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Maths Quotes

MATHEMATICS is a great motivator for all humans.. Because its career starts with "ZERO" but it never end(INFINITY)..

Vignesh R

A MAN IS LIKE A FRACTION WHOSE NUMERATOR IS WHAT HE IS AND WHOSE DENOMINATOR IS WHAT HE THINK ABOUT HIMSELF LARGER THE DENOMINATOR SMALLER THE FRACTION

UNKNOWN

Placed User Comments

M4Math helped me a lot.

Vipul Chavan 4 years ago

Thanks m4 maths for helping to get placed in several companies.
I must recommend this website for placement preparations.

yash mittal 5 years ago

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to (3 years ago) "Other"

A train passes a standing man 11.3 seconds and passes a bridge of length 396m in 18 seconds .the speed of the train is

Reply Like? Yes (1) | No

(3 years ago)

Let the speed of the train be x m/sec and length of the train be y m, then y/x=11.3 or y - 11.3x = 0 --(i)
Also, (y + Length of platform)/x=18
(y+396)/x=18 => 18x-y=396 ---(ii)
Solving (i) & (ii), we get, x=59.10 and y=667.88
Hence speed of the train is 59.10 m/s

Like? Yes (1) | No

(3 years ago) "Other"

When you keep believing, keep trying and keep doing... Someday, you will succeed.

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(3 years ago) "Other"

Find the elements in the relation "have the same remainder when divided by 8" if the
relation is defined on {1, 2, 3 .... 24, 25}. Also, find the distinct equivalence classes
of this equivalence relation.

Reply Like? Yes | No

(3 years ago) "Other"

the average number of people visitedredfort on every day is 2240.but 2200 on every saturday, 3000 on sunday and on wednesday it is 1500people visited . what is the average number of people visited on remaining days in the ,month of december when there are 4 thursdays abd 4 mondays in the month?

Reply Like? Yes | No

(3 years ago)

Average Visited in December = 2240
Then total visitors = 2240*31 = 69440
As there are 4 Thursdays and 4 Mondays the other 3 are Sunday,Friday and Saturday. It means 5 Sundays 5 Fridays and 5 Saturdays
It means 5*2240+5*2200+5*3000=11200+11000+15000=37200
Remaining=69440-37200=32240
Average of remaining=32240/16=2015
So Average =2015

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(3 years ago) "Other"

help me for placements

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(3 years ago)

please give more details ?

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(3 years ago) "Other"

hero
ajjjjjjjjjjjjjjjjjjjjj,,,pckkk

Reply Like? Yes | No (1)

(3 years ago) "Other"

aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

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(3 years ago) "Other"

Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?

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(3 years ago) "Other"

Long ago a princess wanted

Reply Like? Yes | No (2)

(3 years ago) "Other"

during a period of decline in a stock market prices a stock sold at ₹50/share on the first day,₹40/share on the second day and ₹25 on the third day.If a invester bought 100,120&180 shares on the respective 3 days the average price paid per share will be?.

Reply Like? Yes | No

(3 years ago)

Avg. Price = (100*50 + 120*40 + 180*25) / (100+120+180) = 35.75

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(3 years ago) "Other"

Help me to get score in tcs nqt 2021

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(3 years ago) "Other"

On Feb 18 I have TCS NQT can some one help me friends

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(3 years ago) "Other"

A man sets out by cycle from Delhi to Rohtak, and at the same time another man starts from Rohtak by cycle to Delhi. After passing each other they complete their journeys in 3 1/3and 4 4/5 hours respectively. At what rates does the second
man cycle if the first cycles at 8 km per hour?

Reply Like? Yes | No

(3 years ago)

Let A and B are the persons.
A travelled x km,B travelled y km before they meet.
Time taken for A and B to reach their destinations are 10/3h,24/5h
Speeds are y/(10/3),x/(24/5)
At the time they meet they travelled same time => x/(3y/10)=y/5x/24)
10x/3y = 24y/5x=>50x^2=72y^2
=>x^2/y^2=72/50
x/y=√(1.44)=1.2
=>x=1.2y
Total distance =(x+y)=(x+x/1.2)=2.2x/1.2=11x/6
Now time taken for B=(11x/6)/(5x/24)
=11*24/6*5=44/5=8h 48m

Like? Yes (4) | No

(3 years ago) "Other"

ORDER RESEARCH CHEMICALS FROM https://www.highgradeschemicals.com/

Reply Like? Yes (1) | No (1)

(3 years ago) "Other"

If the sum of the first 43 terms of an arithmetic progression is 2967, then find the sum of the 11th and the 33rd terms of the same series.

Reply Like? Yes | No

(3 years ago)

First term = a, Number of terms=n, Difference = d
nth term = a+(n-1)d
11th term = a+10d, 33rd term = a+32d
Sum of 11th & 33rd= 2a+42d = 2(a+21d)=2(22nd term)

Middle term = Total sum/n
43/2 th term = 22nd term = 2967/43 = 69

=>Sum of 11th & 33rd = 2(69) = 138

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(3 years ago)

Sum of first 43 terms in A.P=43(2a+42d)/2=2967
11th term +33rd terms =(a+10d)+(a+32d)=(2a+42d)
43(2a+42d)/2=2967=>(2a+42d)=2967*2/43=138

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(3 years ago) "Other"

solution of quastion

Reply Like? Yes | No (1)

(3 years ago) "Other"

Keshav runs a factory of 210 employes in each 3 shift 80 emp are required no one is allowed to work more than 16 hrsin a day how many emp are required to work 16 hrs in a day

Reply Like? Yes | No

(3 years ago)

80*3 = 240 employees needed
We have 210
So 240-210 = 30 employees need to work double shift
Cross check: 180*8+30*16=1920 hours
240*8 = 1920 hours
So 30 is the answer

Like? Yes | No

(4 years ago) "Other"

We know that the vertices of a quadrilateralare 2, 3, 5, and 6 cm, respectively,from a point P. What is the largest possible area of this quadrilateral?

Reply Like? Yes | No

(3 years ago)

Lets divide the area into 4 triangles
Area of triangle = 1/2 * base * height
So total area for right angle triangles are:
0.5*(2*3+3*5+5*6+6*2) = 31.5cm^2
If we diminish or expand any of the portions we eventually fall into same bucket I guess, so I think 31.5cm^2 should be the answer, all suggestions are welcome. Thanks.

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(4 years ago) "Other"

give me apportunity

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(3 years ago)

What exactly apportunity means? Can you be more specific?

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(4 years ago) "Other"

Twenty five sets of problems on Data Interpretation– one each for the DI sections of 25
CATALYST tests were prepared by the AMS research team. The DI section of each CATALYST
contained 50 questions of which exactly 35 questions were unique, i.e. they had not been used in
the DI section of any of the other 24 CATALYSTs. What could be the maximum possible number
of questions prepared for the DI sections of all the 25 CATALYSTs put together?
(Can anyone help by explaining the solution to this question)

Reply Like? Yes | No

(3 years ago)

Let me try to understand the question:
25 set of papers
50 in each with 35 distinct questions
Did I understand the question correctly?

If yes, the answer is: 35*25 = 875 questions.

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(4 years ago) "Other"

Why 0!=1 ?
Please help me

Reply Like? Yes | No

(4 years ago)

n! = n*(n-1)!
1! = 1*(1-1)!
1! = 1*0!
As 1! = 1, hence 0! = 1

Like? Yes | No

(4 years ago)

We know that n! = n(n-1)(n-2)(n-3).....3(2)(1) which means that
n! = n(n-1)!
Dividing both sides of the equation by n, we have
(n - 1)! = n!/n
Using this fact, we can check the following pattern.
4! = 5!/5 = {(5)(4)(3)(2)(1)}/5 = 24
3! = 4!/4 = {(4)(3)(2)(1)}/4 = 6
2! = 3!/3 = {(3)(2)(1)}/3 = 2
1! = 2!/2 = {(2)(1)}/2=1

Now, we go to 0!
0! = 1!/1 = 1

Like? Yes (1) | No

(4 years ago) "Other"

Like and subscribe my Youtube channel
Asif Iqbal
Maths class 10th and 9th Lectures
https://youtu.be/s7qPmsPs5bA

Reply Like? Yes (1) | No

(4 years ago) "Other"

Ten years ago,the average of family of four members was 24 years.Three children having been born,the average age of family is same today.What are the present ages of children if two children are identically twins and differ by two years from the younger one?

Reply Like? Yes | No

(4 years ago)

24×4 =96 + 4×10 = 136
current age = 24×7 = 168
hence children age = 32
2A + A - 2 = 32
A = 34/3 = 11.33 not possible
data is wrong as child can not be older than 10 years

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(4 years ago) "Other"

hi ,my self Ritik Rathore want to place in a core organisation of civil engineering and groom my self .

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(4 years ago) "Other"

Hi, my name is Alister james lives in Delhi and doing my education in creativethinksmedia want to become an engineer.

Reply Like? Yes (1) | No

(4 years ago) "Other"

hello my name in vuresakunthala iam teacher in private school now free because corona holidays now i need job at home any on help me thq

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(4 years ago) "Other"

here are 20 balls which are red, blue or green. If 7 balls are green and the sum of red balls and green balls is less than 13, at most how many red balls are there?

Reply Like? Yes | No

(4 years ago)

7 balls are green
sum of red balls and green balls is less than 13
7 + R < 13
=> R < 6
Hence at most 5 red balls are there

Like? Yes | No

(4 years ago) "Other"

if the tank is half fulled and set X and set Y are closed how many minutes will it take for set Z to empty the tank if alternate taps of set Z are closed

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(4 years ago)

X, Y & Z details missing

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(4 years ago) "Other"

The number of 5-digit numbers that can be formed from 4,2,0,7 and 3

Reply Like? Yes | No

(4 years ago)

5! is the answer

Like? Yes | No (2)

(4 years ago)

4*5*5*5*5 bcoz 0 cant be at first place

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(4 years ago)

Assuming repetition allowed - 1st Digit can be in 4 ways - Rest 4 can be in ways Hence 4*5*5*5*5 = 2500
Assuming repetition mot allowed = 4*4! = 4 * 24 = 96

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(4 years ago) "Other"

What is the referral code

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(4 years ago) "Other"

please help me in tcs nqt 2021

Reply Like? Yes (2) | No

(4 years ago) "Other"

got placed in infosys

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(4 years ago) "Other"

Three marketers distribute their products in a colony for pilot testing. Marketer A distributes
150 Items to the people equally and then was left with a few items. Marketer B distributes 270
Items to the people equally and then was left with the same number of Items as the number left
with Marketer A. Marketer C distributes 320 items to the people and is left with the same
number of items as the number left with Marketer A. What is the maximum possible number of
people in the colony?

Reply Like? Yes (1) | No

(4 years ago)

Let q are the no of people
150=aq+r----(1)
270=bq+r----(2)
320=cq+r-----(3)
Eqn. 2 -1=q(b-a)=120
Eqn.3-2=q(c-b)=50
Eqn.3-1=q(c-a)=170
H.c.f of all these is 10
Hence the members are 10.

Like? Yes (1) | No

(4 years ago) "Other"

A ball is dropped from a height of 144 m and it rebounds to two thirds of the height from which it falls. if it continues to rebound, what distance will the ball have travelled before coming to rest?

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to (4 years ago) "Other"

hey surbhi
how u get placed

Reply Like? Yes (1) | No (2)

to (4 years ago) "Other"

oh gosh,
are u placed in the company?
if not leave it.
and if yes then please let me know how u get placed?

Reply Like? Yes | No (1)

(4 years ago) "Other"

2 7 19 62 493...next no?

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(4 years ago) "Other"

Important Math questions and it's solutions.

Reply Like? Yes | No (1)

(4 years ago) "Other"

How would you dynamically allocate a one-dimensional and
two-dimensional array of integers?

Reply Like? Yes | No

(4 years ago)

Use loops to iterate through array
And use available random generator functions to allocate any value, dynamically if you are getting values from any where that will work.
Please give more information if you are looking for anything else.

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(4 years ago) "Other"

Adarsh is preparing for a competitive exam. During his practice for the same, he comes across a sample paper which contains 12 yes/no type questions and 12 multiple choice questions, each with four possible answers. In how many distinct ways can Ankit solve the paper?

Reply Like? Yes | No

(4 years ago)

244,672,066 ways
Yesno can be answered in 3 ways -> YesNoNone
Similarly MCQ can be answered in 5 ways
= (3^12)+(5^12)

Like? Yes | No (1)

(4 years ago)

@varun - both need to be multiplied rather than addition.

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to (4 years ago) "Other"

Can please share any resource to learn quantitative aptitude or anything regarding maths please, I want to learn

Reply Like? Yes | No

(4 years ago)

We can find many question and answers in the website by browsing, example at: https://m4maths.com/placement-puzzles.php?SOURCE=maths
You can try to solve the unsolved one as well which helps in learning

Like? Yes | No

(4 years ago) "Other"

Which of the following statements is/are true about locks in database management’?
1. Livelock and Deadlock are same.
2. Phase Locking has 2 stages namely- Expanding phase and Contracting phase.
3. Read Lock can be assigned to inﬁnite transactions simultaneously.

Reply Like? Yes | No

to (4 years ago) "Other"

hi mam i had doudt about probability that sum of two dice are thrown, but sum o two dice are divisble by 4 and 6..i know the answewr is 7/18..
i need the clear explanation, means in a logical way
by adding all the sequence i get 16/36 means 8/18
sum of them are 1,3 /3,1/2,2/ and 1,5/2,4/3,3/4,2/5,1/4 and
these are the only combination i get 4 and 6 by adding of two dice
explain me in soon at email rahimkhan341341@gmail.comeven u
thnaking you.. not only her even u can also share the answer at email..

Reply Like? Yes | No

(2 years ago)

Condition should be.... Sum of two dice is divisible by 4 or 6.
Possible sums are 4,6,8,12.
Possible combinations to meet given conditions = 14
So probability =14/36= 7/18

Like? Yes | No

(4 years ago) "Other"

consider expression (3+x+x^2x^3x^4)^4=p0+P1x+p2x^2+.....P16x^16. Find value of p0+p1+p15+p16

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(4 years ago) "Other"

find the grammatical error i was so surprised that(b) i told me i was imagining things (c) but later others confirmed that they too had seen the same sight

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(4 years ago)

I said I was imagining things

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(4 years ago) "Other"

In how many ways one or more than one fruit, can be selected from 6 varieties of fruits given that there are 5 fruits of each variety?

Reply Like? Yes | No

(4 years ago)

(1) Lets just first select from 1 variety,
In 5 ways one or more of same variety can be picked {1,2,3,4,5}
We have 6 such varieties

(2) Now lets go to second variety,
Additionally,
Picking from second variety can be done in 6 ways including picking zero {0,1,2,3,4,5,6}
And we have 5 such extra varieties
= 5*6*6*5 = 900

Like? Yes | No

(4 years ago) "Other"

Two articles A and B, with the same marked price were sold at 15% and 12% discounts respectively. Percentage of the profit earned on articles A and B was 6.25% and 20% respectively. The cost price of article B was Rs.160 less than the cost price of article A. Find the marked price of the each article.

Reply Like? Yes | No

(4 years ago)

Let the CP of A=x+160 and B=x. Marked Price of A and B=P.
Then, SP of A = P*85/100 = (106.25/100)* (x+160) ---> 17P = (x+160)*21.25 ---(i)
SP of B = P*88/100 = (120/100)*x ---> 11P = 15x ---(ii)
Solving (i) & (ii), we get Marked Price = P=2400 and CP of B=x=1760, CP of A=(x+160)=1920

Like? Yes | No

(4 years ago) "Other"

how many three digits numbers can be formed using 2,3,4and5 with digits being repeated?

Reply Like? Yes (2) | No

(4 years ago)

Unit place has a choice of 4 numbers
Similarly tens,hundredth place has a choice of 4 numbers each
= 4*4*4 = 64

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(4 years ago) "Other"

3) What will be the output of the following pseudocode?
For input a = 8 & b = 9.
Function(input a, input b)
If(a < b)
return function(b, a)
elseif(b != 0)
return (a + function(a,b-1))
else
return 0

a) 56
b) 78
c) 72
d) 68

Reply Like? Yes | No

(4 years ago)

The answer is option (c) , i.e , 72

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(4 years ago) "Other"

Hi, looking for feedback regarding the following question:
There are 500 candies. If 350 have sprinkles and 300 have chocolate chips, and at least 60 have neither sprinkles nor chocolate chips, the number of candies that have both is in this range:
a)40 and 120
b)80 and 180
c)180 and 320
d)210 and 300
e)300 and 350
This question is from this site and I've also placed my reasoning/solution for it.
Any help will be most appreciated.
Joy

Reply Like? Yes | No

(4 years ago)

It is 210 and 300
Total candies 500
Out of these candies with both maximum is 300. Since chocklet chips is subset to sprinkles.
60 is neither of them. So either of them are 500-60=440
Now minimum =350+300-440=210
So it will be 210 and 300

Like? Yes (2) | No

(4 years ago) "Other"

Today is my first day on this site. and I m very excited about learning and also join this site. I hope I do really well and got a placement.

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(4 years ago) "Other"

In how many ways can a team of 5 persons be formed out of a total of 10 persons such that 1. Two particular persons should be included in each team? If any team?
2. two particular persons should not be included in any team? If each team?

Reply Like? Yes | No

(4 years ago)

1.8C3=56
2.8C5=56

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(4 years ago) "Other"

Salaams:
My work for us here as first timer is. Permutation and Combination.
Permutate and Combine the numbers below into 7 groups you can, viz;
7539162 Good luck!

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(4 years ago) "Other"

At the end of the day all the animals, birds, insects receive their daily allowance. If the eagle 🦅got £45, the spider 🕷 earned £71, a bee 🐝 was given £27. How much money would a kangaroo 🦘get?

Reply Like? Yes | No (1)

(4 years ago) "Other"

Solve the following question based on the information provided:
i.Six students A, B, C, D, E and F participated in a self-evaluation test of Quants and Data Interpretation (D.I).
ii.The total marks of A in Quants was just above C and in D.I. just above F.
iii.B was just above C in D.I. but he scored less than D in Quants.
iv.F got more marks than D and E in D.I. but did not perform as well in Quants as in D.I. as compared to D and E.
v.No one is in between C and D in Quant and C and A in D.I.
Which of the given statements is not necessary to answer the questions?

A)(ii)
B)(iii)
C)(iv)
D)All are necessary

Reply Like? Yes | No

(4 years ago) "Other"

whatsapp@ +27638104141 love spells in Málaga,Sevilla,Barcelona,Madrid,Valencia,Calgary,Edmonton,Vancouver,Winnipeg,Ottawa,Toronto,Montreal

Reply Like? Yes | No

(4 years ago) "Other"

hey, there I am Soumen Pal, pursuing my master's degree from Visvabharati University in social science. Is there any platform for me in the government sector?

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(4 years ago) "Other"

Dear Admin,
Please give proper data while making a daily puzzle. ( refer Today's puzzle dated 06.07.2020)
Is it possible to have age difference of 9 years only between daughter and mother?
One year ago, there ages were 3 years and 12 years.
Please ....................

Reply Like? Yes (1) | No

(4 years ago) "Other"

Find the product of all the factors of 3^16

Reply Like? Yes | No (1)

(4 years ago)

1x3x3^2x3^3.......................x3^16=3^136

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(4 years ago) "Other"

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(4 years ago) "Other"

Buy High Quality Counterfeits Bank notes, Real/Fake Passports, Drivers license, Id cards, Visas, Etc... jayroy011@hotmail.com or Whatsapp +27639356786

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to (4 years ago) "Other"

i got answer 1:1 but there is no option

Reply Like? Yes (1) | No

to (4 years ago) "Other"

thank u sir can u please solve remaining problems?

Reply Like? Yes (1) | No

(4 years ago) "Other"

Two alloys contain zinc and copper in the ratio of 2 : 1 and 4 : 1. In what ratio the
two alloys should be added together to get as new alloy having zinc and copper in
the ratio of 3 : 1

Reply Like? Yes (1) | No

(4 years ago)

Let the ratio is x:y
(2x+4y):(x+y)=3:1
2x+4y=3x+3y=>x=y
Now x:y=1:1

Like? Yes | No

(4 years ago) "Other"

How many Kg ot wheat @ Rs. 14 per kg should be mixed with 32 kg of wheat @ Rs
22 per kg so that there is a profit of 25% by selling the mixture @ Rs 23.90 per kg

Reply Like? Yes | No (1)

(4 years ago)

Ans: 18 kg

Let x kg of wheat costing Rs. 14/kg is mixed, then (x*14 + 32*22)/(x+32) = 23.9*(100/125)
(14x + 704) / (x+32) = 19.12
14x + 704 = 19.12x + 611.84
5.12x = 92.16
x = 18

Like? Yes | No

(4 years ago) "Other"

Two types of rice (type 1 and type 2) were mixed in the respective ratio of 1 : 3.
The mixture was then sold @ 75.60 per kg to gain a profit of 20%. If the price of
type 1 rice is Rs. 75 per kg, what is the price of type 2 rice per kg

Reply Like? Yes | No

(4 years ago) "Other"

Gold is 19 times as heavy as water and copper is 9 times as heavy as water. In
what ratio should these be mixed to get an alloy 15 times as heavy as water.

Reply Like? Yes (1) | No

(4 years ago)

Required ratio = (15-9)/(19-15) = 6/4 = 3/2
Therefore, these should be mixed in the ratio 3:2.

Like? Yes | No

(4 years ago) "Other"

Does anyone think that the prize system of today's puzzle needs to be changed and it needs to return the earlier system of distribution of prize amount. Whoever wants to win the prize needs to compete with other candidates. Otherwise there is no benefit of becoming topper of the week again if you already won a prize in a month.

Reply Like? Yes (3) | No (1)

(4 years ago) "Other"

In what respective ratio must water be mixed with juice costing Rs 16 per litre to
obtain a mixture worth Rs 12 per litre ?

Reply Like? Yes (1) | No

(4 years ago)

Water. Juice
0 -------------------------- 16
12
(16-12). ---------------- (12-0)
=4 =12
Therefore, ratio of water & juice = 4 : 12 = 1 : 3

Like? Yes (3) | No

to (4 years ago) "Other"

22000 is correct

Reply Like? Yes | No

(4 years ago) "Other"

Select the right option from the given alternativesKPQR:LRTV:DGHY:?
1 point
A) EIKC
B) ETKC
C) EJKD
D) EHKD

Reply Like? Yes | No

(4 years ago)

Answer is : EIKC (Option A)

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(4 years ago) "Other"

20% of the people own only two cars each, 40% of the remaining, own three cars each and the remaining members own only one car each. Which statement is true ?

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(4 years ago) "Other"

Vedik ganit
https://youtu.be/YzFMYk4s2JE

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(4 years ago) "Other"

For today's puzzle,
CP comes out to be Rs. 28000.
Sp is Rs. 5000.
Loss= Rs. 23000..nobe of given options
But answer has been accepted by calculating loss difference of two selling prices.
What a murder of maths!

Why to calculate cp, if not required to calculate loss.
Please think, think and think if pissible.

Reply Like? Yes (6) | No

(4 years ago)

Good observation.
I think Site administrators are busy somewhere else due to lockdown.
or
Puzzles are being checked by Kirana merchants who are inable to open shops and they compare loss with max sale price (MSP).

Please check and respond .

Like? Yes (3) | No

(4 years ago)

Good observation.
I think Site administrators are busy somewhere else due to lockdown.
or
Puzzles are being checked by Kirana merchants who are unable to open shops and they compare loss with max sale price (MSP) to be expected or max gain possible.

Please check and respond .

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(4 years ago)

Answer should be Rs. 23000/-
option 10. None of these

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(4 years ago) "Other"

best placement questions ...thank u m4maths

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(4 years ago) "Other"

In a class if 1 is absent the rest of them can be divided into 6 equal groups and if two are absent can be divided into 7 equal groups. Find the minimum number of students in the class

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(4 years ago)

6*6=36
If we assume the number is 37 then
37-1=36 divisible by 6
And 37-2=35 divisible by 7

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(4 years ago)

Let the number of students be 'x' then x-1=6y and x-2=7z
=> 6y+1 = 7z+2 or 6y - 7z = 1
Which is true for y=6, z=5
So, minimum number of students=6y+1 or 7z+2 = 37

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(4 years ago) "Other"

Find the largest 2- digit number which when divided by 2,3 and 5 leaves remainder 1, 2 and 4....Any short trick please.

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(4 years ago)

Calculate the l. C. M
That is 30 , 30+4=34 when divisible by 3 gives one remainder but does got go with 2,5 . So the next number can be 37. It helds all the option

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(4 years ago) "Other"

https://en.m.wikipedia.org/wiki/File:FCOC.jpg

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(4 years ago) "Other"

https://en.m.wikipedia.org/wiki/File:FCOC.jpg

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(4 years ago) "Other"

MADAN=CODPC
REENA=.....?

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(4 years ago)

MADAN=CODPC
REENA=.....?=GTECP

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to (4 years ago) "Other"

Please help with this problem.
If two numbers are divided by a dividor produce remaindes 3 and 4, but then the sum of the numbers is divided by that divisor gives remainder 2. Find the divisor.

Reply Like? Yes (1) | No

(4 years ago)

Ans=5

Let the divisor be a, first no. be x and second no. be y, then in given 3 conditions
X = ak + 3 —(i)
y = al + 4 —(ii)
x+y = am + 2 —(iii)
Adding (i) & (iii), and Substituting x+y in (iii), we get (ak+3) + (al+4) = am+2
a(m-k-l) = 5
Prime factorization gives a=5 or 1
As divisor cannot be 1 in above given conditions, so divisor a=5.

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(4 years ago) "Other"

BIHAR=SDMPK
PATNA=.....?

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(4 years ago)

answer tell me please

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(4 years ago) "Other"

NUMBER =UIGSBY
SECOND=......?

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(4 years ago) "Other"

DISTURB=FRANTIC
DTWVUKF=.......?

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(4 years ago) "Other"

where should i start to prepare for aptitude?

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(4 years ago) "Other"

Please give solution.
जब कोई व्यक्ति 60 km/hr की गति से चलता है तो वह सुबह 11:00 am बजे घर पहुंचता है . जब वह 32 km/hr की गति से चलता है तो वह दोपहर 12:00 pm बजे घर पहुंचता है. 46 km/hr की सवारी करने पर वह किस समय घर पहुंचेगा, यदि दिया गया है कि वह प्रत्येक दिन सुबह 9:00 am बजे अपनी यात्रा शुरू करता है
1)11:30 am 2)11:45 am 3)11:24 am 4)11:36 am

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(4 years ago) "Other"

How can we express a rational number as a sum of an integer and a rational number?

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(4 years ago)

5/4 = 1 + 1/4
where 5/4 and 1/4 are rational numbers, and 1 is integer

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to (4 years ago) "Other"

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to (4 years ago) "Other"

Please explain, assistant pipe ha ya admi ?

A barrel full of beer has 2 taps one midway, which draws a litre in 6 minutes and the other at the bottom, which draws a litre in 4 minutes. The lower tap is normally used after the level of beer in the barrel is lower than midway. The capacity of the barrel is 36 litres. A new assistant opens the lower tap when the barrel is full and draws out some beer, As a result the lower tap has been used 24 minutes before the usual time. For how long was the beer drawn out by the new assistant?
Ans 16

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(4 years ago) "Other"

if y = log x(1+x), then x = ?

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(4 years ago) "Other"

The price of sugar increases by 20%, by what % should a housewife reduce the consumption of sugar so that expenditure on sugar can be same as before?

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(4 years ago)

16.66%

Let initial consumption=100 & price=100, then expenditure=100*100=10000
If new consumption=x & price=120, then for same expenditure, 120x=10000
=> x=83.33
So, % reduction=100-83.33=16.66

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to (4 years ago) "Other"

the students of a class appeared for an exam which had 200 questions. Each correct answer was awarded 2 Marks and for each wrong answer one-third of a mark was deducted. two student answered all the question in it. the first student got the maximum possible marks and the second student got 175 marks less than him. find the number of questions correctly answered by the second student. 1)115 2)125 3)135 4)145 ) none of.
Please solve

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(4 years ago)

2) 125

Maximum possible marks, 1st student got = 2*200 = 400
.'. Marks of 2nd student = 400 - 175 = 225
Let for 2nd student, correct answers=x and wrong answers=y
Then, x + y = 200 ---(i) and 2x - y/3 = 225 ---(ii)
Solving equation (i) & (ii), we get x=125, y=75
Hence, 2nd student solved 125 correct answers.

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(4 years ago)

In a game of 80 points, A can give B 5 points and C 15 points. then how many points B can give C in a game of 60?
Devendra can you give brief Sol for this

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to (4 years ago) "Other"

Two cars starts from point A and B to B and A respectively. They cross each other in 1.2 hour and the first car reaches A at 1 hour before the second car reaches B. If the distance between A and B is 50 km, what is the speed of the slower car? 1)20km/hr 2) 10km/hr 3)15km/hr 4)25km/hr........ Which is correct questions in both of. Please solve if any is correct please 🙏😊

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(4 years ago)

Speed of the slower car=16.66 km/hr

Let the speed of the car starting from point A and B be a and b km/hr.
Given, car starting from B reaches A, 1 hour early => Car starting from A is slower, so we have to find 'a'
As car cross each other in 1.2 hrs => 50/(a+b) = 1.2 => a+b = 125/3 ---(i)
Time difference of cars reaching B and A = 50/a - 50/b = 1 ---(ii)
Now substituting, b=125/3 - a from eqn. (i) into (ii), we get 3a² - 425a + 6250 = 0 ---(iii)
(3a-50) (a-125) = 0
a=50/3, a=125, (Ignoring a=125 as with this speed two cars cann't cross each other in 1.2 hrs)
Therefore, speed of slower car=50/3=16.66 km/hr and faster car=25 km/hr.

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to (4 years ago) "Other"

Two cars starts from point A and B to B and A respectively. They cross each other in 1 hour and the first car reaches A at 5/6 hour before the second car reaches B. If the distance between A and B is 50 km, what is the speed of the slower car? 1)20km/hr 2) 10km/hr 3)15km/hr 4)25km/hr

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to (4 years ago) "Other"

Sheela, Sandhya and jyotsna can type a page in in 10, 15 and 18 minutes respectively. they decided to work together for equal time to type a document which contains 980 pages. how many pages are typed by jyotsna ? 1)280 2)275 3)245 4)350 5)none

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(4 years ago)

3) 245

In 1 min, individually Sheela, Sandhya and Jyotsna can type 1/10, 1/15, 1/18 pages respectively.
Together in 1 min they can type 1/10 + 1/15 + 1/18 = 2/9 page.
For 980 pages time required = 980/(2/9) = 4410 min.
So, pages typed by Jyotsna in 4410 min = (1/18)*4410 = 245

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to (4 years ago) "Other"

vimal alone can do a piece of work in 36 days. the time taken by vimal in completing 1/6th of the work equals the time taken by Gopi to complete 2/5th of the same work. in how many days can they both complete the work if they work together?

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(4 years ago)

10 (10/17) days

Days required by Vimal=36. So Vimal can complete 1/6 of the work in (1/6)*36=6 days.
If Gopi takes 'x' days for same work, then days required for 2/5 of work=2x/5=6
=> x=15
Thus 1 day's work of Vimal & Gopi = 1/36 + 1/15 = 17/180
Hence, required days = 180/17 = 10 10/17

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to (4 years ago) "Other"

, Q, R and S are four friends and they are working independently on a work. R can do the work in M days, whereas S can do the same work in 2M days. R started the work and worked for only 144/7 days. then, he was replaced with S, who completed the remaining work in the same time as P and Q working together would finish the entire work. the efficiency ratio of P and Q is 4:3. if P and Q are working on alternate days, with P being first, the work will finished in 41 days.

1)in how many days can R individually complete the total work?

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(4 years ago) "Other"

P, Q, R and S are four friends and they are working independently on a work. R can do the work in M days, whereas S can do the same work in 2M days. R started the work and worked for only 144/7 days. then, he was replaced with S, who completed the remaining work in the same time as P and Q working together would finish the entire work. the efficiency ratio of P and Q is 4:3. if P and Q are working on alternate days, with P being first, the work will finished in 41 days.
1)in how many days can R individually complete the total work?

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(4 years ago)

216/7 days

Given R takes M days, so 1 day's work of R = 1/M
Similarly S takes 2M days, so 1 day's work of S = 1/(2M)
Work completed by R in 144/7 days = (1/M)*(144/7) = 144/(7M) and remaining work = 1 - 144/(7M)

Given, efficiency ratio of P and Q is 4:3.
Days required is inversely proportional to efficiency. Let P & Q can complete the work in x/4 & x/3 days respectively.
Given, P and Q are working on alternate days, with P being first, the work will finished in 41 days.
=> P works for 21 days whereas Q works for 20 days to complete the work.
=> 21*P's 1 day work + 20*Q's 1 day work = 1
21*4/x + 20*3/x = 1
=> x=144
Thus, P takes 144/4=36 days and Q takes 144/3=48 days to complete the work individually.
Now (P+Q)'s 1 day work = 1/36 + 1/48 = 7/144
.'. Together P & Q require 144/7 days = Days required by S to complete remaining work
=> (144/7)*1/(2M) = 1 - 144/(7M)
72/(7M) = (7M - 144)/7M
7M = 216
M = 216/7 = Days required by R individually to complete the work.

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to (4 years ago) "Other"

If 36 persons are engaged on a piece of work, the work can be completed in 40 days. After 32 days, only 3/4 th of the work was completed. How many more persons are required to complete the work on time?
A)10
B)8
C)9
D)12

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(4 years ago)

D)12

Work completed by 36 persons in 32 days=3/4
1 person's 1 days work = (3/4)/(32*36) = 1/1536
Now remaining work=1/4 and remaining days=40-32=8
So, required work in 1 day = (1/4)/8 = 1/32
Total persons required = (1/32)/(1/1536) = 48
Hence, additional persons = 48 - 36 = 12

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(4 years ago) "Other"

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