ULAGUNATHAN 13 years AGO

Thank you so much to m4maths.com, It is very useful.. I can't say in words.. thanks , thanks.. thanks.. we can learn more puzzles.

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Karthick Babu 13 years AGO

Hi admin,
Thank you for considering valuable feedback.

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~Sandeep~ 13 years AGO

Hello Admin,
Could you please re-look into the options for puzzle dated :2011-03-17. Seems more than one option were correct.

~Sandeep.

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V.V.Ravi Teja 13 years AGO

thank u m4maths because of you and my co people who solved some complex problems for me...why because due to this only i got placed in tcs and hcl also........

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suman ghosh 13 years AGO

my college name is not present in the list of the colleges u given to select.
my college name is COLLEGE OF ENGINEERING & MANAGEMENT , KOLAGHAT

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~Sandeep~ 13 years AGO

Dear Admin,

I believe even option 3 for yesterdays puzzle is correct:
"Q. The total cost of 6 Kg. X, 5 Kg. Y and 7 Kg. Z is 125 rupee. Select any one of the following set of rates for X, Y and Z respectively."
Reason:
-------
Option 3 => 8, 7, 6
6*8+5*7+7*6 =125

Please Check!!!

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ULAGUNATHAN 13 years AGO

Dear Admin , If there is any possible to send the answer to the mobile number. ?

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pradeep kumar 13 years AGO

dear admin... plz provide the profile edit option which include the college name edit facility.because most of the member's college name was not in the list when they register for the membership so they have to choose the wrong college name.

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sandy 13 years AGO

my result is missing why

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sandeep reddy m 13 years AGO

THIS WEEK MY SCORE IS 75 BUT MY NAME IS NOT THERE IN RESULTS WHYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

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Saibal Sanyal 13 years AGO

My college name is not listed.Please enlist the name Guru Nanak Institute Of Technology Kolkata in your list.

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Aman 13 years AGO

Depending on consideration of definition/age of new born child, the probability may vary.

If new born child is considered as child of age 1 day only, then prob can be 1 or 1/2.
If new born child is considered as child of age 1 year , then prob can be different..

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priyanka jain 13 years AGO

my college name is not present in the list of the colleges u given to select.
my college name is IIMT engineering college meerut.

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MSReddy 13 years AGO

"A tail has occurred in a coin" then probability of getting an even number in the dice would be" only 6 possibilities

u clearly given a tail has occured then the no of possibilities are only 6.
in this case probability is 1/2.
may i know the reason why my name is not there in results.

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kewal 13 years AGO

Dear Admin,
Pls check again .
I agree with Mahesh and Reddy brothers.

In the statement of coin puzzle, it clearly indicates that Tail has already occured in a coin. It means now dice is to be thrown and coin is not to be flipped again.

So the probability of getting even no will be 1/2 as 3 favourable chances out of 6 possible chances.

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MSReddy 13 years AGO

saturday questions answer is 1/2
because u given that the coin toss tail then probability so ht is not occured
so 3 favour out of 6
probability=1/2

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sandeep reddy m 13 years AGO

in yesterdays puzzle u give that the toss is tail
then only six possibilities.
in which 3 are favor
so probability=3/6=1/2.

if u not given the tail then the answer of u is correct.
lot errors and bugs
what is the need to maintain this much of error.

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Mahesh 13 years AGO

A coin is thrown. If head comes, a coin will be thrown again, otherwise a dice will be thrown. A tail has occurred in a coin, then probability of getting an even number in the dice would be 1/2 and not 3/7. because tail has already occured.
now dice will be thrown.
then possible positions are 1,2,3,4,5,6 and favourable positions are 2,4,6....... 3 chances.

so probability =3/6=1/2

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C.T.Narayanan 13 years AGO

Its given tail has occurred. Ans is 1/2

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pradeep kumar 13 years AGO

Admin sir,

would you please tell me about the ""state support and against"" what it is and what its purpose here along with its rules ? waiting for your response.....

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himani 13 years AGO

Is there any previous year placement paper for birlasoft

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neena 13 years AGO

in yesterday's puzzle you asked for the next number in the given sequence ......... and that was 999999 and not the answer you are giving

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sandeep reddy m 13 years AGO

hi admin i solve some placement puzzles bt i added no points and also tell the procedure of scoring

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Abhishek Agarwal 13 years AGO

Sir i am doing engineering from MNNIT allahabad in computer science. But when i click on "CLICK FOR NOMINATION" for the online test it says that "This test is for engineering student". How can i participate.

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pradeep kumar 13 years AGO

sir, plz add the college "SRMCEM, Lucknow" in your college list in U.P.....sir more details of my college you may visit on ""www.srmcem.ac.in""

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krishna kumar gupta 13 years AGO

sir plz tell me that how update my college name now which was not early included in list but now dat has been included in list....plz

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CT.Subbu Lakshmi 13 years AGO

I answered 3 for wed question and i am not provided any marks.

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meda visweswararao 13 years AGO

how u r nominated the coleeges ,we want to write the exam but there is no my college nam ,how can we writw my college name is VELAGAPUDI RAMAKRISHNA SIDDHARTHA ENGINEERING COLLEGE ,VIJAYAWADA ,A.P

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Subhradip Biswas 13 years AGO

to admin : in the "todays puzzle" published on 10/2/2011, i think you just missed the line in the question : "IN THE ORDER as these letters come in ENGLISH ALPHABETS",i,e,in the order a>e>i>o>u . there is present a,e & u....so,the possible word by the letters must have to follow the order as said, = 3p3.
so the answer will be 5!*(3p3)=720

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Neeraj Gupta 13 years AGO

sir plz add the college "BBDNITM,LUCKNOW" U.P. in your college list.

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Neeraj Gupta 13 years AGO

sir plz add the college "BBDNITM,LUCKNOW" U.P. in your college list.

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C.T.Narayanan 13 years AGO

Thank you. I have sent my address.

For Wednesday;s puzzle, x=-1 will also satisfy the equation.

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Karthik Pandiyan 13 years AGO

Hello Admin ,
I have a question regards 08-02-2011 puzzle.

(x^x)^x – x^(x^x) = 0
How many values of x are possible?

Apart from solution for x = 1 and 2 , If we put x=-1 , that also satisfies above the condition
Please advice me on the above . Thanks in advance

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goutam Choudhury 13 years AGO

after giving right answer on 10-2-11 score show -1 pls clarify

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Dimple 13 years AGO

For yesterday puzzle

Number of methods will be

5! * 6p4

as 4 girls can be placed at the locations marked by X in

XBXBXBXBXBX

120*6*5*4*3=120*360

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pradeep kumar 13 years AGO

sir, plz add the college "SRMCEM, Lucknow" in your college list in U.P.

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krishna kumar gupta 13 years AGO

please add the college BBDNITM LUCKNOW U.P. in your college list ...

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DIPIN 13 years AGO

For yesterday's puzzle

How many methods are possible for arranging 5 boys and 4 girls in such a way that no 2 girls could sit together?

People here have considerede only one arrangement.
i.e.BGBGBGBGB

where as following arrangements also satisfy the given condition
GBGBGBGBB
GBBGBGBGB
GBGBBGBGB
GBGBGBBGB
BBGBGBGBG
GBBGBBGBG
and few more .

It is sure that 2880 is not correct for the given statement of question.
Such repeated errors/mistakes are damaging the reputation of such a nice site with so many intelligent members.

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Dimple 13 years AGO

I think answer given by site administrator for the puzzle (How many methods are possible for arranging 5 boys and 4 girls in such a way that no 2 girls could sit together?) is wrong.

Mr. Biswas has also accepted the same and commented as
there are 10 ways...
and 5!*4!*10=2880
i m not sure ...admin ...plzz update the correct answer clearly fr better understandin......plzzz!!!!

I think
The correct sol will be 5!*7p4
or 120*7*6*5*4.

Pls check and correct.

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Vadivelan M 13 years AGO

@ Prerna,

According to your explanation,

when the condition states three consecutive integers are not allowed, will that mean two consecutive integers also not allowed & also same integer not allowed??? that doesn't imply such way... sorry...

and for Friday puzzle, you can refer postings by MP and Jamat. As they said 52 is the correct answer.

The main thing is 5 boxes r similar so don't consider the order of boxes. Just check for splitting the letters among the boxes. 5,0,0,0,0 4,1,0,0,0 and so on... in that u have to consider which letters u r choosing as group. hope those 2 posts will show that splitting. Here i couldn't explain full scenario as it would be very lengthy. thanks.

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Dimple 13 years AGO

For today's puzzle

How many methods are possible for arranging 5 boys and 4 girls in such a way that no 2 girls could sit together?

I think correct answer is not given in options.

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susmit 13 years AGO

for the puzzle dated 4/2/11,
proper points are not alloted.

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Subhradip Biswas 13 years AGO

sir plzz add BIRBHUM INSTITUTE OF ENGINEERING & TECHNOLOGY...SURI......

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Prerna 13 years AGO

@ Vadivelan,

when even successive integers are not allowed, then how same integer can be allowed in Thursday puzzle?

Can you please explain the logic of your answer for puzzle dated 4/2/2011 for 5 letters and 5 boxes.

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MP 13 years AGO

Dear admin,

Pls check that my answer was option 10 but I am still getting -1 mark .

pls correct the status .

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