In (6^41 * 3^56 * 11^7 * 65^9), find the total number of prime factors

anjali gupta   9 years AGO

41+41+56+7+9+9 = 163

Like? Yes (2) | No   

debanjan   9 years AGO

82+56+9+9+7=163

6^41=2*2*2.....(41 tims)
*3*3*3.......(41 times)

3^56=3*3*3*3.......(56 times)

11^7=11*11*11..... (7 times)

65^9=13*13*13...... (9 times)
*5*5*5...... (9 times)
41+41+56+7+9+9=163

Like? Yes (2) | No   

RAKESH   9 years AGO

2^41 * 3^(41+56) * 11^7 * 5^9 *13^9

no. of prime factors= sum of powers = 163

Like? Yes (1) | No   

NIKHIL JAIN   9 years AGO

factorise 6 as 2*3 and 65 as 5*13
and on adding all the powers we get 163 as the answers.

Like? Yes (1) | No   

Vivek Ratan   9 years AGO

on finding the no of prime nos ini the given seq, and adding their powers we get 163

Like? Yes (1) | No   

JEGATHA.H   9 years AGO

3^41*2^41*3^56*11^7*13^9*5^9
prime factors are the no divisible by itself and 1
total prime factor=41+41+56+7+9+9=`163

Like? Yes (1) | No   

MRITUNJAY   9 years AGO

3^97*2^41*11^7*13^9*5^9
total no of prime factor is 97+41+7+9+9=163
option7

Like? Yes (1) | No   

Maneesh Gupta   9 years AGO

if we break 6^41 into 2^41 & 3^47
same as with 65^9 into 13^9 & 5^9
then 2^41*3^97*11^7*13^9*5^9
41+97+7+9+9=163

Like? Yes (1) | No   

P J S Sailesh Kumar Reddy   9 years AGO

6^41 * 3^56 * 11^7 * 65^9.... for this 6 has 2 primes 2 and 3... so power should be doubled i.e., 82....
3 has no primes so 56 is same.... same for 11 also is 7... 65 has 13 and 5... so power should be doubled 18...
82+56+7+18=163

Like? Yes (1) | No   

Devendra Marghade   9 years AGO

[(3*2)^41]*[ 3^56]*[11^7]*[(13*5)^9], So
Prime Factors--No. of times
3 ------>41
2 ------>41
3 ------>56
11 ----->7
13 ----->9
5 ------->9
Total-->163
Option 7)

Like? Yes (1) | No   

Goutham   9 years AGO

(2*3)^41*3^56*11^7*(13*5)^9
2^41 * 3^41 * 3^56 * 11^7 *13^9 *5^9
sum of all powers=163 are the number of prime factors for given number

Like? Yes (1) | No   

Jaikumar Bhatia   9 years AGO

6^41=2*2*2.............(41times),3*3*3.......(41times)
3^56=3*3*3.............(56times)
11^7=11*11*11......(7times)
65^9=13*13*13.....(9times),5*5*5......(9times)
Then,41+41+56+07+09+09=163
Ans is 163
option is (7)

Like? Yes (1) | No   

Ritesh kumar   9 years AGO

(2*3)^41*3^56*11^7*(13*5)^9=
sum up the factor=2=41
3=56+41
5=9
11=7
13=9
total=163

Like? Yes (1) | No   

shanti bhushan   9 years AGO

(41+41+56+7+9+9)
adding the total power to the prime no.

Like? Yes (1) | No   

satish ojha   9 years AGO

2^41* 3^97 *5^9 *11^7 * 13^9
sum of all power
41+97+9+7+9=163

Like? Yes (1) | No   

gunjan   9 years AGO

express composite nos. 6 and 65 in terms of their prime factors
2^41*3^41*3^56*11^7*13^9*5^9
=2^41*3^97*5^9*11^7*13^9
now that each term has been expressed as a prime no. raised to a power which tells the frequency of their occurrence. adding these powers would get total no. of primes 41+97+9+7+9=163

Like? Yes (1) | No   

swetha rangaraj   9 years AGO

2^41*3^41*3^56*11^7*13^9*5^9
2^41*3^97*11^7*13^9*5^9
41+97+7+9+9=163

Like? Yes (1) | No   

DEBMALYA GHOSAL   9 years AGO

2^41*3^97*11^7*5^9*13^9
total prime factors: 97+41+9+9+7=163

Like? Yes (1) | No   

sugayathri   9 years AGO

[2^41*3^41*3^56*11^7*5^9*13^9]=(41+41+56+7+9+9=163)
=163

Like? Yes (1) | No   

Saleel Kulkarni   9 years AGO

The 6 can be factorized as 2*3 and 65 can be factorized as 13*5
So final equation becomes 2^41*3^41*3^56*11^7*13^9*5^9
So total factors = 41+41+56+7+9+9=163

Option 7)

Like? Yes (1) | No   

Nikhil Shriwastav   9 years AGO

make further factor of 6 and 65 so ans will be
2^41*3^41*3^56*11^7*13^9*5^9
add the powers 41+41+56+7+9+9=163

Like? Yes (1) | No   

Divya jain   9 years AGO

2^41*3^41*3^56*11^7*5^9*13^9
therefore prime numbers are = 41+41+56+7+9+9=163 ans

Like? Yes (1) | No   

vidhisa gajera   9 years AGO

6^41=(2*3)^41 means 41 times 2 and 41 times 3, total=41+41=82.
3^56=(3*1)^56 means 56 times 3 and 1 is not prime no. so it is not consider. total = 56.
11^7=(11*1)^7 means 7 times 11, total =7.
65^9=(13*5)^9 means 9 times 13 and 9 times 5, total =9+9=18
totals prime no. is = 82+56+7+18 = 163

Like? Yes (1) | No   

sumit kumar   9 years AGO

6^41*3^56*11^7*65^9
=>(3*2)^41*3^56*11^7*(13*5)^9
=>3^41*2^41*3^56*11^7*13^9*5^9
so no of prime factor
=41+41+56+7+9+9
=163
option is 7

Like? Yes (1) | No   

PRITI MISHRA   9 years AGO

(3*2)^41* 3^56* 11^7* 5^9* 13^9
2^41* 3^97* 5^9* 11^7* 13^9
required prime factor=41+97+9+7+9 = 163

Like? Yes (1) | No   

pavani   9 years AGO

2^41*3^97*11^7*5^9*13^9
=41+97+7+9+9
=163

Like? Yes (1) | No   

Dinni   9 years AGO

2^41 * 3^41 * 3^56 * 11^7 * 5^9 * 13^9
41+97+7+18
163

Like? Yes (1) | No   

ROHIT KUMAR DUBEY   9 years AGO

prime factor=41+97+7+9+9=163(i.e power raise to 2,3,11,13,5)
if non prime factor then formulae(a+1)(b+1)(c+1)......is applicable

Like? Yes (1) | No