ER. Anjali gupta Profile Page

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Shubham sahu 5 years ago

hey,anjali can u tell me about TCS placement paper.

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gunjali 7 years ago

@anjali u gave ans. of this question

1/x+1/y=1/z where x=12 and y,z positive integer how many possible value of y and z ?
a) 4
b) 7
C) 12
d) infinite

plz explain ur concept?

Reply Like? Yes (2) | No

Rishu 7 years ago

ans is 4

1/z=1/12+1/y
z=1/(1/12+1/y)

z(max)=1/(1/12+1/infinity)=12
z(min)=1/(1/12+1/0)=0

so range of z varies from 0 to 12 for positive integral value of y

y=1/(1/z-1/12)

now substituting z=1,2.3,4,5,6,7,8,9,10,11 in above equation we can easily conclude that y is a positive integer only when z=3,4,6,8

thus there are only 4 possible values of y & z according to given condition

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Ramakrishna 7 years ago

Q: which is the largest animal of cat family ?

a) lion b) tiger

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gunjali 7 years ago

tiger is the largest animal of cat family

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Ramakrishna 7 years ago

Q: sugar is sold at rs 25 per kg or in a pocket of 5 kg for 110.How much will it cost a house wife, if she buys 17kg sugar?

a) 374 b) 380

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anjali gupta 7 years ago

b) 380
17 = 5*3 + 1*2
total cost = 3*110 + 25*2 = 330 + 50 = 380

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Ramesh Krishnan 7 years ago

17 kg can be split into 15kg + 2kg

5kg costs 110 rs so 15kg costs 330rs -------->(1)
1kg costs 25 rs so 2kg costs 50rs -------->(2)
adding 1 and 2 = Rs.380

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Ramakrishna 7 years ago

thanks u.......................

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Ramakrishna 7 years ago

Q: if 25+13=32 and 70+26=30 then find 26+13= ? I NEED COMPLETE SOLUTION PLS HELP ME

a)20 b)24 c)36 d)45

Reply Like? Yes (21) | No

Devendra Marghade 7 years ago

a) 20
.

.

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anjali gupta 7 years ago

@devendra can u give complete solution ?

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Parshuram Kumar 7 years ago

for 25+13=32

25-->5-2=3....A
13-->3-1=2....B
32-->3-2=1....C

ie =>A-B=C =>3-2=1;

for 70+26=30

70-->7-0=7....D
26-->6-2=4....E
30-->3-0=3....F

ie D-E=F =>7-4=3;

now final 26+13=?

26-->6-2=4;
13-->3-1=2;
?...it must be 4-2=2;

now 20-->2-0=2;
and 24-->4-2=2;

but answer will be 20.
because eqn.C=> 32-->left - right=1;

eqn.F=> 30-->left-right=3;

so answer is 20-->left-right=2;

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Anwar 6 years ago

Are you preparing for postman/ mail guard examination ?

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anjali gupta 7 years ago

I gave TCS interview on 19th Dec, and in response i got a mail from "careers@tcs.com"

"We would like to thank you for participating in the TCS Off Campus drive and this is to inform you that offer letters for all the selected candidates are being released in phases and the first phase for the same has been completed today.

Heartiest congratulations from TCS Team to all the selected candidates who have received their offer letters in phase1. We request the remaining candidates to kindly keep checking their mails and campus commune for further updates on their status. "

My patience is getting shorter now.. Anyone has a say on this? I dont know for how long i am suppose to wait.

Reply Like? Yes (4) | No

Monica Shailesh 7 years ago

same wid me.did you receive any mail??

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anjali gupta 7 years ago

Nope.. i got this last mail on 24 Dec . No update since then

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mallaiah 7 years ago

THANK YOU ANJALI CAN U SEND U MAIL I HAVE SOME DOUGHTS PLZ SEND YOUR MAIL TO MALLAIAH1995@GMAIL.COM

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Ramakrishna 7 years ago

which is the best book for RRB (Railway recruitment board) for General knowledge ? pls tell me

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anjali gupta 7 years ago

Sorry.. I dont have much idea about that.. i guess pratiyogita darpan and manorama are good for general knowledge

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Ramakrishna 7 years ago

Thanks medam..............

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anjali gupta 7 years ago

Ur welcome :)

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anjali gupta to sindhuja 7 years ago

speed of faster boat=a
speed of slower boat=b
speed of stream=x
time= dist/speed
downstream,
1.5*d/(a+x) = d/(b+x)
since speed of a downstream= a+x
and of b = b+x
on solving u get,
3(b+x)=2(a+x).. eq 1

upstream,
speed of a= a-x
speed of b= b-x
d/(a-x)=d/(2*(b-x))
on solving u get,
a-x=2(b-x).. eq 2

distance = speed * time
1*(a-b)=8
a=8+b.. eq 3

put a=8+b in eq 1
u get,
b=16-x
put this value of b in eq 2
u get x=4, b=12, a=20
Answer is 20 which is speed of faster boat :)

Reply Like? Yes (1) | No

sindhuja 7 years ago

HI , can u solve this for me
7.Two boats go downstream from point X to point Y. The faster boat covers the distance from X to Y 1.5 times as fast as the slower boat. It is known that for every hour the slower boat lags behind the faster boat by 8 km. However, if they go upstream, then the faster boat covers the distance from Y to X in half the time as the slower boat. Find the speed of the faster boat in still water.

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ER. Anjali
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Anjali gupta (F)

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Score from best 50 Questions

Attempted 25
Date Points

24 Nov 15 -1
26 Nov 15 15
30 Nov 15 15
01 Dec 15 15
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04 Dec 15 15
10 Dec 15 15
11 Dec 15 15
14 Dec 15 15
15 Dec 15 15
16 Dec 15 15
17 Dec 15 15
18 Dec 15 14
21 Dec 15 16
22 Dec 15 15
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24 Dec 15 15
25 Dec 15 15
29 Dec 15 15
30 Dec 15 15
31 Dec 15 15
01 Jan 16 18
04 Jan 16 15
05 Jan 16 15
11 Jan 16 19

Total 366
M4 Score366 / 10 = 36

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