,120*35=39*x+(120-x)*15
x=100

Like? Yes (1) | No   

mithilesh kumar   9 years AGO

Let passed student=x
so total no. of student=x*39+(120-x)*15
120*35=24x+1800 4200
4200-1800=24x
=>x=2400/24
x=100
so total passed student=100

Like? Yes (1) | No   

Tanmay Shah   9 years AGO

Let passed students are x.
So failed student are (120-x).
120*35=39*x+15*(120-x)
so 24*x=2400
so x=100
passed students are 100

Like? Yes (1) | No   

Deepanshu Chaturvedi   9 years AGO

x be no. of students passed
y be no. of students failed
equation formed are
x+y=120
39 x+15 y=4200 (sum=120*35=4200)
solving we get
x=100

Like? Yes (1) | No   

Golluru Lalitha   9 years AGO

Let x= no of students pass in exam,y= no of failure students x+y = 120
39x+15y = 120*35
by solving above equations x=100 , y =20.

Like? Yes (1) | No   

Nizamuddin S   9 years AGO

let number of passed candidates be x = 39*m ,
number of failed candidates be y = 15*(120-3)
given x+y = 4200
on substituting we get m=100.

Like? Yes (1) | No   

KAMARAJAR   9 years AGO

ans=100
120*35=4200
100*39=3900
20*15=300
3900+300=4200

Like? Yes (1) | No   

lavanya   9 years AGO

Let the no. of candidates passed exam =x
therefore
120*35 = 39*x +15(120-x)
x= 100

Like? Yes (1) | No   

GOURANGA SUNDAR MANDAL   9 years AGO

let x student passed,so (120-x) student failed
so,in mathematical problem,39*x +(120-x)*15 =120*35
then, x=100
so option 4 is correct answer

Like? Yes (1) | No   

KUMAR ROHIT   9 years AGO

total marks=120*35
let, total passed=X
i.e, total fail=120-X
so,
120*35=39X + 15(120-X)
=> X=100.

Like? Yes (1) | No   

pappu kumar   9 years AGO

let passed eqn=x
x+y=120, 39x+15y=120*35
39x+15y=4200
solving these two eqn,we get
x=100

Like? Yes (1) | No   

Ashish Kumar Karan   9 years AGO

let passed candidates=x
(39*x) + (120-x)*15=120*35

Like? Yes (1) | No   

apoorv gupta   9 years AGO

Let no. of students passed = x
and no. of students failed = y
so, x + y = 120 ---(1)
(39x + 15y) / 120 = 35 ---(2)
on solving above two equations we get x = 100

Like? Yes (1) | No   

rahul shaw   9 years AGO

let x be the no of passed students
so acc to question,
35*120=39x+(120-x)*15
x=100
option 4

Like? Yes (1) | No   

saicharan   9 years AGO

total score=35*120=4200
let y students passed and no of students failed = 120-y
sum of scores of passed students be 39y
therefore sum of scores of failed students is (120-y)*15=4200-39y
therefore y=100

Like? Yes (1) | No   

Gouri Ajit Ghode   9 years AGO

If we consider X candidates passed the exam then there will be 120-X candidates who failed.
So, 120*35=39*X+15*(120-X)

Like? Yes (1) | No   

Bathula Tejesh   9 years AGO

Total no.of students=120
Let 'x' be the number of passsed students
& their avg is 39.
therefore total=39*x=39x......................(i)
then, (120-x) is the no.of failed students
& their avg is 15
therefore total = (120-x)*15=1800-15x...................(ii)
avg of 120 students=35
therefore total = 120*35=4200.................(iii)
then from the above we have to fid the value of ""x""
the required equation is as follows
(i)+(ii)=(iii)
39x+1800-15x=4200
24x=2400
x=2400/24
x=100
therefore the no.of candidates who passed the examination is """""""""""100"""""""""".

Like? Yes (1) | No   

Mugesh sivagnanam Krishnapillai   9 years AGO

Let the number of passed candidates be x.
then total marks = 120 x 35 = 39x + ( 120 – x ) x 15 or, 4200 = 39x + 1800 – 15x
or, 24x = 2400 So x = 100

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dheeraj ramavatar somani   9 years AGO

total marks=35*120
39*passed std+15*(120-passed std)=total marks
on solving
passed std=100

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Akshit Agarwal   9 years AGO

Answer is 100
Total marks 120*35=4200
Total passing marks 39*100=3900
Total failing marks 15*20=300
Total marks 300+3900=4200
Total students 100+20=120

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khush   9 years AGO

p=sum of marks obtained by passed students
f=sum of marks obtained by failed students
np=no. of passed students
nf= no. of failed students

nf+np=120(given)

(p+f)/120=35 ( given)

p/np=39(given)

f/nf=15 (given)

(p/np) + f(120-np) =35*120--->(1st equation)
p+f=35*120;
p=35*120-f--->(2)

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RAVAL   9 years AGO

suppose passed candidates are is X
& faid candidates are Y then,
35=sum/120
so, sum=4200
X+Y = 120 ......(1)
39X+15Y = 4200....(2)

solve both equation,
X= 100 & Y = 20
ans. = 100

Like? Yes (1) | No   

Sushmita Ghanty   9 years AGO

let x no of students passed in the exam. so,
39x + 15(120-x) = 35*120
or, 24x=2400
or, x=100

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Nanthini   9 years AGO

(x1+x2+....xn)/100=39=>3900
(x1+x2+....xn)/20=15=>300
3900+300=4200/120=35

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Amber Singh   9 years AGO

let no of passed candidates be x and no of failed candidates be y. Then 39x+15y=120*35 and x+y=120.
solving these two linear equations we get x=100.

Like? Yes (1) | No   

kondapuram tirumalreddy   9 years AGO

let the number of passed candidates be x
then the number of failed candidates will be 120-x
so
x*39+(120-x)*15=120*35
39x+1800-15x=4200
x=100

Like? Yes (1) | No   

sonia kalsi   9 years AGO

total marks of passed +total marks of failed=4200
let no. of passed students=x
n no. of failed students=120-x
as total no. of students =120
acc. to ques.
total marks of passed students=39x
total marks of failed students=1800-15x

now equation is:
1800-15x+39x=4200
and
x =100

hence no. of passec students =x=100

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vimal tiwari   9 years AGO

total students = 120*35

let pass be X then fail be 120 - X

pass= 39*X
fail=(120-X )*15

pass + fail =total
(x)*39 + (120 - X)*15 =120*35

X=100

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Anirban Basu   9 years AGO

sum = 35*120
x*39+(120-x)*15=35*120
solve for x

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Harish    9 years AGO

s/120=35 where s=marks of students passed+of those who've failed
p->total marks of passed students
p/x=39 where x-> no of students passed.
similarly s-p/120-x=15 for failed students, s=35*120
solving these 2 we get x=100

Like? Yes (1) | No   

SINJAN   9 years AGO

Total is 120*35
Let x pass and (120-x) fail...
then 39*x+(120-x)*15=120*35

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Anusha Kota   9 years AGO

let no of students who passed= k
let no of students who failed = m
Total number of students = 120= k+m
marks obtained by passed candidates=p
marks obtained by failed candidates=f

avg of all students=( (total marks)/120)=35
=((p+f)/120)=35
passed candidates marks average=(p/k)=39
so, p=39*k
failed candidates marks average=(f/m)=15
so, f=15*m
on substituting above equations, we get
( ( (39*k)+(15*m))/120 )=35
and m=120-k,
we get k=100

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RANJAN KUMAR   9 years AGO

total marks=120*35=4200
suppose number of pass student=x
now,
39*x+15(120-x)=4200
39x+1800-15x=4200
24x=2400
x=100

Like? Yes (1) | No   

arun prasad   9 years AGO

by using trial and error method
i take 100 students are passed and average is 39 so total is 3900
remaining 20 students are fail their average is 15 so total is 300
39x+15y=35*120
3900+300=4200
4200=4200

Like? Yes (4) | No (3)  

ankit rawat   9 years AGO

ratio of fail to pass candidate is 1:5
so..
6x=120
x=20
no. of pass candidate is 5x= 5×20=100

Like? Yes (15) | No (14)  

Ananth Chellooss   9 years AGO

Let the number of passed candidates be x. then total marks = 120 x 35 = 39x + ( 120 – x ) x 15 or, 4200 = 39x + 1800 – 15x
or, 24x = 2400 So x = 100

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yamini shrivastava   9 years AGO

(tm)total marks=marks obtain by pass student(tp)+marks obtain by fail student(tf)
tm/120=35
tm=35*120=4200
tp/x=39 //let x student is pass//
tf/12-x=15
4200=39x+15(120-x)
2400=24x
x=100

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Anurag Sahay Sriavsatav   9 years AGO

let the no of passed candidates=x
let the no of failed candidates=y
so x+y=120
39x+15y=4200
so x=100;
so option (4) is correct.

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Tru Jan   9 years AGO

Total Students = 120
avg marks = 35
ie:- 120*35=4200 (Total marks given)

if pass student = 100
avg marks =39
hence total marks given for passed students = 100*39 =3900

failed students =20
avg marks = 15
hence total marks given for passed students = 20*15 =300

and Total marks given = 4200 = 3900 + 300
ie :- passed + failed student marks....

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S.S.Akhilesh   9 years AGO

sum of marks of total students = average*total number
using that,sum of fail students + sum of passed students = total students

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jonsarath   9 years AGO

total=120*35
pass + fail is 39x+15(120-x)=4200
24x=2400
x=100

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raghvendra   9 years AGO

120*35=4200 total marks
let n be the candidate who pass the so
39 n+(120-n)*15=4200
n=100

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praveen Kumar   9 years AGO

sum of 120 students marks / 120=35
sum of marks of passed students / number of students passed=39
sum of marks of failed students / number of students failed =15
sum of the marks of passed students(mp)+failed students(mf)=sum of 120 student marks(m120).
no. of passed student(p)+failed students(f)=120
m120/120=35

mp/p=39
mf/f=15

(mp+mf)/120=35
(p*39+f*15)/120=35

p*39+(120-p)*15=35*120


p=100

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sahil arora   9 years AGO

sry previous was wrong correct is option 4

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shyamal gayen   9 years AGO

Let the no. of passed candidate is x.so no. of failed candidate is (120-x).
now 39x+15(120-x)=120*35
so x=100

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Aniket Rai   9 years AGO

total marks =120*35;
let n student passed ..
marks obtained by n student = 39*n
marks obtained by failed student = 15*(120-n)
according to the question
120*35 = 39n + 15*(120-n)

solving n = 100

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SAGNIK DATTA   9 years AGO

let passed = x failed =120-x
so 39x + 15(120-x)=120*35
x=100

Like? Yes (1) | No (1)  

Narendra Gopi   9 years AGO

marks obtained by 120 students is 120*35
passed candidates=p
failed candidates-120-p
120*35=39x+(120-x)*15
4200=14x+1800
24x=2400
x=100

Like? Yes (1) | No (1)  

ABID PASHA   9 years AGO

average of 120 students is 120*35=4200
let x who passed and 120-x who failed
then 39x+(120-x)15=4200
24x+1800=4200
24x=2400
x=100

Like? Yes (1) | No (1)