Mayur 15 years AGO

well explained, Dpin. The administrator has solved this puzzle with limited vision and simple approach in single plane only. In single plane maximum 5 triangles can be made by any 5th standard student as pointed out by Shikha. In the arrangement suggested by Dipin, 7 triangles can be made as desired in question for max no of triangles by arranging 9 equal sticks.

There is no constraint for arrangement of sticks in one plane only. I appreciate the approach of Shikha and Dipin. I hope that administrator will definitely consider the request of Shikha and think again with open mind to accept this solution gracefully.

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DIPIN 15 years AGO

Dear Siddhartha,

If u can visualise , then I shall try to explain here.

Make an equilateral triangle with 3 sticks in centre.... Now with 3 sticks on each side , make two triangular pyramids on each side of this base.

Each pyramid will have 3 triangles.

so total 3+3+1 ( common ) =7 triangles

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Siddharth Gupta 15 years AGO

"If all the 9 edges along length and breadth of a chess board are the tracks, then how many ways
are possible for a man to reach the diagonally opposite point starting from a corner in shortest track."
Sir ,please exlain me how to solve it.
I am not able to understand its solution.
Thanking you.

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S. Singh 15 years AGO

Thanks a lot, Shikha ji for raising this point.

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Dolly 15 years AGO

Administrator should check the answer for 10.3.10 puzzle again..

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sameera 15 years AGO

waiting for todays

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Dolly 15 years AGO

No doubt about it.

Shikha is right.

Although I have got marks for my answer , I agree with Shikha.

Really a perfect thinking.
Answer should be 7 triangles.

Administrator should check that .

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Jagat 15 years AGO

I think Shikha is right.

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sameera 15 years AGO

what the hell i didnt get it

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Mayur 15 years AGO

You can make 7 triangles with 9 sticks of equal size.

Pls check yesterday's puzzle.

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Khanna 15 years AGO

The answer for previous day puzzle 10.3.10 will be 7 triangles. pls check.

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Shikha 15 years AGO

Dear administrator,

It is not fair that you have deleted my entry from the discussion forum.

I humbly request you to check the question of 10.3.10 with open mind and right prospective to raise the level of this site from primary school to prestigious Institute level.

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Shikha 15 years AGO

Surprised to note that accepted answer for the qn of 10.3.10 ..... There are nine sticks of equal size. Maximum number of triangles formed by using these sticks in one attempt are....5...........

If this question is asked in a class of 5th standard , then this answer would have been acceptable and consolation prize/marks can be given to the student for this answer.

But when this question is asked at a site called www.m4maths.com with participating members from Elite organisations and ccolleges/schools , then answer is not correct.
..................
One can make maximum 7 triangles if thjese 9 sticks are properly used.
...........................
7 triangles can be achieved by making two triangular pyramids with common base.

Then each pyramid will have 3 triangles and one common base triangle making total 7 triangles.
........................
Please check it with open mind.
........................
You may not give marks to me for this qn but this ans of max 5 triangles is not correct.

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sameera 15 years AGO

waiting eagerly for todays question

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sameera 15 years AGO

this poor girl is also waiting dear freinds

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DIPIN 15 years AGO

Dear Administrator,

Thanks a lot for reconsidering the qn of 27.1.10.

Regards,

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Siddharth Gupta 15 years AGO

sir if you put the questions from different Management exams for "Today's Puzzele" and mention the exam in which it has been asked then I will really thankful to you......

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Shikha 15 years AGO

Thanks, But the credit goes to Dipin who pointed out this mistake on the same day.
I only tried to explain his point.

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Bawa 15 years AGO

congratulations, Dipin and Shikha.

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Shikha 15 years AGO

Dear Sir,

Please read the qn and options

Six men do a piece of work in 10 days with an effort of 6 hours per day. How many extra men are required for doing the work of double strength in 4 days with an effort of 5 hours per day

1) 3
2) 2
3) 1
4) 4
5) 5
6) 6
7) 7
8) 8
9) 9
10) 0


Your calculation for men reqd = (6*10*6*1)/(4*5*2) -6 = 9-6=3 persons, which is in options .... is not correct.

In this calculation you have not considered the work of double strength but men of double strength.
Normal work requires 6*10*6 = 360 man hours.
work of double strength will require 720 man hours.................
Total men required for doing the work of double strength( of 720 man hours ) in 4 days with an effort of 5 hours per day = 720/(4*5) = 36 men

Additional men reqd will be 36-6 =30 men.

Hope it is clear now.

Please excuse me for continuing discussion.

Your answer is only valid if all men now employed are of double strength and work is normal which only for 360 man hours.

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DIPIN 15 years AGO

Please check qn of 27.1.2010 and its solution again.

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Garima 15 years AGO

Shikha has raised a valid point.

Administrator should check it again.

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Jino Ann John 15 years AGO

Hey admin,
You ve nt yet replied 2 my query....luks lik u missd it...wt i wanna 2 knw is hw 2 change te employee details???tere is no optn 4 tat in settings?

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Shikha 15 years AGO

According to 27.1.2010 question,

Six men do a piece of work in 10 days with an effort of 6 hours per day. How many extra men are required
for doing the work of double strength in 4 days with an effort of 5 hours per day.


Answer given is option 1...3 persons.

Means total 9 persons are required to do the work of double strength ( as clarified by Administrator).

As per clarificatin , the answer should be

(6*10*6*2)/(4*5*2) -6 = 18-6=12 persons
which is not in options.

I think there must be additional men of double strength in addition to 6 men of normal strength ( as pointed out by Dipin)

Please check again.

Regards,

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Deepak 15 years AGO

Hi, last day (16 Feb). I submit first time login and submit right answer (7), that is showing in the next day (17 Feb) is correct. But there for my scoring is showing -1 point. So I request to site ownew pls see it.

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Kalidas 15 years AGO

Nice site.

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Tijo Jose 15 years AGO

I read about the bonus point rules... If someone joins by our referral, we get bonus for that day. What will happen, if someone joins on a Saturday or Sunday? Will we get those points still?

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Jino Ann John 15 years AGO

Hey,
First of all congrats 4 doing a grt job - am logging into my account after a long time - i was really surprzd by the new look..its really cool...

I wanna to edit my job details...but when i go to settings,i cant see there any text box or option to change employee details,only name,mail,alternate mail,mobile,DOB etc are there...what I should I do?

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Saranjit Singh 15 years AGO

Good observation, Dipin.

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S. Singh 15 years AGO

I think Dipin is right.

Sukham has already predicted that confusion on 5.2.2010.

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DIPIN 15 years AGO

when x=-1

x^2=1
x^3 = -1.

Difference between x^3 and x^2 =2
Difference between x^2 and x is 2.
so equal difference.
difference is always absolute.

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DIPIN 15 years AGO

Pls check the statement of question.

The difference of cube and square of a real number is equal to the difference of its square and itself.
Total number of such real numbers are ....

Sol given is 2.
based on explanation

x^3 - x^2 = x^2 - x
which is correct.

But please note according to given statement, there is one more equation that satisfies given condition which is

x^3 - x^2 = x - x^2

Here the question is about difference.

this equation gives one more value of x i.e. -1.

so answer should be 3... option 4.

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Sukham 15 years AGO

Statement of today's ( 5.2.2010) is also not clear.

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Bimal 15 years AGO

I think Dipin and Sukham are right.

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Sukham 15 years AGO

The ans for yesterday's qn should be 6 persons.

Normal 18 persons are reqd to complete work in 4 days with an effort of 5 hours per day.



Additional normal persons required = 12
Additional persons of double strength = 12/2=6

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DIPIN 15 years AGO

in additional to existing normal 6 persons, additional 6 persons of double strength are required to complete the work.

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DIPIN 15 years AGO

I think ans for qn of 27.1.10 should be 6 additional persons
( option6).

After waiting for the response of admin for whole day, I changed my ans from option 1 to option 6 considering the best possible interpretation of statement of question.


As per question of 27.1.10, the initial persons are of normal strength.

Only additional persons are of double strength .

Then additional persons ( of double strength ) required will be 9-6/2= 9-3=6 .

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Mayur 15 years AGO

I think the statement should be ...
......





Six men do a piece of work in 10 days with an effort of 6 hours per day. How many extra men of double strength are required for doing the same work in 4 days with an effort of 5 hours per day ?

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Shikha 15 years AGO

Question is not clear.

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DIPIN 15 years AGO

In today's ( 27.1.10) questiuon, there is one doubt.

Six men do a piece of work in 10 days with an effort of 6 hours per day. How many extra men are required for doing the work of double strength in 4 days with an effort of 5 hours per day ?


Is the total work of double strength as compared to first case ?

or

The additional men are of double strength than men in first case ?

or

All men for new work will be of double strength than men in first case ?

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Renjith C G 15 years AGO

why are there no new puzzles in placement puzzles section

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susmit 15 years AGO

Thanks PRERNA. PLEASE NOTE I AM SUSMIT AND NOT SUSHMIT. THANKS AGAIN

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Prerna 15 years AGO

Good going ,Sushmit.

Congrats in advance.

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ankush 15 years AGO

i think the time for new puzzle should be 00:00 hours

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ankush 15 years AGO

my college name is not present in the list....
it is motilal nehru national institute of technology allahabad..

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DIPIN 15 years AGO

For 30.12.2009 puzzle

in case of 79.6 %


Then diff of marks will be 63.

possible combinations are

18 and 81
29 and 92.

18 and 29 are less than passing marks (30).

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DIPIN 15 years AGO

Thanks, Tijo jose

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