If 3^(n + 4) - 3^(n + 2) = 8, What is the value of n?

G.S.Kantharao   7 years AGO

3^(n+4) -3^(n+2)=8
3^n*3^4-3^n*3^2=8
3^n(81-9)=8
3^n=8/72=1/9=3^-2
Hence n=-2.
The Right option is 8👈

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Sanju patidar   7 years AGO

3^2-3^0=8
n+4=2, n+2=0
So,
n=-2

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Mukesh Kumar   7 years AGO

Since 3^0=1
so,
3^(-2+4)-3^(-2+2)=9-1=8

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Disha agarwal   7 years AGO

3^(n+2)(3^2-1) = 8
3^(n+2)*8 = 8
3^(n+2) = 1
so here we get n = (-1)

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Akash   7 years AGO

3^(n+4) - 3^(n+2) = 8
(3^n)(3^4) - (3^n)(3^2) = 8
(3^n)(81-9) = 8
(3^n) = 8/72 = 1/9 = 1/(3^2)

So n = -2

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Mukund Manohar   7 years AGO

3^n(3^4 - 3^2) = 8
3^n = 8/72 = 1/9 =3^(-2)
So, n= -2

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palak Jain   7 years AGO

3^(n+4)-3(n+2)=8
3^n(81-9)=8
3^n(72)=8
72/9=8
n=-2

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jyothi chhabria   7 years AGO

3^n (3^4-3^2)=8
3^n=8/72
3^n=1/9
ien= -2

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Sneha Shailesh   7 years AGO

3^(n+4)-3^(n+2)=8
Expanding and taking common terms out
3^n*3^2*(3^2-1)=8
8 will cancel with bracket term
3^n=3^-2
Hence n=-2

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Devendra Marghade   7 years AGO

3^(n+4) - 3^(n+2) = 8
3^n * 3^4 - 3^n * 3^2 = 8
3^n * 3^2 (9 - 1) = 8
3^(n+2) = 1
3^(n+2) = 3^0
=> n+2 = 0 or n= -2
Option 8)

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VAIBHAV SRIVASTAVA   7 years AGO

3^(n+4)-3^(n+2)=8
3^(n+2) [3^2 - 3^0 ]=8
3^(n+2)*8=8
3^(n+2) =1
3^(n+2) =3^0
n+2=0
n = -2

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Shreya Katiyar   7 years AGO

3^(n+4) - 3^(n+2)=3^2 - 3^0
On comparing,
n+4=2 and n+2=0
therefore n=-2

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aparna padakanti   7 years AGO

3^n*81-9*3^n=8
723^n=8
3^n=1/9
3^n=3^-2
n=-2

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Gokul Krishnan   7 years AGO

3^(n+4)-3^(n+2)=8
3^n(81-9)=8
3^n=1/9
n= -2

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Kalpesh   7 years AGO

Put n = -2
3^(-2+4) - 3^(-2+2) = 3^ 2 - 3^ 0 = 9 - 1 = 8

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Himanshu Arora   7 years AGO

rhs =8=9-1
take log both sides
then use log x - log y = log(x/y)
now remove log from both sides
we'll get n+4=2 ...... i.e. n= -2

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ganesh chemanchula   7 years AGO

3^(n+4)-3^(n+2)=8
3^(n+2)(3^2-1)=8
3^(n+2)=1....3^(n+2)=3^0
n+2=0
n=-2
So option 8.

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Nitish Sinha   7 years AGO

3^(-2+4) - 3^(-2+2)
=3^2 - 3^0
= 9 - 1
= 8
Therefore we get n= -2
Ans.Option 8

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Varsha Kumari   7 years AGO

3^(n+4) - 3^(n+2) = 8
3^(-2+4) - 3^(-2+2) = 8
3^2 - 3^0= 8
9 - 1 = 8
8 = 8

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Siva   7 years AGO

3^(n+4)-3^(n+2)=8
[3^(n+2)]*8=8
3^n=3^-2
n=-2

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M4 Murali   7 years AGO

3^(n+2)[3^2-1]=8
3^(n+2)*8=1
3^(n+2)=3^0
n+2=0
n=-2

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Taraka sai reddy   7 years AGO

3^(n+2)(3^2-1)=8
3^n+2=1
3^n=1/9
3^n=3^-2
n=-2

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saiakhil   7 years AGO

by option verification
3^(-2+4)-3^(-2+2)=9-1=8

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ankit   7 years AGO

3^(n+2)[3^2-1]=8
3^(n+2)[8]=8
3^(n+2)=1
taking log
(n+2)log3 =log1
(n+2)log3 =0
n+2=0
n=-2

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Jayanth.V   7 years AGO

Trial and error method
-2 will solve the equation perfectly
9 - 1 =8

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Mayur Shinde   7 years AGO

3^((-2)+4)=9
3^((-2)+2)=1

so 3^((-2)+4)-3^((-2)+2)=9-1=8

so value of n is -2

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binaya   7 years AGO

3^(-2+4)-3^(-2+2)
=3^(2)-3^0
=9-1
=8

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sreeja   7 years AGO

here we can write 8 as 9-1 which is equals to 3*3-1... if we want to get that then n=-2 is right

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Poulami Banik   7 years AGO

3 ^(n+4)-3^(n+2)=8
3^n*3^2*(3^2-1)=8
3^n*3^2=8/8
3^n=3^-2
n=-2

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